The value of ΔS° for reaction is - 22.2 J/K.mol
[tex]SO_{2}(s)+NO_{2} (g)[/tex] → [tex]SO_{3}(g)+NO(g)[/tex]
Calculation,
Given value of S°(J/K.mol) for
[tex]SO_{2}(s)[/tex] = 248.5
[tex]NO_{2} (g)[/tex] = 240.5
[tex]NO(g)[/tex] = 210.6
[tex]SO_{3}(g)[/tex] = 256.2
Formula used:
ΔS° (Reaction) = ∑S°(Product) - ∑S°(Reactant)
ΔS° = (256.2 + 210.6 ) - ( 248.5 + 240.5) = 466.8 - 489 = - 22.2 J/K.mol
The change in stander entropy of reaction is - 22.2 J/K.mol. The negative sign indicates the that entropy of reaction is decreases when reactant converted into product.
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Justify the statement, "nuclear energy is harmful as well as useful."
Nuclear energy is harmful because it releases of harmful ionizing radiation and has been employed in the production of atomic bombs and hydrogen bombs.
Nuclear energy is beneficial in that it produces vast amount of energy for domestic and industrial purposes.
What is nuclear energy?Nuclear energy refers to the energy which is produced as a result of the changes that occur in the nucleus of atoms of elements.
Nuclear energy produces the largest amount of energy when compared to other forms of energy sources.
Nuclear energy is produced by two types of nuclear reactions:
Nuclear fission and Nuclear fusionNuclear energy is harmful in that it results in the release of harmful ionizing radiation which damages cells and tissues of living organisms.
Nuclear energy is also harmful because nuclear energy has been employed in the production of atomic bombs and hydrogen bombs.
On the other hand, nuclear energy is beneficial in that it produces vast amount of energy which can be used for domestic and industrial purposes. It also produces fewer wastes that damage the environment compared to fossil fuels.
In conclusion, nuclear energy is both beneficial and harmful.
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The equilibrium concentration of sulfide ion in a saturated lead sulfide solution is M. (Assume that .)
What property should a radioisotope used for dating have?
OA. It must be an isotope not commonly found in the fossil.
OB. Its half-life should be similar to the age of the fossil.
OC. It must have a half-life much longer than the fossil age.
OD. It must decay to a stable isotope of the same element.
The property a radioisotope used for dating should have is Its half-life should be similar to the age of the fossil and is denoted as option B.
What is a Radioisotope?This is an element which is unstable and releases radiation to achieve its stability.
The half-life of the element used in dating should be similar to that of the fossil for easy comparisons and accuracy.
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Answer:
b, half life should be similar to the fossil
Explanation:
A Carnot cycle operates between the temperatures limits of 400 K and 1600 K, and produces 3600 kW of net power. The rate of entropy change of the working fluid during the heat addition process is
The rate of entropy change:
The rate of entropy change of the working fluid during the heat addition process is 3 kW/K
What is the Carnot cycle?
The Carnot Cycle is a thermodynamic cycle made up of reversible isothermal expansion, adiabatic expansion, isothermal compression, and adiabatic compression processes in succession. The ratio of the heat absorbed to the temperature at which the heat was absorbed determines the change in entropy.The entropy of a system:
The rate of heat addition is expressed as,
Q = [tex]\frac{WT_{H}}{T_{H}- T_{L}}[/tex]
The entropy of a system is a measure of how disorderly a system is getting. The rate of entropy generation during heat addition is,
[tex]S_{gen} = \frac{Q}{T_{H}} = \frac{W}{T_{H} - T_{L}}[/tex]
Calculation:
Given:
[tex]T_{L}[/tex] = 400K
[tex]T_{H}[/tex] = 1600K
W = 3600 kW
Put all the values in the above equation, and we get,
[tex]S_{gen} = \frac{W}{T_{H} - T_{L}}[/tex] = [tex]\frac{3600}{1600-400}[/tex] = 3 kW/K
The rate of entropy change is 3 kW/K
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A sparingly soluble metal hydroxide, m(oh)2 has a molar solubility of s mol/l at 25°c. its ksp value is:______
The value of the Ksp can be obtained in terms of s as 4s^3.
What is Ksp?The term Ksp has to do with the solubility product. It is the extent to which a substance can dissolve in water. We know that the solubility of the substance can be given as;
M(OH)2(s) ⇔M^+(aq) + 2OH^-(aq)
Ksp = s * (2s)^2
Ksp = s * 4s^2
Ksp = 4s^3
Thus it follows that the value of the Ksp can be obtained in terms of s as 4s^3.
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Please Help! Is it possible to have two other resonance structures with the double bond being connected to the chlorine.
It is possible for two other resonance structures to be connected but results in positive formal charge which isn't suited for a very electronegative atom such as chlorine.
What is a Lewis structure?This is a type of diagram which depicts the bonding between atoms and lone pairs which are present in the molecule.
Adding two other resonance structures will also result in the poor overlap between the p-orbitals.
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Given the following equation: __ Al(s) __ O2(g) --> __ Al2O3(s) When the equation is correctly balanced using smallest whole numbers, the coefficient of Al(s) is:
Answer:
The coefficient for Al(s) is 2.
Explanation:
__ Al(s) __ O2(g) --> __ Al2O3(s)
__ Al(s) __ O2(g) --> 1 Al2O3(s)
1 Al(s) __ O2(g) --> 1 Al2O3(s)
1 Al(s) + 1.5 O2(g) --> 1 Al2O3(s) [Use a fraction to make it balance]
2 Al(s) + 3 O2(g) --> 2 Al2O3(s) [Convert the 1.5 fraction to a whole number by multiplying all coefficients by 2]
Monosaccharides are the smallest building blocks of sugars and have similar chemical compositions. Considering that simple sugars are a component of carbohydrates, what is the general chemical composition of monosaccharides
Answer:
See below
Explanation:
Monosaccharides:They are the simplest sugars.They can not be hydrolyzed.They are sweet in taste.They are soluble in water.They have the general formula of [tex]C_n(H_2O)_n[/tex]Chemical composition:They are composed of:CarbonHydrogenOxygen[tex]\rule[225]{225}{2}[/tex]
A sample of aluminum metal is placed in a graduated cylinder. It is noted that 5.50 mL of water is displaced by the aluminum. The aluminum is then reacted with excess nitric acid to produce aluminum nitrate and hydrogen gas. Given the density for aluminum is 2.702 g/mL, how many grams of hydrogen gas are produced in the reaction
117.3 grams of hydrogen gas is produced in the reaction
What is Graduated cylinders?Graduated cylinders are long, slender vessels used for measuring the volumes of liquids. They are not intended for mixing, stirring, heating, or weighing. Graduated cylinders commonly range in size from 5 mL to 500 mL. Some can even hold volumes of more than a liter.
Density - density is the mass of a material substance per unit volume. d = M/V, where d is density, M is mass, and V is volume, is the formula for density. Grams per cubic centimetre are a typical unit of measurement for density.
2Al + 6 HCl = 2AlCl₃ + 3H₂
Density = mass / volume
2.702 g/mL = m / 5.50 mL
m = 14.861 g
mol Al = mass / molar mass
= 14.861 g / 26.98 g/mol
= 0.551 mol
So number of mol of aluminium nitrate formed will also be 0.551 mol
Mass of aluminium nitrate = mol x molar mass
= 0.551 mol x 212.996 g/mol
= 117.3 grams
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(REALLY NEED HELP) What refers to the amount of electric force that could be created if the electric current were to flow?
electrical energy
electrical potential
electrical charge
electrical conduction
Answer:
electrical conduction
Explanation:
Carbon disulfide is a linear molecule with two double bonds. According to valence bond theory, which orbitals on carbon are used for pi bonding?
According to valence bond theory, 2s and 2p orbital of carbon atom will be formed pi bonding.
One of it's two fundamental theories created to use quantum mechanics to describe chemical bonding would be the valence bond theory, and molecular orbital theory.
Eight valence electrons should be used to generate two double bonds in the CS2 molecule. As a result, it uses up eight of the 16 valence electrons. These valence electrons are located in the carbon atom's 2s and 2p orbitals, where they join to create a double bond.
Therefore, according to valence bond theory, 2s and 2p orbital of carbon atom will be formed pi bonding.
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I NEED HELP ASAPPPP
Once extracted and purified, 20.0 grams of a pure sample of
substance X is thermally decomposed at 840oC. The two products of this reaction are calcium oxide and carbon dioxide gas. Write a balanced chemical equation and calculate the mass of calcium oxide produced. Show your process.
BALANCED CHEMICAL EQUATION:
PROCESS:
Answer:
11.2 grams CaO
Explanation:
It appears that substance X may be calcium carbonate: CaCO3
CaCO3 can be thermally decomposed to CO2 and CaO in the following balanced reaction:
CaCO3(s) ⇒ CaO(s) + CO2(g) (with applied heat, 840°C)
The molar ratio between the product, CaO, and the reactant, CaCO3, is 1:1. If we start with 1 mole CaCO3, we should produce 1 mole of CaO.
We have 20.0 grams of substance X, which we'll label CaCO3. Calculate the moles of CaCO3 by using its molar mass of 100.1 grams/mole.
20.0 grams/(100.1 grams/mole) = 0.1998 or 0.200 moles of CaCO3.
This should produce, with a molar ratio of 1 to 1, 0.200 moles of CaO
Convert this to grams CaO by multiply by it's molar mass of 56.1 g/mole:
(0.200 moles)*(56.1 g/mole) = 11.2 grams CaO. Any less, then blame it on your lab partner. But don't try taking credit if you have more than 11.2 grams. Scraping debri off the counter into the beaker doesn't count.
Draw the major product formed in the reaction of an epoxide with methoxide in methanol.
the major product of the reaction is (2S,3R)-3-methoxy-3-methylpentan-2-ol.
Epoxy, epoxide, oxirane, and ethoxyline are all names for substances that contain the epoxide functional group. Oxides are a common name for simple epoxides. Consequently, ethylene oxide is the epoxide of ethylene (C2H4).
Reaction and explanation.
In order to answer this question, we must draw the main product and the studio chemistry. Yeah. Therefore, we will begin by drawing the reactant, which is an oxide.
As with this structure. Therefore, C. S. is applied to this epoxy side. Three ohs and two hash marks. As a result, the oxygen will be presented with the lone pair on the initial stage. And after that, we will receive the prototype for a thirty-plus-year-old product. And everything else will proceed as usual, even this.
Now this bond will be severed, and three miners from O. C. S. will attack from the back, in which case we will receive the finished product as seen here.
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(2S,3R)-3-methoxy-3-methylpentan-2-ol is the reaction's main product.
Epoxide functional group-containing compounds go by the names epoxy, epoxide, oxirane, and ethoxyline. Simple epoxides are frequently referred to as oxides. As a result, ethylene oxide is ethylene's epoxide (C2H4).Reaction and justification.We must illustrate the primary product and the studio chemistry in order to provide a response. As a result, we shall start by drawing the oxide reactant.similar to this structure C. S. is therefore applied to this epoxy side. Two hash marks and three OHs. As a result, on the initial stage, the oxygen will be presented with the sole pair. Then we will get the prototype for a product that has been around for more than thirty years. And even this will occur according to plan.This relationship will now be broken, and three O. C. S. miners will assault from behind, resulting in the finished article you see here.To learn more about epoxide visit:
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CONCLUSIONS: Suppose a student titrated a sample of monoprotic acid of unknown concentration using a previously standardized solution of NaOH. volume of 0.125 M NaOH dispensed 24.68 mL volume of acid solution 50.00 mL Given the data in the table above, what is the concentration of the unknown acid?
Concentration of unknown acid is 0.061 M
Given:
Concentration of NaOH = 0.125 M
Volume of NaOH = 24.68 mL
Volume of acid solution = 50.00 mL
To Find:
Concentration of the unknown acid
Solution: Concentration is the abundance of a constituent divided by the total volume of a mixture. The concentration of the solution tells you how much solute has been dissolved in the solvent
Here we will use the formula for concentration:
M1V1 = M2V2
0.125 x 24.68 = 50 x M2
M2 = 0.125 x 24.68 / 50
M2 = 0.061 M
Hence, the concentration of unknown acid is 0.061 M
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Consider the reaction. At 298 K, the equilibrium concentration of O2 is 1.6 x 10-2 M, and the equilibrium concentration of O3 is 2.86 x 10-28 M. What is the equilibrium constant of the reaction at this temperature
The value of the equilibrium constant is 1.99 × [tex]10^-^5^0[/tex] .
Given:
Concentration of [tex]O_2 = 1.6[/tex] × [tex]10^-^2 M\\[/tex]
Concentration of [tex]O_3 = 2.86[/tex] × [tex]10^-^2^8 M[/tex]
A chemical reaction known as an equilibrium reaction occurs when the reactants remain in a stable condition both during and after the reaction.
The given balanced equilibrium reaction is,
[tex]3O_2 (g) = 2O_3 (g)[/tex]
The expression for equilibrium constant will be,
[tex]K_c = \frac{[O_3] ^2}{[O_2]^3}[/tex]
Now put all the given values in this formula, and we get
[tex]K_c = \frac{(2.86 * 10^-^2^8] ^2}{[1.6 * 10 ^-^2]^3}[/tex]
[tex]K_c = 1.99[/tex] × [tex]10^-^5^0[/tex]
Therefore, the value of the equilibrium constant is 1.99 × [tex]10^-^5^0[/tex] .
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What is the electron structure of a beryllium atom? 1s ²2s 1 O 1s 22s 2 1s ¹2s 2 1s 23s 2
Answer:
Be = 1s²2s²
Explanation:
Beryllium (Be) is the 4th element on the periodic table. As such, beryllium has 4 electrons. It is the second element located in the second row in the s-block. Therefore, beryllium's electron structure should consist of 2 completely filled s-orbitals.
Answer:
Explanation:
8281s
What is the energy change when 100g of Benzene boils at 80.1°C?
The enthalpy of vaporization for Benzene is 30.8 kJ/mol. 39.42 kJ is the energy change when 100g of Benzene boils at 80.1 degrees Celsius.
What is Enthalpy of Vaporization ?The amount of enthalpy or energy that must be added to a liquid substance into gas substance is called Enthalpy of Vaporization. It is also known as Latent heat of vaporization.
How to find the energy change from enthalpy of vaporization ?To calculate the energy use this expression:
[tex]Q = n \Delta H_{\text{vapo.}[/tex]
where,
Q = Energy change
n = number of moles
[tex]\Delta H_{\text{Vapo.}}[/tex] = Molar enthalpy of vaporization
Now find the number of moles
Number of moles (n) = [tex]\frac{\text{Given Mass}}{\text{Molar mass}}[/tex]
= [tex]\frac{100\ g }{78\ g/mol}[/tex]
= 1.28 mol
Now put the values in above formula we get
[tex]Q = n \Delta H_{\text{vapo.}[/tex]
= 1.28 mol × 30.8 kJ/mol
= 39.42 kJ
Thus from the above conclusion we can say that The enthalpy of vaporization for Benzene is 30.8 kJ/mol. 39.42 kJ is the energy change when 100g of Benzene boils at 80.1 degrees Celsius.
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Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: The enthalpy of vaporization for Benzene is 30.8 kJ/mol. What is the energy change when 100g of Benzene boils at 80.1 degrees Celsius?
_____ is a buildup of fluid within the eye.
a. macular
b. degeneration
c. cataracts
d. glaucoma
e. osteoporosis
Glaucoma Is a buildup of fluid within the eye.
The optic nerve, which is necessary for clear vision, is harmed by a group of eye conditions collectively referred to as glaucoma. This injury typically happens as a result of an excessively high amount of pressure in your eye. Glaucoma is one of the leading causes of blindness in persons over 60. Glaucoma frequently results from high intraocular pressure. Diabetes, however, can also increase your risk of developing glaucoma. We'll go into more detail about the connection between diabetes and glaucoma in this piece. We'll also talk about some preventative steps you may take to help keep your eyes healthy. Loss of side or peripheral vision: Often, this is the first glaucoma symptom.
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Influence of bromine and iodine chemistry on annual, seasonal, diurnal, and background ozone: CMAQ simulations over the Northern Hemisphere
It does not have a strong seasonal influence on ozone over the Northern Hemisphere.
OzoneThree oxygen atoms make up ozone, a highly reactive gas. The stratosphere, the upper atmosphere of the planet, and the lower atmosphere both include this naturally occurring and artificial substance (the troposphere). Ozone has an impact on life on Earth, but only depending on where it resides in the atmosphere.
Molecular oxygen and solar ultraviolet (UV) light interact to naturally create stratospheric ozone. The "ozone layer," which is located 6 to 30 miles above the Earth's surface, decreases the quantity of dangerous UV light that reaches the surface.
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Regions in the human genome where one nucleotide has been substituted for another in at least 1% of the population are called:_______
Regions in the human genome where one nucleotide has been substituted for another in at least 1% of the population are called single nucleotide polymorphism
What are nucleotides?Nucleotide can simply be defined as the basic building block of nucleic acids either RNA and DNA
Generally, nucleotides consists of a sugar molecule (either ribose in RNA or deoxyribose in DNA) attached to a phosphate group and a nitrogen-containing base.
A region is any considerable and connected part of a space or surface; specifically, a tract of land or sea of considerable but indefinite extent, a country, a district, in a broad sense, a place without special reference to location or extent but viewed as an entity for geographical, social or cultural reasons.
So therefore, regions in the human genome where one nucleotide has been substituted for another in at least 1% of the population are called single nucleotide polymorphism.
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Consider the balanced chemical equation when 18.3 g Al is reacted with 113 g I₂ to form AlI₃(g).
What is the mass in grams of the excess Al remaining after the partial reaction of 18.3 g Al with 113 g I₂?
2 Al(s) + 3 I₂(g) → 2 AlI₃(g)
Answer:
10.3 g Al
Explanation:
To find the excess mass of Al, you need to (1) convert grams I₂ to moles I₂ (via molar mass), then (2) convert moles I₂ to moles AlI₃ (via mole-to-mole ratio from equation coefficients), then (3) convert moles AlI₃ to grams AlI₃ (via molar mass). Now that you have the actual amount of AlI₃ produced, you need to (4) convert grams AlI₃ to moles AlI₃ (via molar mass), then (5) convert moles AlI₃ to moles Al (via mole-to-mole ratio from equation coefficients), and then (6) convert moles Al to grams Al (via molar mass). Now that you know the amount of Al actually needed to produce the product, you need to (7) find the excess mass of Al.
Molar Mass (Al): 26.982 g/mol
Molar Mass (I₂): 2(126.90 g/mol)
Molar Mass (I₂): 253.8 g/mol
Molar Mass (AlI₃): 26.982 g/mol + 3(126.90 g/mol)
Molar Mass (AlI₃): 407.682 g/mol
2 Al(s) + 3 I₂(g) -------> 2 AlI₃(g)
113 g I₂ 1 mole 2 moles AlI₃ 407.682 g
------------- x ---------------- x ---------------------- x ------------------- = 121 g AlI₃
253.8 g 3 moles I₂ 1 mole
121 g AlI₃ 1 mole 2 moles Al 26.982 g
--------------- x ------------------ x --------------------- x ----------------- = 8.01 g Al
407.682 g 2 moles AlI₃ 1 mole
Starting Amount - Mass Needed = Excess
18.3 g Al - 8.01 g Al = 10.3 g Al
what is the formula n²o
Answer:
Nitrous oxide
Explanation:
Nitrous+ Oxygen (ygen becomes -ide when it is combined) = Nitrous oxide
just learnt these in school, hope this is correct
hii kiran hru my darling
C3H8 has a boiling point than C2H6
Answer:
C₃H₈ has a higher boiling point than C₂H₆
Explanation:
The boiling point is the temperature at which the intermolecular bonds holding molecules in liquid form are overcome and change the state into a gas. C₃H₈ experiences stronger intermolecular bonds then C₂H₆ because it has more carbons. While the strength of each bond is the same between the two molecules, C₃H₈ has more opportunities to create these bonds due to the higher carbon count. The more bountiful the intermolecular bonds, the more energy is needed to overcome them all. Thus, C₃H₈ has a higher boiling point.
Help me ASAP please!!!
The concentration of the sodium hydroxide will be 0.016 M
Stoichiometric problemFirst, the concentration of the diluted nitric acid needs to be found.
m1 = 2.0 M, v1 = 100 mL, v2 = 300.0 mL
m2 = 2 x 100/300 = 0.6667 M
The equation of the reaction goes thus: [tex]HNO_3 + NaOH = NaNO_3 + H_2O[/tex]
The mole ratio is 1:1.
Mole of 0.6667 M, 7.05 mL HNO3 = 0.6667 x 0.00705 = 0.0047 mol
Equivalent mole of NaOH = 0.0047 mol
Molarity of 0.0047 mol, 30.0 mL NaOH = 0.0047/0.3 = 0.016 M
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Comparison of IR of starting materials (given in the lecture) to IR of product What indicates the purity of the product on the IR spectrum of product
The Old Way
If the peaks matched those of known impurities, they could use the intensities to calculate the purity of the ester.
What is IR Spectrum ?IR-spectroscopy is perhaps the most frequently used technique in the organic chemistry labs at PSU. It is routinely used to identify products and to verify that an experiment has succeeded.
An IR -spectrum routinely shows peaks from the range of 3600 to 500 cm-1. IR -frequencies correspond to the frequencies of molecular vibrations. The IR spectrum can be used to show that there is not any starting material left by the loos of the alkene bond(C=C) between 1500cm^-1 and 1800cm^1 from 1-hexene and the addition of a hydroxyl group(-OH) of 2-Hexanol between 3000cm^-1 and 3300cm^-1.Learn more about IR Spectrum here:
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When taking ph measurements of solutions, why is it important to stir thoroughly after adding each reagent?.
A solid form of matter in which there is long range repeating order is called ________
Answer: A solid form of matter in which there is long-range repeating order is called crystalline.
Explanation:
A solid is crystalline if it has long-range order. Once the positions of an atom and its neighbors are known at one point, the place of each atom is known precisely throughout the crystal.
In your reaction you started with a solution that was approximately 8 M acetic acid and 4 M isopentyl alcohol. Use the equilibrium expression for this reaction to calculate the final concentrations of water, isopentyl acetate, isopentyl alcohol, and acetic acid (you'll need to use the quadratic equation to solve this expression) assuming that the equilibrium constant is 4.2. Calculate the percent yield of isopentyl acetate to which this value would correspond.
The final concentrations of water, isopentyl acetate, isopentyl alcohol, and acetic acid obtained on using equilibrium expression are 3.4M, 3.4M, 0.6M , 4.6M
Using ICE table:-
Acetic acid + Isopentyl alcohol ------> Isopentyl acetate + water
I 8M 4M 0 0
C 8-x 4-x +x +x
E 8-x 4-x +x +x
Equilibrium constant (Keq) = 4.2
On using the equilibrium expression -
Keq = [Product] / [Reactant]
Keq = x^2 / (8-x) (4-x )
4.2 = x^2 / 32 - 8x - 4x + x^2
x = 3.4
Concentration of acetic acid = 8-x = 8-3.4 = 4.6M
Concentration of isopentyl alcohol = 4-x = 4-3.4 = 0.6M
Concentration of isopentyl acetate = x = 3.4M
Concentration of water = x = 3.4M
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(RLLY NEED HELP) What is caused by friction between two objects?
Static electricity
Dry air
A circuit
Moist air
How many grams of aluminum are required to react with 35 mL of 2.0 M hydrochloric acid, HCl?__ HCl + __ Al --> __ AlCl3 + __ H2
Answer:
0.6258 g
Explanation:
To determine the number grams of aluminum in the above reaction;
determine the number of moles of HCldetermine the mole ratio,use the mole ratio to calculate the number of moles of aluminum.use RFM of Aluminum to determine the grams required.Moles of HCl
35 mL of 2.0 M HCl
2 moles of HCl is contained in 1000 mL
x moles of HCl is contained in 35 mL
[tex]x \: mol \: = \: \frac{2 \: \times \: 35}{1000} \\ = 0.07 \: moles \: [/tex]
We have 0.07 moles of HCl.
Mole ratio
Balanced equation6HCl(aq) + 2Al(s) --> 2AlCl3(aq) + 3H2(g)
Hence mole ratio = 6 : 2 (HCl : Al
but moles of HCl is 0.07, therefore the moles of Al;[tex] = \frac{2}{6} \times 0.07 \\ \: = 0.0233333 \: moles[/tex]
Therefore we have 0.0233333 moles of aluminum.
Grams of Aluminum
We use the formula;
[tex]grams \: = moles \: \times \: rfm[/tex]
The RFM (Relative formula mass) of aluminum is 26.982g/mol.
Substitute values into the formula;
[tex] = 0.0233333 \: moles \: \times \: 26.982 \: \frac{g}{mol} \\ = 0.625799 \: grams[/tex]
The number of grams of aluminum required to react with HCl is 0.6258 g.