tony wants to add 97 to 298 and first add 100 to 300 what must he now subtract from this result to obtain 97+298

Answer:

it must be less than 90 degrees

The height of Dange who can jump 27.5% of her height is 10.4 inches.

A percentage is a value per hundredth. Percentages can be converted into decimals and fractions by dividing the percentage value by a hundred.

Given, Dange measures and finds that she can do a vertical jump that is 27.5 % of her height f and the distance of the jump is 13.2 inches.

Therefore. (100 + 27.5)% = 127.5% of f is 13.2 inches, This can be numerically expressed as,

(127.5/100)×f = 13.2.

1.275f = 13.2.

f = 13.2/1.27.

f = 10.4 feet.

So, The height of Dange is 10.4 inches.

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2048 people would fill the stadium to its full capacity

percentage, a relative value indicating hundredth parts of any quantity.

Given that a stadium is filled to 80% capacity

There are  2,560 people are in the stadium

We need to find how many people would fill the stadium to its full capacity.

We have to convert 80% to decimal by dividing 2560 with 100

80/100

0.8

Now multiply 0.8 with 2560

0.8×2560

2048

Hence, 2048 people would fill the stadium to its full capacity

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The builder should buy x meters of $20/m fence for the front side and 3x + 2y meters of $10/m fence for the other three sides.

To minimize the cost of the fence, the builder needs to use the least expensive type of fence for the three sides of the land that are not the front. Since the fence along the front of the land costs $20 per meter and the fence for the other three sides costs $10 per meter, the builder should use the $10 per meter fence for the other three sides.

To find out how much of each type of fence the builder needs to buy, we need to determine the total length of the three sides that are not the front. Since the land is a rectangular shape, we can use the formula for the perimeter of a rectangle:

Perimeter = 2(length) + 2(width)

Let's assume the length of the front side is x and the width of the land is y, the perimeter of the land is:

2x + 2y = 60,000

To find out the total length of the three sides that are not the front, we need to subtract the length of the front side from the perimeter of the land:

60,000 - x = 3x + 2y

The total length of the three sides that are not the front is 3x + 2y.

Now we can calculate how much the builder will pay for each type of fence:

Total cost of the fence = $20x + $30x + $20y = $50x + $20y

To minimize the cost, the builder should choose the values of x and y that minimize the total cost of the fence. To do this, the builder should set the derivative of the total cost function with respect to x and y and then set them equal to zero and solve for x and y.

However, in this case, we can simply see that the total cost is minimized by using the $10/m fence for the other three sides and using the $20/m fence only for the front side. Therefore, the builder should buy:

This way, the builder minimizes the cost of the fence and ensures that the security of the land is maintained.

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Answer:

jason: 60mph

marie: 50mph

Step-by-step explanation:

let jason drive at x miles per hour

let marie drive at x-10 miles per hour

let jason drive for y hours

let marie drive for y+1 hours

distance = speed * time

for jason:

300 = x * y

for marie:

300 = (x-10) * (y+1) = x*y + x - 10y -10

300 = x*y

divide both sides by x to solve for y

300/x = y

plug this into the second equation

300 = (x-10) * (300/x+1) = 300 -3000/x +x -10

300 = 300 -3000/x +x -10

subtract 300 from both sides

0 = -3000/x + x - 10

multiply both sides by x to get rid of the denominator

0 = x^2 -10x -3000

factor

0 = x^2 - 60x +50x -3000

0 = x(x-60) + 50(x-60) = (x+50)(x-60)

x = 60 or -50

x cannot be negative so x = 60mph

marie = 60-10 = 50mph

Answer:

65 cars

Step-by-step explanation:

On solving the provided question, we can say that - here in the given equation we got x- 1 = 0; x = 1, y = 2

An equation is a formula in mathematics that joins two statements with the equal symbol = to represent equality. The definition of an equation in algebra is a mathematical statement proving the equality of two mathematical expressions. In the equation 3x + 5 = 14, for instance, the terms 3x + 5 and 14 are separated by an equal sign. The link between two phrases on either side of a letter is expressed mathematically. There is often only one variable, which is also the symbol. instance: 2x - 4 Equals 2.

y = 2x +1

y = 3x - 1

x- 1 = 0

x = 1, y = 2

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Using the number line, the difference between 4 1/2 and 8 will come to -31/2.

A number line is a depiction of a graded straight line that serves as a visual representation of real numbers in primary mathematics. Every point on a number line is presumed to be a real number, and every real number is assumed to be a point.

Subtraction on a number line makes it much easier to subtract smaller values. When subtracting numbers from a number line, we must leap (move) to the left side of the number line.

Thus, moving to the left, 8 times from 4.5 will help us arrive at -3.5. See attached Number line.

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The equation for the side of the line that contains the first two vertices' opposite side is 3x+y=12

Given that,

Three of a parallelogram's vertices have the coordinates (-3, 4), (-2, 1), and (2, 6).

We have to find what is the equation for the side of the line that contains the first two vertices' opposite side.

We know that,

The equation of the line is

y=mx+b

Here, we find m and d

Take the points (-3,4) (-2,1)

m = y₂-y₁ / x₂-x₁

m = 1 - 4 / -2-(-3)

m = -3 / 1

m = -3

Now take point (2,6)

6 = -3(2) + b

6 = -6 + b

6 + 6 = b

12 = b

We get m =-3 and b=12

The equation will be y=-3x+12

3x+y=12

Therefore, the equation for the side of the line that contains the first two vertices' opposite side is 3x+y=12

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Answer:

The equation you have provided is 8 + 9x = 7, where x is the unknown number.

To solve for x, you can first subtract 8 from both sides of the equation to get

9x = -1

Then divide both sides by 9

x = -1/9

So the number x is -1/9, which means that the product of x and 9 is equal to -1.

Keep in mind that this is not a natural number and it is not possible to represent the solution as a whole number.

Step-by-step explanation:

Step-by-step explanation:

I'm assuming that its 23 to the power x since you said it is an exponential equation.

as for the hint there is no specific base specified so I'll do the best I can with the answer.

Angie can begin solving by applying log to the base 23 on both sides. when this is done, Angie will be left with:

[tex] log_{23}( {23}^{x} ) = log_{23}(6) [/tex]

and as we know the power rule in logarithms allows us to remove the power within the expression.

hence, we'll get:

[tex]x log_{23}(23) = log_{23}(6) [/tex]

furthermore, if we have the same number and base within a logarithmic expression it will simply become 1 giving us the final answer:

[tex]x = log_{23}(6) [/tex]

if the question that I've answered is different to yours please let me know and I'll make sure to fix it.

hope this helps :)

Answer:

8

Step-by-step explanation:

[tex]\bar{x}=np=10(0.8)=8[/tex]

In the given pairs of polygons the scale factor of figure A to figure B is  2:4.

The scale factor is calculated using the following fundamental formula: Scale factor = Dimension of the new shape Dimension of the old shape. The formula for calculating the scale factor is expressed as Scale factor = Larger figure dimensions Smaller figure dimensions in the event that the original figure is magnified.

The ratio of a smaller figure's side to its corresponding side in the bigger figure is the scale factor between the two figures.

As a result, the smaller figure's side length of 4 units and its side length of 10 units are equivalent.

Therefore:

Scale factor = 4:10

i.e. 2:5

Simplify

Scale of the smaller figure to the larger is equal to 2:4.

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-9/7 is the inverse of 9/7.

-9/-7 = 9/7

9/7 + (-9/7) = 0

-9/7 is consequently the additive opposite of -9/-7.

By merely switching the integer's sign, you can add the original number and the additive inverse to produce a result equal to 0. The value that, when added to the original number, results in zero is known as a number's additive inverse. It is what we add to a number to make it equal to zero. Considering that an is the starting number, its additive inverse will be a minus one, or -a, such that;

a+(-a) = a – a = 0

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Answer:

Step-by-step explanation:

Answer:90

Step-by-step explanation:

Answer:

The plumber would earn $190 in 5 hrs and 30 mins

Step-by-step explanation:

- We know the plumber worked from 2:30-8:00 which is 5 hrs and 30 min [5.5 hrs]

- We know the plumber charges the client $80 for the call and $20/hr for the work

1. I multiplied $20 x 5.5= $110+80=$190

or you could just do 100 x 5.5 [but it would it work since the plumber is charging per hour]

Have a great day, hope this helped <3

Answer: 29 ft

Step-by-step explanation:

Based on the description we are given. we know that we can form a right triangle, where 20 and 21 are the legs. The length from the girl to the bike would be the hypotenuse. To do this, we need to use the Pythagorean Theorem, which is [tex]a^2+b^2=c^2[/tex], where a and b are legs, and c is hypotenuse. We can go ahead and plug them in.

[tex]20^2+21^2=c^2[/tex]            [exponent]

[tex]400+441=c^2[/tex]            [add]

[tex]841=c^2[/tex]                      [square root both sides]

[tex]c=29[/tex]

Therefore, the distance from the girl to the bike is 29 ft.

Best represents the constant rate at which cupcakes are sold at the bake sale $0. 55 per cupcake

Mrs. Campos is making cupcakes for a bake sale. She uses the equation c = 0. 55x to determine the cost, c, for x cupcakes. Which best represents the constant rate at which cupcakes are sold at the bake sale?

55 cupcakes per dollar

$0. 55 per cupcake

$4 per cupcake

c = 0. 55x

to determine the cost, c,

for x cupcakes.

CASE 1

55 cupcakes per dollar

therefor x = 55

c = 0. 55x

c = 0. 55 × 55

 = 30.25

case2

$0. 55 per cupcake

x = 1

c = 0. 55x

c = 0. 55 × 1

   =  0. 55

case 3

$4 per cupcake

x = 1

c = 0. 55x

c = 0. 55 × 1

   =  0. 55

therefor conclusion is best represents the constant rate at which cupcakes are sold at the bake sale $0. 55 per cupcake

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The ratios equivalent to 2:14 are 3:21 and 16:112. Option A &C

Equivalent ratios are the ratios that are the same when we compare them. Two or more ratios can be compared with each other to check whether they are equivalent or not. For example, 1:2 and 2:4 are equivalent ratios.

2:14 = 2/14

Reducing 2/14 to the lowest terms = 1/7

2:14 is equivalent to 1:7

3:21 = 3/21 = 1/7

Reducing 3/21 to the lowest terms = 1/7

3:21 is equivalent to 1:7

1:2 = 1/2

1:2 is not equivalent to 1:7

16:112 = 16/112 = 1/7

Reducing 16/112 to the lowest terms = 1/7

16:112 is equivalent to 1:7

Hence, 2:14, 3:21 and 16:112 are all equivalent ratios

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Hence, The equation of the line is y=5x/3-3

The slope-intercept form of a line is represented by y=mx+c where m=slope and c is the y-intercept of the line

Given here: The line 3x+5y=15 , Rearranging in the slope intercept form we get y=-3x/5+3 and thus slope of the line that is perpendicular to this line must be equal to 5/3 and it passes through (3,2) then we get the equation of the line as y=5x/3+c and putting (3,2) in the equation we get the value of c as c=-3

∴ The equation of the line is y=5x/3-3

Hence, The equation of the line is y=5x/3-3

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Step-by-step explanation:

this is a multiplication dot, right ?

so,

(f.g)(x)

or

(f×g)(x)

any arithmetic operation (like +, -, ×, ÷) between 2 functions is done by applying that operation to the functional expressions.

(f×g)(x) = (x² - 12x + 35)(x - 5) =

= x³ - 5x² - 12x² + 60x + 35x -175 =

= x³ - 17x² + 95x - 175

Step-by-step explanation:

(f.g)(x) = f(x) . g(x)

= (x² - 12x + 35)(x - 5)

=x(x²-12x+35) - 5(x²-12x+35)

= x³-12x²+35x-5x²+60x-175

(f.g)(x)=x³-17x²+95x-175

The time taken by the package to reach the ground will be 5.45 seconds.

The motion of an object is related to the forces acting on it by Newton's laws of motion. According to the first law, unless a force acts on an object, it will not alter its motion. According to the second law, an object's force is determined by multiplying its mass by its acceleration. According to the third law, when two objects interact, they exert equal-sized and opposite-direction forces upon one another.

Solution:-

vo=12m/s

h=80m=yo

Then,

[tex]y-yo= vot-1/2gt^2[/tex]

⇒[tex]0-80m=(12m/s)t - 1/2(9.8m/s^2)t^2[/tex]

⇒[tex](4.9m/s^2)t^2-(12m/s)t-80m=0[/tex]

⇒[tex](4.9m/s^2)t^2-(12m/s)t-80m=0[/tex]

⇒[tex]t=5.45s, t=-3.00s[/tex]

∴[tex]t=5.45s[/tex]

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The positive value of the distance between the two objects

is [tex]r = +\sqrt \frac{GM_1M_2}{F_g}[/tex].

A quadratic equation is an algebraic expression in the form of variables and constants.

A quadratic equation has two roots as its degree is two.

Given, The formula to calculate the gravitational force between two objects

is [tex]F_g = \frac{GM_1M_2}{r^2}[/tex] where r is the distance between the objects M is the individual masses and G is the gravitational constant.

Solving for r would result in two values one positive and one negative and distance can not be negative so we want the positive value.

[tex]F_g = \frac{GM_1M_2}{r^2}[/tex].

[tex]r^2 = \frac{GM_1M_2}{F_g}[/tex].

[tex]r = \pm\sqrt \frac{GM_1M_2}{F_g}[/tex].

[tex]r = +\sqrt \frac{GM_1M_2}{F_g}[/tex].

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In algebra, a symbol is used to denote an unknown numerical value in an equation or algebraic expression.

A variable in mathematics is a letter that is substituted for an unknown integer in equations, expressions, and formulas.

An unknown numerical value in an equation or algebraic expression is represented by a symbol (often a letter) in algebra. A variable is, to put it simply, a quantity that may be altered and is not fixed.

The two primary categories of variables are categorical and numeric. Then, for categorical and numerical variables, respectively, nominal or ordinal and discrete or continuous subcategories are created for each category. This section provides a quick overview of these types.

A.) (x) ≈ 0.572[tex]$$x^4[/tex] − 15.63x³ + 146.273x² − 523.325x + 687.334

Approximately 203 automobiles were produced in 2007, according to estimates.

B.) f(x) ≈ 0.423x³ − 12.463x2 + 123.485x − 223.309

Approximately 178 automobiles were produced in 2007, according to estimates.

C.) f(x) ≈ 0.572[tex]$$x^4[/tex] + 15.63x³ − 146.273x² − 523.325x + 687.334

Approximately 203 automobiles were produced in 2007, according to estimates.

D.) f(x) ≈ 0.423x³ + 12.463x² − 123.485x + 223.309

Approximately 178 automobiles were produced in 2007, according to estimates.

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Number of cars manufactured in 2007 will be equal to 178 or 203 based on quartic model.

A variable in mathematics is a letter that is substituted for an unknown integer in equations, expressions, and formulas.

An unknown numerical value in an equation or algebraic expression is represented by a symbol (often a letter) in algebra. A variable is, to put it simply, a quantity that may be altered and is not fixed.

The two primary categories of variables are categorical and numeric. Then, for categorical and numerical variables, respectively, nominal or ordinal and discrete or continuous subcategories are created for each category. This section provides a quick overview of these types.

A.) (x) ≈ 0.572 − 15.63x³ + 146.273x² − 523.325x + 687.334

Approximately 203 automobiles were produced in 2007, according to estimates.

B.) f(x) ≈ 0.423x³ − 12.463x2 + 123.485x − 223.309

Approximately 178 automobiles were produced in 2007, according to estimates.

C.) f(x) ≈ 0.572 + 15.63x³ − 146.273x² − 523.325x + 687.334

Approximately 203 automobiles were produced in 2007, according to estimates.

D.) f(x) ≈ 0.423x³ + 12.463x² − 123.485x + 223.309

Approximately 178 automobiles were produced in 2007, according to estimates.

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Hello there!

Answer:

[tex]V = 18432\pi[/tex] or approximately 57876.48

Step-by-step explanation:

[tex]V = \frac{4}{3} \pi R^{3}[/tex]

R = 24

[tex]V = \frac{4}{3} \pi *24^{3} = 18432\pi[/tex]

if [tex]\pi =3.14[/tex] then:

[tex]V = 57 876.48[/tex]

Answer:

D

Step-by-step explanation:

Because the account that gets debited depends on the specific transaction

Answer:

$8.28

Step-by-step explanation:

0.18*46=8.28

The  5 operations of functions are

1. Input

2. Processing

3. Output

4. Storage

5. Maintenance

Input: When a function is used, it takes in an input value. This input value is used to compute the output. For example, if a function is used to calculate the area of a circle, the input would be the radius of the circle.

Processing: Once the input value is taken, the function will use the input to perform some type of operation on it. For example, if the function is used to calculate the area of a circle, the operation would be to multiply the input by itself and then multiply it by the constant pi.

Output: The output of a function is based on the input. For example, if the function is used to calculate the area of a circle, the output would be the area of the circle.

Storage: Once the output of a function is computed, it can be stored for later use. This allows the same output to be used multiple times without having to recalculate the output.

Maintenance: Functions need to be maintained and updated over time. This can include updating the input, operation, and output, as well as any additional changes that might be needed. This ensures the function is up-to-date and still provides accurate results.

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Since the square root of a negative number does not exist in the real numbers, there are no real solutions for x. Therefore, the system of equations has no solutions.

An algebraic expression in mathematics is an expression created using variables, constant algebraic numbers, and algebraic operations. A good example of an algebraic expression is 3x2 2xy + c.

A constant has a fixed value and does not vary over time. For instance, the size of a shoe, a piece of clothing, or any other article of clothing will never alter. x+y = 8 is an algebraic equation, and 8 is a constant that cannot be altered. Variables are concepts that change or fluctuate throughout time.

To solve this system of equations algebraically, we can substitute y = x-3 into the first equation

y = x² - 15x + 60

x-3 = x² - 15x + 60

x² - 16x + 63 = 0

We know that this quadratic equation has no real solutions because its discriminant (b^2 - 4ac) is negative, so the system of equations has no real solutions.

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