The mean of 10 numbers is 9, then the sum (total) of these numbers will be​

This question is incomplete, the complete question is;

To convert from the U.S. Customary (FPS) system of units to the SI system of units. A first-year engineering student records three separate measurements as 653 lb, 69.0 mi/h, and 293 × 10⁶ ft². Suppose this engineering student has to turn in the results, but the professor only accepts results given in SI units.  

Required:

What is the area measurement, 293 × 10⁶ ft², in SI units?

293 × 10⁶ ft² = ?km²

Answer:

the area measurement is  27.221 km²

Explanation:

Given the data in the question;

What is the area measurement, 293 × 10⁶ ft², in SI units

we are to the result of the measured area from ft² to km²

we know that;

1 meter = 3.2808 ft

1 km = 1000 m

1 ft = (1 / 3.2808)m

1 m = ( 1/1000 ) km

since our measured are is 293 × 10⁶ ft²

hence

A = 293 × 10⁶ × [ (1 / 3.2808)m ]²

A = 27221252.74 m²

A = 27221252.74 × [ ( 1/1000 ) km ]²

A = 27.221 km²

Therefore, the area measurement is  27.221 km²

Answer:

Answer: hello attached below is the question properly written

a) 2670 Kw

b) product will be made up of vapor and liquid

c) Product will be a super cooled liquid

Explanation:

mass Flow rate ( m ) = 175 kg/min

pressure = 1 atm

molecular weight of ethylene glycol ( mw ) = 62.07 g/mol

enthalpy of vaporization ( ΔHv ) = 56.9 KJ/mol

Using values from the table 8.1 related to the question

a) Determine the rate at which heat must be transferred from condenser

Using values from the table 8.1 related to the question

ΔH = 2670 Kw

b) If heat is transferred  at a lower temperature the product will be made up of vapor and liquid

c) If heat was transferred at a higher temperature the product will be a super cooled liquid

Answer:

the maximum bending stress in the strap is 3.02 ksi

Explanation:

Given the data in the question;

steel strap thickness = 0.125 in

width = 2 in

circular arc radius = 600 in

we know that, standard value of modulus of elasticity of L2 steel is; E = 29 × 10³ ksi;

Now, using simple theory of bending

1/p = M/EI

solve for M

Mp = EI

M = EI / p ----- let this be equation 1

The maximum bending stress in the strap is;

σ = Mc / I -------let this be equation 2

substitute equation 1 into 2

σ = ( EI / p)c / I

σ = ( c/p )E

so we substitute in our values

σ = ( (0.125/2) / 600 )29 × 10³

σ = 0.00010416666 × 29 × 10³

σ = 3.02 ksi

Therefore, the maximum bending stress in the strap is 3.02 ksi

Answer:

When you come up on a steady yellow traffic light you should always yield to cross traffic if you can yield safely. The flashing yellow light is there to inform drivers to be careful and to slow down.

Explanation:

hope it helped!

Answer:

can you translate

Explanation:

what Is that?

Answer:

False.

Explanation:

Project management can be defined as the process of designing, planning, developing, leading and execution of a project plan or activities using a set of skills, tools, knowledge, techniques and experience to achieve the set goals and objectives of creating a unique product or service.

Generally, projects are considered to be temporary because they usually have a start-time and an end-time to complete, execute or implement the project plan.

The fundamentals of Project Management includes;

1. Project initiation.

2. Project planning.

3. Project execution.

4. Monitoring and controlling of the project.

5. Adapting and closure of project.

Basically, the specifications of a project or manufacturing process outlines the minimum requirements and quality that are acceptable. Thus, it must be adhered to strictly in order to achieve a successful and desired outcome.

As a rule, it is essential to check at every stage of a project if the sponsor or customer requirements and expectations have been met regarding the quality of the project deliverables.

Answer:

The AGC circuit operates with an input voltage range of 60 dB (5 mV p-p to 5 V p-p), with a fixed output voltage of 250 mV p-p.

Explanation:

Answer:

37.33 grams

Explanation:

The missing information embedded in the idea section is attached in the image below:

The aim of this question is to determine the atomic wt. of Iron (Fe) from the hypothetic formula:

Fe₁O₁

Here, we know that the mole ratio can be written as:

[tex]\dfrac{O}{Fe}=\dfrac{1}{1}[/tex]

Suppose we assume that the atomic wt. of Fe = β(unknown)???

Then the grams of O and Fe that is contained in Fe₁O₁ can be expressed as:

For O:

1 × 16 grams of Oxygen = 16 grams of O

For Fe:

1 × β grams of Fe = β grams of Fe      

Now, let's take a look at the idea experiment, the mole solution can be computed as:

[tex]\dfrac{O}{Fe} = \dfrac{3}{2} \\ \\ \text{It implies that} \implies \dfrac{(3\times 16) \text{grams of O}}{(2 \times 56 ) \ \text{grams of Fe}}[/tex]

Equating both expressions above, we have:

[tex]\implies \dfrac{16}{ \beta} = \dfrac{3\times 16}{2\times 56}[/tex]

[tex]{ \beta} = \dfrac{(2\times 56)\times 16}{ 3\times 16}[/tex]

[tex]\mathbf{{ \beta} = 37.33 \ grams}[/tex]

Answer:

Explanation:

From the information given:

The instantaneous expression of the electric field in the wave is:

[tex]E(r,t)= (i_x \sqrt{3} -i_z) 2 \ sin (2 \pi*10^8t + 2 \pi x/3+2 \pi z /\sqrt{3} + 30 ^0) , \ V/m[/tex]

To determine the unit vector in line with the wave electric field, we take the first term in E(r,t) for [tex]I_E^\to[/tex] as:

[tex]I_E^\to = i_x \sqrt{3}-i_z \\ \\ I_E^\to = \dfrac{i_x \sqrt{3}-i_z}{\sqrt{3 +1}} \\ \\ \mathbf{ I_E = \dfrac{i_x\sqrt{3} -i_z}{2}}[/tex]

The amplitude is denoted by the numerical value after the first term, which is:

[tex]\mathbf{E_o = 2}[/tex]

The wavelength can be determined by using the expression:

[tex]\beta =\dfrac{2 \pi}{\lambda }[/tex]

from the given instantaneous expression:

[tex]\beta = \dfrac{2 \pi}{3}x+\dfrac{2 \pi}{\sqrt{3}}z[/tex]

[tex]\beta = \sqrt{\dfrac{2 \pi}{(3)^2}+\dfrac{(2 \pi}{(\sqrt{3})^2}}[/tex]

[tex]\beta = \sqrt{\dfrac{2 \pi}{9}+\dfrac{2 \pi}{{3}}}[/tex]

Factorizing 2π

[tex]\beta =2 \pi \sqrt{\dfrac{1}{9}+\dfrac{1}{{3}}}[/tex]

[tex]\beta =2 \pi \sqrt{\dfrac{9+3}{9*3}}}[/tex]

[tex]\beta =2 \pi \sqrt{\dfrac{12}{27}}}[/tex]

[tex]\beta =2 \pi \sqrt{\dfrac{4*3}{9*3}}}[/tex]

[tex]\beta =2 \pi \sqrt{\dfrac{4}{9}}}[/tex]

[tex]\beta =2 \pi\times {\dfrac{2}{3}}}[/tex]

recall from the expression using in calculating wavelength:

[tex]\beta =\dfrac{2 \pi}{\lambda }[/tex]

∴

equating both together, we have:

[tex]\dfrac{2 \pi}{\lambda }= 2 \pi\times {\dfrac{2}{3}}}[/tex]

[tex]\lambda = \dfrac{3}{2}[/tex]

λ = 1.5 m

In line with the wave direction; unit vector [tex]i_k[/tex] can be computed as follows:

[tex]i_k = - [ \beta_1x +\beta_2z]/\beta[/tex]

where;

[tex]\beta_1 = \dfrac{2 \pi }{3} \ ; \ \beta_2 = \dfrac{2 \pi }{\sqrt{3}} \ ; \ \beta = \dfrac{2 \pi \times 2}{3} ;[/tex]

∴

[tex]i_k = - \Big[\dfrac{2 \pi}{3}x + \dfrac{2 \pi}{\sqrt{3}} z\Big]\times \dfrac{1}{\dfrac{2 \pi *2}{3}}[/tex]

[tex]i_k = - \Big[\dfrac{x}{2} + \sqrt\dfrac{{3}}{4}} z\Big][/tex]

[tex]i_k = - \Big[\dfrac{1}{2}x + \sqrt{\dfrac{3}{4} }z\Big][/tex]

[tex]\mathbf{i_k = - \Big[0.5x +0.86 z\Big]}[/tex]

Answer:

a. 6.6 Mpsi

b. 5.64 Mpsi

c. i. 0.095  ii. -0.095

Explanation:

a. The true stress in tension is:

The true stress in tension, σ = σ'(1 + ε) where σ' = engineering stress in tension = 6 Mpsi and ε = engineering strain under tension = (L₁ - L₀)/L₀ where L₀ = gage length = 2 inches and L₁ = length at elongation under tension = 2.2 inches. So,  ε = (L₁ - L₀)/L₀ = (2.2 - 2)/2 = 0.2/2 = 0.1

So, σ = σ'(1 + ε)

σ = 6 Mpsi(1 + 0.1)

σ = 6 Mpsi(1.1)

σ = 6.6 Mpsi

b. The true stress in compression is:

The true stress in tension, σ₁ = σ"(1 + ε) where σ' = engineering stress in tension = 6 Mpsi and ε' = engineering strain under tension = (L₂ - L₀)/L₀ where L₀ = gage length = 2 inches and L₂ = length at elongation under compression = 1.818 inches. So,  ε' = (L₂ - L₀)/L₀ = (1.818 - 2)/2 = -0.182/2 = -0.091

So, σ₁ = σ'(1 + ε')

σ₁ = 6.2 Mpsi[1 + (-0.091)]

σ₁ = 6.2 Mpsi[1 - 0.091)

σ₁ = 6.2 Mpsi(0.909)

σ₁ = 5.64 Mpsi

c. The true strains in both tension and compression are :

i. The true strain in tension

The true strain in tension ε" = ㏑(1 + ε) where ε = engineering strain in tension = 0.1

So, ε" = ㏑(1 + ε)

ε" = ㏑(1 + 0.1)

ε" = ㏑(1.1)

ε" = 0.095

ii. The true strain in compression

The true strain in tension ε₁ = ㏑(1 + ε') where 'ε = engineering strain in compression = -0.091

So, ε₁ = ㏑(1 + ε')

ε₁ = ㏑[1 + (-0.091)]

ε₁ = ㏑(1 - 0.091)

ε₁ = ㏑(0.909)

ε₁ = -0.095

Answer:

a) Zero

b) the rate of entropy generation in the system's universe = ds/dt = 0.2603 KW/K

Explanation:

a) In steady state  

Net rate of Heat transfer = net rate of heat gain -  net rate of heat lost  

Hence, the rate of heat transfer = 0

b) In steady state, entropy generated  

ds/dt = - [ Qgain/Th1 + Qgain/Th2 - Qlost/300 K]

Substituting the given values, we get –  

ds/dt = -[5/1500 + 3/1000 – (5+3)/300]

ds/dt = - [0.0033 + 0.003 -0.2666]

ds/dt = 0.2603 KW/K

Answer:

a) 4-input XOR, input data-1001  = 0 Even parity Bit

b)  5-input XOR, input data-10010 = 0 Even parity Bit  

c) 6-input XOR, input data-101001 = 1 Even parity Bit

d) 7-input XOR, input data 1011011 = 1 Even parity Bit

Explanation:

a) 4-input XOR, input data-1001  ;  generates 0 Even parity Bit

b)  5-input XOR, input data-10010 ; generates 0 Even parity Bit  

c) 6-input XOR, input data-101001 ; generates 1 Even parity Bit

d) 7-input XOR, input data 1011011 ; generates 1 Even parity Bit

Attached below is the Logic circuits of the data inputs

78950W the answer

Explanation:

A 75- kw, 3-, Y- connected, 50-Hz 440- V cylindrical synchronous motor operates at rated condition with 0.8 p.f leading. the motor efficiency excluding field and stator losses, is 95%and X=2.5ohms. calculate the mechanical power developed, the Armature current, back e.m.f, power angle and maximum or pull out torque of the motor

A 75- kw, 3-, Y- connected, 50-Hz 440- V cylindrical synchronous motor operates at rated condition with 0.8 p.f leading. the motor efficiency excluding field and stator losses, is 95%and X=2.5ohms. calculate the mechanical power developed, the Armature current, back e.m.f, power angle and maximum or pull out torque of the motor

Answer:

d. Styrene

Explanation:

An alternating copolymer repeat unit types if the other is Styrene. The equation to calculate m is :

m = Mn / Dp

m = 100,000 / 2210 = 45.25g/ mol

alternating copolymer is chain fraction than of each repeat unit type then chain fraction is styrene and unknown repeat units.

Answer:

1 NAND gate

Explanation:

The minimum number of 2 input NAND gates that can be used to implement the combinational circuit = 1

The only true combinations conditions that can produce a false result ( i.e. condition/result different from the expected result as stated in the question )

Sensor 2 activated + Emergency switch pressed = False ( Line will keep moving )

Answer:

is there a picture of the figure?

Android provides a huge set of 2D-drawing APIs that allow you to create graphics.

Android has got visually appealing graphics and mind blowing animations.

The Android framework provides a rich set of powerful APIS for applying animation to UI elements and graphics as well as drawing custom 2D and 3D graphics.

1. Property Animation

2. View Animation

3. Drawable Animation

Answer:

The type of succession is:

Primary succession

Explanation:

This is a type of succession that occurs after a volcanic eruption or earthquake; it involves the breakdown of rocks by lichens to create new, nutrient rich soils.

Primary succession is one of the two types of succession we have. It begins on rock formations, such as volcanoes or mountains, or in a place with no organisms or soil.

Answer:

Calcium Chloride

Brine Wash

Drierite

Explanation:

Removal of small amounts of water from a polar solvent is Calcium Chloride

Removal of visible pockets of water from an organic solvent is Brine Wash

Storage of solvents or other materials in a desiccator is Drierite

Answer:

8.4627 m

Explanation:

Transmissivity( T ) = 300 m^2/day

Storativity( S )  = 0.0005

well radius ( r ) = 0.3m

Determine the drawdown in well at 100 days

Drawdown at 100 days = ∑ Drawdown at various period

We will use the equation : S = Q / U*π*T [ -0.5772 - In U ]  ----- ( 1 )

where : Q = discharge , T = transmissivity

             S = drawdown ,

U = r^2*s / 4*T*t  --- ( 2 )

r = well radius , S = Storativity, t = time period

i) During 0-20

U1 = r^2*s / u*π*t  = 1.875 * 10^-9

Input values into equation 1

S1 = 2.5885

ii) During 20-50

U2 = r^2*s / 4*π*t = 0.3^2 * 30 / u * 300 * 30 = 1.25 * 10^-9

input values into equation 1

S2 = 1.5854 m

iii) During 50 -90

U3 = r^2*s / 4*π*t = 9.375 * 10^-10

input values into equation 1

S3 = 4.2888 m

iv) During 90-100

U4 = 0

s4 = 0

Drawdown at 100 days = ∑ Drawdowns at various period

                                       = s1 + s2 + s3 + s4 = 2.5885 + 1.5854 + 4.2888 + 0

                                       = 8.4627 m

Answer:

For  lower disk :   V = e^θ​rω(0)/h  = 0

At the upper disk:  V = e^θ​rω(h)/h  = e^θ​rω

Hence The physical boundary conditions are satisfied

Explanation:

Velocity field ( V ) = e^θ​rωz/h

Upper disk located at  z = h

Determine the dimensions of the velocity field

velocity field is two-dimensional ; V = V( r , z )

applying the no-slip condition

condition : The no-slip condition must be satisfied

For  lower disk Vo = 0 when disk is at rest z = 0

∴  V = e^θ​rω(0)/h  = 0

At the upper disk  V = e^θ​rω  given that a upper disk it rotates at z = h

∴ V = e^θ​rω(h)/h  = e^θ​rω

Hence we can conclude that the velocity field satisfies the appropriate physical boundary conditions.

Answer:

In the clevis shown in Fig. 1-11b, find the minimum bolt diameter and the minimum thickness of each yoke that will support a load P = 14 kips without exceeding a shearing stress of 12 ksi and a bearing stress of 20 ksi.

127-clevis-double-shear-bolt.gif

Solution 127

Hide Click here to show or hide the solution

127-fbd-clevis-double-shear-bolt.gifFor shearing of rivets (double shear)

P=τA

14=12[2(14πd2)]

d=0.8618in → diameter of bolt answer

For bearing of yoke:

P=σbAb

14=20[2(0.8618t)]

t=0.4061in → thickness of yoke answer

Answer:

[tex]\gamma=0.122^oC[/tex]

Explanation:

From the question we are told that:

Word length[tex]n=14bit[/tex]

Full scale voltage of 100 mV

Thermo-couple shows:

[tex]0.5 mV\ at\ 50^oC[/tex]

[tex]3.052\ mV\ at\ 100^oC.[/tex]

Generally the equation for Average output voltage V_[avg} is mathematically given by

[tex]V_[avg}=\frac{3.052-0.5}{100-50}[/tex]

[tex]V_[avg}=0.05mv[/tex]

Since

[tex]Word lenght =14[/tex]

Therefore

[tex]Voltage\ steps=\frac{100}{2^{14}}[/tex]

[tex]Voltage\ steps=6.10*10^3mv steps[/tex]

Generally the equation for The required temperature resolution\gamma is mathematically given by

[tex]\gamma=\frac{100}{2^{14}*V_[avg}}[/tex]

[tex]\gamma=\frac{100}{2^{14}*0.05}[/tex]

[tex]\gamma=0.122^oC[/tex]

Answer:

Following are the program to the given question:

def calculate_storage(filesize):#definging a method calculate_storage that takes filesize as a parameter  

 block_size = 4096#definging block_size that holds value

 full_blocks = filesize//block_size#definging full_blocks that divides the value and hold integer part

 partial_block_remainder = filesize%block_size#definging partial_block_remainder that holds remainder value

 if partial_block_remainder > 0:#definging if that compare the value

   return block_size*full_blocks+block_size#return value

 return block_size*full_blocks#return value

print(calculate_storage(1))    # calling method by passing value

print(calculate_storage(4096)) # calling method by passing value

print(calculate_storage(4097)) # calling method by passing value

Output:

4096

4096

8192

Explanation:

In this code, a method "calculate_storage" is declared that holds a value "filesize" in its parameters, inside the method "block_size" is declared that holds an integer value, and defines "full_blocks and partial_block_remainder" variable that holds the quotient and remainder value and use it to check its value and return its calculated value. Outside the method, three print method is declared that calls the method and prints its return value.

Answer:

The molecular weight will be "28.12 g/mol".

Explanation:

The given values are:

Pressure,

P = 10 atm

  = [tex]10\times 101325 \ Pa[/tex]

  = [tex]1013250 \ Pa[/tex]

Temperature,

T = 298 K

Mass,

m = 11.5 Kg

Volume,

V = 1000 r

   = [tex]1 \ m^3[/tex]

R = 8.3145 J/mol K

Now,

By using the ideal gas law, we get

⇒ [tex]PV=nRT[/tex]

o,

⇒ [tex]n=\frac{PV}{RT}[/tex]

By substituting the values, we get

       [tex]=\frac{1013250\times 1}{8.3145\times 298}[/tex]

       [tex]=408.94 \ moles[/tex]

As we know,

⇒ [tex]Moles(n)=\frac{Mass(m)}{Molecular \ weight(MW)}[/tex]

or,

⇒        [tex]MW=\frac{m}{n}[/tex]

                   [tex]=\frac{11.5}{408.94}[/tex]

                   [tex]=0.02812 \ Kg/mol[/tex]

                   [tex]=28.12 \ g/mol[/tex]