what effect does ligand binding have on receptor tyrosine kinase proteins?

Answers

Answer 1

Ligand binding to an RTK protein induces a conformational change in the protein, activates the kinase associated with it, and initiates a signaling cascade that transmits the signal to the target cell.

Ligand binding has a number of effects on RTK(Receptor tyrosine kinases) proteins such as it  induces a conformational change in the protein, activating it which is achieved through a process known as dimerization, in which the ligand binds to the extracellular domain of the protein, bringing the two halves of the protein together to form an active state. Ligand binding also triggers the autophosphorylation of the RTK protein, which is the addition of phosphate groups to specific amino acid residues. It activates the enzyme associated with the RTK protein, which then initiates a signaling cascade.

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Related Questions

Classify each description as associated with either positive or negative selection. TCR must recognize MHC T-lymphocyte survival dependent on not recognizing self-antigen T-lymphocyte survival dependent on ability to bind MHC Thymic epithelial cells present MHC to T-lymphocytes TCR must not bind self- antigen Cells develop self-tolerance Dendritic cells present MHC with self-antigen to T-lymphocytes Positive Selection Negative Selection TCR must recognize MHC TCR must not bind self- antigen Thymic epithelial cells present MHC to T-lymphocytes Dendritic cells present MHC with self-antigen to T-lymphocytes T-lymphocyte survival dependent on ability to bind MHC T-lymphocyte survival dependent on not recognizing self-antigen Cells develop self-tolerance

Answers

Positive Selection:

TCR must recognize MHCThymic epithelial cells present MHC to T-lymphocytesT-lymphocyte survival dependent on ability to bind MHC

Negative Selection:

TCR must not bind self- antigenDendritic cells present MHC with self-antigen to T-lymphocytesT-lymphocyte survival dependent on not recognizing self-antigenCells develop self-tolerance

What should you know about TCR must recognize MHC?

T-cell receptor (TCR) must recognize major histocompatibility complex (MHC) molecules in order to initiate an immune response. MHC molecules are found on the surface of cells and they bind to and present foreign peptides to T-cells, which are then activated to recognize and eliminate the foreign substance. MHC molecules come in two types, MHC class I and MHC class II, which present antigens to CD8+ T-cells and CD4+ T-cells, respectively. The specificity of TCR for MHC molecules is essential for the proper functioning of the immune system, as it enables T-cells to recognize and respond to a wide range of foreign pathogens while ignoring healthy cells.

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19. In humans, a Widow's peak is dominant to having a straight hairline, and free earlobes are dominant to
having attached ones. A woman who is homozygous for her Widow's peak and heterozygous for her
earlobes marries a man that has a straight hairline and is also heterozygous for his earlobes. Determine
the phenotypic ratio. What is the probability that they have a child who looks like mom?

Answers

Answer:

Explanation:

there is a 50/100 chance that the child will look like its mom since the dad also has the same characteristics

Why is it unhealthy to be overweight?


PLEASE IT’S URGENT, WILL GIVE BRAINLIEST!!!

Answers

It is unhealthy to be overweight because you are more at risk for diabetes, deadly diseases and certain cancers. Heart disease is the top reason why being overweight can be bad for a person. This means that you could get heart attacks and die faster than a healthy person. You are also at risk of stress which can lead to depression.

Answer:

Overweight people have an increased risk of:

heart disease

stroke

some cancers

diabetes

stress / anxiety / depression

And many more...

Explanation:

When people eat too much or too many fatty meals, they become overweight. You acquire body mass if the energy in the food is greater than the energy you spend. Under the skin, this is stored as fat. Obese is a term used to describe someone who has gained a lot of weight.

What structures receive postganglionic axons from the ciliary ganglion?

Answers

These postganglionic neurons' axons emerge from the ciliary ganglion, pass through the choroid, enter the eye, and innervate the sphincter muscle of the iris.

Preganglionic and postganglionic fibers synapse at the ciliary ganglion. Postganglionic fibers exit through the short ciliary nerve and nourish the ciliaris muscle and sphincter pupillae. The nasociliary nerve is the source of the sensory root.

Uninterrupted sensory fibers from the eyeball go through the ganglion. The muscles that contract the pupil, a hole in the iris that allows light to enter the eye, are innervated by nerves from the ciliary ganglion. Additional ciliary ganglion fibers travel to the muscles that regulate the curvature of the eye's lens.

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true or false: the nature and sensitivity of the microorganism and the overall medical condition of the patient need to be considered before antimicrobial treatment begins.

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True, the nature and sensitivity of the microorganism and the overall medical condition of the patient need to be considered before antimicrobial treatment begins.

How does antimicrobial treatment work?

Antimicrobial treatment works by targeting and killing or inhibiting the growth of microorganisms such as bacteria, viruses, fungi, and parasites. The specific mechanism of action depends on the type of antimicrobial agent used.

For example, antibiotics work by targeting specific components of bacterial cells, such as their cell walls, protein synthesis machinery, or DNA replication enzymes. Antivirals target specific steps in the viral life cycle, such as viral entry, replication, or assembly. Antifungals work by targeting fungal cell walls or disrupting fungal membrane integrity. Antiparasitics target various stages of the parasite life cycle, such as growth, replication, or metabolic processes.

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When substance A was added to an enzyme reaction, product formation decreased. The addition of more substrate did not increase product formation. From this we conclude that substance A could be . . .

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Product production decreased when substance A was introduced to an enzyme process. More substrate was not added, but product formation was not increased. This leads us to the conclusion that substance A might act as an inhibitor.

What is an enzyme reaction?

Enzyme reactions are chemical reactions that occur as a result of enzyme catalysts. Enzymes are proteins that catalyze chemical reactions, speeding up chemical reactions in cells by up to a billion times.

The product is the outcome of the reaction. Enzyme reactions convert substrates into products. An enzyme-substrate complex is formed when the enzyme and substrate interact. The substrate is then converted to the product after the reaction is complete.

An inhibitor is a substance that slows down or prevents an enzyme-catalyzed reaction. The addition of substance A to the enzyme reaction caused a decrease in product formation, implying that substance A inhibited the reaction. The addition of more substrate did not increase product formation, implying that there was no enzyme activity. As a result, substance A may be an inhibitor of the enzyme's action.

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What is the mutation type that is the least likely to alter the amino acids in a protein?a. insertionb. deletionc. substitutionWhich of those mutations is most likely to be dangerous?

Answers

Each amino acid is stored by a distinct sequence of three of the four potential base pairs in DNA (A–T, T–A, G–C, and C–G, the individual letters referring to the four nitrogenous bases adenine, thymine, guanine, and cytosine ). As a result, a mutation that alters the DNA code can alter the amino acid sequence, possibly...

These mutations can be totally innocuous, deadly, or somewhere in the middle. A point mutation, defined as a change in a single nitrogen base in a DNA sequence, is typically the least damaging form of DNA mutation.

As a result, a mutation that alters the DNA code can alter the amino acid sequence, possibly reducing or inactivating a protein's function. A alteration in the regulatory DNA code of a gene.The area can have a detrimental effect on the timing and availability of the gene's protein, as well as cause severe cellular malfunction.

When an additional base pair is introduced to a base sequence, an insertion mutation develops. A deletion mutation is the inverse of an insertion mutation; it happens when a base pair is removed from a chain. These two kinds of point mutations are clustered together because they both have the potential to significantly alter the sequence of amino acids generated.

Insertion or deletion causes a frame-shift, which changes the reading of consecutive codons and thus modifies the complete amino acid sequence that follows the mutation; thus, insertions and deletions are typically more damaging than substitutions, which only affect one amino acid.

there were two types of dinosaur: those such as tyrannosaurus rex that had hip structures similar to

Answers

Yes, there were two main types of dinosaurs: Saurischian and Ornithischian. Saurischian dinosaurs, such as the Tyrannosaurus rex, had hip structures similar to modern birds, with the hip socket facing upward and inward. Ornithischian dinosaurs, however, had hip structures that faced outward and downward, like those of modern lizards.


There were two types of dinosaurs: those such as Tyrannosaurus Rex which had hip structures similar to those of modern birds and those that had hip structures like modern reptiles. The Tyrannosaurus Rex falls under the first category. The type of hip structure the dinosaurs possessed is an indication of their evolution.

Hip Structure of Dinosaurs:

Dinosaurs are classified based on their hip structures. There are two main groups: Ornithischia (bird-hipped) and Saurischia (lizard-hipped). The Ornithischia, as the name implies, have hip structures that resemble those of birds. On the other hand, the Saurischia has a hip structure that is similar to modern reptiles, such as lizards or crocodiles. Tyrannosaurus Rex and other carnivorous dinosaurs are part of the Saurischia. The long axis of the pubis bone in the Saurischia points forward. Furthermore, their thigh bones are parallel to one another, which indicates that the dinosaurs walked with their legs placed directly beneath their bodies.

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The axial skeleton can be divided into the skull, the vertebral column, and the: a. thoracic cage c. hip bones b. femur d. humerus.

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The axial skeleton can be divided into the skull, the vertebral column, and the thoracic cage.

The head and boot bones of a vertebrate make up the axial skeleton, which is the portion of the skeleton. The 80 bones of the human skeleton are divided into six parts: the skull (22 bones), the ossicles of the middle ear, the hyoid bone, the rib cage, the sternum, and the vertebral column. The axial and appendicular skeletons work together to make up the entire skeleton. The bones of the vertebrae, sacrum, coccyx, cranium, ribs, and sternum are included in another definition of the axial skeleton.

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what happened to the e. coli cells you spread on the lb/ampicillin plates that did not contain a pclone plasmid?

Answers

The E. coli cells that were spread on the LB/Ampicillin plates that did not contain a pclone plasmid would not have been able to grow properly on the plates.

What is pclone plasmid?


The e. coli cells that were spread on the lb/ampicillin plates but did not contain a pclone plasmid would not have grown on the plates. The pclone plasmid is generally used to generate clones and for research purposes. E. coli cells that contain pclone plasmid are able to grow in the presence of ampicillin antibiotic, while the cells that do not contain pclone plasmid cannot grow in the presence of ampicillin antibiotic.

The growth of the E. coli cells on the LB/ampicillin plates would indicate that the cells have the pclone plasmid. Cells that did not grow on the plates would indicate that they did not have the plasmid.

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Which of the following statements correctly describe(s) the driving forces for diffusion of na and k ions through their respective channels? select all that apply. view available hint(s)for part b because ions carry a charge (positive or negative), their transport across a membrane is governed not only by concentration gradients across the membrane but also by differences in charge across the membrane (also referred to as membrane potential). together, the concentration (chemical) gradient and the charge difference (electrical gradient) across the plasma membrane make up the electrochemical gradient. consider the plasma membrane of an animal cell that contains a sodium-potassium pump as well as two non-gated (always open) ion channels: a na channel and a k channel. the effect of the sodium-potassium pump on the concentrations of na and k as well as the distribution of charge across the plasma membrane is indicated in the figure below. a diagram of a plasma membrane containing a sodium-potassium pump, a non-gated na plus channel, and a non-gated k plus channel. outside the cell, the concentration of na plus is high, the k plus concentration is low, and the charge is positive. inside the cell, the concentration of na plus is low, the k plus concentration is high, and the charge is negative. na plus flows through the na plus channel inside the cell, while k plus flows through the k plus channel outside the cell. the sodium-potassium pump is moving three na plus ions outside and two k plus ions inside. which of the following statements correctly describe(s) the driving forces for diffusion of na and k ions through their respective channels? select all that apply. the diffusion of na ions into the cell is facilitated by the na concentration gradient across the plasma membrane. the diffusion of na ions into the cell is impeded by the electrical gradient across the plasma membrane. the diffusion of k ions out of the cell is impeded by the k concentration gradient across the plasma membrane. the diffusion of k ions out of the cell is impeded by the electrical gradient across the plasma membrane. the electrochemical gradient is larger for na than for k .

Answers

The statements correctly describe the driving forces for the diffusion of Na+ and K+ ions through their respective channels are

The diffusion of Na+ ions into the cell is facilitated by the Na+ concentration gradient across the plasma membrane.The diffusion of K+ ions out of the cell is impeded by the electrical gradient across the plasma membrane.The electrochemical gradient is larger for Na+ than for K+

The diffusion of Nа ions into the cell is fаcilitаted by the Nа concentrаtion grаdient аcross the plаsmа membrаne. The diffusion of K ions out of the cell is impeded by the K concentrаtion grаdient аcross the plаsmа membrаne. The diffusion of K ions out of the cell is fаcilitаted by the electricаl grаdient аcross the plаsmа membrаne. The electrochemicаl grаdient is lаrger for Nа thаn for K.

Your question is incomplete, but most probably your full question can be seen in the Attachment.

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Human and other animal waste can result in water and air pollution.(a) Eutrophication of waterways is a potential environmental problem that can result from concentrated animal feeding operations (CAFOsCAFOs).Question 1: Describe how eutrophication negatively affects waterways.Question 2: Propose a realistic solution to prevent eutrophication of waterways near CAFOsCAFOsQuestion 3: Justify the solution you described in (a)(ii) with an additional environmental benefit.

Answers

Eutrophication is a process that occurs when waterways receive excess nutrients, such as nitrogen and phosphorus, from various sources including animal waste.

What is a waste ?

Waste refers to any material or substance that is no longer useful or necessary and is discarded or disposed of. This can include materials such as household trash, industrial waste, construction debris, hazardous waste, and electronic waste.

Waste can be generated by human activities, such as manufacturing, agriculture, transportation, and consumption. Improper disposal of waste can have negative environmental impacts, including pollution of water and air, harm to wildlife, and contribution to climate change. Therefore, proper waste management practices, such as reducing waste generation, reusing and recycling materials, and disposing of waste safely and responsibly, are important for minimizing the negative impacts of waste on the environment and human health.

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State the advantages and disadvantages of asexual reproduction over sexual reproduction in plants.

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Asexual reproduction is a form of reproduction in which offspring are produced from a single parent, without the involvement of gametes or fertilization.

What is the advantages and disadvantages of asexual reproduction over se---xual reproduction in plants?

Advantages of asexual reproduction in plants include:

Efficiency: Asexual reproduction is a faster and more efficient way of producing offspring than sexual reproduction. There is no need to search for a mate or to produce and distribute gametes.

Genetic uniformity: Offspring produced through asexual reproduction are genetically identical to the parent plant, which means that desirable traits can be maintained and propagated.

Survival: Asexual reproduction can help plants survive in harsh conditions, such as in environments with low resources or in areas where pollinators or mates are scarce.

Disadvantages of asexual reproduction in plants include:

Lack of genetic diversity: Because offspring are genetically identical to the parent plant, there is no genetic diversity, which can make the plant more vulnerable to diseases and environmental changes.

Adaptability: Because there is no genetic variation, plants that reproduce asexually may not be able to adapt to changing environmental conditions as well as sexually reproducing plants.

Accumulation of deleterious mutations: Asexual reproduction can lead to the accumulation of deleterious mutations over time, which can have negative effects on the health and fitness of the offspring.

Advantages of se---xual reproduction in plants include:

Genetic diversity: Se---xual reproduction leads to offspring with genetic diversity, which increases the chance that some offspring will have traits that are beneficial in different environments.

Adaptability: Se---xual reproduction allows plants to adapt to changing environmental conditions by producing offspring with different traits.

Elimination of deleterious mutations: Se===xual reproduction can help eliminate deleterious mutations by recombining genetic material from two parents.

Disadvantages of se---xual reproduction in plants include:

Energy cost: Se---xual reproduction is a more energy-intensive process than asexual reproduction, as it requires the production and maintenance of gametes and involves the search for a mate.

Reduced efficiency: Se---xual reproduction is a less efficient way of producing offspring than asexual reproduction, as only half of the offspring will inherit desirable traits from each parent.

Risk of producing less fit offspring: Se---xual reproduction increases the chance of producing less fit offspring, as the traits of the offspring are determined by chance and may not be as well-suited to the environment as the traits of the parents.

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Which event is required for cell cycle arrest following DNA damage involving double-strand breaks ?
A Dephosphorylation of p53. < Nope
B Transcription of a CKI. <<<<<< I THINK THIS IS RIGHT
C Destruction of cyclins by ubiquitination. < Definitely nope
D Inhibition of ATM/ATR kinases. <-NOT RIGHT
E Binding of MDM2 to p53. < NOPE
"How DNA damage can inhibit progression of cell cycle at G1/S checkpoint, via synthesis of cyclin-dependent kinase inhibitors CKI's"

Answers

The event required for cell cycle arrest following DNA damage involving double-strand breaks is the Transcription of a CKI. Therefore the correct option is B.

A checkpoint in the G1-S phase of the cell cycle is triggered by DNA damage, which delays progression through the cell cycle by inhibiting cyclin-dependent kinases (CDKs).

The damage triggers a complex series of signals that activate the checkpoint and lead to the transcription of cyclin-dependent kinase inhibitors (CKIs).

As a result, CDK-cyclin complexes are inhibited, preventing the cell from progressing to the S phase, allowing time for the damage to be repaired, and ensuring genomic stability in cells. Therefore the correct option is B.

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what are the three most common shapes of bacterial cells?

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The three most common shapes of bacterial cells are cocci, bacilli, and spirilla.

These bacterial cell shapes vary greatly in size and are classified based on their shape. The three most common shapes of bacterial cells are:

1. CocciCocci are spherical or ball-shaped bacterial cells that are commonly found in clusters or chains. Some species of cocci are capable of forming spores that can survive for long periods of time under harsh environmental conditions.

2. BacilliBacilli are rod-shaped bacterial cells that can be either single cells or arranged in chains. They are larger than cocci and can range from being straight to slightly curved or even spiral in shape. Bacilli can be further categorized based on their staining properties, such as gram-positive or gram-negative.

3. SpirillaSpirilla are spiral-shaped bacterial cells that are larger and more rigid than cocci or bacilli. They are commonly found in aquatic environments and are capable of moving through water by rotating their spiral shape. Spirilla can also be further categorized based on their cell morphology, such as helical, comma-shaped, or corkscrew-shaped.

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Given what is known about the minimal essential functions of cellular life, if you could create an artificial cell, which of the following structures must you include?
a. nucleus
b. ribosome
c. cell wall
d. mitochondria

Answers

To create an artificial cell, you must include ribosomes. The correct option is (b).

Artificial cells have been created that mimic the essential functions of living cells. This has allowed scientists to study the fundamentals of life without relying on the natural environment.  There are a number of structures that must be present in an artificial cell to make it viable.

It includes a lipid bilayer, which can form a boundary between the inside and outside of the cell. Artificial cells must also be able to communicate with one another, which requires a system of proteins and enzymes. To perform these functions, artificial cells also need energy.

This can come from a number of sources, such as light, glucose, or other chemical compounds. Artificial cells also need to be able to synthesize proteins, which is why ribosomes are required in them. The ribosome is responsible for translating RNA into protein, which is a fundamental step in the process of building a living cell.

There are other structures that could also be included in an artificial cell. For example, mitochondria are responsible for energy production in natural cells. However, they are not necessary for an artificial cell to function. Similarly, a cell wall is not necessary for an artificial cell, as it is not present in all types of living cells.

Therefore, the correct answer is option B.

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when a peptide bond is formed, two amino acids are linked between the group of one amino acid and the group of the other.

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When a peptide bond is formed, two amino acids are linked together through a condensation reaction, also known as a dehydration synthesis.

Specifically, the carboxyl group (-COOH) of one amino acid reacts with the amino group (-NH2) of another amino acid, releasing a molecule of water (H2O) in the process. The resulting covalent bond between the carbon atom of the carboxyl group and the nitrogen atom of the amino group forms the peptide bond.

This reaction can be repeated many times to form a polypeptide chain, which is the primary structure of a protein. The sequence of amino acids in the polypeptide chain determines the unique structure and function of the protein.

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Oxaloacetate is a key intermediate in the citric acid cycle, but it is also needed as a precursor for the synthesis of glucose during gluconeogenesis. Oxaloacetate is also fairly chemically unstable and undergoes spontaneous decarboxylation to pyruvate. Although oxaloacetate is not depleted by participation in the citric acid cycle, it can become depleted by other processes, necessitating its replenishment by various synthetic pathways. Use the Metabolic Map to identify enzymes that can replenish oxaloacetate or other citric acid cycle intermediates. o pyruvate carboxylase o malic enzyme o pyruvate kinase o pyruvate decarboxylase o glutamate dehydrogenase o pyruvate dehydrogenase Choose all the true statements about the citric acid cycle. o Citric acid cycle products include NADH, GTP, FADH2, coenzyme A, and CO2- o The citric acid cycle oxidizes acetyl groups to produce the reduced cofactors NADH and FADH2.
o Each turn of the citric acid cycle requires two molecules of acetyl-CoA. o The citric acid cycle occurs in the cytoplasm of the cell. o The citric acid cycle is strictly an aerobic process.

Answers

The correct statements about the citric acid cycle include formation of products such as NADH, GTP, FADH₂, coenzyme A, and CO₂. The citric acid cycle occurs in the mitochondria of the cell.

What is Citric acid cycle?


The citric acid cycle products include NADH, GTP, FADH₂, coenzyme A, and CO₂. The citric acid cycle oxidizes acetyl groups to produce the reduced cofactors NADH and FADH₂. Each turn of the citric acid cycle requires two molecules of acetyl-CoA. The citric acid cycle occurs in the mitochondria of the cell. The citric acid cycle is a combined aerobic and anaerobic process.

Enzymes that can replenish oxaloacetate or other citric acid cycle intermediates include Pyruvate carboxylase, Malic enzyme, Pyruvate kinase, Pyruvate decarboxylase, Glutamate dehydrogenase, and Pyruvate dehydrogenase.

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The glycerol and fatty acid components of ______ molecules present in food can be converted into pyruvate and acetyl CoA, respectively, which then enter the pathways of aerobic respiration

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The glycerol and fatty acid components of Triglyceride molecules present in food can be converted into pyruvate and acetyl CoA, respectively, which then enter the pathways of aerobic respiration.

The chemical digestion of fats begins in the small intestine with the action of lipase enzymes. These enzymes hydrolyze the triglyceride molecule into a glycerol molecule and three fatty acids.

The glycerol molecule is an alcohol compound and can be converted into pyruvate. Pyruvate is the end product of glycolysis in which glucose is converted into pyruvate with the net production of 2 ATP molecules. The glycerol enters into the glycolysis pathway and is converted to pyruvate which then enters the pathways of aerobic respiration.

The fatty acids are oxidized through β-oxidation, which is a cyclical process that results in the formation of two-carbon units of acetyl CoA. The acetyl CoA enters the citric acid cycle which is a part of the aerobic respiration process.

In this cycle, Acetyl-CoA combines with Oxaloacetate to form Citrate which then goes through a series of chemical reactions that release CO₂ and hydrogen atoms.

These hydrogen atoms are taken by NAD⁺ and FAD to form NADH and FADH₂ respectively. NADH and FADH₂ are electron carriers that donate their electrons to the electron transport chain which produces a large amount of ATP by oxidative phosphorylation in the mitochondria.

Therefore, different components of Triglyceride molecules present in food can be converted into their required forms and can then enter the respiratory path.

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Drugs that target RNA polymerase are direct inhibitors of. A. DNA replication. B. translation. C. reverse transcription. D. transcription.

Answers

Drugs that target RNA polymerase are direct inhibitors of transcription.

RNA polymerase is an enzyme that helps to create RNA from DNA. It is an essential enzyme that is involved in gene expression by regulating the transcription of DNA into RNA.

RNA polymerase produces a strand of RNA using one strand of DNA as a template. There are many drugs that target RNA polymerase, and they are used as inhibitors of transcription.

Direct inhibitors of RNA polymerase are commonly used to treat cancer, bacterial infections, and viral infections. These drugs act by blocking the enzyme from synthesizing RNA molecules.

By inhibiting RNA synthesis, these drugs can prevent the expression of certain genes, which can be useful in treating various diseases.

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what are the different types of gene editing technologies?

Answers

There are several types of gene editing technologies, Each of these gene editing technologies has its own strengths and weaknesses, and researchers are continually working to improve and refine them for various applications in medicine, agriculture, and biotechnology.

CRISPR-Cas9: This technology uses RNA to guide an enzyme called Cas9 to specific locations in the DNA where it cuts the double helix. The DNA can then be repaired or modified. Zinc Finger Nucleases (ZFNs): These enzymes use a DNA-binding domain called a zinc finger to target specific locations in the genome. Once bound, the enzyme cuts the DNA, allowing for repair or modification. Transcription activator-like effector nucleases (TALENs): Like ZFNs, TALENs use a DNA-binding domain to target specific locations in the genome. The enzyme then cuts the DNA for repair or modification. Homing endonucleases: These enzymes occur naturally in bacteria and yeast, and can be engineered to target specific locations in the genome for modification. Base editors: These technologies use enzymes to change specific letters in the DNA code, without cutting the DNA. This can be used to correct disease-causing mutations.

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the ras protein normally regulates cell growth. a mutation that occurs in the gene encoding ras can cause ras to become overactive, which results in cancer. this means that ras is an example of a/an

Answers

The ras protein is an example of an oncogene, a gene that has the potential to cause cancer when mutated or overexpressed.

Normally, the ras protein plays a role in regulating cell growth and division by transmitting signals from cell surface receptors to the nucleus. However, mutations in the gene that encodes ras can lead to the overactivation of the protein, disrupting normal cellular signaling and leading to uncontrolled cell growth and division. This can result in the formation of tumors and the development of cancer. The identification of oncogenes such as ras has led to a better understanding of the molecular mechanisms underlying cancer and the development of targeted therapies for the treatment of cancer.

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the posterior nasal apertures are also called the ______.

Answers

Answer:

The choanae

Explanation:

The choanae is an opening towards the back of the nasal cavity; the posterior nasal aperture.

which of the following is true of tree plantations? question 2 options: they are not biologically diverse. they take a very long time to return a profit. they are usually clear-cut before they are sufficiently mature. they cannot be used for paper products. they contain trees that are not of a uniform age.

Answers

Among the following options, it is true that tree they contain trees that are not of a uniform age and  plantations are not biologically diverse.

What are tree plantations?

Tree plantation is a large-scale farming technique that is primarily used for commercial purposes. In this process, many trees are grown in a specific area, and when they reach maturity, they are harvested, processed, and sold for wood or other wood-based products. It is a method that is becoming more popular due to the demand for timber, wood-based products, and renewable resources. The tree plantations only contain a single species of tree, which are all the same age. As a result, they cannot be considered biologically diverse. The second point on the question, “they take a very long time to return a profit”, is untrue because, in the early years, trees will grow very quickly, and the plantation owner can sell a portion of the trees as a source of income.

Furthermore, the last option in the list, “they contain trees that are not of a uniform age”, is also true since it is typical for plantations to contain trees of various ages due to the inconsistencies of growth rates.

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ITS TIMED HELP
1. To be useful, a scientific name should refer to
A. all living species
B. all living and extinct species
C. all species in one habitat
D. a single species

2. American vultures are now classified with storks instead of with African vultures because of bio-molecular evidence.
A. True
B. False

3. Which feature allowed scientists to classify amoebas as a eukaryote:
A. cytoplasm
B. water vacuole
C. food vacuole
D. nucleus

Answers

Answer: D, A, D

Explanation:


1. To be useful, a scientific name should refer to

A. all living species

B. all living and extinct species

C. all species in one habitat

D. a single species

- D : a single species

2. American vultures are now classified with storks instead of with African vultures because of bio-molecular evidence.

A. True

B. False

- A : True

3. Which feature allowed scientists to classify amoebas as a eukaryote:

A. cytoplasm

B. water vacuole

C. food vacuole

D. nucleus

- D : nucleus

*
Note : I do not know if these answers match what you have learned... I am answering based off of what I know...

To be useful, a scientific name should refer to a single species. It is false that American vultures are now classified with storks instead of with African vultures because of bio-molecular evidence. The correct options are D, B and D respectively.

What is eukaryote?

Eukaryotes are organisms with nuclei and other membrane-bound organelles.

A scientific name is used to identify and distinguish one species from others. It is a one-of-a-kind and universal name that refers to a single species.

American vultures are not related to storks. While some reclassifications based on genetic evidence have been proposed, the classification of American vultures as distinct from African vultures remains unchanged.

Amoebas are eukaryotes because they have nuclei, which distinguishes eukaryotic cells.

Bacteria and other prokaryotes lack a true nucleus, and their DNA is not separated from the rest of the cell by a membrane.

Amoebas and other eukaryotes have a nucleus surrounded by a membrane that separates the DNA from the cytoplasm.

Thus, the correct options are D, B and D respectively.

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The digestive, circulatory, respiratory, immune, and excretory systems all work together to maintain homeostasis. Discuss how a minor malfunction in one of these systems could lead to major malfunctions in others. If methods were developed to improve the efficiency and effectiveness of one system, what effect might that improvement have on the other systems?

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All the major systems of the body work together to maintain homeostasis, like, a respiratory disease preventing enough oxygen to reach the body directly affects the circulatory system as heart cannot function efficiently in less oxygen. Methods improving one system will directly improve the other systems as well, like, when the disease is treated, enough oxygen will be available and heart will function properly.

Homeostasis is the condition of maintenance of equilibrium condition inside the living body. Homeostasis is necessary for the body to function correctly and efficiently. Every organ system is involved in maintaining the homeostasis.

Circulatory system of the body is involved in the transport of blood and other nutrients to the whole body. The system comprises of heart, blood vessels, the blood and its components.

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Which of the following statements about diffusion is correct?a. It is an active process in which molecules move from a region of lower concentration to one of higher concentration.
b. It is very rapid over long distances.
c. It requires an expenditure of energy by the cell.
d. It is a passive process in which molecules move from a region of lower concentration to a region of higher concentration.
e. It is a passive process in which molecules move from a region of higher concentration to a region of lower concentration.

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The correct statement about diffusion is option e: It is a passive process in which molecules move from a region of higher concentration to a region of lower concentration.

Diffusion is the process by which molecules move from an area of high concentration to an area of low concentration. It occurs spontaneously and does not require energy input from the cell, making it a passive process. The molecules move down their concentration gradient, which is the difference in concentration between two areas until equilibrium is reached. Diffusion is a fundamental process for the exchange of gases and nutrients in biological systems. Diffusion occurs at a rate that depends on several factors, including the size and charge of the molecule or ion, the temperature, and the nature of the medium through which the diffusion is occurring. Diffusion is slower over longer distances, but can still occur rapidly over short distances.

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which process occurs in meiosis but not in mitosis? a. attachment of spindle fibres to the centromeres of each chromosome b. movement of homologous chromosomes to opposite ends c. replication of dna prior to the start of cell division d. separation of sister chromatids during anaphase

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Meiosis is a process that includes some activities that are unique to it. Among the options given, movement of homologous chromosomes to opposite ends is a process that occurs in meiosis but not in mitosis.

Homologous chromosomes are chromosomes that are the same in length, shape, and gene placement but may have different alleles for a given trait. During meiosis, there is a homologous chromosome pair that separates into different cells, and one of each chromosome pair is included in each new cell.

Homologous chromosomes are present in pairs, unlike sister chromatids, which are present in duplicates. During meiosis, homologous chromosomes pair, and then they separate and migrate to the opposite poles of the cell. This ensures that each cell has one set of chromosomes that are distinct from the original cell.

During mitosis, the sister chromatids of each chromosome separate, and each of the new daughter cells receives one chromatid from each chromosome. This is referred to as mitotic cell division.

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A signal transmitted via phosphorylation of a series of proteins is generally associated with which of the following events?
A. conformational changes to each protein in the series
B. binding of a hormone to an intracellular receptor
C. activation of a ligand-gated ion channel
D. production of ATP in the process of signal transduction

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The answer for "A signal transmitted via phosphorylation of a series of proteins is generally associated with " is conformational changes to each protein in the series. The correct answer is option A.

Phosphorylation is the chemical reaction that is used to transfer a phosphate group from a molecule, which is typically ATP (adenosine triphosphate), to an amino acid of a protein. The phosphate is usually transferred to the hydroxyl group of the amino acid serine, threonine, or tyrosine. The main objective of signal transduction pathways is to cause a response in the target cell. When a signal reaches the target cell, a series of signaling proteins and transcription factors are activated. The activation of the signaling protein is generally accomplished by covalent modification, which usually involves phosphorylation

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which of the following is not a function of the spleen? destruction of old red blood cells removal of impurities storage of blood absorption of digested fats

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The spleen doesn't absorb digested fats. That is the function of the lymphatic system in our body.

The spleen is an organ in the body's lymphatic system, which functions to regulate and filter blood as it circulates. It is positioned in the upper-left portion of the abdomen, below the diaphragm, and to the left of the stomach. The spleen helps in the maintenance of a healthy immune system, blood cell metabolism, and other important body functions. It stores white blood cells and platelets, which play a crucial part in fighting infection and clotting blood.

The following are the primary functions of the spleen: Destruction of old red blood cells: When red blood cells reach the end of their lifespan, the spleen filters them out of the bloodstream and destroys them. Removal of impurities: The spleen's white pulp assists in the removal of impurities from the blood, including germs, viruses, and bacteria.Storage of blood: The spleen serves as a blood reservoir, storing excess blood that can be released into the bloodstream as needed.

Absorption of digested fats: The lymphatic system, not the spleen, absorbs digested fats. Fats and fat-soluble vitamins from our diet are absorbed in the intestines and transported via the lymphatic system to the bloodstream, where they can be utilized as required.

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