What is the first step in solving the equation 2/3x+1/3x+2=5

Answer:

(6,9)

Step-by-step explanation:

Answer:

no

Step-by-step explanation:

the sum of all 3 angles does not add up to 180 degrees, so no

Answer:

theres no expression..?

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

6

Answer:

Step-by-step explanation:

Not sure what you mean by quotient but 2956?0.03

=98,533.3333333333333333333333

Answer: x=35 and y=72.5

Step-by-step explanation:

Everything os 360, so x is 35 because it los like it has the same measure as the another 35, so if you substract 70 360=290 and 290/4 = 72.5

The negative solution is [tex]-\frac{3}{5}[/tex]

First, add 3 on both sides.

[tex]-2|5x-1|=-8[/tex]

Then, Divide both sides by -2

[tex]|5x-1|=4[/tex]

We know 5x-1 = 4     or 5x-1=-4

[tex]x=1[/tex]             (positive)

[tex]x=-\frac{3}{5}[/tex]          (negative)

The expression sin2x is a trigonometric expression

The equivalent of sin2x is (d) 2sinxcosx

The expression is given as:

sin2x

Rewrite properly as:

sin(2x)

To solve the expression, we make use of the following double angle ratio

sin(2a) = 2sin(a)cos(a)

Substitute x for a in the above equation

sin(2x) = 2sin(x)cos(x)

Rewrite the equation as

sin2x = 2sinxcosx

Hence, the equivalent of sin2x is (d) 2sinxcosx

Read more about trigonometric expressions at:

https://brainly.com/question/8120556

Answer:

D

Step-by-step explanation:

A P E X

Step-by-step explanation:

[tex] \frac{ \tan(x) + \cot(x) }{ \cot(x) } [/tex]

[tex] \frac{ \tan(x) }{ \cot(x) } + 1[/tex]

[tex] \frac{ \frac{ \sin(x) }{ \cos(x) } }{ \frac{ \cos(x) }{ \sin(x) } } + 1[/tex]

[tex]{ \tan {}^{2} (x) } + 1[/tex]

[tex] = \sec {}^{2} (x) [/tex]

Answer:

○ [tex]\displaystyle (2x + 1)(2x - 5) = 0[/tex]

Step-by-step explanation:

Find two quantities that when differed to 8, they also multiply to 20. Those will be 2 and 10. The TINIER quantity gets the plus symbol because the B-value is −8, therefore 10 gets the minus symbol, leaving 2 with the plus symbol. In extension, sinse we have a leading coefficient greater than one, we need to take extra procedures. Here is how it is done:

[tex]\displaystyle y = 4x^2 - 8x - 5 \\ \\ y = [4x^2 - 10x] + [2x - 5] \\ \:\:\:\:\:\:\:\:\:\:\:2x[2x - 5]+ 1[2x - 5] \\ \\ \boxed{[2x - 5][2x + 1] = 0}[/tex]

I am joyous to assist you at any time.

Answer: 4x + 30

Steps: x + (x + 30) + 2x​

Remove the parentheses: x + x + 30 + 2x

Group like terms: x + x + 2x + 30

Add similar elements: 4x + 30

Plz mark brainliest :)

Answer:

Consider the sequence

12,4,14,7,18 ,10,⋯. Calculate the sum of the first 50 y terms of that sequence

Answer:

x=1

Step-by-step explanation:

Solution:

[tex]\rightarrow \frac{4^{-3} \times 3^{4} \times 4^{2} }{3^{5} \times 4^{-2} }[/tex]

[tex]\rightarrow 4^{-3 + 2} \times 3^{4 - 5} \times 4^{2} }[/tex]

[tex]\rightarrow 4^{-1} \times 3^{-1} \times 16}[/tex]

[tex]\rightarrow \frac{1}{4} \times \frac{1}{3} \times 16}[/tex]

[tex]\rightarrow \frac{1}{12} \times 16}[/tex]

[tex]\rightarrow \frac{16}{12}[/tex]

[tex]\rightarrow \boxed{\bold{\frac{4}{3} \tex\text{ (Option B)}}}[/tex]

Answer:

[tex]\dfrac43[/tex]

Step-by-step explanation:

      [tex]\dfrac{4^{-3}\cdot3^4\cdot4^2}{3^5\cdot4^{-2}}[/tex]

Separate like terms:

[tex]\implies \dfrac{4^{-3}\cdot4^2}{4^{-2}}\cdot \dfrac{3^4}{3^5}[/tex]

Use exponent rule [tex]a^b \cdot a^c=a^{(b+c)}[/tex] :

[tex]\implies \dfrac{4^{(-3+2)}}{4^{-2}}\cdot \dfrac{3^4}{3^5}[/tex]

[tex]\implies \dfrac{4^{-1}}{4^{-2}}\cdot \dfrac{3^4}{3^5}[/tex]

Use exponent rule   [tex]\dfrac{a^b}{a^c}=a^{(b-c)}[/tex]

[tex]\implies 4^{(-1--2)}\cdot {3^{(4-5)}[/tex]

[tex]\implies 4^{1}\cdot {3^{-1}[/tex]

Use exponent rule  [tex]a^{-1}=\dfrac{1}{a}[/tex]

[tex]\implies 4\cdot \dfrac13[/tex]

[tex]\implies \dfrac43[/tex]

The answer is -1331 because if you multiply -11x-11x-11 you get -1331.

Answer:

-1331

Step-by-step explanation:

Because i have a calculator

Answer: x=0, 13/2......

Answer:

Vertex A'  (-8,4)

Vertex B'  (-12,12)

Vertex C'  (-4,12)

Step-by-step explanation:

Multiply all the coordinates by 4!

Answer:

[tex]A'(-8,4)\\B'(-12,12)\\C'(-4,12)[/tex]

Step-by-step explanation:

** Scale and/or dilate signal the operation symbol to be multiplication.

Definitions

[tex]A=(-2,1)\\B=(-3,3)\\C=(-1,3)[/tex]

Formulas

[tex]A'=A4\\B'=B4\\C'=C4[/tex]

Solve

[tex]A'=(-2,1)(4)=(-8,4)\\B'=(-3,3)(4)=(-12,12)\\C'=(-1,3)(4)=(-4,12)[/tex]

Answer: x^2 + 4x + 7

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

Last Option

Step-by-step explanation:

For this to be true, everyone who works at school must be getting a wage of 8$ so the hourly range of working students at the school IS 8$

Answer:

Step-by-step explanation:

hello :

Polynomial:2x²+x-210 =0

Equation : x(2x+1)=210

Answer:

D

Step-by-step explanation:

I is true. Limits don't care if the point defined or not. All they care about is if they are approaching a value from both sides, unequivocally.

II is not true. We need more information about the type of function.

III is true. Since the point isn't defined but the limit exist, we have a removable discontinuity

Answer:

True

Step-by-step explanation:

y = -2x + 9 is already in slope-intercept form, so we can leave it be. 8x + 4y = 28, however, is not, so we have to convert it to find the answer.

To do this we have to separate the variable 4y from the rest.

We get 4y = -8x + 28.

But, y must equal zero, so to achieve this, we divide the entire equation by 4.

Then we get y = -2x + 7

Since the slopes are the same (-2x = -2x) the lines are parallel.

Answer:

78.75 ft^2

Step-by-step explanation:

right triangle area

(6 X 20) ÷ 2 = 60 ft^2

left triangle area

do Pythagoras with 6 and 15:

√(15^2 - 6^2) ≈ 13.75

20 - 13.75 = 6.25

(6 X 6.25) ÷ 2 = 18.75 ft^2

total = 60 + 18.75