Which linear inequality is represented by the graph? y > 2x 3 y < 2x 3 y > −2x 3 y < −2x 3

Responda:

181 pessoas / km²

Explicação passo a passo:

Dado que:

Densidade populacional = razão entre o número de habitantes e a área

Número de habitantes em São Paulo = 45 milhões

Área do estado de São Paulo = 248210 km²

Portanto, a densidade populacional de São Paulo:

Número de habitantes / área

45.000.000 pessoas / 2.48210 km²

181,29809 pessoas / km²

= 181 pessoas / km² (aproximadamente

Answer:

y = 1300 - 100x

Step-by-step explanation:

Zachary purchased a computer for $1300

The first step is to calculate the purchase he paid after 2 months

= 1,300-1,100

= $200

Then the purchase after 1 month is

= $200/2

= $100 per month

The purchase made after 4 months is

= 1,100-900

= $200

The purchase after a month is

= $200/2

= $100 per month

Therefore the equation that models the balance y after x months is

= initial amount of payment plan - amount per month

y= 1,300 - 100x

Hope this helps~! Brainliest is 'preciated if it does!

The transformation of the expression [tex]x^{2} -2x-2[/tex] is [tex](x-1)^2 -3[/tex].

Given equation is: [tex]x^{2} -2x-2[/tex]

The expansion of (a+b)² is a²+b²+2ab.

We can rewrite the given expression as:

[tex]x^{2} -2x+1 -3[/tex]..........(1)

We know that [tex]x^{2} -2x+1[/tex] is the expansion of [tex](x-1)^2[/tex].

So, (1) can be written as:

[tex]x^{2} -2x+1 -3[/tex]

[tex](x-1)^2 -3[/tex]

So, [tex]x^{2} -2x-2 = (x-1)^2-3[/tex]

Therefore, the transformation of the expression [tex]x^{2} -2x-2[/tex] is [tex](x-1)^2 -3[/tex].

To get more about polynomials visit:

https://brainly.com/question/2833285

Answer:

The answer is B. (x-1)^2 - 3

Step-by-step explanation:

HOPE THIS HELPS! JUST HELPING PEOPLE IN NEED!

Answer:

The slope is 0 or there is no slope.

Step-by-step explanation:

Only a y-intercept of -4.

Answer:

0

Step-by-step explanation:

The slope is defined as rise/run. Since y does not increase at all as x increases, the slope is 0.

Answer:

I don't really know what you mean so I would say to just look on the tag but if you gave more info then I could help you out

Answer:

[tex]m=\frac{17}{37}[/tex]

Step-by-step explanation:

When given two coordinates, you must use this formula to find the slope of a line:

[tex]m= \frac{y_{2} - y_{1}}{x_{2}-x{1}}[/tex]

where m is your slope.

So, plug in your coordinates. Remember, a coordinate is denoted by (x,y). So, for example, your [tex]x_{1}[/tex] would be -18 and your [tex]x_{2}[/tex] would be 19.

[tex]m =\frac{4--13}{19--18}[/tex]

[tex]m =\frac{17}{37}[/tex]

And that would be your slope. (Answer choice D.)

Answer:

Rational

Step-by-step explanation:

An irrational number is any number that cannot be turned into a fraction. 7 can be turned into a fraction.

Answer:

y=3/4 x- 1/2

Step-by-step explanation:

Answer:

100 red balls and 20 blue balls.

Step-by-step explanation:

So to find out what you need to multiply the ratio by to get the answer, you add 10 and 2. That's 12. 120/12 is 10. 10:2 times 10 = 100: 20, so there are 100 red balls and 20 blue balls.

Answer:

f=88

g=60

h=32

x=17

Step-by-step explanation:

Answer: The answer is C. Yes, because it passes the vertical line test.

Hope this helps.

Answer:

C. Yes, becuase it passes the vertical line test.

Step-by-step explanation:

Using the vertical line test, you can clearly see the function has one input for exactly each output.

Answer:

B. -3

Step-by-step explanation:

From (-1,4) it goes down 3 (rise) units then 1 unit (run) to the right. Simply, its sloping to the left, so negative.

Solving using slope formula:

y2-y1/x2-x1

4--2/ -1-1

6/-2

3/-1

-3

Answer:  B

Step-by-step explanation:

y2-y1/x2-x1

-2-4/1-(-1)

-6/1+1

-6/2

-3

Answer:

x = 3 +√43, x = 3 - √43

Step-by-step explanation:

x^2 - 6x - 34 = 0

move the 34 across

x^2 - 6x = 34

take -6 and divide by two, then square it

(-6/2)^2 = 9

add the product to your equation

x^2 - 6 + 9 = 34 + 9

solve

(x - 3)^2 = 43

x - 3 = ± √43

x = 3 ± √43

[tex] {n}^{2} - n - 56 = [/tex]

[tex](n - 8)(n + 7)[/tex]

_____________________________________________

[tex]a {x}^{2} + bx + c = 0[/tex]

[tex]delta = {b}^{2} - 4ac[/tex]

[tex]x(1) = \frac{ - b + \sqrt{delta} }{2a} \\ [/tex]

[tex]x(2) = \frac{ - b - \sqrt{delta} }{2a} \\ [/tex]

_____________________________________________

[tex] {n}^{2} - n - 56 = 0[/tex]

[tex]delta = ({ - 1})^{2} - 4(1)( - 56)[/tex]

[tex]delta = 1 + 224[/tex]

[tex]delta = 225[/tex]

Thus ;

[tex]n(1) = \frac{ - ( -1) + \sqrt{225} }{2 \times 1} \\ [/tex]

[tex]n(1) = \frac{1 + 15}{2} \\ [/tex]

[tex]n(1) = \frac{16}{2} \\ [/tex]

[tex]n(1) = 8[/tex]

[tex]n(2) = \frac{ - ( - 1) - \sqrt{225} }{2 \times 1} \\ [/tex]

[tex]n(2) = \frac{ 1 - 15}{2} \\ [/tex]

[tex]n(2) = - \frac{14}{2} \\ [/tex]

[tex]n(2) = - 7[/tex]

[tex]n(1) = 8[/tex]

[tex]n(1) - 8 = 0 \: \: \: (\alpha )[/tex]

[tex]n(2) = - 7[/tex]

[tex]n(2) + 7 = 0 \: \: \: \: \: ( \beta )[/tex]

_____________________________________________

[tex] \alpha \times \beta = [/tex]

[tex](n - 8)(n + 7)[/tex]

Answer:

  244 sq. ft.

Step-by-step explanation:

The net for a triangular prism consists of a central rectangle and two triangles. The length of the central rectangle is equal to the perimeter of the triangular faces.

__

The area of the central rectangle of the net is ...

  A = LW = (12 +7 +10 ft)(6 ft) = 174 ft²

The two triangles are right triangles, so the area of each is half the product of the leg lengths.

  A = 1/2(bh) = 1/2(10 ft)(7 ft) = 35 ft²

Then the sum of the rectangle and two triangles is ...

  surface area = 174 ft² +2 × 35 ft² = 244 ft²

Answer:

About $75.08

Step-by-step explanation:

79.66-[{(79.66/100)x12}-{(79.66/100)x6.25}]

79.66-[{0.7966x12}-{(79.66/100)x6.25}]

79.66-[{0.7966x12}-{0.7966x6.25}]

79.66-[9.5592-{0.7966x6.25}]

79.66-[9.5592-4.97875]

79.66-4.58045

75.07955

75.08

Answer:(that was a joke)

1.) acute

2.) right

3.) obtuse

4.) acute

5.) obtuse

6.) right

Step-by-step explanation:

if hes doing advanced stuff like isosceles equilateral and that then im sorry for the answer.

Answer:

Step-by-step explanation:

You need to construct the ellipse then you would be able to find the standard form

Answer:

= 1= RHS

Step-by-step explanation:

shee i got u bud ok LHS-

(1+cot^2A)(1+cosA)(1-cosA)

=Cosec^2A(1-cos^2A)

=1/sin^2A×(sin^2A)

= 1= RHS

Answer:

1st is correct

Step-by-step explanation:

Like charges repel each other.

HOPE THIS HELP YOU ,FOR ANY QUESTION PLEASE ASK ME

Answer:

r=2

Step-by-step explanation:

r + 8 r + 11 = 29

( 1 + 8 ) r + 11 = 29 9 r + 11 = 29

Now we can isolate and solve for r while always keeping the equation balanced: First, subtract 11 from each side of the equation:

9 r + 11 − 11 = 29 − 11

9 r + 0 = 18

9 r = 18

Now we can divide each side of the equation by 9 to get

r : 9 over 9 = 18 under 9

1 r = 2

r = 2

Answer: r = 2

Steps:  

r + 8r + 11 = 29

9r + 11 = 29

9r + 11 - 11 = 29 - 11

9r = 18

r = 2

plz mark brainliest

Answer:

No, it is not correct. You should divide by 21 and 3.

Step-by-step explanation:

3x=21

x=7

Q 1)

3(x + 5) = 36

3x + 15 = 36

3x = 36 - 15

3x = 21

x = 21/3

x = 7

Verification:

3(x + 5) = 36

3(7 + 5) = 36

3(12) = 36

36 = 36

Hence proved that x = 7

PLEASE CHECK THE ATTACHED FILE

We are given that ;

[tex]{\quad \longrightarrow \displaystyle \sf \lim_{x\to 0}\bigg\{1+\dfrac{p(x)}{x^2}\bigg\}=2}[/tex]

Where p(x) is a polynomial of degree 4 , it will help us later, but let's do some manipulations first ;

Can be further written as ;

[tex]{:\implies \quad \displaystyle \sf 1+\lim_{x\to 0}\bigg\{\dfrac{p(x)}{x^2}\bigg\}=2}[/tex]

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 0}\bigg\{\dfrac{p(x)}{x^2}\bigg\}=1}[/tex]

So, here p(x) is polynomial of degree 4, so it will be a biquadratic polynomial, so we will write p(x) in the form of general biquadratic polynomial, so p(x) = ax⁴ + bx³ + cx² + dx + e

Now, first find p(x)/x² ;

[tex]{:\implies \quad \sf \dfrac{p(x)}{x^2}=\dfrac{ax^{4}+bx^{3}+cx^{2}+dx+e}{x^2}}[/tex]

[tex]{:\implies \quad \sf \dfrac{p(x)}{x^2}=ax^{2}+bx+c+\dfrac{d}{x}+\dfrac{e}{x^2}}[/tex]

So now, as [tex]{\bf{x\to 0}}[/tex] , for any values of a, b, c, d and e, the RHS will approach ∞ iff d ≠ e ≠ 0, as the denominator of d and e will be approaching 0 and so the whole limit will be ∞ , but we want the limit to be approaching 1, so when if d = e = 0, the denominator of d and e will be approaching 0 (not absolutely 0), and if d = e = 0, we will have the limit be approaching ax²+ bx + c for x approaching 0 being the limit 1 , and for any values of a, b and c . So now we have ;

[tex]{:\implies \quad \displaystyle \bf \lim_{x\to 0}\dfrac{p(x)}{x^{2}}=\begin{cases}\bf \infty \:, iff\: d\neq e\neq 0 \\ \\ \bf 1\:, iff\: d=e=0\end{cases}}[/tex]

So, now we had to consider the second case, for which the limit is approaching 1, for d = e = 0, so the limand here will just be ax² + bx + c

Now, we so have ;

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 0}ax^{2}+bx+c=1}[/tex]

Putting the limit we will have ;

[tex]{:\implies \quad \sf c=1}[/tex]

So, now as p(x) have extremum at 1 and 2, so p'(x) = 0, for x = 1, 2 , so now finding p'(x)

[tex]{:\implies \quad \sf p(x)=ax^{4}+bx^{3}+x^{2}\quad \qquad \{\because c=1\: and\: d=e=0\}}[/tex]

So, differentiating both sides wr.t.x ;

[tex]{:\implies \quad \sf p^{\prime}(x)=4ax^{3}+3bx^{2}+2x}[/tex]

Now, p'(1) and p'(2) must be 0

[tex]{:\implies \quad \sf p^{\prime}(1)=4a+3b+2=0}[/tex]

[tex]{:\implies \quad \sf p^{\prime}(2)=32a+12b+4=0}[/tex]

So, now we have ;

[tex]{\quad \longrightarrow \displaystyle \begin{cases}\bf 4a+3b=-2 \\ \\ \bf 32a+12b=-4\end{cases}}[/tex]

On multiplying first equation by 8 on both sides we can thus obtain ;

[tex]{\quad \longrightarrow \displaystyle \begin{cases}\bf 32a+24b=-16 \\ \\ \bf 32a+12b=-4\end{cases}}[/tex]

On solving both the equations we will be having ;

[tex]{\quad \longrightarrow \displaystyle \begin{cases}\bf a=\dfrac{1}{4} \\ \\ \bf b=-1\end{cases}}[/tex]

So , now as d = e = 0, c = 1, a = (1/4), b = -1, so putting all the values in p(x) we can obtain p(x) as ;

[tex]{:\implies \quad \sf p(x)=\dfrac{1}{4}(x)^{4}-(x)^{3}+x^{2}}[/tex]

Now, at x = 2 ;

[tex]{:\implies \quad \sf p(2)=\dfrac{1}{4}(2)^{4}-(2)^{3}+2^{2}}[/tex]

[tex]{:\implies \quad \sf p(2)=4-8+4=8-8}[/tex]

[tex]{:\implies \quad \bf \therefore \quad \underline{\underline{p(2)=0}}}[/tex]

This is the required answer

Answer:

A

Step-by-step explanation: You have two variables, the time and the number of cartons. If time wasn't a variable here, the number of cartons would remain static. You need time, otherwise there would be no change. Now that you know there are two variables, the last two choices must not be correct. Between A and B, the difference is that A says every dip is a purchase and B says every horizontal line is a purchase. Obviously, a horizontal line doesn't mean a purchase; it means the time gone WITHOUT  a purchase. This leaves you with A.