The area of the sector of the given circle is: 40 units²
What is circle?A circle is a round-shaped figure that has no corners or edges. In geometry, a circle can be defined as a closed, two-dimensional curved shape.
The set of all points on a plane that are a fixed distance from a center,
A circle is a special kind of ellipse in which the eccentricity is zero and the two foci are coincident.
The circle is the shape with the largest area for a given length of perimeter.
Given the following:
r = 8
θ = 1.25 radians
Area of sector = (1/2) × r²θ = (1/2) × (8²)(1.25)
Hence, the Area of sector = 40 units²
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Given 3x+y=1
Write the equation in general form Ax+By+C =0
3* -y+=0
-3x +y-1=0
3x-y=-1
QUESTION:- Given 3x+y=1
Write the equation in general form Ax+By+C =0
3x-y+1=0
-3x +y-1=0
3x-y=-1
[tex]3x + y - 1 = 0 \: \: ✔[/tex]
ANSWER:-
Equation-->[tex]3x + y = 1 [/tex]
Form of the given equation->
[tex]Ax + By = C[/tex]
so we need to change the side of the C !
while changing side of C we need to change the sign of C !
[tex] \bold{ \red{SO :- }}[/tex]
[tex]3 x + y = 1 \\ 3x + y - 1 = 0[/tex]
FORM OF THE RESULTED EQUATION:-
[tex]Ax + By + C = 0 \\
A = 3 \\ B = 1 \\ C = - 1[/tex]
3. What is the velocity of a collision if a railway train with a mass of 6000 kg is moving to the right at 2.0 [tex]{12{\frac{m}{s}}}[/tex] and collides with an empty freight train with a mass of 3000 kg which ia moving to the left on the same track at 3.0 [tex]{12{\frac{m}{s}}}[/tex]
[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: } [/tex]
[tex]\huge\underline{\sf{\red{Problem:}}}[/tex]
3. What is the velocity of a collision if a railway train with a mass of 6000 kg is moving to the right at 2.0 [tex]{12{\frac{m}{s}}}[/tex] and collides with an empty freight train with a mass of 3000 kg which ia moving to the left on the same track at 3.0 [tex]{12{\frac{m}{s}}}[/tex][tex]\huge\underline{\sf{\red{Given:}}}[/tex]
[tex]\quad\quad\quad\quad\sf{mass \: 1 \: = \: 6000 \: kg}[/tex]
[tex]\quad\quad\quad\quad\sf{velocity\: 1\: = \: 2.0\: m/s}[/tex]
[tex]\quad\quad\quad\quad\sf{mass \: 2\: = \: 3000 \: kg}[/tex]
[tex]\quad\quad\quad\quad\sf{velocity\: 2\: = \: 3.0\: m/s}[/tex]
[tex]\huge\underline{\sf{\red{Fomula:}}}[/tex]
[tex]\quad\quad\quad\quad\boxed{\sf{vf\: = \frac{ \small{m }\tiny{1} \small{v} \tiny{1} \small{ \: + \: m} \tiny{2} \small{v} \tiny{2}}{( \small{m} \tiny{1}\small{ \: + \: m} \tiny{2} \small{)} }}}[/tex]
[tex]\huge\underline{\sf{\red{Solution:}}} [/tex]
[tex]\quad\quad\quad\quad\sf{vf\: = \frac{ \small{m }\tiny{1} \small{v} \tiny{1} \small{ \: + \: m} \tiny{2} \small{v} \tiny{2}}{( \small{m} \tiny{1}\small{ \: + \: m} \tiny{2} \small{)} }}[/tex]
[tex]\quad\quad\quad\quad\sf{vf\: = \frac{(6000 \: kg)(2.0\:m/s)+(3000\:kg)(3.0\:m/s)}{(6000\:kg)+(3000\:kg)}}[/tex]
[tex]\quad\quad\quad\quad\sf{vf\: = \frac{(12,000kgm/s)+(9,000\:kgm/s)}{(9,000kg)}}[/tex]
[tex]\quad\quad\quad\quad\sf{vf\: = \frac{21,000 \: kgm/s}{9000kg}}[/tex]
[tex]\quad\quad\quad\quad\sf{vf\: = \frac{21,000 \cancel{ \red{ kg}}m/s}{9000 \cancel{ \red{kg}}}}[/tex]
[tex]\quad\quad\quad\quad \sf{vf\: = \boxed{ \sf{ 2.33 \:m /s}}}[/tex]
[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]
[tex]\huge\quad\quad \underline{ \sf{\boxed{ \sf{ \red{ 2.33 \:m /s}}}}}[/tex]
[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: } [/tex]
[tex]\sf{\red{︎✰}ShineBrighter\red{︎✰}}[/tex]
[tex]\sf{✍︎ C.Rose\red{❀}}[/tex]
ฅ^•ﻌ•^ฅ
Answer this PLZZZZZZ
Answer:
Hy^2 = H^2 + B^2
= 7^2 + 12^2
D.) = 193 square root
i just need these 2 questions and I’m done please help.!;(
I’ll mark you brainliest.!
Answer:
gal = 663902.4
11 pavers
Step-by-step explanation:
V = l × w × h
V = 164 × 82 × 6.6
V = [tex]88757ft^3[/tex]
**********************************
The Swimming pool is a
rectangular prism. Write
the formula for its volume
and calculate it.
l...length of this prism
w...width of this prism
h...height of this prism
V ...volume
*********************************
To know how many
gallons are in the pool,
multiply the volume by
the number of gallons
in [tex]1ft^3[/tex] gal...number of
gallons
********************************
gal = 88757 × 7.48
gal = 663902.4
********************************
First to not confuse
anybody on this, we need
to convert the meters into
centimeters.
Rule: 1 m = 100 cm
3 m = 300 cm
2.5 m = 250 cm
********************************
so for every meter, we
multiply 100 to get the
amount of centimeters
********************************
so then add the
centimeters of 3 m and
2.5 m
Answer: 550 cm
so then now compare
the measurings...
3 m = 300 cm
50cm × y = 300cm
50cm × 6 = 300cm
y = 6
2.5 m = 250 cm
50cm × y = 250cm
50cm × 5 = 250cm
y = 5
6 + 5 = 11 pavers
so Oliver will need 11 pavers
4400 dollars is place in an account with annual interest rate of 8.25% How much will be in the account after 22years to the nearest cent
Answer: A = 4400(1 + 0.0825 x 22)
Step-by-step explanation:
A = accumulated amount
P = original amount unloaded- $4400
r = rate - 8.25% = 0.0825
t = years = 22
= 4400(1 + 0.0825 x 22)
Answer:
y = 25169.04
Step-by-step explanation:
O is the centre of the circle, EF is a tangent, angle BCE = 28°, angle ACD = 31°
Line AB = line AC
Write down the size of
a) angle BAC
b) angle ABC
c) angle ADC
d) angle COB
Answer
a. 28˚
b. 76˚
c. 104˚
d. 56˚
Step-by-step explanation
Given,
∠BCE=28° ∠ACD=31° & line AB=AC .
According To the Question,
a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚
thus , ∠ABC=76° .
c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°
Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)
∠DAB = 180° - 107° ⇔ 73°
& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°
Now, In Triangle ADC Sum of angles in a triangle is 180°
∠ADC = 180° - (31° + 45°) ⇔ 104˚
d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre
For Diagram, Please Find in Attachment
6ײ+3×y-2a×-ay (need answers)
Answer:
(If the x means the variable in your equation) 2a^2y+6x^2+3xy
Step-by-step explanation:
We have to simplify the equation to find the answer
6x^2+3xy−2a(−a)y
=6x^2+3xy+2a^2y
Name the marked angle in 2 different ways.
1) angle LKM
2) angle MKL
Jaheem has a goal running a total of 125 miles this month. Each day that he ran, he ran 7 miles. Which expression could Jaheem use to determine how many miles he has left to run after running for d days?
x a.
125 – 7d
x b.
7d + 125
x c. fraction numerator 125 over denominator 7 d end fraction
x d.
7d
Answer:
a. 125 – 7d
Step-by-step explanation:
Let d be the number of days.
Given the following data;
Total distance (month) = 125 miles
Distance covered per day = 7 miles
To determine how many miles he has left to run after running for "d" days, this mathematical expression can be used;
Total distance - distance covered per day = number of miles remaining
[tex] 125 - 7d [/tex]
Find one value of x that is a solution to the equation:
(x^2+4)^2 – 11(x^2+4) + 24 = 0
Answer:
x = ±2
x = ±i
Step-by-step explanation:
(x^2+4)^2 – 11(x^2+4) + 24 = 0
Let m = x^2 +4
(m)^2 – 11(m) + 24 = 0
Solving this quadratic
What two numbers multiply to 24 and add to -11
-8*-3 =24
-8-3 = -11
(m-8)(m-3) =0
m = 8 m=3
Now substitute back
x^2 +4 = 8 x^2 +4 = 3
x^2 +4-4 = 8-4 x^2+4-4 = 3-4
x^2 = 4 x^2 = -1
Taking the square root
sqrt(x^2) = sqrt(4) sqrt(x^2) = sqrt(-1)
x = ±2 x = ±i
Answer:
one value of x = 2
Step-by-step explanation:
[tex](x^2 + 4 )^2 - 11(x^2 + 4 ) + 24 = 0\\\\x^4 + 16 + 8x^2 - 11x^2 -44 + 24 = 0\\\\x^4 - 3x^2 -4 = 0\\\\[/tex] ------ ( 1 )
[tex]Let \ x^2 \ = \ u[/tex]
( 1 ) => [tex]u^2 - 3u - 4 = 0[/tex]
[tex]u^2 -4u + u - 4 = 0\\\\u(u - 4) + 1 (u - 4) = 0\\\\(u + 1) (u - 4) = 0\\\\u = -1 \ , \ u = 4[/tex]
[tex]=> x^2 = - 1 \ and \ x^2 = 4[/tex]
[tex]x = \sqrt {-1} = i[/tex]
[tex]x = \sqrt{4} = \pm 2[/tex]
A bagel shop sold 8 plain bagels and 13 rye bagels. What is the ratio of the number of rye bagels to the number of plain bagels sold?
Answer:
13 : 8
Step-by-step explanation:
Number of plain bagels sold = 8
Number of rye bagels sold = 13
Ratio of the number of rye bagels to the number of plain bagels sold = 13 : 8
Also written as
13/8
Or
13 to 8
A bagel shop sold 8 plain bagels and 13 rye bagels. What is the ratio of the number of rye bagels to the number of plain bagels sold?
Answer: It is 13: 8.
A bicycle shop owner offers five styles of mountain bikes for $450, $275, $675, $490, and $300. He wants to increase the mean price but keep the median price and range of prices the same Suggest a new set of prices for the five styles. (Show All Work)
Answer:
275, 300, 450, 490, 675
Median: 450
Q1: 287
Step-by-step explanation:
Find the circumference of this circle.
Use 3.14 to approximate a.
C=2ar
14 ft
C = [?] ft
Answer:
circumference of a circle =2 pi r
radius=14/2=7
2×3.14×7=43.96ft
The circumference of the circle is 43.96 ft.
Given,
Diameter of the circle = 14 ft
π = 3.14
We need to find the circumference of a circle.
What is the circumference of a circle?The circumference is the total length of the surface of the circle.
The circumference is given by:
= 2πr
r = radius of the circle
Diameter = 2radius
Example:
We have,
Diameter = 14 ft
π = 3.14
Radius = diameter / 2 = 14/2 = 7 ft
Circumference:
= 2πr
= 2 x 3.14 x 7
= 43.96 ft
Thus the circumference of the circle is 43.96 ft.
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what is the result of convetting 35 ounces into pounds?
Answer:
35 oz = 2.1875 lb
Step-by-step explanation:
There are 16 ounces in a pound.
35/16 = 2.1875
35 oz = 2.1875 lb.
Hope this helps.
A. write the ratio of girls to boys in the class with 12 girls and 15 boys. reduce to the lowest terms.
B. use the information from part A to estimate the number of girls in the school if there are a total of 1350 students in the whole school and in part A is representative of all classes in the school
WILL GIVE BRAINLIEST plz
The sum of 10 and twice Mai’s age
Answer:
Can I get the full question please
Step-by-step explanation:
x + y = 10 - - - 1
x=2y - - - - - 2
Putting the value of x in eqn 1,
2y+y=10
y=10/3
=3.33 yrs
Which i feel is incorrect
1. Area =
Perimeter =
help me pls i wanna go home ;(
Answer:
Area of a triangle=1/2base x height
1/2x12x4
6x4
24units
Perimeter is the distance round the given figure
9+12+5
26units
Can someone helppppp and explain plsss:))
Answer:
Step-by-step explanation:
Name the marked angle in 2 different ways.
1) angle LJK
2) angle KJL
The marked angle can be named as angle LJK and angle KJL.
What is angle?An angle is a corner whether constituting a projecting part or a partially enclosed space. It is a combination of two rays with a common endpoint.
How to name angles?The angle can be named in two ways depending on the rays that are making angle.In our question the marked angle can be named as LJK and opposite if this KJL because it does not change the value of angles. Whether we start writing from one point to second point and from second point to first point. Main point is that the point at which the angle is formed comes in between both the points of rays.
Hence the marked angle can be named as angle LJK and angle KJL.
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If y=2x+5, then determine the value of y if x=4.
Please help me on this imagine math question!
Answer: the 24 oz hazelnuts
Step-by-step explanation:
Answer:
hazelnuts
Step-by-step explanation:
pecans = $15.2/16= .95
cashews = 5.60/8=.7
almonds = 20.48/32= .64
hazelnuts = 13.5/24 = .56
Which of the numbers listed below are multiples of 3 and 4? 1 ; 2 ; 3 ; 4 ; 6 ; 8 ; 9 ; 12 ; 15 ; 16 ; 18 ; 20 ; 21 ; 24
Answer: 12 and 24
Step-by-step explanation:
Please help me it’s getting late and it’s due tomorrow
For what value(s) of b does the equation
x +3 - x = (bx - 5) have
exactly one solution?
Answer:
[tex]b = \dfrac{11}{x} + 1[/tex]
Step-by-step explanation:
The equation is given as follows;
[tex]x + 3 - \dfrac{1}{2} \cdot x = \dfrac{1}{2} \cdot (b \cdot x - 5)[/tex]
By expanding and collecting terms in x we get;
[tex]3 + \dfrac{x}{2} = \dfrac{b \cdot x}{2} - 2.5[/tex]
[tex]\therefore 3 + 2.5 + \dfrac{x}{2} = 5.5 + \dfrac{x}{2} = \dfrac{b \cdot x}{2}[/tex]
b = (11 + x)/x = 11/x + 1
The equation has exactly one solution when b = 11/x + 1
Divide the following polynomials. (hint; use long division)
(h³ - 4h + 12) / (h+3)
PLZ I NEED HELP!!!!!!!!!!!!!!!!
WILL GIVE BRAINEST!!!!!!!!!!!!!
Answer:
[tex]h^2-3h+5\:\text{remainder }3 \text{ or }h^2-3h+5-\frac{3}{h+3}[/tex]
Step-by-step explanation:
Question: [tex]\frac{h^3-4h+12}{h+3}[/tex] (divide using long division)
To start, our quotient must have a degree of 2, since [tex]h\cdot h^2=h^3[/tex].
From long division, multiply by the highest degree possible with appropriate constants to ride terms of the dividend when necessary. When you finish, the final term at the bottom will be your remainder and your quotient will be on top (in long division form).
The result is [tex]\frac{h^3-4h+12}{h+3}=h^2-3h+5\text{ with a remainder of } 3[/tex]. You can write it in quotient-remainder form, or as one long polynomial: [tex]\implies h^2-3h+5-\frac{3}{h+3}[/tex].
Verify:
[tex](h^2-3h+5)(h+3)=h^3-4h+15=\bold{h^3-4h+12}+\underline{3} \:\checkmark[/tex]
A right triangle with the leg lengths of 7ft and 10ft. Using this information, find the length of the hypotenuse. Then round your answer to the nearest hundredth.
Answer:
12.21
Step-by-step explanation:
Explanation:
This is a right triangle, so the Pythagorean Theorem applies.
The Pythagorean Theorem states that the sum of the squared legs of a triangle is equal to the squared hypotenuse.
The legs of a triangle are the sides that form the right angle.
The hypotenuse of a triangle is the longest side.
Formula/solve:
[tex]a^2+b^2=c^2[/tex]
[tex]a,b-legs[/tex]
[tex]c-hypotenuse[/tex]
Here, I am solving for the hypotenuse.
[tex]7^2+10^2=c^2[/tex]
[tex]49+100=c^2[/tex]
[tex]149=c^2[/tex]
Conclude:
The last step is the cancel out c² by finding the square root of 149.
149 is not a perfect square, so I must round the square root to the nearest hundredth.
[tex]12.2065556157[/tex] ≈ [tex]12.21[/tex]
I, therefore, believe the length of the hypotenuse is 12.21 feet.
Jacob has gained weight.
He now weighs 88kg, which is 10% higher than his normal weight.
What is Jacob's normal weight?
Answer:
x = 80
Step-by-step explanation:
x + .1x = 88
or
x(1+.1) = 88
which ever makes more sense to you
1.1 x = 88
x = 88/1.1
x = 80
Otis and his 2 brother went to their favorite restaurant. Their total bill was $22.42. They used a coupon for 20% off of the total bill. If they split the bill evenly, how much will each person owe, to the nearest cent?
Answer:
$ 5.98
Step-by-step explanation:
20/100 × 22.42/1 = $ 4.48
$ 22.42 - $ 4.48 = $ 17.94
If they split that bill in two each would pay $ 5.98
I hope this helps.
What is the x value of the solution to the system of equations
4y=2x+8
Y=-x+2
Answer:
x=0;y=2
Step-by-step explanation:
4(-x+2)=2x+8 -4x+8=2x+8 -4x-2x=8-8 -6x=0 x=0 y=-x+2 y=0+2 y=2
All the whole numbers from 1 to 100 are written in a row next to each other. How many 7s are there in the formed number?
Please solve with explanation
Answer:
56+8√2=8(7+√2)
Step-by-step explanation:
1. P= AB+BC+CD+DE+EF+FG+GA
2. AB=DC=12
BC=16
AG=ED=4
AG+ED+GE=16
4+4+GE=16
GE=16-8
GE=8
GF²= EF²+GE²
GF²=64+64
GF²=128
GF=8√2
3.P= 12+16+12+4+8+8√2+4= 56+8√2
Answer:
Area = 160 sq cm
Perimeter = 67.31 cm
Step-by-step explanation:
Area of the figure = Area of rectangle with dimensions 16 cm and 12 cm - Area of the right triangle with base and height ecah 8 cm.
=16*12 - 1/2 * 8 *8
= 192 - 32
= 160 sq cm
GEF is a right triangle.
Therefore, by Pythagoras theorem:
[tex] FG^2 = FE^2 + GE^2 [/tex]
[tex] \therefore FG^2 = 8^2 + 8^2 [/tex]
[tex] \therefore FG^2 = 64+64 [/tex]
[tex] \therefore FG^2 = 128 [/tex]
[tex] \therefore FG =\sqrt {128}[/tex]
[tex] \therefore FG =11.3137085[/tex]
[tex] \therefore FG = 11.31\: cm[/tex]
Perimeter of the figure
= 12 + 16 + 12+4+8+11.31+4
= 67.31 cm