What is called composite function?

A = 1, y = -2/3, The value of a for which the system of equations has a unique solution is a = -3.

1. Set the first equation equal to 0:

2x + ay = 2

2. Subtract 2x from both sides of the equation to get:

ay = -2

3. Divide both sides of the equation by a to get:

y = -2/a

4. Substitute this value of y into the second equation to get:

6x + 3(-2/a) = 3

5. Multiply both sides of the equation by a and simplify to get:

6ax - 6 = 3a

6. Add 6 to both sides of the equation to get:

6ax = 3a + 6

7. Divide both sides of the equation by 6 to get:

x = (3a + 6)/6

8. The value of a for which the system of equations has a unique solution is a = -3.

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A system that has no solution is classified as inconsistent.

A system that has one and only one solution is classified as  independent

The system of equation graphed is consistent and independent.

The equations given by the graph are expressed as;

3x - 4y = 32

3x + 5y = 24

Now, if we subtract eq 1 from eq 2, we will get;

5y - (-4y) = 24 - 32

9y = -8

y = -8/9

Put 8/9 for y in eq 2 to get;

3x + 5(8/9) = 24

3x = 24 - 40/9

3x = 176/9

x = 176/27

Now, to classify solution to equations, we say that;

1) When there is no solution, it is inconsistent.

2) When there is one and only one solution, it is independent

Since we have a solution and only one solution, then we can say that the system of equation graphed is consistent and independent.

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On solving the provided question, we can say that - the charge for 42 units = is $139.20; so, charge per unit is 139.20/42 = $3.3142857143

The unit technique is an approach to problem-solving that involves first determining the value of a single unit, then multiplying that value to determine the required value. The unit method, to put it simply, is used to extract a single unit value from a supplied multiple. For instance, 40 pens would cost 400 rupees, or the price of one pen. The process for doing this may be standardized. a single country. anything that has an identity element. (mathematics, algebra) (Linear algebra, mathematical analysis, mathematics of matrices or operators) Its adjoint and reciprocal are equivalent.

here,

the charge for 42 units = is $139.20.

so, charge per unit is 139.20/42 = $3.3142857143

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Answer:

A directed segment is a segment that has distance (length) and direction. Hope this helps.

Answer:

Kumain ka Ng pansit para ka Maka sagot

Step-by-step explanation:

follow pleas helpme

The point satisfies the equation ! 8 = 4 × (2)

Answer:

Yes

Step-by-step explanation:

If you plug in the numbers to the equation, you should get:

8 = 4(2)

Then,

8 = 8

therefore, (2,8) does satisfy the equation y = 4x.

The derivative function for equations 1 and 2 will be

y' = -1/ [2√(1-x²)] and y' = 3/[2(1 + x²)] respectively

Here we need to find the derivative of

[tex]y = tan^{-1}\sqrt{\frac{1-x}{1+x} }[/tex]

Let x = cos2z

Hence we get

[tex]y = tan^{-1}\sqrt{\frac{1-cos2z}{1+cos2z} }[/tex]

[tex]or, y = tan^{-1}\sqrt{\frac{2sin^{2}z}{2cos^{2}z} }[/tex]

[tex]or, y = tan^{-1}(tanz)[/tex]

or, y = z

Hence dy/dx = dz/dx

We know that

x = cos2z

or, 2z = cos⁻¹x

or, 2 dz/dx = -1/√(1-x²)

Hence dy/dx = -1/ [2√(1-x²)]

The second equation is

[tex]y = 3tan^{-1}[x-\sqrt{1+x^{2}} ][/tex]

Let x = cotz

Hence we get

[tex]y = 3tan^{-1}[cotz-\sqrt{1+cot^{2}z} ][/tex]

[tex]y = 3tan^{-1}[cotz-\sqrt{cosec^{2}z} ][/tex]

or, y = 3tan⁻¹ [cotz - cosecz]

or, y = 3tan⁻¹ [cosz/sinx - 1/sinz]

or, y = 3tan⁻¹ [(cosz - 1)/sinz]

or, y = 3tan⁻¹ [-2sin²(z/2)/{2sin(z/2) cos(z/2)}]

or, y = 3tan⁻¹ [-sin(z/2)/cos(z/2)]

or, y = 3tan⁻¹ [-tan{z/2)]

or, y = 3tan⁻¹ [tan{-z/2)]

or, y = -3z/2

or, dy/dz = -3/2 dz/dx

We have

x = cotz

or, z = cot⁻¹z

or, dz/dx = -1/(1 + x²)

Hence we get

dy/dx = 3/[2(1 + x²)]

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Answer:

-3 (x - 4) (x - 1)

Step-by-step explanation:

The number of times the diameter of Uranus is larger than the diameter of Mars is 7.5 times

From the question, we have the following parameters that can be used in our computation:

The diameters of Uranus and Mars

These diameters are given as

Diameter of Uranus: 5.11×10^4 kilometers

Diameter of Mars: 6.79×10^3 kilometers

Express the diameters properly

So, we have the following representation

Diameter of Uranus: 5.11 × 10⁴ kilometers

Diameter of Mars: 6.79 × 10³ kilometers

This means that

Number of times larger = Diameter of Uranus/Diameter of Mars

Substitute the known values in the above equation, so, we have the following representation

Number of times larger = 5.11 × 10⁴ kilometers/6.79 × 10³ kilometers

Evaluate the quotient

So, we have the following representation

Number of times larger = 7.5

Hence, the number of times is 7.5

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The behavior of the graph at the intervals are as follows

(0, 4} = increasing

(0, 2} = negative

{-2, 0) = decreasing

(-4, -1) = positive

The intervals represents some numbers and the numbers within the interval depends on the type bracket

(0, 4} = integer values from 1 2 3 4 at this interval the curve is going up hence increasing

(0, 2} =  integer values from 1 2 at this interval the curve is on the negative side

{-2, 0)  =  integer values from -2 -1  at this interval the curve is on the decreasing

(-4, -1) = integer values from  -3 -2 -1  at this interval the curve is on the on the positive side

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Answer:

165 students or the sophomore class of 220 are not athletic.

Step-by-step explanation:

60/240 = .25 This means that 25% of the class is athletic.  That would mean and .75 or 75% are not athletic.

220 x .75 = 165

This type of blinding is used to prevent a potential source of bias in the experiment. By keeping the subjects unaware of the treatment they are receiving, the researchers can eliminate the possibility of any psychological effects influencing the outcome of the study. This is particularly important in cases where a treatment is being evaluated for subjective outcomes such as pain, anxiety, or depression, as the subjects' expectations and beliefs can influence their perception of the treatment's effectiveness. By keeping the subjects blinded to their treatment, researchers can ensure that the results of the study are as unbiased as possible.

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Given the function p(x)=6x+2, p(-2) is -10 while p(4) is 26, this shows that value of p(-2) is smaller than the value of p(4). The correct option is B.

A function is an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable). It is a relation between a set of inputs and a set of permissible outputs with the property that each input is related to exactly one output. Let A & B be any two non-empty sets; mapping from A to B will be a function only when every element in set A has one end, only one image in set B.

p(x)=6x+2

for p(-2)

p(-2) = 6(-2) + 2

p(-2) = -12 + 2

p(-2) = -10

for p(4)

p(4) = 6(4) + 2

p(4) = 24 + 2

p(4) = 26

p(-2) < p(4)

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Answer:

(B) "The value of p(-2) is smaller then the value of p(4)" is True

Step-by-step explanation:

p(x)=6x+2

p(-2) = 6*(-2)+2

p(-2) = -12+2

p(-2) = -10

p(4) = 6*(4)+2

p(4) = 26

====

p(-2) = -10

p(4) = 26

===

(A) The value of p(-2) is larger then the value of p(4).   False

(B) The value of p(-2) is smaller then the value of p(4).  True

(C) The value of p(-2) is the same as the value of p(4).  False

(D) The values of p(-2) and p(4) cannot be compared.   False

The arithmetic expression may be used to get the formula T = (11 + w)/4, which is the distance Kane runs in a training session after w weeks.

Every training session, Kane begins out by running 3 miles, and he has a plan to improve that distance by 1/4 mile each week.

The number of weeks is w.

The arithmetic progression may be used to calculate an expression that displays the distance Kane runs during a training session after w weeks.

T = A + (n-1)d is the formula for the nth term in an arithmetic operation, where an is the first term, which is 3, d is the difference between two consecutive terms, which is, is the last term, and n is the total number of terms.

We get, T = (11+w)/4

This is the expression to show the distance Kane runs in a training session after w weeks.

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Complete question - Kane is training for a marathon. He starts by running 3 miles during every training session each week plans to increase the distance of his runs by 1/4 mile. Let w be the number of weeks. Write and expression to show the distance Kane runs in a training session after w weeks

3a) Rounded to the closest benchmark, Samuel walked about 3 Miles on the parade route.

3b)  Rounded to the closest benchmark, Samuel walked about 2 Miles home

3c) Samuel walked about 5 Miles in all

We know that when rounding a fraction to the closest benchmark:

1) if the numerator is much smaller than the denominator, round a fraction to 0

2) if the numerator  is about half the denominator, round a fraction to 1/2

3) if the numerator is nearly equal to the denominator, round a fraction to 1

Samuel walked 3 1/8 miles along the parade route.

Rounding to the closest benchmark a fraction 3 1/8 woule be

3 1/8

= 3            

This means, he walked about 3 Miles on the parade route.

Samuel walked 2 5/6 miles home.

Rounding to the closest benchmark a mixed fraction 2 5/6 woule be

2 5/6

= 2            

This means, he walked about 2 Miles homes.

The total distance would be,

d = 3 + 2

d = 5 miles

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To simplify the expression 5c−3d−12c+d−6, we can combine like terms:

5c − 12c + d − d − 6 = (-12c + d) + (-6)

Therefore, the expression 5c−3d−12c+d−6 can be simplified to -12c + d - 6.

The area of the semi-circle with the radius of 4.1 mm, round to the nearest tenth is 52.8 mm²

The area of the semi-circle will be calculated by the formula -

Area = 1/2πr², where r is the radius of the circle.

Keep the values in formula to find the value.of area of semi circle

Area = 1/2×3.14×4.1²

Performing multiplication on Right Hand Side of the equation to find the area of the semi-circle

Area = 52.78 mm²

Round off the nearest tenth

Area = 52.8 mm²

Thus, the area of semi-circle with mentioned radius is 52.8 mm².

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The percentage of adults from this country who viewed a college education as essential for success x years after the first year can be represented by the function P(x) = 31 + 2.6x.

What is the percentage function?

To determine the percentage, we have to divide the value by the total value and then multiply the resultant by 100. Percentage formula = (Value/Total value) × 100. Example: 2/5 × 100 = 0.4 × 100 = 40 per cent.

The percentage of adults from this country who viewed a college education as essential for success x years after the first year can be represented by the function:

P(x) = 31 + 2.6x

Where P(x) is the percentage of adults who viewed college education as essential for success x years after the first year, and x is the number of years after the first year.

The function shows that the percentage increase by 2.6 every year for x years after the first year, and the initial percentage is 31%.

This function is representing a linear trend since the coefficient of x is constant.

Hence, The percentage of adults from this country who viewed a college education as essential for success x years after the first year can be represented by the function P(x) = 31 + 2.6x.

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Therefore, there are 12 bandages in 2 boxes, which is the answer to the unitary method presented problem.

The term "unitary" refers to a single or separate unit or variable . As a result, this strategy's objective is to establish values in terms of a single unit. For instance, if a car travels 44 kilometres on two litres of gas, the unitary technique can be used to determine how many kilometers it will drive on one.

Here,

Given: Each box of bandages has three packs, with two bandages in each pack.

Now, determine how many bandages there are in two boxes.

Therefore, we solve using the unitary method:

One pack contains two bandages.

In 3 packs, there are therefore = 2*2 = 6 bandages.

One box contains three packs as stated.

Consequently, we multiply 2 by 6 to obtain the bandages in 2 boxes:

=> 2 * 6 = 12

Therefore, there are 12 bandages in 2 boxes, which is the answer to the unitary method's presented problem.

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Proportion is the ratio of the two equal fractions. It compares the part of a whole to another part of another whole. Option c is the correct option which is, The test provides convincing evidence the proportion is greater than 90% but the actual proportion is equal to the 90%.

What is proportion?

proportion is the ratio of the two equal fraction. It compare the part of a whole to other part of of the another whole.

Given

Options for the following question are,

A) The test does not provide convincing evidence that the proportion is greater then 90 percent but the actual proportion is greater then 90 percent.

B) The test does not provide convincing evidence  the proportion is greater than 90% but the actual proportion is equal to the 90%.

C)The test provides convincing evidence the the proportion is greater than 90% but the actual proportion is equal to the 90%.

D)The test provides convincing evidence that the proportion is greater then 90 percent but the actual proportion is greater then 90 percent.

E) All type 1 error is not possible for this hypothesis test.

The Null Hypothesis for the given question is,

The proportion of all washers produced with the specified diameter is equal to 90 percent. The Null Hypothesis for the given case is true and actual proportion is equal to 90 percent.

Hence, option c is the correct option which is, The test provides convincing evidence tha the proportion is greater than 90% but the actual proportion is equal to the 90%.

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Answer:

30 degrees

Step-by-step explanation:

Answer:

Here are a few of the factor pairs. The rest you can find in the pdf below.

The measure of angle B is, 67°.

A triangle is a three sided polygon, which has three vertices and three angles which has the sum 180 degrees.

Given that;

Interior angles are,

⇒ ∠ C = 83°

⇒ ∠ B = 6x + 7

An exterior angle is,

⇒ ∠ A = 15x

Now, We know that;

The sum of two interior angles in a triangle is equal to the exterior angle in a triangle.

⇒ 83° + 6x + 7 = 15x

⇒ 90 = 15x - 6x

⇒ 90 = 9x

⇒ x = 10

Thus, The measure of B is,

⇒ m ∠B = 6x + 7

             = 6×10 + 7

             = 60 + 7

             = 67

⇒ m ∠B =  67

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The answer would be −6q−11

Answer:

-6q-11

Step-by-step explanation:

Answer:

C - 16√5

Step-by-step explanation:

Simply subtract 19 and 3 while keeping √5 the same.

19√5 - 3√5 = 16√5

Answer: Based on the survey results, we can calculate the number of ice cream cones to sell for each flavor by multiplying the percentage of the flavor by the total number of ice cream cones to be sold.

Mint: 10% of 300 ice cream cones = 0.1 * 300 = 30 ice cream cones

Strawberry: 25% of 300 ice cream cones = 0.25 * 300 = 75 ice cream cones

Chocolate chip: 15% of 300 ice cream cones = 0.15 * 300 = 45 ice cream cones

Vanilla: 50% of 300 ice cream cones = 0.5 * 300 = 150 ice cream cones

So, based on the survey results, you should sell 30 ice cream cones of Mint flavor, 75 ice cream cones of Strawberry flavor, 45 ice cream cones of Chocolate chip flavor, and 150 ice cream cones of Vanilla flavor.

It's worth mentioning that the sum of the percentages provided, 10+25+15+50 = 100%. Which means that it is a proper survey and the total number of ice cream cones you expect to sell is equal to the survey results.

Step-by-step explanation:

Based on the survey results flavors sold at the sporting event are, 30 mint ice creams, 75 Strawberry icecreams, 45 Chocolate chip icecreams, and 150 Vanilla icecreams.

A percentage is a value per hundredth. Percentages can be converted into decimals and fractions by dividing the percentage value by a hundred.

The number of different types of ice creams can be obtained as follows,

10% - Mint.

= (10/100)×300.

= 30.

25% - Strawberry.

= (25/100)×300.

= 75.

15% - Chocolate chip.

= (15/100)×300.

= 45.

50% - Vanilla.

= (50/100)×300.

= 150.

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Yes, the rate 4.8 laps every 8 minutes; 3.6 laps every 6-minute form a proportion.

A proportion is an equation that sets two ratios at the same value. For instance, you might express the ratio as follows:

1: 3 if there is 1 boy and 3 girls (for every one boy there are 3 girls) There are 1 in 4 boys and 3 in 4 girls. 0.25 are male (by dividing 1 by 4)

4.8 lap every 8 minutes will be equal to (4.8/8) = 0.6 lap a minute.

3.6 lap every 6 minutes will be equal to (3.6/6) = 0.6 lap in a minute.

Here, as the value of the ratio of both the quantities are same so the given values are said to be in Proportion.

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By plot in graph, we get Y=6 and x=-1 is perpendicular lines.

Parallel lines are lines in a plane that are always the same distance apart and never intersect. They are coplanar lines that do not intersect each other, and they have the same slope.

Perpendicular lines are lines that intersect at a right angle (90 degrees). In other words, they are lines that are at a 90-degree angle to each other. The slope of perpendicular lines are opposite reciprocals of each other, meaning that if one line has a slope of m, the other line will have a slope of -1/m.

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An imaginary number is produced when we square a negative number.

The value of I is -1.

This article's introduction included a proposition. The specific measure or value of what I stands for was the subject of the statement. It is discussed in this section of the article along with an explanation of its value.

Iota is the term used to describe the imaginary portion of a complex number. The symbol "iota" or I is used to represent an imaginary number's value. An imaginary number is produced when we square a negative number.

The value of I is -1.

The concept of complex numbers is understood using this value of i.

x2 plus 1 equals zero in a quadratic equation.

x2 = -1

x = √-1

The imaginary portion is shown as -1.

I = √-1

i2 = -1

An imaginary number can be squared to get a negative value, as was previously discussed.

I = √-1

both sides being square

i2 = -1

An imaginary number plus a real number are combined to get any complex number. Iota, sometimes known as I stands for all non-real quantities.

Real numbers include 10, -20, 3, and other like values.

The integers 2i, -5, -i, etc. are examples of imaginary numbers.

Complex numbers take the form of a + ib, where I denotes the imaginary component. In addition, the number zero is complicated. Only the imaginary component of a complex number can be added to or subtracted from the imaginary part, and vice versa for the real part of the complex number.

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