The other name of eureka can

Answer:

Water > Box of books > Stone > Ball

Explanation:

We'll begin by calculating the potential energy of each object. This can be obtained as follow:

For stone:

Mass (m) = 15 Kg

Acceleration due to gravity (g) = 10 m/s²

Height (h) = 3 m

Potential energy (PE) =?

PE = mgh

PE = 15 × 10 × 3

PE = 450 J

For water:

Mass (m) = 10 Kg

Acceleration due to gravity (g) = 10 m/s²

Height (h) = 9 m

Potential energy (PE) =?

PE = mgh

PE = 10 × 10 × 9

PE = 900 J

For ball:

Mass (m) = 1 Kg

Acceleration due to gravity (g) = 10 m/s²

Height (h) = 20 m

Potential energy (PE) =?

PE = mgh

PE = 1 × 10 × 20

PE = 200 J

For box of books:

Mass (m) = 25 Kg

Acceleration due to gravity (g) = 10 m/s²

Height (h) = 2 m

Potential energy (PE) =?

PE = mgh

PE = 25 × 10 × 2

PE = 500 J

Summary:

Object >>>>>>>> Potential energy

Stone >>>>>>>>> 450 J

Water >>>>>>>>> 900 J

Ball >>>>>>>>>>> 200 J

Box of books >>> 500 J

Arranging from greatest to least, we have:

Object >>>>>>>> Potential energy

Water >>>>>>>>> 900 J

Box of books >>> 500 J

Stone >>>>>>>>> 450 J

Ball >>>>>>>>>>> 200 J

Water > Box of books > Stone > Ball

You're supposed to divide the mass by the volume, which is going to equal to 5

Answer:

It should be Mass, Gravity and Height

Explanation:

Answer:

t = 4.34 s

Explanation:

To get this, we need to calculate the time of each part for both vehicles.

In the case of the bicycle, we can calculate the time duration with it's acceleration:

a = Vf - Vo/t ------> t = Vf - Vo / a

But Vo = 0 so time:

t = 21 / 14 = 1.5 s

Doing the same with the car:

t = 49 / 8 = 6.125 s

With these values of time, we can calculate the distance covered by both vehicles during acceleration:

X = Vo*t + at²/2

X = at² / 2

With the bicycle:

X = 14 * (1.5)² / 2 = 15.75 mi

With the car:

X = 8 * (1.5)² / 2 =  9 mi

And now, we can also get the speed of the car, after the time of 1.5 s has passed.

V = 8 * 1.5 = 12 mi/h

Now we can actually write an equation with both data of the vehicles in function of the distance. We are going to say that "t" would be the time taken by both vehicles, to meet each other.

Distance covered by the bicycle = distance covered by car

Distance covered by the bicycle would be:

15.75 mi + 21t

Distance covered by car:

9 + 12t + (8t²/2)

Equalling both expressions:

15.75 + 21t = 9 + 12t + 4t²

4t² - 9t - 6.75 = 0

Solving for t, using quadratic expressions we have:

t = 9 ± √(9)² + 4*4*6.75 / 2*4

t = 9 ±√189 / 8

t = 9 ± 13.75 / 8

t₁ = 2.84 s

t₂ = -0.594 s

We are taking the positive time.

Then, the time where both vehicles meet, which is the same time interval when the bicycle is ahead of the car will be:

t = 2.84 + 1.5

Hope this helps

Answer:

The acceleration due to gravity at the location of the pendulum is 34.74 m/s².

Explanation:

Given that,

The length of a simple pendulum, l = 5.5 m

It makes 10.0 complete swings in 25 s.

Frequency of pendulum,

[tex]f=\dfrac{10}{25}\\\\f=0.4\ Hz[/tex]

The time period of a simple pendulum is given by :

[tex]T=2\pi \sqrt{\dfrac{l}{g}}[/tex]

Frequency,

[tex]f=\dfrac{1}{T}\\\\f=\dfrac{1}{2\pi \sqrt{\dfrac{l}{g}} }\\\\f=\dfrac{1}{2\pi}\sqrt{\dfrac{g}{l}}[/tex]

g is the acceleration due to gravity at the location where the pendulum is placed. So,

[tex]f^2=\dfrac{g}{4\pi^2l}\\\\g=f^2\times 4\pi^2l\\\\g=0.4^2\times 4\pi^2\times 5.5\\\\g=34.74\ m/s^2[/tex]

So, the acceleration due to gravity at the location of the pendulum is 34.74 m/s².

Answer:

Mixed in a smoothie it like it licked

Explanation:

a = 32.79 m/s²

F = = 26,232 N

Given

mass = 800 kg

velocity = 20 m/s

r = 12.2 m

Required

The acceleration

The net force

Solution

Circular motion :

a = v²/r

a = 20²/12.2

a = 32.79 m/s²

The net force⇒Centripetal force

F = mv²/r

F = 800 kg x 32.79 m/s²

F = 26,232 N

Answer:

N = 1364 N

Explanation:

given data

accelerate upward = 5.70 m/s²

mass = 88.0 kg

solution

normal force is in upward direction so, weight of the student in downward direction and acceleration is in upward direction so formula is express as

N - mg = ma        ...........................1

N = m × (g+a)

put here value

N = 88.0 × (9.8 + 5.70)

N = 1364 N

Answer:

(4) Its kinetic energy is a minimum.

Explanation:

Stone experiments a parabolic motion, which is a combination of horizontal motion at constant speed and vertical uniform accelerated motion due to gravity, where effects from air viscosity and Earth's rotation are neglected. Meaning that stone represents a conservative system.

When stone reachest highest point, horizontal velocity remains unchanged and vertical velocity is zero. Acceleration remains constant and different of zero. Hence, gravitational potential energy is a maximum and kinetic energy is a minimum.

Correct answer is: (4) Its kinetic energy is a minimum.

The highest point, that stone reaches its kinetic energy is a minimum. therefore the option 4 is correct.

Projectile motion -The motion of an object, thrown (projected) into the air is known as projectile motion.

(1) Its acceleration is zero-

When an object is at its highest point the acceleration will be equal to the gravitational force (9.8 m/sec squared). If we take air resistance into the account it will be slightly greater than the 9.8 meters per second squared but not equal to zero in any case. Hence, statement 1 is incorrect.

(2) Its acceleration is a minimum, but not zero-

At the highest point, the object will be at the one place where air resistance does not affect the object, and thus acceleration is exactly equal to the acceleration due to gravity and at this position, it will be the maximum. Hence, statement 2 is incorrect.

(3) Its gravitational potential energy is a  minimum-

At the highest point, the object will stop for the moment and have zero velocity. Thus it will have zero kinetic energy. Therefore total energy will have in the form of gravitational potential energy and which is maximum at this point. Hence, statement 3 is incorrect.

(4) Its kinetic energy is a minimum-

At the highest point the object will stop for the moment and have zero velocity. Thus it will have zero kinetic energy. Hence, statement 4 is correct.

At the highest point, that stone reaches its kinetic energy is a minimum. therefore the option 4 is correct.

For more about the projectile motion, follow the link below-

https://brainly.com/question/11049671

Answer:

0.125m

Explanation:

Given that:

Length of spring = 100m

Extension, e = 0.250

Recall :

F = ke - - - - (1)

Therefore, if spring is cut into 2 halves :

Then,

k = k1 + K2 ; since k1 and K2 are of equal length

Extension = e'

k = 2k

F = ke'

Then,

F = 2ke' - - - - - (2)

Equate (1) and (2)

ke = 2ke'

e = e'

0.250 = 2e'

0.250 / 2 = e'

e' = 0.125m

Answer:

6 * 10^5 N/m²

Explanation:

Given that :

Area of lid = 0.004m²

Force of block needed to keep the lid from being pushed off the container = 2000 N

Absolute Pressure = atmospheric pressure + force / Area

Force / Area = 2000 N / 0.004 m² = 500,000 = 5 * 10^5

Atmospheric pressure = 1.01325 * 10^5 N/m²

Absolute Pressure = (1.01325 * 10^5) + (5 * 10^5)

Absolute Pressure = 6.01325 * 10^5

= 6 * 10^5 N/m²

Kinetic energy = mv²

Therfore kinetic energy =14175 joule

Explanation:

Cheetahs can go from 0 to 60 miles per hour in just 3.4 seconds and reach a top speed of 70 miles per hour. While they are the fastest land animal in the world, they can only maintain their speed for only 20 to 30 seconds.

Answer:

making sense of a 3-d world from 2-d data

Explanation:

Answer:

1.5 * 10^-2 Tm^2

Explanation:

Electric Flux = B.A cos(theta)

B = 0.055 T

A = 0.32 m^2

theta = 30

Electric Flux = (0.055 T).(0.32 m^2).Cos(30) = 0.0152 = 1.5 * 10^-2 Tm^2

Answer:

lactose

Explanation:

Answer:The 50-kg has the greater potential energy because it has greater mass

Explanation:

Answer: Force of Gravity

Explanation:

Because if a force is applied to an object then the force of gravity will move the object.

Hope this helps you!

Answer:

10s

Explanation:

Horizontal velocity is the velocity of an object in an horizontal direction

The ball's horizontal velocity is approximately 33.078 ft./s

Reason:

The known parameter are;

The horizontal distance the footballer kicks the ball, d = 43 yards

The time after which the ball lands, Δt = 3.9 seconds

Required:

To find the velocity of the ball

Solution:

[tex]Velocity = \dfrac{Distance}{Time} = \dfrac{d}{\Delta t}[/tex]

Therefore;

[tex]Horizontal \ velocity \ of \ the \ ball, \ v_x= \dfrac{43 \ yard}{3.9 \ seconds} \approx 11.026 \ yd/s[/tex]

The ball's horizontal velocity, vₓ ≈ 11.026 yd/s

1 yard = 3 feet

[tex]11.026 \ yard = 11.026 \ yard \times \dfrac{3 \ feet}{yard} = 22.078 \ feet[/tex]

The ball's horizontal velocity, vₓ ≈ 33.078 ft./s

Learn more about horizontal velocity here:

https://brainly.com/question/14898646

Answer:

a. i. -4.65 m/s ii. -13.95 m/s b. 5.89 m c. 2.85 s

Explanation:

a. What is the velocity of the box at (i) t = 1.00 s and (ii) t = 3.00 s?

We write the equation of the forces acting on the mass.

So, T - mg = ma where T = tension in vertical rope = (36.0 N/s)t, m = mass of box = 3.50 kg, g = acceleration due to gravity = 9.8 m/s² and a = acceleration of box = dv/dt where v = velocity of box and t = time.

So, T - mg = ma

T/m - g = a

dv/dt = T/m - g

dv/dt = (36.0 N/s)t/3.50 kg - 9.8 m/s²

dv/dt = (10.3 m/s²)t - 9.8 m/s²

dv = [(10.3 m/s²)t - 9.8 m/s²]dt

Integrating, we have

∫dv = ∫[(10.3 m/s³)t - 9.8 m/s²]dt

∫dv = ∫(10.3 m/s³)tdt - ∫(9.8 m/s²)dt

v = (10.3 m/s³)t²/2 - (9.8 m/s²)t + C

v = (5.15 m/s³)t² - (9.8 m/s²)t + C

when t = 0, v = 0 (since at t = 0, box is at rest)

So,

0 = (5.15 m/s³)(0)² - (9.8 m/s²)(0) + C

0 = 0 + 0 + C

C = 0

So, v = (5.15 m/s³)t² - (9.8 m/s²)t

i. What is the velocity of the box at t = 1.00 s,

v =  (5.15 m/s³)(1.00 s)² - (9.8 m/s²)(1.00 s)

v = 5.15 m/s - 9.8 m/s

v = -4.65 m/s

ii. What is the velocity of the box at t = 3.00 s,

v =  (5.15 m/s³)(3.00 s)² - (9.8 m/s²)(3.00 s)

v = 15.45 m/s - 29.4 m/s

v = -13.95 m/s

b. What is the maximum distance that the box descends below its initial position?

Since v = (5.15 m/s³)t² - (9.8 m/s²)t and dy/dt = v where y = vertical distance moved by mass and t = time, we need to find y.

dy/dt = (5.15 m/s³)t² - (9.8 m/s²)t

dy = [(5.15 m/s³)t² - (9.8 m/s²)t]dt

Integrating, we have

∫dy = ∫[(5.15 m/s³)t² - (9.8 m/s²)t]dt

∫dy = ∫(5.15 m/s³)t²dt - ∫(9.8 m/s²)tdt

∫dy = ∫(5.15 m/s³)t³/3dt - ∫(9.8 m/s²)t²/2dt

y = (1.72 m/s³)t³ - (4.9 m/s²)t² + C'

when t = 0, y = 0.

So,

0 = (1.72 m/s³)(0)³ - (4.9 m/s²)(0)² + C'

0 = 0 + 0 + C'

C' = 0

y = (1.72 m/s³)t³ - (4.9 m/s²)t²

The maximum distance is obtained at the time when v = dy/dt = 0.

So,

dy/dt = (5.15 m/s³)t² - (9.8 m/s²)t = 0

(5.15 m/s³)t² - (9.8 m/s²)t = 0

t[(5.15 m/s³)t - (9.8 m/s²)] = 0

t = 0 or [(5.15 m/s³)t - (9.8 m/s²)] = 0

t = 0 or (5.15 m/s³)t = (9.8 m/s²)

t = 0 or t = (9.8 m/s²)/(5.15 m/s³)

t = 0 or t = 1.9 s

Substituting t = 1.9 s into y, we have

y = (1.72 m/s³)t³ - (4.9 m/s²)t²

y = (1.72 m/s³)(1.9 s)³ - (4.9 m/s²)(1.9 s)²

y = (1.72 m/s³)(6.859 s³) - (4.9 m/s²)(3.61 s²)

y = 11.798 m - 17.689 m

y = -5.891 m

y ≅ - 5.89 m

So, the maximum distance that the box descends below its initial position is 5.89 m

c. At what value of t does the box return to its initial position?

The box returns to its original position when y = 0. So

y = (1.72 m/s³)t³ - (4.9 m/s²)t²

0 = (1.72 m/s³)t³ - (4.9 m/s²)t²

(1.72 m/s³)t³ - (4.9 m/s²)t² = 0

t²[(1.72 m/s³)t - (4.9 m/s²)] = 0

t² = 0 or (1.72 m/s³)t - (4.9 m/s²) = 0

t = √0 or (1.72 m/s³)t = (4.9 m/s²)

t = 0 or t = (4.9 m/s²)/(1.72 m/s³)

t = 0 or t = 2.85 s

So, the box returns to its original position when t = 2.85 s

Answer:

B. Light energy can exist independently of matter.

Explanation:

In science, matter can be defined as anything that has mass and occupies space. Any physical object that is found on earth is typically composed of matter. Matter are known to be made up of atoms and as a result has the property of existing in states.

Generally, matter exists in three (3) distinct or classical phases and these are;

I. Solid.

II. Liquid.

III. Gas.

Light energy is different from both sound and heat energy because light energy can exist independently of matter.

Generally, we know that light energy is a type of electromagnetic waves and as such do not require a medium of propagation for it to travel through a vacuum of space where no particles exist. For example, light energy from distant galaxy of stars and the sun.

However, both sound and heat energy are mechanical waves which are highly dependent on matter for their propagation and transmission.

Answer:

a)   v = 26.2 m / s, b) acceleration is radial, a = 27.4 m / s², c)   a = 2.8 g and

d) a = - 8.73 10⁻² m / s²,  τ = 1.09 10⁴ N m

Explanation:

a) For this exercise we can use the relationships between rotational and linear motion

           v = w r

let's reduce the magnitudes to the SI system

          w = 10 rpm (2pi rad / 1 rev) 1 min / 60s) = 1,047 rad / s

          r = 25.0 m

let's calculate

          v = 1.047 25.0

          v = 26.2 m / s

b) When the body is rotating at constant speed, the relationship must be perpendicular to the speed, therefore the direction of acceleration is radial, that is, towards the center of the circle and its magnitude is

            a = v² / r

            a = 26.2²/25

            a = 27.4 m / s²

c) Let's look for the relationship between the centripetal acceleration and the acceleration due to gravity

           a / g = 27.4 / 9.8

           a / g = 2.8

           a = 2.8 g

d) let's find the deceleration and torque to stop the centripette in 5 min

           t = 5 min (60 s / 1min) = 300 s

let's use the rotational kinematics relations

           w = w₀ + α t

initial angular velocity is wo = 1,047 rad / s and the final as is stop do w = 0

           α = - w₀ / t

           α = - 1,047 / 300

           α = -3.49 10⁻³ rad / s²

angular and linear are related

           a = α r

           a = -3.49 10⁻³ 25

           a = - 8.73 10⁻² m / s²

the negative sign indicates that the acceleration is stopping the movement

torque is

           τ = F r

The force can be found with Newton's second law

          F = m a

we substitute

         τ = m a r

         τ = 5000.0   8.73 10⁻²  25

         τ = 1.09 10⁴ N m

Answer:

Specific heat (Cp) water (at 15°C/60°F): 4.187 kJ/kgK = 1.001 Btu(IT)/(lbm °F) or kcal/(kg K)

Answer:

Explanation:

Force of friction = μ N , where μ is coefficient of friction , N is normal force on the body .

a )

Given,

Normal force N = 400 N

Force of friction = 300 N

μ = coefficient of static friction = ?

Putting the values ,

300 = 400 μ

μ = .75

b )

Normal force N = 400 N

Force of friction = 200 N

μ = coefficient of kinetic  friction = ?

Putting the values ,

200 = 400 μ

μ = .50

c ) see attached file .

Answer with Explanation:

a. Option d is true.

a negatively charged plane parallel to the end faces of the cylinder

b. Radius of cylinder, r=0.66m

Magnitude of electric field, E=300 N/C

We have to find the net flux through the closed surface.

Net electric flux,[tex]\phi=-2 EA=-2E(\pi r^2)[/tex]

[tex]\phi=-2\times 300\times (3.14\times (0.66)^2)[/tex]

[tex]\phi=-820.67 Nm^2/C[/tex]

c.

Net charge,[tex]Q=\epsilon_0\times \phi[/tex]

Where

[tex]\epsilon_0=8.85\times 10^{-12}[/tex]

[tex]Q=-820.67\times 8.85\times 10^{-12}[/tex]

[tex]Q=-7.26\times 10^{-9} C[/tex]

[tex]Q=-7.26nC[/tex]

Where [tex]1nC=10^{-9}C[/tex]

Answer:

3.24×10¯² nN

Explanation:

From the question given above, the following data were obtained:

Mass of girl (M₁) = 61.6 kg

Mass of boy (M₂) = 71.2 kg

Distance apart (r) = 95 m

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Force (F) =?

The force of attraction between the girl and the boy can be obtained as follow:

F = GM₁M₂ /r²

F = 6.67×10¯¹¹ × 61.6 × 71.2 / 95²

F = 6.67×10¯¹¹ × 61.6 × 71.2 / 9025

F = 3.24×10¯¹¹ N

Finally, we shall convert 3.24×10¯¹¹ N to nN. This can be obtained as follow:

1 N = 10⁹ nN

Therefore,

3.24×10¯¹¹ N = 3.24×10¯¹¹ N × 10⁹ nN / 1 N

3.24×10¯¹¹ N = 3.24×10¯² nN

Thus, the force attraction between the girl and the boy is 3.24×10¯² nN

Answer:

The angular displacement is 37.5  radian.

Explanation:

Given that,

The radius of the car, r = 0.3 m

The acceleration of the car, [tex]\alpha =3\ rad/s^2[/tex]

The initial speed of the car, [tex]\omega_i=0[/tex]

Time, t = 5 s

The angular displacement can be calculated using second equation of motion i.e.

[tex]\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\\\theta=\dfrac{1}{2}\alpha t^2\\\\\theta=\dfrac{1}{2}\times 3\times (5)^2\\\\\theta=37.5\ rad[/tex]

So, it will make 37.5 radians.

Answer:

84kliometers

Explanation:

divide one hundred and sixty eight kilo meters by two hours