Since volume grows as a cube of radius, a planet with a 1.5 earth radius would have a volume that is 1.53, or roughly 3.375 times that of the current Earth.
Given that Earth has a density of 5.513 g/cm3, its new density would be around 1.63 g/cm3 if its radius were doubled by 50% but its mass remained constant. Jupiter has a density of 1.326 g/cm3 as a point of comparison. However, it's possible that you're referring to what would happen if both size and mass were scaled appropriately, making this new Earth identical to existing super-earths with 1.5 earth radii. The density would then be around 6-7 g/cm3.
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Read the passage.
At the sound of the gun, the runners' legs began to
cross the starting line in a blur, and their bodies surged
forward as if propelled by unseen engines. The lanes
were runways, and the runners could take flight at any
moment. But they stayed on earth, their feet drumming
the ground in an uneven staccato that reverberated in
the chests of the cheering crowd that choked the fence
along the track.
Which statement best describes the use of diction in
this passage?
O The author uses several words with negative
connotations.
O The author uses a variety of specific and interesting
verbs.
O The author uses a number of words that are
informal.
O The author uses a variety of specific and unusual
adjectives.
The author uses a variety of specific and interesting verbs, 2nd option.
What is a diction?Diction refers to the choice and use of words in speech or writing. It can also refer to the style or manner of speaking or writing, including the level of formality, the choice of vocabulary, and the grammatical structures used. In literature, diction is an important aspect of a writer's style, and can be used to create a certain tone or atmosphere in a text.
Formal diction, slang diction, informal diction, concrete diction, colloquial diction, and abstract diction are all examples of diction. A good diction should have words that are accurate and easy to understand. The writer used interesting verbs like "surged" and "choked' in "choked the fence" etc.
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Answer:
B
Explanation:
The normal force R that a car makes with the ground is 5000N. What is the maximum force of static friction that the car's wheels can experience with the flat concrete road? What is the force of friction that the wheels experience when the car is moving?
The maximum force of static friction that the car's wheels can experience with the flat concrete road is μ×5000 N.
The force of friction that the wheels experience when the car is moving is less than maximum force of static friction.
What is static friction?
The definition of static friction is: The resistance people feel when they attempt to move a stationary object across a surface without actually causing any relative motion between their body and the surface they are moving the object across.
As the normal force = 5000 N.
The maximum force of static friction = μ×5000 N.
The force of friction that the wheels experience when the car is moving is less than maximum force of static friction.
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A typical laboratory diffraction grating has 5500 lines/cm , and these lines are contained in a 4.00 cm width of grating. a.What is the chromatic resolving power of such a grating in the first order? b.Could this grating resolve the lines of the sodium doublet (λ1 = 589.00nm, λ2 = 589.59nm ) in the first order?
c.While doing spectral analysis of a star, you are using this grating in the second order to resolve spectral lines that are very close to the 587.8002-nmspectral line of iron. For wavelengths longer than the iron line, what is the shortest wavelength you could distinguish from the iron line? d.For wavelengths shorter than the iron line, what is the longest wavelength you could distinguish from the iron line? e.What is the range of wavelengths you could not distinguish from the iron line?(Values of λshorter and λlonger you have calculated in two previous parts.)
a. The chromatic resolving power of such a grating in the first order is 1.8 x 10^-6 cm.
b. This grating resolve the lines of the sodium doublet (λ1 = 589.00nm, λ2 = 589.59nm ) in the first order cannot resolve the lines of the sodium doublet in the first order.
c. The shortest wavelength you could distinguish from the iron line is 587.8
d. The longest wavelength you could distinguish from the iron line is 587.8
e. The range of wavelengths you could not distinguish from the iron line?(Values of λshorter and λlonger you have calculated in two previous parts.) is 587.8002 - 587.8)nm to (587.8 - 587.8002)nm.
How do you arrive at the values given above?a. The chromatic resolving power of a diffraction grating is given by the formula: R = mλ/Δλ, where m is the order of diffraction, λ is the wavelength, and Δλ is the minimum separation of two wavelengths that can be resolved. In the first order, m = 1. Therefore, the chromatic resolving power is R = mλ/Δλ = 1 * (1/5500 cm) = 1.8 x 10^-6 cm.
b. To determine if the grating can resolve the lines of the sodium doublet, we need to compare the separation of the doublet lines (589.59nm - 589.00nm = 0.59nm) to the chromatic resolving power of the grating. If the separation is greater than the resolving power, the lines can be resolved. The resolving power is 1.8 x 10^-6 cm, which is equivalent to 1.8 x 10^-9 m. The separation of the doublet lines is 0.59 x 10^-9 m, which is less than the resolving power, so this grating cannot resolve the lines of the sodium doublet in the first order.
c. In the second order, m=2, the shortest wavelength that can be distinguished from the 587.8002 nm line of iron is 587.8002 nm - (1.8 x 10^-6 cm) = 587.8002 nm - (1.8 x 10^-9 m) = 587.8002 nm - 0.00000000018 m = 587.8002 - 0.000000018 m = 587.8.
d. In the second order, m=2, the longest wavelength that can be distinguished from the 587.8002 nm line of iron is 587.8002 nm + (1.8 x 10^-6 cm) = 587.8002 nm + (1.8 x 10^-9 m) = 587.8002 nm + 0.00000000018 m = 587.8002 + 0.000000018 m = 587.8.
e. The range of wavelengths that cannot be distinguished from the iron line of 587.8002 nm is from (587.8002 - 587.8)nm to (587.8 - 587.8002)nm.
Therefore, the correct answers are as given above
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knowing that at the instant shown the velocity of collar a is 900 mm/s to the left determine a.velocity of rod ABD b. velocity of point B
7.1 m/s. allows us to determine the angular velocity of the rod after it has been struck by the bullet. Calculated value: = 29.1 s-1.
The angular velocity (w), a vector quantity in uniform circular motion, is determined by dividing the angular displacement (), also a vector quantity, by the change in time (t).
If the ball is rolling without slipping, the rotational acceleration and the provided acceleration will be perpendicular at point B, and the no slip condition will be satisfied at point O by applying mr=I. nevertheless I=mr 2
α= \sr \sω
Angle acceleration is equal to r.
If a ball rolls without slipping, the acceleration caused by rotation and the supplied acceleration will be perpendicular at point B, making the total acceleration at point A equal to a 2 + (r) 2.
s = \s2 \s \s ω
Point A's velocity is 2
t=2 /2.5*2
= 7.1 m/s.
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A 3.00-kg ball rests in a frictionless groove as shown in the figure
(a) What is the magnitude of the force that the left side of the groove exerts on the ball?
(b) What is the magnitude of the force that the right side of the groove exerts on the ball?
Answer: (a) 26.4 N (b) 21.5 N
(a) Magnitude of the force that the left side of the groove exerts on the ball is 26.4 N. (b) Magnitude of the force that the right side of the groove exerts on the ball is 21.5 N.
(a) Magnitude of the force that the left side of the groove exerts on the ball:
The centripetal force (Fc) required to keep the ball moving in a circle can be calculated using the equation:
Fc = (m × v²) / r
m × g × h = (1/2) × m × v²
v² = (2 × g × h)
v² = 2 × 9.81 × 1.20
v² = 23.55
v = √(23.55)
v = 4.854 m/s
Now, we can find the centripetal force (Fc):
Fc = (3.00 × (4.854)²) / 1.40
Fc = 26.4 N
(b) Magnitude of the force that the right side of the groove exerts on the ball:
Weight of the ball (Fg) = m × g
Fg = 3.00 × 9.81 m/s² = 21.5 N
So, the magnitude of the force that the right side of the groove exerts on the ball (the normal force) is approximately 21.5 N.
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Can nuclei of the same element have different values of Z? Of N? Of A?
Check all that apply.
1 Nuclei of the same element must have the same values of Z, N, and A.
2 Nuclei of the same element can have different values of Z.3
3 Nuclei of the same element can have different values of A.
4 Nuclei of the same element can have different values of N.
Can nuclei of different elements have the same values of Z? Of N? Of A?
Check all that apply.
1 Nuclei of the same element can have the same values of Z.
2 Nuclei of the same element must have different values of Z, N, and A.
3 Nuclei of the same element can have the same values of N.
4 Nuclei of the same element can have the same values of A.
Nuclei of the same element can have different values of A and Nuclei of the same element can have different values of N and Nuclei of the different elements can have the same values of A.
Who is the founded of atomic nucleus ?On the basis of the 1909 Geiger-Marsden gold foil experiment, Ernest Rutherford identified the atomic nucleus in 1911, which is the compact, dense region made up of protons and neutrons at the heart of an atom.
There are 118 species of atoms listed in the periodic table of elements, and each of these can be found (either naturally or artificially) in several iterations with various neutron counts, leading to a total of around 3,000 distinct atomic nuclei.
Both nuclei are held together by the electron, which "orbits" them. We have a molecular ion because the total charge is undoubtedly non-zero. According to Wikipedia, this system is referred to as the dihydrogen cation and goes by the symbol H+2.
the solution is
The proton ratio (Z) for a particular element is fixed. The mass number can vary depending on the number of neutrons (N) in the same element and other elements (A).
Atoms having the same Z and different N (and hence different A) are called isotopes. They are usually forms of the same element.
Sometimes atoms of different element can have the same mass number (A) but different atomic number (Z) and neutron number (N) that makes up the same mass number (A). They are called isobars
Also,atoms of different element can have the same neutron number (N) but different atomic (Z) and mass number (A). they are called isotones
therefore
A) Option 3 and 4
B) Option 3 and 4
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What is the difference between a dynamically hot population and a dynamtically cold popluation in astronomy?
In astronomy, a dynamically hot population refers to a group of stars or other celestial objects that have high velocities and a wide range of orbits.
They are characterized by high kinetic energy and low potential energy, and are typically found in the halo of a galaxy or in the outskirts of galaxy clusters.
On the other hand, a dynamically cold population refers to a group of stars or celestial objects that have low velocities and a narrow range of orbits. They are characterized by low kinetic energy and high potential energy, and are typically found in the disk of a galaxy or in the central regions of galaxy clusters.
In summary, a dynamically hot population is one that is characterized by high velocities, wide range of orbits, high kinetic energy and low potential energy, while a dynamically cold population is one that is characterized by low velocities, narrow range of orbits, low kinetic energy and high potential energy.
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Consider the first-order decomposition of A molecules (red spheres) in three vessels of equal volume.
A) What are the relative rates of decomposition in vessels (1)-(3)?
B) What are the relative half-lives of the reactions in vessels (1)-(3)?
C) How will the rates be affected if the volume of each vessel is decreased by a factor of 2?
D) How will the half-lives be affected if the volume of each vessel is decreased by a factor of 2?
Consider the first-order decomposition of A molecules (red spheres) in three vessels of equal volume - A) 2:4:3 , B) 1:1:1 , C) increase by a factor of 2, D) remain the same.
What is first-order decomposition ?
When the reaction's pace is proportional to the concentration of the reactant, it is referred to as a first-order reaction. On the other hand, as the concentration rises, the reaction rate doubles. One or two reactants are used in the decomposition process, an illustration of a first-order reaction.
What is molecules ?
A molecule is a collection of at least two chemically bound atoms from the same or distinct elements. One molecule of water, for instance, is created when two hydrogen atoms and one oxygen atom combine.
Therefore, the first-order decomposition of A molecules (red spheres) in three vessels of equal volume - A) 2:4:3 , B) 1:1:1 , C) increase by a factor of 2, D) remain the same.
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need help please answear with an easy and simple answer
The acceleration of the car is - 4.0m/s². Hence, option (B) is correct.
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
Initial velocity of the car: u = + 65 m/s.
Final velocity of the car: v = + 45 m/s.
Time interval: t = 5 seconds.
Hence, acceleration of the car = change in velocity/time interval
= (v - u)/t
= ( +45 - 65)/5 m/s²
= - 20/5 m/s²
= - .0m/s².
So, acceleration of the car is - 4.0m/s².
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Consider the circuit shown in (Figure 1). Assume I = 0.86 A. Part A What is the value of resistor R?
According to the question of circuit, the value of resistor R will be 10 Ω.
What is circuit?
Circuit is an electrical network consisting of connected components that allow electrical signals or power to pass through it. The components are usually connected by conductors such as wires, cables, or printed circuit boards. Circuits can be simple and consist of only a few components, or extremely complex containing thousands of components. Circuits can be used to control machines, computers, household appliances, and more. They are used in almost every area of electronics and electrical engineering, from the communication signals in a cellphone to the power distribution in a skyscraper.
R is calculated by Ohm's law, which states that the voltage (V) across a resistor is equal to the current (I) multiplied by the resistance (R). Therefore, R = V/I = 6V/0.86A = 10 Ω.
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iron has a density of 7.86 g/cm3. the volume occupied by 55.85 g of iron is
According to the given statement So, the volume occupied by 55.85 g of iron is 7.12 cm³.
What is Density ?The quantity of matter per unit volume is referred to as dense (volumetric mass density or specific mass). Density is most frequently represented by the lowercase Greek letter rho, but the Latin letter D is also acceptable.
The density of matter varies with temperature and pressure. This variation is typically small for solids and liquids and much larger for gases. Increasing the pressure on an object decreases the volume of the object, thus increasing its density. Increasing the temperature of a substance.
The following formula determines an object's density:
density = mass / volume
Given that the density of iron is 7.86 g/cm³ and the mass of the iron is 55.85 g, we can calculate the volume occupied by the iron as:
volume = mass / density = 55.85 g / 7.86 g/cm³ = 7.12 cm³
So, the volume occupied by 55.85 g of iron is 7.12 cm³.
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what condition is necessary for a sustained flow of electric charge through a conducting medium?
To maintain an electric potential difference and maintain a voltage, a sustained electric current needs a proper pumping mechanism.
There must be some form of pushing force in order to keep an even (or sustained) passage of electric charge across a conductor. The term "emf" for this is electromotive force. Voltage affects current, in other words. Current can be made to flow through a conductor by using a potential difference or voltage. In order for charge to go across a circuit, there needs to be a closed conducting loop and an energy source that can provide an electric potential difference. A supply of freely flowing electric charges (electrons), some sort of push to move the charges across the circuit, and a path to carry the charges are necessary for the production of an electric current.
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A ball is tossed off the edge of a cliff with the same speed but at different angles, as shown. From greatest to least, rank the (a) initial PEs of the balls relative to the ground below. (b) initial $\mathrm{KEs}$ of the balls when tossed. (c) $\mathrm{KEs}$ of the balls when they hit the ground below. (d) times of flight while airborne.
From greatest to least, rank is
a. A=B=C
b. A=B=C
c. A=B=C
d. B, A, C
How do you find initial potential energy?
The formula for potential energy depends on the force acting on the two objects. For the gravitational force, the formula is P.E. = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m / s2 at the surface of the earth) and h is the height in meters.
What is the formula for initial kinetic energy?
Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: K.E. = 1/2 m v2. If the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.
What happens to kinetic energy when you throw a ball?
When a ball is thrown straight up into the air, all its initial kinetic energy is converted into gravitational potential energy when it reaches its maximum height.
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find the length of the arc of the curve from point p to point q. y = 1 2 x2, p −7, 49 2 , q 7, 49 2find the length of the arc of the curve from point p to point q. y = 1 2 x2, p −7, 49 2 , q 7, 49 2
The angle in degrees. It is the middle angle of the arc or the angle that separates the two arc radii. 180 r, where r is the radius and L is the length of an arc.
We may get the length of an arc using the following formula given an angle and a circle's diameter:
ArcLength = (angle / 360) * (2 * pi * radius)
where diameter equals 2 * radius, angle is in degrees, and
pi = 22/7.
The arc length formula for a circle is times the radius of a circle. When r is in radians, the formula for arc length can be written as arc
length = r.
Arc Length
= (/180) r,
where r is the radius and L is the length of an arc.
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A toaster oven is rated at 1900 W for operation at 120 V , 60 Hz .
a)What is the resistance of the oven heater element?
b)What is the peak current through it?
c)What is the peak power dissipated by the oven?
7.58 ohms , 22.39 A and 3800 W are the correct answers .
What is resistance ?
Resistance is measured in ohms and represented by the Greek letter omega (Ω). Ohm is named after German physicist Georg Simon Ohm (1784-1854), who studied the relationship between voltage, current and resistance. He has been credited with formulating Ohm's law.
All substances resist the flow of electricity to some degree. They fall into one of two broad categories:
conductor: A material that offers very little resistance through which electrons can easily move. example:
silver, copper, gold, aluminium.
Insulator:
A substance that has a high resistance and restricts the flow of electrons. example:
Rubber, paper, glass, wood, plastic.
a) R= V^2/P = 120*120/1900 = 7.58 ohms
b) P= IV
I=1900/120 = 15.83A
I peak = sqrt2*15.83= 22.39 A
c) average power= 2*average power = 2*1900= 3800 W
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The surface area of a ball is measured to be A = 85 cm2.
a. Write an equation for the radius of the ball, r, treating it as a sphere, in terms of its surface area. Then calculate the radius.
b.The mass is measured to be M = 160 g. Calculate its density rho in g/cm3.
c. What is the density rhokg/m3 in kg/m3?
a)The radius is 2.6 cm and b) The mass is measured to 4.76 g/cm³ and c)0.00476 kg/m³ is the density kg/m³ in kg/m³.
What is Density ?The quantity of matter per unit volume is referred to as densities (volumetric mass density or specific mass). Density is most frequently represented by the lowercase Greek letter rho, but the Latin letter D is also acceptable. Density is calculated mathematically by dividing mass by volume.
a. The formula: gives the surface area of a spherical.
A = 4 * pi * r²
where A is the surface area, pi is approximately 3.14, and r is the radius of the sphere.
Given the surface area A = 85 cm², we can write the equation for the radius as:
85 = 4 * pi * r²
Solving for r, we get:
r = sqrt(85 / (4 * pi)) = sqrt(85 / 12.56) = sqrt(6.77) = 2.6 cm (approx)
b. The density of an object is given by the formula:
density = mass / volume
The following formula determines a sphere's volume:
V = (4/3) * pi * r³
where V is the volume and r is the radius of the sphere.
Given the mass of the ball M = 160 g, we can calculate the density as:
density = mass / volume = 160 g / [(4/3) * pi * (2.6 cm)^3] = 160 g / (33.51 cm^3) = 4.76 g/cm³
c. To convert the density from g/cm³ to kg/m³, we need to divide the value by 10³.
density = 4.76 g/cm³ / (10³) = 0.00476 kg/m³
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An LC circuit with C = 18 m F undergoes LC oscillations with period 2.4 s. Find the inductance.
Inductance is a measure of a component or circuit's ability to store electrical energy in the form of a magnetic field when an electric current is flowing through it.
What is Inductance?
Inductance is a property of a circuit or electronic component that opposes changes in current, producing a voltage in the circuit proportional to the rate at which the current is changing. This voltage is known as an inductive reactance, and is related to the frequency of the current. Inductance is a fundamental property of materials, and is the basis of many electrical components, including transformers, chokes, and inductors. Inductance is also responsible for the generation of electromagnetic fields, which are used in many applications, such as motors and generators.
The equation for the period of an LC oscillator is:
T = 2π √(L x C)
Thus,
2.4 = 2π √(L x 18 x 10^-3)
L = 6.8 x 10^-3 H = 6.8 mH
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3. A 1.23 kg object slides down a 1.25 m incline of 35º. Use the data table to construct a graph for force due to gravity vs. distance. Trial 1 Trial 2 Trial 3 Averages Distance (m) 1.25 1.32 1.28
4. Based on the graph in #3, calculate the work done by gravity. Assume work is constant for this data.
5. Using the data from #3, construct a free body diagram and calculate work done by gravity. Explain how this value compare to the value determined graphically in #4.
Remember that this object is on an angle. You'll need to multiply the value for work by cos0
Keep in mind that you'll need to use the angle that forms between the force of gravity and distance.
Answer:
Explanation:
To construct a graph of force due to gravity vs. distance, we need to collect data for force due to gravity (Fg) and distance (d) and plot the data points on a graph. From the information given, we have the mass of the object (1.23 kg) and the angle of the incline (35º), but we do not have any data for force due to gravity or distance. Without this data, it is not possible to construct a graph for force due to gravity vs. distance.
Since we don't have the data for force due to gravity or distance, it's not possible to calculate the work done by gravity using the data table.
Without the data for force due to gravity, distance, or time it's not possible to construct a free-body diagram or calculate work done by gravity. Also, we don't have the angle of the incline, so we cannot calculate the work done by gravity by multiplying it by the cosine of the angle.
It's important to note that work done by gravity (W) = force due to gravity (Fg) x distance (d) x cos(theta), where theta is the angle between the force of gravity and the distance.
It's also important to remember that work is a scalar quantity and not a vector, and it's the angle between the force and the displacement that is important to calculate the work done by gravity, not the angle of the incline.
An astronaut on the ISS is doing an experiment with two puffy Cheetos inside a carefully sealed container. A charge of 1.2 E−5 C is place on the first Cheeto. The second one receives a charge of 2.5 E−6 C. The force acting on the first Cheeto is 5.73 E−1 N. What is the distance between the Cheetos if k = 8.99 E9 N*m2/C2?
A. 40 cm
B. 49 cm
C. 60 cm
D. 70 cm
A. 40 cm
We can use Coulomb's law to calculate the distance between the two Cheetos:
F = k * (q1 * q2) / r^2
where F is the force acting on the first Cheeto, q1 and q2 are the charges on each Cheeto, k is the Coulomb constant and r is the distance between the two Cheetos.
Given that the force acting on the first Cheeto is 5.73 E−1 N, the charge on the first Cheeto is 1.2 E−5 C, the charge on the second Cheeto is 2.5 E−6 C and the Coulomb constant is 8.99 E9 N*m2/C2.
We can rearrange the equation to solve for the distance r:
r = (k * q1 * q2 / F)^(1/2)
r = (8.99 E9 N*m2/C2 * 1.2 E−5 C * 2.5 E−6 C / 5.73 E−1 N)^(1/2)
r = 0.04 m
So the distance between the two Cheetos is 40 cm.
If you walk 5 meters north, 2 meters west, 4 meters south, and 7 meters east....what is your displacement?
If you walk 5 meters north, 2 meters west, 4 meters south, and 7 meters east....then the displacement is [tex]\sqrt{26}[/tex].
What is Displacement?A displacement is a vector whose length is the shortest distance from the initial to the final position of a point P undergoing motion.
Solution:
As per the given statement when you walk 5 meters north, 2 meters west, 4 meters south, and 7 meters east... then you will be resulting in forming a right angled triangle from origin to ending point.
That right angled triangle will have
base=5m
perpendicular=1cm
hypotenuse=?
to find hypotenuse we use Pythagoras theorem:
[tex]h^{2}[/tex]=[tex]b^{2}+ p^{2}[/tex]
On putting values we get
[tex]h^{2}[/tex]=[tex]b^{2}+ p^{2}[/tex]
h=[tex]\sqrt{25+1}[/tex]
h=[tex]\sqrt{26}[/tex]
Hence, the displacement is [tex]\sqrt{26}[/tex].
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HELP!!! an 8 kg mass is moving at 9.6 m/s east and it collides inelastically with a 6 kg mass moving 14.8 m/s west. After the collision, what is the velocity of the 8 kg mass? (east is positive and west is negative in terms of direction)
Answer:
After the inelastic collision, the velocity of the 8 kg mass would be the same as the center of mass velocity. Which is the velocity of the combined system of both masses. To find the velocity of the center of mass, we can use the following formula:
vcm = (m1v1 + m2v2) / (m1+m2)
where m1 = 8kg, v1 = 9.6 m/s east, m2 = 6kg, v2 = 14.8 m/s west
vcm = (89.6 + 6(-14.8)) / (8 + 6) = -0.8 m/s (west)
Therefore, after the inelastic collision, the velocity of the 8 kg mass would be -0.8 m/s (west)
Find the magnitude and direction of the resultant of the two concurrent vectors shown below
Given a position vector →v=⟨a,b⟩,the magnitude is found by |v|=√a2+b2.
How do you find the magnitude and direction of the resultant Vectors?The components of a vector, which is symbolized by an arrow, are a magnitude (the size of a measurement) and a direction (the direction the arrow is pointing), for example, 2 meters south. A solitary vector is a vector that exists by itself. A resultant vector is produced by adding two or more single vectors.
A combined force that is smaller than either individual force is created when two forces engage in opposition to one another. Subtract the magnitude of the smaller force from the magnitude of the bigger force to determine the resultant force. The smaller force and the resultant force both have the same direction.
If v=a,b is the position vector, then |v|=a2+b2 will give the magnitude. Depending on the application, the direction is equal to the angle made with the x-axis or the y-axis. The direction of a position vector is determined by the formula tan=(ba)=tan1(ba).What is the Magnitude of a Vector?|A| stands for the magnitude of a vector A, which represents its length. It is the sum of the squares of the vector's component parts' square roots.
A two-dimensional vector's magnitude can be calculated from its coordinates by:
How to Find Magnitude of a Vector?
Step 1 is to list each of its parts.Step 2: Calculate the total of each component's squares.Step 3: Calculate the square root of the resultant total.To know more about How to find the magnitude and direction of the resultant Vectors refer to:
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Daniel scores 68,84,76 and 80 in four test. what mark should he score in the fifth test so that his average mark for the five test would be 78.
(I) what was his median score in the five test
Answer
68+84+76+80+x / 5 =78
x= it is value of his result in 5th test
x=82
Explanation:
Then you put all value from smallest to the biggest
68,76,80,82,84
median = 80
Each contour line as you go inland
represents ground that is at a constant
elevation 5 meters higher than the
previous contour.
a) At what points on the map are there
steep cliffs? Show at least three
places.
b) There are two high areas, label the
How high are they?
Mark a straight-line path to climb
from sea level to the high point B
with the most gentle slope.
d) You are interested in how much work
it takes to lift your body mass from
sea level to the B peak. If you follow
the path you chose in part C will
you minimize the amount of work to
climb to the top, or will it make no
difference?
Each contour line as you go inland represents ground that is at a constant
elevation 5 meters higher than the previous contour are:
a) Steep cliffs can be found at points A, D, and F on the map.
b) High area A is 35 meters above sea level and high area B is 50 meters above sea level.
c) The path from sea level to high point B with the most gentle slope would be to follow the contour lines from sea level upwards in a spiral pattern, starting at point A and ending at point B.
d) Following the path in part C will minimize the amount of work to climb to the top, as it follows the contour lines which represent the most gentle slopes.
What is contour line?
A contour line is a line drawn on a map that connects points of equal elevation, such as the peaks and valleys of a landscape. Contour lines are used to show the shape of the land, which can help map-readers to understand the features of the terrain and the change in elevation of the landscape.
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8
unit 1
Which of the following best describes on ston
protons, neutrons, and elections all in the cont
B. a core of negatively and positely chared parts
Surrounded by nextral particles
c. a core
surrounded
of positive and neatral particles
by negative particles
D. acore of elections and neations surtou
by protons.
Answer: C.
Explanation: The core or Nucleus of an atom contains Protons and Neutrons. A proton has a +1 charge while a Neutron is a Neutral or 0 charge. Electrons orbit the Nucleus and have a -1 charge.
Find the value of xx between 0 and 1.00 mm where the electric potential is zero.Express your answer to three significant figures and include appropriate units.
The electric potential is zero when there is no difference in electric potential energy between two points. Therefore, the value of xx between 0 and 1.00 mm where the electric potential is zero is 0.500 mm.
The electric potential at a given point is the amount of electric potential energy per unit charge at that point in space. This can be found by measuring the electric potential difference between two points, one of which is the point at which we are interested in finding the electric potential. In this case, the electric potential at any point between 0 and 1.00 mm is zero since there is no difference in electric potential energy between the two points. Therefore, the value of xx where the electric potential is zero is 0.500 mm.
The electric potential is zero when there is no difference in electric potential energy between two points. Therefore, the value of xx between 0 and 1.00 mm where the electric potential is zero is 0.500 mm.
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A skier with a mass of 80.7 kg hits a ramp of snow at 16 m/s and becomes airborne. At the highest point of flight, the skier is 3.43 m above the ground. What is the skier’s gravitational potential energy at this point? Round your answer to the nearest ones place.
The gravitational potential energy of the skier is 2,712.65 J.
What is the skier’s gravitational potential energy?The skier’s gravitational potential energy at this point is calculated by applying the following formula.
P.E = mgh
where;
m is the mass of the skierg is acceleration due to gravityh is the height of the skierThe gravitational potential energy of the skier is calculated as follows;
P.E = ( 80.7 kg ) x ( 9.8 m/s² ) x ( 3.43 m )
P.E = 2,712.65 J
Thus, the gravitational potential energy of the skier is a function of the height and mass of the skier.
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Monochromatic 545-nm light is incident on a 15-μm-wide slit. If the diffraction pattern is cast on a screen 510 mm from the slit, what is the linear distance from the center of the pattern to the n = 4 dark fringe?
The linear distance from the center of the pattern to the n = 4 dark fringe is 0.7142m
What are dark fringes?Dark fringes are formed by destructive interference where the waves are out of the phase. Bright fringes are formed by constructive interference where waves are in phase.
d= 1.5 x 10^-6m
D = 510 x 10^-3
n=4
lamda = 545 x 10^-9m
Distance= 4 xD x λ/d
Distance= 4 x545 x 10^-9/1.5 x 10^-6
Distance= 0.7142mm
How do you calculate dark fringe?The distance between 2 adjacent dark or bright color fringes is mainly denoted as “fringe width”, calculated as the formula: “β = λD/d”. If the “resultant amplitude” is zero then the interference is determined as “destructive”.
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Aluminum wire #1 has a length L and diameter d. Aluminum wire #2 has length 3L and diameter 3d. What statement about resistances of these wires is correct? O The resistance of wire #1 is three times the resistance of wire #2 O Resistance of wire #1 is 9 times resistance of wire #2. O The resistance of wire #1 is the same as the resistance of wire #2 O The resistance of wire #1 is 1/9 of the resistance of wire #2 O Resistance of wire #1 is 1/3 of resistance of wire #2.
The resistance of wire one is three times of resistance of wire 2. The correct option is (a).
The resistance of a wire is directly proportional to length (L) and inversely proportional to the cross-sectional area.
For wire 1:
R₁ = k ×L ÷(π × (d÷2)²)
Here,
Diameter (d) and constant (k).
For wire 2:
R₂ = k × 3L ÷ (× ((3d)÷2)²)
R₂ = (1/3) × k ×L ÷(π × (d÷2)²)
R₂ = 1÷ 3R₁
R₁ = 3R₂
Hence, The resistance of wire one is three times of resistance of wire 2. The correct option is (a).
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A student uses a spring loaded launcher to launch a marble horizontally across a table. The mass of the marble is 0.24 kg and the spring constant is 241 N/m. How fast is the marble moving immediately after the spring is released if the spring was compressed 2.4 cm?
Answer:
4.09 m/s
Explanation:
1/2 * k * x^2 = 1/2 * 241 N/m * (0.024 m)^2
= 1.56 Nm
KE = 1/2 * m * v^2
v^2 = 2 * KE/m
v = √(2*1.56 Nm / 0.24 kg)
v = 4.09 m/s