Two spherical objects have masses of 1. 5 x 10^5 kg and 8. 5 x 10^2 kg.

Their centers are separated by a distance of 2500 m. Find the

gravitational attraction between them.

Answer:

Centimeters.

Explanation:

There are only 2 viable answers here. This is due to the fact that moles are used not to measure diameters but instead the number of atoms.

Similarly, milligrams are not used to measure diameters but instead small volumes.

This leaves us with kilometers and centimeters, and since all 3 objects are more easily representable in centimeters than kilometers, the answer must be centimeters. One example would be the diameter of a ping pong ball, which is approximately 4cm, or in other words, 0.00004km, with 4cm being much more easy to represent as it overall involves less digits.

You could do to make the magnetic disk rotate faster: regular usage of a disc defragmentation program.

A magnetic disk is a storage device that writes, rewrites, and accesses data using the magnetization process. It has a magnetic layer that retains data as tracks, spots, and sectors.

You could do to make the magnetic disk rotate faster:

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With 20.23 ms⁻¹,  maximum speed can it go around a curve having a radius of 60.0 m

The highest rate of speed a person can reach is called maximum speed. When athletes alter the magnitude (how quickly they are moving) or direction (or both) of their motion, or both, their acceleration changes as well since acceleration is related to velocity, which has both a magnitude and a direction connected with it.

ac max = V² max / R   ....(1)

Inserting given values we get

ac, max  =  (34.5)² / 150 = 7.935 ms⁻²

For a changed radius of the curve of 60.0 m, the maximum safe speed from (1) becomes

Unew, max= √ac, max R new

Unew, max = √6.826 x 60

Unew, max 1 = 20.23 ms⁻¹, rounded to one decimal place.

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Index fossils are fossils that are used to help determine the relative age of rock layers and sedimentary strata. They are typically small, widely distributed organisms that lived for a relatively short period of time and are characteristic of a specific geological period. Index fossils are useful because they can help geologists and paleontologists to determine the relative age of rock formations and to understand the Earth's geological history.

It is unlikely that humans would be useful as index fossils in the future, as the time period during which humans have existed on Earth is relatively short compared to the age of the Earth as a whole. In addition, humans are not small, widely distributed organisms like many of the commonly used index fossils. Instead, humans are large, highly adapted organisms that have a wide range of habitats and are found on most of the continents.

However, it is possible that artifacts or other remains associated with human activity could be used as index fossils in the future. For example, the presence of certain types of tools or other materials might be used to help determine the relative age of a site or to understand the environmental conditions and human activity in a particular region at a specific point in time.

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The size of smallest object that a detect wing is 22°C bat can echolocation when air temperature is 31 mm.

Bat need to use because as high frequencies for echolocation compared to lower frequencies, higher. frequencies gives them more regarding size of the object in speed and frequency the prey direction of its waver are not early detailed information their path, range, pray. Also high detected by the prey.

For care the Jame of bat, dolphin frequency as explained in alio  high radiation. Thus despite poor visibility under water, dolphin can high frequency and avoid to catch its wave it Predator. we there to find its path and to catch its prey and also to avoid its peredetor.

Bat sounds are emitted only during wing upbeat to minimize physiological costs. Air pressure in calls is just below blood pressure in lungs physiological maximum. FM is best for determining target distance Measure time delay between pulse and echo return FM sweep labels each part of pulse with a frequency value.

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When the frequency of a standing wave set up in a pipe (with both ends open) first harmonic is 300 Hz, the length of pipe is 0.567 metres.

Therefore the answer is 0.567 m.

The speed of sound in air is approximately 340 m/s, and the wavelength of the first harmonic of a standing wave in an open pipe is twice the length of the pipe. Therefore, if the frequency of the first harmonic is 300 Hz, the wavelength can be calculated as:

wavelength = speed of sound / frequency

wavelength = (340 m/s) / (300 Hz)

The length of the pipe can be calculated as half the wavelength:

L = wavelength/2

L = (340 m/s) / (2×300 Hz)

L ≈ 0.567 m

So the length of the pipe is 0.68 m

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To find the average speed of the cyclist, we need to divide the distance traveled by the time it took to travel that distance. So we would divide 100 meters by 40 seconds, which gives us 2.5 meters per second. This is the average speed of the cyclist.

Answer:

The Average Speed is 2.5metres per second

Explanation:

Using Distance,Time,Speed Triangle,

[tex]S = \frac{D}{T}[/tex]

[tex]S = \frac{100}{40}\\[/tex]

[tex]S = 2.5[/tex]

Hence ,  the average speed is 2.5m/s

The time on the surface of an object would run most slowly on an object with the same mass as the Sun but twice as large in radius.

What is mass?

Mass is a measure of the amount of matter in an object and is typically expressed in kilograms (kg). It is an intrinsic property of matter and is different from weight, which is a measure of the force of gravity acting on an object. Mass is an important factor in determining the physical properties of an object, such as density, momentum, and inertia. Mass is also used to calculate the gravitational force between two objects, as well as the energy required to move it.

This is because the surface gravity of an object is inversely proportional to the square of its radius. Therefore, the object with the same mass as the Sun but twice as large in radius would have a much lower surface gravity, and time would run more slowly on its surface.

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The intensity of 60 dB sound is 10⁻⁶ W/m².

A common conversation between two persons seated at a distance of around one meter (3 14 feet) is as loud as 60 dB. It is equivalent to the typical noise level in a restaurant or office.

The decibel scale is a logarithmic one rather than a linear one. Accordingly, 10 dB denotes a sound that is 10 times louder than 0 dB, which represents no sound at all. Now, a sound at 20 decibels is 100 times louder than one at 0 decibels. And so on until a sound that is 100 decibels is 1 billion times louder than total silence (0 decibels).

A sound at 60 dB is therefore 100 times louder than a sound at 40 decibels and 1000 times louder than a sound at 30 decibels, while being 10 times louder than a sound at 50 decibels.

The formula for sound volume is L = log(I/I₀), or (I/I₀) = 10^L.

Given that L = 60dB = 6bel and that we know that I₀ = 10⁻¹² W/m²,

I/I₀ = 10⁶.

or I = 10⁻¹² × 10⁶ = 10⁻⁶ W/m²

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Answer:

2000

Explanation:

180/0.09

=2000

pressure=force/area

Because the charges at rest are unable to produce a magnetic field, neither of the two stationary charges will do so.

There is no magnetic field created when a charge is stationary since there is no motion inside the charge. Thus, nothing except an electric field is created.

Charges that are at rest can also feel the electric force. Charges in motion can experience magnetic force. Therefore, the electric field must not be zero and the magnetic field may or may not be zero if a charged particle at rest experiences an electromagnetic force.

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Block B on the exterior f-F = ma c f-F = mv2 2d f-F = D = mv2 d f-F E f-F = v2 2d.

A thing's top, exterior, or outermost layer: Tropical rain forests once covered 10% of the earth's surface. The marble has a smooth, polished surface.

The surface of the picture is covered in little fissures. The bowl's exterior has a glossy finish. The wood was rough on the outside. Ice-covered roads ought to be avoided. The phrase "on the surface" describes how something seems, even if it isn't really the case.

The formulas F- f = mv2 / d can be used to determine the force of friction that the surface exerts on the block.

F - f = ma

a = v/t

t = d/v

F - f = m × v / t

F- f = m ×

F- f = m × v²/d

Therefore,

F- f = mv² / d

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The spring constant with given length that stretches upto certain length and has specified mass has a spring constant that is calculated to be 147 N/m.

Given that,

Initial length of the spring = 0.400 m

Final length of the spring = 0.450 m

Change in length, Δx = 0.450 m - 0.400 m = 0.050 m

Mass of the hung object = 0.750 kg

Weight of the hung object, w = 0.750 × 9.8 N = 7.35 N

From Hooke's law it is said that, mathematically

Spring constant = Weight of the hung object/ change in length

Putting in the above given values into the equation, we have,

Spring constant = 7.35/0.050 = 147 N/m

The required spring constant is calculated to be 147 N/m.

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With the use of wave speed and echo formula, the distance is 540 m

Echo can simply be defined as a reflection of sound wave. Where as, Sound wave is longitudinal wave.

Given that a naval navigator is using sonar to look for sunken cargo. The waves he is using have a frequency of 120 kHz and a wavelength of 3 mm.

The wave speed V = Fλ

Where

V = 120000 × 0.003

V = 360 m/s

How far away is the cargo if the sound wave is emitted at exactly 9:24 a.m. and returns to hit the ship's sensor 3 seconds later?

Speed V = 2S/t

where

360 = (2 × S)/3

360 × 3 = 2S

S = 1080/2

S = 540 m

Therefore, the cargo is 540 m away

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Answer:

Below

Explanation:

17.4 inches = 441.96 mm      14.8 inches = 375.92 mm

volume = 441.96 X 375.92 X T  

                                   = 166141.6 T  mm^3  <===where T = thickness in mm

Volume X density = mass

 166141.6 T mm^3  * 2.7 gm/cm^3  * cm^3 / 1000mm^3  = 10.8 gm

     solve for T = .024 mm

The weight of the automobile and trailer together is 2000 kg. The vehicle will accelerate at a rate of 2.5 m/s2.

Acceleration is measured in meters per second squared (ms2), or m s 2. Formula for Average Acceleration: The final velocity minus the initial velocity, divided by the change in time, is the equation for average acceleration (a). A = v t = v f v I t.

The product of an object's mass (m) and velocity (v) is its linear momentum. Higher momentum makes it more difficult to halt an object. P = mv is the equation for linear momentum.

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"At a yellow light, after checking to the rear, stop before entering the intersection or at the stop bar." If stopping safely is not possible, cautiously cross the junction.

Devices that are typically located at significant sites, such as busy junctions, are used to give out traffic signals in order to control the flow of traffic.

A yellow traffic light serves as a warning that the red signal will soon be shown. As a result, as soon as you notice a yellow light, you should begin to slow down in preparation for a red light. Additionally, if for some reason you are unable to stop, you should keep an eye out for any vehicles that may be approaching the intersection at the same moment.

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Since I0 is the lowest sound intensity that a person with normal hearing can detect, it is chosen as the reference point. Given that log10 1 = 0, the decibel level of a sound with an intensity of 10–12 W/m2 is = 0 dB. In other words, the human hearing threshold is zero decibels.

The reference value I0 is 10–12 W/m2, which corresponds to the threshold of hearing intensity at 1000 Hz. The Sound Intensity Level, or SIL for short, is the intensity decibel scale. The related sign, like in our text, is LI.

Much more frequently than sound intensities in watts per square meter, sound intensity levels are expressed in decibels (dB). Both the scientific literature and the public media use decibels as their preferred measurement unit. The rationale behind this decision of units has to do with how we hear. There is a reference intensity, I0 = 1012 W/m2. The lowest or threshold intensity of sound that a person with normal hearing can perceive at a frequency of 1000 Hz is specifically known as I0. The degree of sound intensity is not the same as the intensity. is a unitless quantity that informs you of the sound level in relation to a predefined standard (1012 W/m2, in this case), as it is defined in terms of a ratio.

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Answer:

it gives off 71.0 kJ of heat.

Explanation:

The weight of the book and your lifting power will be the only two forces operating, assuming that air resistance is minimal (gravity).

The book's displacement was x=(2.3-0.75)m=+1.55m.

The book weighs W= m(-g)= 2.0 kg(-10N/kg)= 20 N.

Therefore, the weight's work (energy delivered by the weight) is equal to W.x (-20N).

(+1.55m) = -31 Nm =-31 J.

This outcome, -31J, demonstrates that the weight caused the rising book to lose 31J of kinetic energy, increasing the gravitational potential energy of the book.

You lifted the book, which gave it kinetic energy from the chemical energy stored in your muscles. The weight is thereby decreasing the kinetic energy of the book while the lifting force from you increases it.

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By using the formulae, λ = h/mv, The De Broglie wavelength of the muon is calculated to be 4.13 × 10^10 m, as according to the given data in the question.

The shortest measured time is 100 attoseconds. A quadrillionth of a minute is a femtosecond. One quadrillionth of a minute is a picosecond. One quadrillionth of a second is a nanosecond.

Particles are smaller than just a nanometer. Depending on the element, an atom is between 0.1 and 0.3 nm in size. Atoms on the a surface in a SEM image.

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Answer:

To solve this problem, you can use the formula F = ma, where F is the force applied to an object, m is the mass of the object, and a is the acceleration of the object. In this case, the force applied to the object is 51.3 newtons and the acceleration of the object is 48.7 m/s2. So, you can set up the equation like this:

51.3 newtons = m x 48.7 m/s2

To solve for the mass of the object, you can divide both sides of the equation by 48.7 m/s2:

51.3 newtons / 48.7 m/s2 = m x 48.7 m/s2 / 48.7 m/s2

This simplifies to:

1.05 kg = m

So, the mass of the softball is approximately 1.05 kilograms.

Answer:

Explanation:

period is 2pi / B which is 2pi/8 which is 1/4 pi

amplitude is a which is 10

Answer:

Weight of a 35kg object on Earth is 350N, while it is 56N on the Moon.

Explanation:

The conversion of mass (kg) to weight (N) on Earth is 1kg to 10N.
Thus, the weight of a 35kg mass on Earth is
35kg × 10 = 350N

On the Moon, conversion of mass to weight is 1kg to 1.6N.
Thus, the weight of a 35kg mass on the Moon is
35kg × 1.6 = 56N

Remember, mass remains constant regardless of location, while weight depends on the strength of the gravitational field.

Answer:

Approximately [tex](-61)\; {\rm m\cdot s^{-2}}[/tex], assuming that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex].

Explanation:

Under the assumptions, the vehicle would be in a free fall. Acceleration would be constant: [tex]a = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}[/tex].

Let [tex]u[/tex] denote the initial velocity of the vehicle. Let [tex]v[/tex] denote the velocity of the vehicle at the bottom of the drop. Let [tex]x[/tex] denote the displacement of the vehicle during the drop.

It is given that the initial velocity is [tex]u = 0\; {\rm m\cdot s^{-1}}[/tex]. During the drop, displacement would be [tex]x = (-190)\; {\rm m}[/tex] (negative since the vehicle is below where it started.) The value of final velocity [tex]v[/tex] needs to be found.

It is known that the vehicle is moving downwards at the end of the fall. Therefore, the value of [tex]v\![/tex] would be negative. Apply the SUVAT equation [tex]v^{2} - u^{2} = 2\, a\, x[/tex] to find [tex]v[/tex] from [tex]u[/tex], [tex]a[/tex], and [tex]x[/tex].

[tex]\begin{aligned}v^{2} &= u^{2} + 2\, a\, x\end{aligned}[/tex].

[tex]\begin{aligned}v &= -\sqrt{u^{2} + 2\, a\, x} \\ &= -\sqrt{(0\; {\rm m\cdot s^{-1}})^{2} + 2\, (-9.81\; {\rm m\cdot s^{-2}})\, (-190\; {\rm m})} \\ &\approx (-61)\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

(Note that [tex]v[/tex] is negative.)

In other words, the velocity of the vehicle would be approximately [tex](-61)\; {\rm m\cdot s^{-1}}[/tex] at the end of the drop.

As Projectile range is independent of mass, so They all will have same range.

When an object is close to Earth's surface, its gravitational attraction is calculated using the formula F = mg, where m is the object's mass and g is a constant whose value varies depending on the location. On the surface of the earth, it averages 9.81 meters per second. And when one moves away from the surface in either an inner or an outward direction, this value drops.

Although the strength of the earth's gravitational pull changes depending on the mass of the object, the acceleration caused by it is constant (of course close to the surface). Consequently, when two items of different masses are dropped from the same height, they hit the ground simultaneously (neglect air resistance).

Any motion of a projectile simply consists of vertical and horizontal motion. Regardless of the direction the projectile is going in, gravity controls vertical motion since it only acts in that direction. Additionally, the acceleration caused by gravity is not reliant on the mass of the item. Therefore, the mass has no bearing on the vertical motion.

A projectile moves horizontally in a very straightforward manner. A projectile is not affected by horizontal forces. As a result, its horizontal velocity does not change. Additionally, the range is influenced by horizontal velocity and flying time. Flight time is influenced by vertical motion.

We now know that mass has no bearing on flying duration or range. And if you run into a projectile motion problem, simply divide the problem into horizontal and vertical motions. And handle it the same way you would a single-direction motion. greatly simplifies matters.

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Explanation:

This intense stretching method uses bouncing movements to push your body beyond its normal range of motion. Whereas static stretches are performed slowly and gradually, the ballistic method stretches muscles much farther and faster. You can do many of the same stretches as ballistic or static stretches.

"Effort multiplied by an arm equals burden multiplied by an arm," The various loads on the proportionally shorter load arm can be moved by the effort arm.

A lever is a straightforward device with a solid beam and a fulcrum. The effort (input force) and load (output force) are applied to the beam's ends. The pivot of the beam is thought to be the fulcrum.

Levers are devices that increase force, to put it simply. Because they merely have the handle and the fulcrum, we refer to them as "basic machines." The "arm" of the lever is the handle or bar; it is the portion that you push against or pull towards.

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The cables and machinery used to transport electric energy from the supplying utility to the wiring system of the premises served are referred to as "service" in the NEC. The Service Point is the location where the customer's premises wiring starts and the utility supply terminates.

Drop in service. between the service point and the utility's electrical supply infrastructure, the overhead conductors.

Service conductors are the wires that run from the service point to the method of terminating the service (service equipment, not meter). For both above (service drop) and subterranean, service conductors would include service-entrance conductors (service lateral).

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The resistor that is equivalent to the resistance of the circuit is 1 2/7 Ohms

The equivalent resistance of a circuit is the (single) resistance that can replace the combination of resistances in the circuit such that the current flowing in the circuit remains the same.

Please find attached the drawing of the circuit, created with an online circuit building tool.

Whereby the capacitor also acts as a resistor of 6 Ohms, we get;

Resistors R₄, R₅, and R₆ are parallel

The resistor equivalent to the three resistors is found as follows;

Req₁ =  1/(1/R₄ + 1/R₅ + 1/R₆)

Therefore, Req₁ = (1/(1/2 + 1/1 + 1/6)) = 0.6

Req₁ is in series with R₁, therefore;

Req₂ = Req₁ + R₁ = 0.6 + 3 = 3.6

Req₂, (Req₁ + R₁  combined) is parallel to R₂ and R₃, therefore;

Req₃ = 1/(1/Req₂ + 1/R₂ + 1/R₃)

Req₃ = 1/(1/3.6 + 1/3 + 1/6) = 9/7 = 1 2/7

The equivalent resistor of the circuit is 1 2/7 ohms

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