Which hyperbola has one focus point in common with the hyperbola (y+11)^2/(15^2)-(x-7)^2/(8^2)=1
Answers
Answer:
3 &4
Step-by-step explanation:
The hyperbola with one focus point in common with the given hyperbola is:
[(y + 11)² / 10²] - [(x - 7)² / 15²] = 1
Which hyperbola has one focus point in common with the given hyperbola?To find a hyperbola that shares one focus point with the given hyperbola, we need to find another hyperbola with the same focus point but different characteristics (e.g., eccentricity or axis length).
The equation of the given hyperbola is:
[(y + 11)² / 15²] - [(x - 7)² / 8²] = 1
The general equation of a hyperbola with its center at (h, k) is:
[(y - k)² / a²] - [(x - h)² / b²] = 1
The center (h, k) of the given hyperbola is (7, -11).
To share one focus point, we need to keep the center at (7, -11) but change the values of a and b. The eccentricity of a hyperbola is defined as e = c / a, where c is the distance from the center to the focus.
Let's assume the new hyperbola has an eccentricity different from the given hyperbola. We'll keep the same value of c and change the value of a to get a different eccentricity.
Let's say the new hyperbola has a value of a' = 10. Since the eccentricity is different, the value of b' will change accordingly. Let's calculate b' using the eccentricity formula:
e = c / a'
15 / 10 = 1.5
Now, we can find b' using the eccentricity:
e = c / a' = c / 10
c = e * a' = 1.5 * 10 = 15
Now, we have the center (7, -11), the value of a' = 10, and the value of c = 15. The equation of the new hyperbola with one focus point in common is:
[(y + 11)² / 10²] - [(x - 7)² / 15²] = 1
Learn more on hyperbola here;
https://brainly.com/question/15935373
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There are 300 kids who go to school 5/8 are intermediate 1/3 are junior the rest are primary
(from my call to teach grade 7 math fractions,decimals,percentages
Answers
Answer:
188 kids in intermediate, 100 juniors, and 13 children that attend primary school.
Step-by-step explanation:
K there are 300 kids.
5/8 are intermediate, so 5/8 * 300 = 187.5, you can't have half a kid, so we can round to 188 kids are intermediates.
1/3 are juniors, so 1/3 * 300 = 100 are juniors.
The rest are primary:
(1)-(5/8 + 1/3)= 1/24
Thus, 1/24 are primary students, so 1/24 * 300 = 12.5 and again we will round up to 13 children in primary classes.
I am not sure if this is answering your question since you don't specifically have one listed.
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f(x) = (3/16)(x+4)(x-4)(x-2)
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Answer:
Step-by-step explanation:
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Step-by-step explanation:
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Step-by-step explanation:
I hope this helps you on your question
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Answers
Answer:
She picked up her camera at -25ft
Step-by-step explanation:
Given
[tex]Initial\ Position = -30ft[/tex]
Required
Determine the position she retrieved her camera
The position where she dropped her camera is given as:
[tex]Position = -10ft[/tex]
She swim down 15ft;
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[tex]New\ Position = -10ft - 15ft[/tex]
[tex]New\ Position = -25ft[/tex]
Hence; She picked up her camera at -25ft
Note that: Negative signs represent that she is below the sea level
Answer:
C
Step-by-step explanation:
Hilary was scuba diving. She was 30 feet below the surface when she swam toward the dive platform. She dropped her camera when she was 10 feet from the surface and had to swim down 15 feet to get it. At what elevation did Hilary retrieve her camera?
-25feet
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Answer:
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Step-by-step explanation:
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Step-by-step explanation:
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Answer
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
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Answers
Answer:
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Step-by-step explanation:
Solution,
or , N/28 = 4/7
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Answers
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Answers
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Answers
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[tex]{\boxed{\bf{a_{n}=a+(n-1)d}}}[/tex]
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[tex]{:\implies \quad \sf a_{n}=6+(n-1)6}[/tex]
[tex]{:\implies \quad \sf a_{n}=6+6n-6}[/tex]
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[tex]{:\implies \quad \bf \therefore \quad \underline{\underline{a_{n}=6n}}}[/tex]
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Answers
Answer:
D
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
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Step-by-step explanation:
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Answers
Answer:
10-5+3=8
Step-by-step explanation:
6-4+10=12
Answer:
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Answers
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Step-by-step explanation:
trust me bro
Answer:
m=7
Step-by-step explanation:
[tex]\frac{m}{10}-\frac{1}{2}=\frac{1}{5}[/tex]
[tex]\mathrm{Add\:}\frac{1}{2}\mathrm{\:to\:both\:sides}[/tex]
[tex]\frac{m}{10}-\frac{1}{2}+\frac{1}{2}=\frac{1}{5}+\frac{1}{2}[/tex]
[tex]\mathrm{Simplify}[/tex]
[tex]\frac{m}{10}=\frac{7}{10}[/tex]
[tex]\mathrm{Multiply\:both\:sides\:by\:}10[/tex]
[tex]\frac{10m}{10}=\frac{7\cdot \:10}{10}[/tex]
[tex]\mathrm{Simplify}[/tex]
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~Learn with Lenvy~
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Answers
Answer:
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Step-by-step explanation:
Answer:
D
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Answers
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How to find the area of the image?The area will be the area of the rectangle plus the area of the semicircle.
We can see that the width of the rectangle is equal to the diameter of the semicircle, and the radius of the semicircle is 5 units, so its diameter is:
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Adding these two we get:
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If you want to learn more about areas, you can read:
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Step-by-step explanation:
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Step-by-step explanation:
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Step-by-step explanation:
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Answers
Answer:
x = 5
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You could also use a replacement set.
▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬
Replacement Set↓ What x can be[tex]\left[\begin{array}{ccc}5&6&7\\8&9&10\\11&12&13\end{array}\right][/tex]
And so on.
Please click the thanks button.
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