Two lasers are shining on a double slit, with slit separation d. Laser 1 has a wavelength of d/20, whereas laser 2 has a wavelength of d/15. The lasers produce separate interference patterns on a screen a distance 4.60 mm away from the slits.

A) Which laser has its first maximum closer to the central maximum?

B) What is the distance between the first maxima (on the same side of the central maximum) of the two patterns?

Answers

Answer 1

Answer:

A. Laser 1 has its first maximum closer to the central maximum.

B. 0.077 mm

Explanation:

A) Which laser has its first maximum closer to the central maximum?

Since for a double slit interference, sinθ = mλ/d where θ is the angle between the central axis and the maximum point, m = order of fringe, λ = wavelength of light and d = width of slit.

Also tanθ = y/D where θ is the angle between the central axis and the maximum point, y = distance between maximum point and central axis and D = distance between slit and screen = 4.60 mm.

Since θ is small,  sinθ ≅  θ and  tanθ ≅ θ

So, sinθ ≅ tanθ  

mλ/d = y/D

So, y = mλD/d for the first maximum, m = 1.

So,  y = (1)λD/d

y = λD/d

For the Laser 1, λ = d/20

So, y = λD/d

y = (d/20)D/d  

y = D/20

y = 4.60 mm/20

y = 0.23 mm

For the Laser 2, λ' = d/15

So, y' = λ'D/d

y' = (d/15)D/d  

y' = D/15

y' = 4.60 mm/15

y' = 0.307 mm

Since y = 0.23 mm < y' = 0.307 mm, Laser 1 has its first maximum closer to the central maximum.

B) What is the distance between the first maxima (on the same side of the central maximum) of the two patterns?

The distance between the first maxima (on the same side of the central maximum) of the two patterns is Δy = y' - y = 0.307 mm - 0.23 mm = 0.077 mm


Related Questions



how does the mass of object 1 and object 2 relate to gravitational force

Answers

Answer:

They are directly proportional to gravitational force.

Explanation:

Newton's Law of Gravity states that [tex]F_G=\frac{Gm_1m_2}{r^{2}}[/tex]. The two "m" values are the masses of the objects, r is the distance between their centers, and G is the gravitational constant. Notice how the "m" values are in the fraction's numerator (i.e., on top)? That means increasing even one of the objects' masses will increase the gravitational force. This is known as a direct relationship.

Of course, you could always use the wonderful table provided to solve this! You don't believe what I wrote above? Take on of the two objects' masses, divide the gravitational force by that number, and see what happens. Multiply the two masses together, and see what happens. Prove it for yourself!

I hope this increases your understanding of this concept. Have yourself a wondrous day, 'kay?

PLS ANSWER FAST WILL GIVE BRAINLEST!!!


Calculate the missing variables using the necessary formula and rules using "FORCE"

A water filled balloon with an overall mass of 1 kg undergoes an acceleration of 2m/s2. How much force is being applied to the ballon?

Answers

Answer:

2 Newtons

Explanation:

[tex]F = ma[/tex]

Therefore, your mass would be 1kg and your acceleration would be 2m/s/s

Plug the numbers into the equation:

[tex](1kg)(2m/s/s)[/tex]

which will equal

[tex]2 Newtons[/tex]

Use the drawing below to answer the following question.
1 kg
10 kg
20 kg
50 kg
All of the boxes shown above can slide easily. Which box will move farthest if each is
struck with the same amount of force?
A.
the 1-kg box
B. the 10-kg box
C. the 20-kg box
D. the 50-kg box

Answers

Answer:

A

Explanation:

Force =  mass x acceleration

if the force is constant for each of the boxes, the smaller a boxes mass the greater its acceleration while the force is applied

Therefore the smaller box will have a greater initial velocity and will slide the furthest before it stops.

3. If you were in a car collision, would you rather be hit by Vehicle 1 (2,027 kg) or Vehicle 2 (1,415 kg) from Activity 73? Explain.​

Answers

Answer:

I say vehicle one, because both will apply the same amount of force but, because vehicle two has less mass, it will accelerate more rather than vehicle one which will accelerate less.

The frequency of the wave is 0.4 Hz. Calculate the period.

Answers

Answer:

use the formula

Explanation:

F = 1/T

where F = frequency and T = period

so put 0.4 Hz into the frequency

0.4 =1/T

T = 2.5 seconds

hope this helps

A sound wave produced by a chime 515 m away is heard 1.50 s later. What is the speed of the sound in the air?

Answers

Answer:

the speed of the sound in the air is 343.3 m/s

Explanation:

The computation of the speed of the sound in the air is shown below:

As we know that

Speed = Distance ÷ time

So, here speed be 515 m

And, the time is 1.50 seconds

So, the speed of the sound is

= 515 m ÷ 1.50 seconds

= 343.3 m/s

hence, the speed of the sound in the air is 343.3 m/s

Which statement is true for nuclear reactions but not for chemical reactions?

Answers

Answer:

D

Explanation: this is why they release so much energy

Answer:

They convert some mass into energy

Explanation:

Ap3x

What is the length of the rod as measured by this ruler?

2.0 cm

2.1 cm

2.2 cm

2.3 cm

Answers

2.2 CM is your answer

jfkanfnakcndbcnd

Answer:

2.2 cm

Explanation:

milimeters are the little hash marks and there are ten so it is 2.2 cm

Suppose the Sun is 1.29025 X 108 km from
Earth.
The speed of light is 2.99792 x 108 m/s.
How long does it take for its light to reach
us?
Answer in units of min.

Answers

Answer:

It takes the Sun's light 7.17 minutes to reach us.

Explanation:

We can calculate the time that takes the light to reach us by using the following equation:

[tex] t = \frac{d}{c} [/tex]    

Where:

d: is the distance = 1.29025x10⁸ km = 1.29025x10¹¹ m

c: si the speed of light = 2.99792x10⁸ m/s  

Hence, the time is:

[tex] t = \frac{d}{c} = \frac{1.29025 \cdot 10^{11} m}{2.99792 \cdot 10^{8} m/s} = 430.38 s = 7.17 min [/tex]

Therefore, it takes the Sun's light 7.17 minutes to reach us.

I hope it helps you!

A child is standing on the platform of a station, watching the trains.
.
A train travelling at 30 m/s takes 3 s to pass the child.
What is the length of the train?
A 10m
B 30 m
C 90 m
D 135 m

Answers

C. 90 m

30m per second... and it takes 3 seconds

3x30= 90
c 90 m
30 times 3 equals 90

II NEED HELP WITH THIS QUESTION PLS

Answers

Answer:

Suppose that the frequency of the first harmonic is F, then the frequency of the second harmonic will be 2*F

The third one will be 3*F

and so on.

Then:

a) the first harmonic is 262 Hz,

Then the third harmonic will be 3*262Hz = 786 Hz

b) if F is the frequency of the first harmonic, and we want to find this.

We know that the fifth harmonic frequency is 1700Hz

Then:

5*F = 1700 Hz

F = (1700Hz)/5 = 340Hz

c) We want to find the fifth harmonic such that we know that the third overtone frequency is 984 Hz.

An overtone is any frequency larger than the fundamental frequency; overtone is just another name for harmonic.

Such that the second overtone is the same as the second harmonic, the third overtone is the same as the third harmonic, etc.

Then the third overtone is the same as the third harmonic.

This means that if F is the first harmonic, then:

3*F = 984 Hz

F = 984Hz/3 = 328 Hz

And the fifth harmonic will be:

5*328 Hz = 1640 Hz

A 30 N force is applied to a box, as shown below in the diagram. (g = 10 m/s2) 30N 2kg The acceleration of the box is​

Answers

30 N = (2 kg)(a)
30 N/2 kg = a
a = 15 m/s/s

what are subtomic particles

Answers

Answer:

In the physical sciences, subatomic particles are smaller than atoms. They can be composite particles, such as the neutron and proton; or elementary particles, which according to the standard model are not made of other particles. Particle physics and nuclear physics study these particles and how they interact.

Explanation:

Answer:

In physical sciences, subatomic particles are smaller than atoms. They can be composite particles, such as the neutron and proton; or elementary particles, which according to the standard model are not made of other particles.

Can someone help me please

Answers

the answer to your question is distance

Answer:

distance i think im not sure

help please!!!!!!!!!!!?!!

Answers

Each of the questions can be answered by the browser

At what point does the ball have the most gravitational potential energy?

Answers

Point C. at this point, which is the highest point, all of the ball’s energy is gravitational potential energy.

What is the netforce?

Answers

Answer:

6 Newtons to the left.

Explanation:

We can convert  this into a generic algebra equation by giving directions positive and negative values.

The 6 will be positive, and the 10 and 2 will be negative.

Add 10 and 2 to have 12.

6-12 = -6.

Therefore you have 6 newtons to the left (negative).

Take the force towards the right as positive (+6N) and towards the left as negative (-12N)
Add both as net force is the sum of all forces acting on an object
6N+(-12N)= -6N

What force controls the movement of the planets around the sun, holds together stars grouped in galaxies, and galaxies grouped in clusters?

Answers

Answer:

Gravity.

Explanation:

The force that controls the movement of the planets around the sun, holds together stars grouped in galaxies, and galaxies grouped in clusters is called gravity.

This ultimately implies that, gravity is considered to be a universal force of attraction that acts between all objects that has both mass, energy and occupy space. Therefore, it acts in such a way as to bring objects together.

Additionally, the gravity of earth makes it possible for all physical objects to possess weight.

Weight can be defined as the force acting on a body or an object as a result of gravity.

Mathematically, weight is given by the formula;

[tex] Weight = mg [/tex]

Where;

m is the mass of an object.

g is acceleration due to gravity.

Which of the following wavelengths have the highest frequency? Group of answer choices a.infrared waves b. radio waves c.microwaves d.visible light

Answers

b...radio waves answer

The height of a transverse waves is known as its?

Answers

Answer:

amplitude

Explanation:

amplitude of a wave is the maximum displacement of a point from its rest position.

hope you get it,

Use newton's law to explain the vertical acceleration of a projectile

Answers

Answer:

Explained below

Explanation:

Newton's first law of motion: This law states that an object will remain at rest or continue in constant motion except it's acted upon by an external force. In projectile motion, the horizontal component of velocity will remain unchanged because we ignore air resistance since no force is acting in that horizontal direction.

Newton's second law of motion: This law states that force is the product of mass and acceleration. In projectile the force acts downwards, thus f = mg.

But g = a since internal forces will cancel out.

Thus, F = ma

HELP PLS




2. How would these gravity forces change if the Sun got much bigger?
Decrease. Increase. Stay the same

3. How would these gravity forces change if the Earth was much closer to the Sum?
Decrease Increase. Stay the same

4. How would these gravity forces change if the Earth got much smaller?
Decrease. Increase. Stay the same
face

Answers

Answer:

2. increase

3. stay the same

4. Decrease

Explanation:

(let me know if im wrong on any we learned this last year so I might be a little rusty on this subject)

The force of gravity increases with increase in the size of the Sun and with decrease in the distance between the earth and the Sun. However, it decreases with decrease in the size of the earth.

What is gravity?

Gravity is the force of attraction that exists between two bodies separated by a given distance.

The force of gravity increases with increase in the size of the bodies as well as with a decrease in the distance of separation.

However, the force of gravity decreases with decrease in the size of the bodies as well as with a increase in the distance of separation.

Thus, for the force of gravity between the earth and the Sun;

Force of gravity increases with increase in the size of the SunForce of gravity increases with decrease in the distance between the earth and the Sun Force of gravity decreases with decrease in the size of the earth.

Therefore, the force of gravity is affected by size of the bodies as well as the distance separating the bodies.

Learn more about force of gravity at: https://brainly.com/question/24783651

#SPJ2

An object is placed 110 mm from a concave mirror with a focal length of 5.0 cm.

Answers

Answer:

Approximately 92 mm.

Explanation:

Object's distance, u = 110 mm = 11 cm

focal length of the mirror = 5 cm

Image distance, v = ?

To determine the image distance, apply the mirror's formula;

[tex]\frac{1}{f}[/tex] = [tex]\frac{1}{u}[/tex] + [tex]\frac{1}{v}[/tex]

[tex]\frac{1}{v}[/tex] = [tex]\frac{1}{f}[/tex] - [tex]\frac{1}{u}[/tex]

   = [tex]\frac{1}{5}[/tex] - [tex]\frac{1}{11}[/tex]

   = [tex]\frac{11-5}{55}[/tex]

[tex]\frac{1}{v}[/tex] = [tex]\frac{6}{55}[/tex]

⇒ v = [tex]\frac{55}{6}[/tex]

       = 9.166667

v = 9.2 cm

The image distance is 92 mm.

What is the velocity of a 750 kg object at a height of 0m if it’s ME is 3590J?

Answers

Answer:

Sorry for this question

Why do we not feel air pressure?

Answers

Answer:

Explanation:

Is beacuse of the air within our bodys is exerting the same pressure out wards so tjere is no pressure difference

Answer:

it is because our body itself is not  adept enough to resist the air pressure. For every reaction, there be an balanced opposite reaction according to Newton's law. namely, all forces such as air pressure are in proportion therefore we will not perceive air pressure which also means no net force.    

Explanation:

what's the optical illusion also known as?​

Answers

Answer:

An optical illusion (also called a visual illusion) is an illusion caused by the visual system and characterized by a visual percept that arguably appears to differ from reality. ... Cognitive visual illusions are the result of unconscious inferences and are perhaps those most widely known.

Scientists treat the number of stars in a given volume of space as a Poisson random variable. The density of our galaxy in the vicinity of our solar system is 3 stars per 10 cubic light-years. What is the probability of one or more stars in 10 cubic light-years? Round your answer to 4 decimal places.

Answers

Answer:

[tex]P(X\ge 1) = 0.9502[/tex]

Explanation:

Given

Density = 3 starts in 10 cubic light years.

Required

Determine the probability of 1 or more in 10 cubic light years

Since the number of stars follow a Poisson distribution, we make use of:

[tex]P(X=k) = f(x) = (\lambda T)^k\frac{ e^{-\lambda T}}{k!}[/tex]

[tex]\lambda = density[/tex]

[tex]\lambda = \frac{3}{10}[/tex]

[tex]\lambda = 0.3[/tex]

T = the light years

[tex]T = 10[/tex]

Calculating [tex]P(X \ge 1)[/tex]

In probability:

[tex]P(X \ge 1) = 1 - P(X = 0)[/tex]

Calculating P(X=0)

Substitute 0 for k and the values for [tex]\lambda[/tex] and T in

[tex]P(X=k) = f(x) = (\lambda T)^k\frac{ e^{-\lambda T}}{k!}[/tex]

[tex]P(X=0) = (0.3* 10)^0 * \frac{ e^{-0.3 * 10}}{0!}[/tex]

[tex]P(X=0) = (3)^0 * \frac{ e^{-0.3 * 10}}{1}[/tex]

[tex]P(X=0) = (3)^0 * e^{-0.3 * 10}[/tex]

[tex]P(X=0) = 1 * e^{-0.3 * 10}[/tex]

[tex]P(X=0) = 1 * e^{-3}[/tex]

[tex]P(X=0) = e^{-3}[/tex]

[tex]P(X=0) = 0.04979[/tex]

Substitute 0.04979 for P(X=0) in [tex]P(X \ge 1) = 1 - P(X = 0)[/tex]

[tex]P(X\ge 1) = 1 - 0.04979[/tex]

[tex]P(X\ge 1) = 0.95021[/tex]

[tex]P(X\ge 1) = 0.9502[/tex] ---  approximated

Hence, the required probability is 0.9502

another A b c or d about the earth...

Answers

Answer:

B seismic wave

Need help ASAP
Thanks + BRAINLIST only for correct answer

1.Cell phones convert sound waves into______waves.
-light waves
-sound waves
-radio waves

2.Electromagnetic waves used in cell phone communications are called?
-microwave
-radio wave
-infrared
-all of the above

3.To send out a radio signal far and wide...it is called?
-broadcast
-casting
-antenna

Answers

Answer:

answer my question

Explanation:

Mhm yeah correct I think yeah yeah lol

If a runner goes 500 meters with an average speed of 7.0 m/s. How long were they running?

Answers

Answer: s=d/t= 500/7.0=71.42 m/s

Explanation:

If a runner goes 500 meters with an average speed of 7.0 m/s, then he would have run in about 71.42 seconds.

What is speed?

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object.

average speed = total distance /Total time

As given in the problem If a runner goes 500 meters with an average speed of 7.0 m/s then we have to find out How long was he running,

time consumed  by the runner = distance covered by the runner/average speed of the runner

time consumed  by the runner = 500 meters /7 meters/seconds

                                                   = 71.42 seconds.

Thus, the time consumed by the runner would have been 71.42 seconds.

Learn more about speed from here, refer to the link;

brainly.com/question/7359669

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