The weights of gala apples follow a Normal distribution with a mean of 140 grams and a standard deviation of 12 grams. The owner of an apple orchard randomly selects 5 apples from the harvest and records the mean weight. What is the shape of the distribution of the sample mean for all possible random samples of size 5 from this population?

Answers

Answer 1

Answer:

The shape is approximately normal, with mean of 140 grams and standard deviation of 5.37 grams.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

What is the shape of the distribution of the sample mean for all possible random samples of size 5 from this population?

By the Central Limit Theorem, the shape is approximately normal.

Mean is [tex]\mu = 140[/tex]

Standard deviation is [tex]s = \frac{12}{\sqrt{5}} = 5.37[/tex]

The shape is approximately normal, with mean of 140 grams and standard deviation of 5.37 grams.


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Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Hope this helped! Have a nice day! Plz mark as brainliest!!!

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An employee's salary,
S
(
n
)
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The relationship between
n
and
S
(
n
)
is shown in the table below.

Answers

The question is incomplete. Here is the complete question.

An employee's salary, S(n), in dollars, at a company is a function of the number of years, n, that the employee has worked at the company.

The relationship between n and S(n) is shown in the table below.

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C. S(n) = 40,000(1.05)ⁿ⁻¹

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Answer: A. S(n) = 40,000(1.05)ⁿ

Step-by-step explanation: The table shows an exponential function, which is, in general, is of the form:

[tex]S(n)=S_{0}r^{n}[/tex]

where

S₀ is the initial value

r is the rate the salary grows

n is the years the employee worked

From the table, in the first year, an employee receives $40,000, so, that is the initial value.

The salary increases at a constant rate of 1.05 per year, as shown below:

[tex]r=\frac{42,000}{40,000}=\frac{44,100}{42,000}=\frac{46,305}{44,100}[/tex]

r = 1.05

So, the rate the salary grows is r = 1.05 or 5%.

Therefore, the equation that shows an explicit formula for S(n) is [tex]S(n)=40,000(1.05)^{n}[/tex].

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Answers

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Answers

Answer:(c)

Step-by-step explanation:

Given

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the value increases exponentially with the rate of [tex]r\%[/tex]

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Answers

Answer:

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Answer:

Step-by-step explanation:

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Answer:

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Answer:

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The answers B!

Box A contains 3 red and 2 blue marbles while Box B contains 2 red and 8 blue marbles. A fair coin is tossed. If the coin turns up heads, a marble is chosen from Box A; if it turns up tails, a marble is chosen from Box B.
A. Find the probability that a red marble is chosen.
B. Referring to above information, suppose that the person who tosses the coin does not reveal whether it has turned up heads or tails (so that the box from which a marble was chosen is not revealed) but does reveal that a red marble was chosen. What is the probability that Box A was chosen (i.e., the coin turned up heads)?

Answers

Answer:

A. [tex]\frac{4}{10}[/tex]

B. [tex]\frac{3}{4}[/tex]

Step-by-step explanation:

Given - Box A contains 3 red and 2 blue marbles while Box B contains 2

            red and 8 blue marbles. A fair coin is tossed. If the coin turns up

            heads, a marble is chosen from Box A; if it turns up tails, a marble

            is chosen from Box B.

To find -  A. Find the probability that a red marble is chosen.

              B. Referring to above information, suppose that the person who

                  tosses the coin does not reveal whether it has turned up

                  heads or tails (so that the box from which a marble was

                  chosen is not revealed) but does reveal that a red marble was

                  chosen. What is the probability that Box A was chosen (i.e.,

                  the coin turned up heads)?

Proof -

As given ,

Box A : 3 red marbles and 2 blue marbles.

Box B : 2 red marbles and 8 blue marbles.

a.)

As we have to find the probability that a red marble is chosen.

A red marble is chosen in two different ways - either it can be from Box A or Box be .

If Box A is chosen , then Probability of red ball is [tex]\frac{3}{5}[/tex]

If Box B is chosen , Then Probability of Red ball is [tex]\frac{2}{10} = \frac{1}{5}[/tex]

Now,

Probability of Box A is Chosen = [tex]\frac{1}{2}[/tex]

Probability of Box B is chosen = [tex]\frac{1}{2}[/tex]

∴ we get

Probability that a Red marble is chosen =  [tex]\frac{1}{2}[/tex]×[tex]\frac{3}{5}[/tex] + [tex]\frac{1}{2}[/tex]×[tex]\frac{1}{5}[/tex] = [tex]\frac{3}{10} + \frac{1}{10} = \frac{4}{10}[/tex] = 0.4

b.)

Now,

Probability that Box A is chosen given that Red marble is chosen is

P(Box A | Red marble ) = [tex]\frac{(\frac{3}{5})(\frac{1}{2}) }{(\frac{3}{5})(\frac{1}{2}) + (\frac{1}{5})(\frac{1}{2})} = \frac{\frac{3}{10} }{\frac{3}{10} + \frac{1}{10} } = \frac{\frac{3}{10} }{\frac{4}{10}}[/tex] = [tex]\frac{3}{4}[/tex]

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