When you see the bright flash of a meteor, what are you actually seeing?.

Answers

Answer 1
a pea-sized particle and the surrounding air as the particle burns up in our atmosphere (In other words, you do not see the particle itself, but only the effects it has on the surrounding air as it burns up.)
Answer 2

The actual things we are seeing if we see the bright flash of a meteor are a pea-sized particle and the surrounding air as the particle burns up in our atmosphere.

What are meteors?

A meteor is a space rock that enters the atmosphere of the earth and produces a streak of light in the sky. Sometimes, people refer to them as shooting stars. When meteoroids enter the earth's atmosphere, they become meteors.

The night sky can be illuminated by meteors, also known as shooting stars, which are bits of space dust and debris that burn up in the Earth's atmosphere.

A pea-sized particle burns up in our atmosphere, and the surrounding air In other words, you do not see the particle itself, but only the effects it has on the surrounding air as it burns up.

Thus, we are seeing burned particles or dust when we see meteors.

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Related Questions

Examples of energy conversion in daily life

Answers

Answer:

Energy conversion, also termed as energy transformation, is the process of changing one form of energy into another. Energy conversion occurs everywhere and every minute of the day. There are numerous forms of energy like thermal energy, electrical energy, nuclear energy, electromagnetic energy, mechanical energy, chemical energy, sound energy, etc. On the other hand, the term Energy Transformation is used when energy changes forms from one form to another. Whether the                                                                    energy is transferred or transformed, the total amount of energy doesn’t change and this is known as the Law of Conservation of Energy.

Explanation:

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What is the kinetic energy of a 2,000-kg boat moving at 5.0 m/s?

Answers

Answer:

25kJ

Explanation:

K = 1/2 mv^2 = 1/2 x 2000kg x (5.0m/s)^2

= 25 x 10^3 J = 25kJ

What happens in a nucleus during beta decay

The numbers of protons increases

The number of neutrons increases

The number of protons decrease

The number of protons plus the number of neutrons decreases

Answers

The number of protons plus the number of neutrons decreases

Beta decay occurs when, in a nucleus with too many protons or too many neutrons, one of the protons or neutrons is transformed into the other. In beta minus decay, a neutron decays into a proton, an electron, and an antineutrino: n Æ p + e - +.

Pliss help...

Di bawah ini manakah yang termasuk organ-organ sistem peredaran darah pada manusia adalah...
a. jantung - ginjal - paru-paru
b. jantung-pembuluh darah - darah
c. jantung - ginjal - hati
d. jantung - paru-paru​

Answers

Answer:

I think it is A

Explanation:

Below, what belongs to the organs of the circulatory system in humans is...

a. heart - kidneys - lungs

b. heart-blood vessels - blood

c. heart - kidney - liver

d. heart - lungs

Di bawah ini manakah yang termasuk organ-organ sistem peredaran darah pada manusia adalah...

a. jantung - ginjal - paru-paru

b. jantung-pembuluh darah - darah

c. jantung - ginjal - hati

d. jantung - paru-paru

=================================

Opsi > A

a. jantung - ginjal - paru-paru

b. jantung-pembuluh darah - darah

c. jantung - ginjal - hati

d. jantung - paru-paru

What happens when you want to move the boat forward? You pull the oars toward yourself.Explain why you do this.

Answers

Answer:

You pull on the oars. By the third law, the oars push back on your hands, but that’s irrelevant to the motion of the boat. The other end of each oar (the blade) pushes against the water. By the third law, the water pushes back on the oars, pushing the boat forward.

Sheeeeeeeeeeeeeeeeeeeeeeeeeeeeesh

3. A mouse crawls 9 meters left in a tube, pauses and then crawls back 5 meters before
stopping. The entire trip took a total of 7 seconds.
a. What is the average speed of the mouse over these 7 seconds?
b. What is the average velocity of the mouse over these 7 seconds?
c. What was the instantaneous velocity of the mouse when it turned around?

Answers

Answer:

A

Explanation:

If it is loooking for a proper question, it wants to know how fast the mouse was going

Answer: The answer for this is A.

Explanation: I know this cause i'm smart and totally didn't copy the other guy just to get points

If you blow up a balloon, tie it off, and release it, it will fall to the ground.
Why does it fall instead of float?
NO LINKS YA FILTHY VERMINS

Answers

Answer:

carbon dioxide (what you are blowing up the balloon with) is a heavy gas. so when you fill the Balloon with it, the balloon will not float. helium is a light gas and floats. gravity takes another. part in this

If you eat cheese are you 1 percent cheese?

Answers

Answer:

No. Exactly what you eat doesn’t make up your internal structure.

:)

Answer:

Explanation:

Light cheeses are less than 20 %, low fat cheeses are 20 to 30%, fat cheeses are 50 to 60%, double-cream cheeses are at least 60% and triple-cream cheeses are at least 75 %.

Analyze the effects on a passenger riding in a car traveling at
50 km/h that collides head-on with a solid object.

Answers

Without:

The passenger will get seriously injuredColliding with the windshield at 50km/hCould result in death

With safety:

The seatbelt holds tge passengers body back so they dont collide with anythingTheir head is cushioned by the airbagThe passenger might get minor injuries but nothing serious will happen

A block of mass m is initially at rest on a rough horizontal surface when a constant force F is exerted on it, as shown. The block accelerates to the right and is moving with speed v once it has moved a distance d. Which of the following equations can be used to solve for the force of friction exerted on the block by the surface?

Answers

The equations that can be used to solve for the force of friction exerted on the block by the surface is F- f = mv² / d

The constant force F is exerted on the block of mass and it accelerates with a speed, v and covering a distance of d in the direction of the force. The force of friction is an opposing force to the applied force.

Therefore,

using Newtons third law

F - f = ma

a = v/t

t = d/v

F - f = m × v / t

F- f = m × [tex]\frac{v}{\frac{d}{v} }[/tex]

F- f = m × v²/d

Therefore,

F- f = mv² / d

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A 0.04 kg honeybee circles a field looking for a flower upon which to land. The radius of the circle she travels is 2.5 m and it takes her 1.57 s to complete the circle.

Find the following:
a) Tangential Velocity
b) Centripetal Acceleration
c) Centripetal Force.​

Answers

For the honeybee that circles a field looking for a flower upon which to land, we have:

a) The tangential velocity is 10.01 m/s.

b) The centripetal acceleration is 40.1 m/s².

c) The centripetal force is 1.60 N.

a) The tangential velocity can be calculated as follows:

[tex] v = \omega r = \frac{2\pi r}{T} [/tex]  (1)

Where:

r: is the radius of the circle = 2.5 m

ω: is the angular velocity = 2π/T

T: is the period = 1.57 s

By entering the above values into equation (1), we have:

[tex] v = \frac{2\pi r}{T} = \frac{2\pi 2.5 m}{1.57 s} = 10.01 m/s [/tex]  

Hence, the tangential velocity is 10.01 m/s.

b) The centripetal acceleration is related to the tangential velocity as follows:

[tex] a_{c} = \frac{v^{2}}{r} = \frac{(10.01 m/s)^{2}}{2.5 m} = 40.1 m/s^{2} [/tex]

Therefore, the centripetal acceleration is 40.1 m/s².

c) The centripetal force is given by:

[tex] F = ma_{c} [/tex]

Where:

m: is the honeybee's mass = 0.04 kg

[tex] F = ma_{c} = 0.04 kg*40.1 m/s^{2} = 1.60 N [/tex]

Hence, the centripetal force is 1.60 N.

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I hope it helps you!

If a net force of 24 Newtons is applied on an object of mass 6
kilograms, what will be the acceleration of the object?
a 2 m/s2
b. 6 m/s2
C 10 m/s2
d 4 m/s2

Answers

Answer:

4 m/s²

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

f is the force

m is the mass

From the question

f = 24 N

m = 6 kg

We have

[tex]a = \frac{24}{6} = 4 \\ [/tex]

We have the final answer as

4 m/s²

Hope this helps you

how is pure salt obtained from the sea water ?describe in brief ​

Answers

Answer:

Evaporation

Explanation:

Evaporation

Answer:

Salt from sea water is obtained by the process of evaporation. ... The sea water evaporates due to the sun's heat and solid salt is left behind. The left salt is collected and refined to get purified salt. Hence, salt is obtained from sea water by evaporation.

Which state of matter has molecules that move the most?

liquid

solid

gas

They are all the same.

Answers

Answer:

gas

Explanation:

in gaseous state molecules move the most because force of attraction between atoms are least in gaseous state

What is one effect of the uneven heating of Earth caused by the Sun?

options:

Rotation of Earth


Generation of wind


Oceans losing salt


Plants failing to grow

Answers

Answer:

The uneven heating results in some of the atmosphere to be warmer than other parts and changes in volume and pressure which result in updrafts and can cause thunderstorms and other violent weather.

Explanation:

Generation of wind

which statement about moist air moving over a mountain is correct?

Answers

Answer:

Explanation:

The orographic effect occurs when air masses are forced to flow over high topography. As air rises over mountains, it cools and water vapor condenses. As a result, it is common for rain to be concentrated on the windward side of mountains, and for rainfall to increase with elevation in the direction of storm tracks.

Select the correct answer.
What represents the value of the second-best alternative that a person gives up when making a choice?
OA. marginal spending
ОВ.
marginal benefit
OC. opportunity cost
OD. marginal cost

Answers

The answer should be opportunity cost

A 46.5-kg ball has a momentum of 57.2 kg m/s. What is the ball's speed?

Answers

Answer:

1.23 m/s

Explanation:

p=mv

57.2 = 46.5v

v= 57.2/46.5

v= 1.23

If you want to verify your answer, just insert the value of v in the equation.

Best definition of an electromagnetic wave?

A) an electromagnetic wave is a longitudinal wave with electricity

B) an electromagnetic wave is a mechanical wave

C) an electromagnetic wave is a transversal wave that has electrical and magnetic properties

Answers

Answer:

Longitudinal and mechanical waves require a medium to support their transmission:

C) is the correct answer

A feather drops in a vacuum. What is the feather's final velocity if it falls for 3.48s?

A. -34.1 m/s
B. 59.3 m/s
C. -59.3 m/s
D. 34.1 m/s

Answers

Answer:

34.104

Explanation:

the time * acceleration = final velocity.

so 3.48s * 9.8m/s (gravity) = 34.1 m/s

The Kentucky Derby is one of the most exciting horse races run every year. In 1973, the horse Secretariat set a record that still stands. This 500-kg horse ran the 2000-m track in 120 s. What was Secretariat’s average kinetic energy? (1 kJ = 1000 J)

Need answers with explanaitions please

A. 4.2 kJ
B. 8.3 kJ
C. 69.0 kJ
D. 139.0 kJ

Answers

Answer:

C.69 kJ

Explanation:

kinetic energy

[tex] = 1 \div 2mv {}^{2} [/tex]

C 69.0 kj is correct

I rode my bicycle to grandmother's house at 6 km/h in a flat road for 5 min before reach a hill. I went at 2 km/h up the hill for 3minutes. I met a friend and stopped to talk for 5 minutes. I went on at 2 km/h to my grandmother's house. Draw (plot) the v against t graph for this motion.​

Answers

The graph can be plotted based on the given information which are given

in pairs (velocity and time), and which the coordinate pairs are formed.

Please find attached the required v against t graph created with MS Excel

Reasons:

The given data are presented in a tabular form as follows;

[tex]\begin{tabular}{|c|c|c}\underline{Duration (Minutes)} & \underline{Speed (km/h)}\\0 - 5 &6 \\5 - 8&2\\8 -13&0&\\13- &2&\end{array}[/tex]

The velocity time graph can be plotted using the above table values on

MS Excel using the above table elaborated as follows;

[tex]\begin{tabular}{|c|c|c}\underline{Duration (Minutes)} & \underline{Speed (km/h)}\\0 &6 \\5&6\\5 &2\\8&2\\8&0\\13&0&\\13 &2&\end{array}[/tex]

The attached graph can then be created using the Insert Chart menu

after selecting the data above inputted in the spreadsheet button on MS

Excel.

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a race car traveling at 44m/s slows at a constant rate to a velocity of 22m/s over 11 seconds , how far does it move during this time

find distance and acceleration
FAST PLEASE !!

Answers

Answer:

-1.2×10^2 m

I hope this helps you

If larger-diameter tires are mounted on the car instead, how will that affect the speedometer reading? The speedometer

Answers

Answer:

A speedometer is related to the number of complete revolutions.

A larger diameter tire will travel farther in one revolution.

N D = S    where N is the number of revolutions and S the distance traveled

N = S / D     so the speedometer will record less revolutions and less distance traveled if the diameter is increased and the distance traveled will be too small as compared to the actual distance traveled.

Acceration is a change in motion over time:
True False

Answers

The answers is definitely true for a fact

What force causes an automobile to move.

Answers

Answer:

Thrust

Explanation:

Thrust is the force that causes a car to move in the direction that it wants to.

What decides free energy.

Answers

Answer: when free energy is extensive property that means its magnitude depends on the amount  of a substance.

Explanation:

srry if im wrong :( .

Answer:

state of the system

Explanation:

Without friction, what is the mass of an ball accelerating at 1.8 m/sec2 to which an
an unbalanced force of 42 Newtons has been applied?
A 75.60 kg
B 00.04 kg
C 23.33 kg
D 43.80 kg

Answers

Answer:

23.33 kg

Explanation:

The mass of the object can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question we have

[tex]m = \frac{42}{1.8} = 23.3333... \\ [/tex]

We have the final answer as

23.33 kg

Hope this helps you

Answer:

[tex]\boxed {\boxed {\sf C. \ 23.33 \ kg}}[/tex]

Explanation:

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

[tex]F=ma[/tex]

The mass of the ball is unknown. The ball is accelerating at 1.8 meters per second squared. An unbalanced force of 42 Newtons is applied to the ball.

Convert the units of force. 1 Newton is equal to 1 kilogram meter per second squared, so our answer of 42 Newtons is equal to 42 kg*m/s².

F= 42 kg*m/s² a= 1.8 m/s²

Substitute the values into the formula.

[tex]42 \ kg*m/s^1 = m * 1.8 \ m/s^2[/tex]

We are solving for the mass, so we must isolate the variable m. It is being multiplied by 1.8 meters per second squared. The inverse operation of multiplication is division. Divide both sides by 1.8 m/s².

[tex]\frac {42 \ kg*m/s^2}{1.8 \ m/s^2} = \frac{a*1.8 \ m/s^2}{1.8 \ m/s^2}[/tex]

[tex]\frac {42 \ kg*m/s^2}{1.8 \ m/s^2} =m[/tex]

The units of meters per second squared cancel.

[tex]\frac {42 \ kg}{1.8 } =m[/tex]

[tex]23.3333333 \ kg=m[/tex]

Round to the hundredth place. The 3 in the thousandth place tells us to leave the 3 in the hundredth place.

[tex]23.33 \ kg \approx m[/tex]

The mass of the ball is approximately 23.33 kilograms.

The strength of the electric field 0. 5 m from a 6 µC charge is _______ N/C. (Use k = 8. 99 × 109 N•meters squared per Coulomb squared and round answer to the nearest whole number. ) 215760 539400 697976 512356.

Answers

The strength of the electric field at a distance of 0.5 m from a 6 μC punctual charge is 143,840 N/C.

We want to calculate the strength of the electric field 0.5 m (r) from a 6 μC charge (Q).

What is the electric field?

The electric field (E) is a region around a charged particle or object within which a force would be exerted on other charged particles or objects.

We can calculate the electric field at some distance from a punctual charge using the following formula.

E = (k × Q) / r²

E = [(8.99 × 10⁹ N.m².C²) × (4 ×  10⁻⁶ C)] / (0.5 m)² ≈ 143,840 N/C

where,

k is the Coulomb's law constant.

The strength of the electric field at a distance of 0.5 m from a 6 μC punctual charge is 143,840 N/C.

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The mercury in a barometer of a cross-sectional area 1 cm² stands at 75 cm, and the space above it is 9 cm in length. What
volume of air, measured at 3. The mercury in a barometer of a cross-sectional area 1 cm² stands at 75 cm, and the space above it is 9 cm in length. What
volume of air, measured at atmospheric pressure, would have to be admitted into the space to cause the column of the mercury
to drop to 59 cm?

Answers

The ideal gas equation and the pressure in barometer allows us to find the amount of air that we must introduce into the barometer for the change in height of the mercury column is:

The  variation  of the volume is: ΔV = 7.67 cm³

Pressure is defined by the relationship between force and area.

       P = F / A

The ideal gas equation establishes a relationship between pressure, volume, and temperature of an ideal gas.

          PV = nR T

Where P is pressure, V is volume, and T is temperature.

Let's write this equation for two points assuming that the temperature has not changed.

          P₀ V₀ = P₁ V₁

          V₁ = [tex]\frac{P_o}{P_1} \ V_o[/tex]                 (1)

The subscript "o" is used for the start point and the subscript "1" for the end point.

The pressure in a barometer is:

         P = ρ g y

They indicate the initial height of the barometer y₀=75 cm, the distance from empty space y'₀ = 9 cm and the final height of the barometer y₁ = 59 cm.

 

The volume of the cylinder is

         V = π r² y

Let's calculate the initial volume.

         V₀ = π 1 9

         V₀ = 28.27 cm³

We substitute in equation 1.

         V₁ = [tex]\frac{\rho \ g \ y_o}{\rho \ g \ y_1} \ V_o[/tex]  

         V₁ = [tex]\frac{y_o}{y_1} \ V_o[/tex]  

Let's calculate.

        V₁ = [tex]\frac{75}{59} \ 27.27[/tex]  

        V₁ = 35.94 cm³

The volume to be incremented is

         ΔV = V₁ - V₀

         ΔV = 35.94 - 28.27

         ΔV = 7.67 cm³

Using the ideal gas equation and the pressure in barometer we can find the amount of air that we must introduce into the barometer for the change in height of the mercury column is:

The change of the volume is: ΔV = 7.67 cm³

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