The compounds that follow will show a noticeable peak at (M-127) are CH3CH2CH2I
What is meant by compounds?A compound in chemistry is a material that is created when two or more separate chemical elements are mixed in a specific order. The interaction of the elements creates chemical connections that are challenging to break. Shared or exchanged electrons between atoms cause the formation of these bonds. (KOM-pownd) A substance in science that is created through the chemical joining of two or more distinct elements Table salt (NaCl), which is derived from the elements sodium and chloride, and water (H2O), which is created from the elements hydrogen and oxygen, are two examples of compounds.A compound is a material that is created when two or more components are bonded chemically.To learn more about compounds, refer to:
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Analyze the following reaction and the given scenarios to discuss the relationship between volume and reaction rate. Determine which reaction will happen at a faster rate and explain why.
NH3(g) + 2O2(g) → HNO3(l) + H2O(l)
The first reaction is started in a gas chamber with a volume of 10 L. The second reaction is started in a gas chamber with a volume of 5 L.
The second reaction with the volume of 5L will occur faster as compared to the first reaction of volume 10L.
Volume is inversely proportional to the rate of reaction.
As volume increases rate of reaction decreases and as volume decreases rate of reaction increases.
Let's consider a reaction A → B.
r is rate of reaction and K is rate constant, A is the concentration of reaction.
r = k(A)
r is directly proportional to the A.
But the concentration of A is in Moles/liters (i.e. moles per unit volume)
r is inversely proportional to the volume of vessel or chamber.
Hence as volume increases rate of reaction decreases.
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A gaseous compound containing hydrogen and carbon is decomposed and found to contain 90.00% carbon and 10.00% hydrogen by mass. The mass of 371 mL of the gas, measured at 415 mm Hg and 41°C, is found to be 0.315 g. What is the molecular formula of the compound?
The molecular formula of the compound is C₃H₄.
What is the molecular formula of the compound?The molecular formula of the compound is determined from the molecular mass of the compound.
The molecular mass of the compound is derived using the general gas equation as follows:
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁T₂/P₂T₁
Volume at STP, V₂ = (415 * 371 * 298(760 * 314)
V₂ = 192.26 mL = 0.192 L
Molar mass of gas = 22.4/0.192 * 0.315 = 36.75 g
Molecular formula is then determined from the mole ratio of the elements;
Carbon = 0.9 * 36.75/12 = 3
Hydrogen = 0.1 * 40/1 = 4
Thus, the molecular formula of the compound is C₃H₄.
In conclusion, the molecular formula of the gas is derived from the molecular mass.
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What would the hydrogen ion concentration be if the pOH was 6?
Answer:
10-6mol/l
Explanation:
hope i helped
If you react 9.10g of vinyl chloride with 7.80g of oxygen, what is the theoretical yield of carbon dioxide
The theoretical yield of the CO2 produced is 4.22 g.
What is the theoretical yield of carbon dioxide?The balanced reaction equation is;
2C2H3Cl + 5O2 ------>2CO2 + 2H2O + 2HCl
Number of moles of vinyl chloride = 9.10g /62 g/mol = 0.15 moles
Number of moles of oxygen = 7.80g/32 g/mol = 0.24 moles
Now;
2 moles of C2H3Cl reacts with 5 moles of oxygen
0.15 moles of C2H3Cl reacts with 0.15 moles * 5 moles / 2 moles
= 0.375 moles
Hence oxygen is the limiting reactant;
5 moles of oxygen produces 2 moles of CO2
0.24 moles of oxygen produces 0.24 moles * 2 moles /5 moles
= 0.096 moles
Mass of CO2 produced = 0.096 moles * 44 g/mol
= 4.22 g
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How many moles of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas?
Taking into account the reaction stoichiometry, 340.0 moles of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas
Reaction stoichiometryIn first place, the balanced reaction is:
CO₂ + 4 H₄ → CH₄ + 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
CO₂: 1 moleH₄: 4 moles CH₄: 1 moleH₂O: 2 molesMoles of CH₄ formedThe following rule of three can be applied: if by reaction stoichiometry 1 mole of CO₂ form 4 moles of CH₄, 85.1 moles of CO₂ form how many moles of CH₄?
[tex]moles of CH_{4} =\frac{85.1 moles of CO_{2}x4 moles of CH_{4} }{1 moles of CO_{2}}[/tex]
moles of CH₄= 340.4 moles
Then, 340.0 moles of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas
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What would the hydrogen ion concentration be if the pOH was 6?
Taking into account the definition of pH and pOH, the hydrogen ion concentration will be 1×10⁻⁸ M.
Definition of pHpH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.
The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or H₃O⁺:
pH= - log [H⁺]= - log [H₃O⁺]
Definition of pOHSimilarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:
pOH= - log [OH⁻]
Relationship between pH and pOHThe following relationship can be established between pH and pOH:
pOH + pH= 14
Hydroxide ion concentrationIn this case, you know that pOH= 6.
Replacing in the relationship established between pH and pOH, the pH can be calculated as:
pH + 6= 14
Solving:
pH= 14 - 6
pH= 8
Replacing in the definition of pH the concentration of H⁺ ions is obtained:
- log [H⁺]= 8
Solving:
[H⁺]= 10⁻⁸
[H⁺]= 1×10⁻⁸ M
In summary, the hydrogen ion concentration will be 1×10⁻⁸ M.
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what is the solubility of KCI?
Answer:
Potassium chloride.
(Yield Problem)
3Mg+2FeCl3=2Fe+3MgCl2
When 20.5 g of Mg reacts with an excess of FeCl3, 25.9 g of Fe is produced. What is the percent
yield of the reaction?
Answer:
Percent Yield Fe = 82.5%
Explanation:
The actual yield is the value produced after an experiment is conducted. The theoretical yield is the value calculated using the balanced chemical equation and atomic/molar masses.
To find the percent yield of iron (Fe), you need to (1) convert grams Al to moles Al (via atomic mass), then (2) convert moles Al to moles Fe (via mole-to-mole ratio from equation coefficients), then (3) convert moles Fe to grams Fe (via atomic mass), and then (4) calculate the percent yield. It is important to arrange the ratios in a way that allows for the cancellation of units. The final answer should have 3 sig figs to reflect the sig figs of the given values.
Atomic Mass (Mg): 24.305 g/mol
Atomic Mass (Fe): 55.845 g/mol
3 Mg + 2 FeCl₃ -----> 2 Fe + 3 MgCl₂
20.5 g Mg 1 mole 2 moles Fe 55.845 g
----------------- x ----------------- x ---------------------- x ----------------- =
24.305 g 3 moles Mg 1 mole
= 31.4 g Fe
Actual Yield
Percent Yield = ---------------------------------- x 100%
Theoretical Yield
25.9 g Fe
Percent Yield = -------------------- x 100%
31.4 g Fe
Percent Yield = 82.5%
Which is the number of moles of carbon dioxide produced from the complete combustion of 4.3 moles of ethanol?
The number of moles of carbon dioxide produced will be 8.6 moles.
Stoichiometri mole ratiosFirst, let's look at the balanced equation of the reaction. The complete combustion of ethanol gives carbon dioxide and water as follows:
[tex]C_2H_5OH + 3O_2 --- > 2CO_2 + 3H_2O[/tex]
We can see from the equation that the burning of 1 mole of ethanol produces 2 moles of carbon dioxide. In other words, the mole ratio is 1:2.
Thus, with 4.3 moles of ethanol, the amount, in moles, of carbon dioxide that will be produced will be:
4.3 x 2 = 8.6 moles
In other words, 8.6 moles of carbon dioxide will be produced from the complete combustion of 4.3 moles of ethanol.
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what are the factors affecting qualitative analysis in chemistry
Answer:
Techniques and Tests
Qualitative analysis typically measures changes in color, melting point, odor, reactivity, radioactivity, boiling point, bubble production, and precipitation.
How many moles of nitrogen gas are there in 6.8 liters at room temperature and pressure (293 K and 100 kPa)?
A. 163.2
B. 0.28
C. 152.3
D. 0.30
0.28 moles of nitrogen gas are there in 6.8 liters at room temperature and pressure (293 K and 100 kPa).
Ideal gas law :
An ideal gas is a gas in which atoms dose not exert any force on each other even after collision which walls and other atoms (inelastic collisions).
Mole definition:
The mole is the amount of compound present in a given system which has molecular mass as that of the mass of carbon12 .carbon 12
Using ideal gas law ,
PV=nRT
Given,
pressure = P = 100kPa
Volume = V = 6.8 Lit
Temperature = room temperature = T = 293 K
R= universal gas constant = 8.314
n= moles = ?
∴[tex]n = \frac{PV}{RT}[/tex]
∴ n = 100 × 6.8 / 8.314 × 293
∴n = 0.28 moles
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In this activity, you are tasked with designing an airbag for a company that creates airbags for automobiles. You must design the driver’s front airbag for a specific car model so it will protect the driver as effectively as possible. For this car, the airbag must have a volume of 58 liters when fully inflated. To provide an adequate cushion for the driver’s head, the air pressure inside the airbag should be 4.4 psi. This pressure value is in addition to the normal atmospheric pressure of 14.7 psi, giving a total absolute pressure of 19.1 psi, which equals 1.30 atmospheres.
The airbag is designed to produce the volume of nitrogen gas required to fill up the airbag.
What is the function of an airbag?An airbag is a bag which is designed to self-inflate and serve as a cushion for the head and neck of a driver to prevent injuries when an impact occurs head-on on the car.
The gas that inflates the airbag is nitrogen which is produced from sodium azide according to equation below:
2NaN₃ → 2Na + 3N₂In conclusion, the design of the airbag is such that the correct amount of sodium azide is present to produce the volume of nitrogen required to fill up the airbag.
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What is common to solving all mola mass problems?
All you need to do is to follow these 3 steps.
1. Estimate the number of each kind of atom present in the compound using the chemical formula in order to determine the molar mass of the molecule.
Divide each element's atomic weight (found in the periodic table) by the quantity of that element's atoms in the compound.Add up the total, then follow the number with the units of grams/mole.eg. Water
2 hydrogen atoms and 1 oxygen atom make up the chemical formula H20.H- 1's atomic weightO-16's atomic weightNumber of H atoms overall in formula 2Number of O atoms overall in formula 1The molar mass will thus be as follows: H 2 x 1= 2 O 1 x 16= 16 16+2= 18Water's molar mass is 18 g/mol as a result.In the following reaction, what element is losing mass?
Mg(s) + CuSO4(aq) -> MgSO4(aq) + Cu(s)
A. Mg
B. Cu
C.O
D. S
The element which is losing mass from the above reaction is Cu
Mg(s) + CuSO4(aq) -> MgSO4(aq) + Cu(s)
What is a compound?A compound simply refers to a chemical compound which contains two contains two or more elements which are chemically combined together.
So therefore, the element which is losing mass from the above reaction is Cu
Mg(s) + CuSO4(aq) -> MgSO4(aq) + Cu(s)
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Question 8
If I have an unknown quantity of gas at a pressure of 3.85 atm, a volume of 32.4 liters, and a temperature of
80.4°C, how many moles of gas do I have?
Answer:
4.30 moles
Explanation:
You need to use the Ideal Gas Law. The equation looks like this:
PV = nRT
In this equation,
-----> P = pressure (atm)
-----> V = volume (L)
-----> n = moles
-----> R = Ideal Gas Constant (0.08206 atm*L/mol*K)
-----> T = temperature (K)
Before you can plug the given values into the equation and simplify to find "n", you need to convert Celsius to Kelvin. The final answer should have 3 sig figs to match the sig figs of the given values.
P = 3.85 atm R = 0.08206 atm*L/mol*K
V = 32.4 L T = 80.4 °C + 273.15 = 353.55 K
n = ? moles
PV = nRT
(3.85 atm)(32.4 L) = n(0.08206 atm*L/mol*K)(353.55 K)
124.74 = n(29.012313)
4.30 = n
A[?] is a heterogeneous mixture which settles on standing and its components can be separated by filtration. colloid suspension
I think it should be suspension.
A 36.65g sample of solid is placed in a flask. Toluene in which the solid is insoluble ,is added to the flask so that the volume of solid and liquid together is 50.00mL.The solid and toluene together weigh 58.58 g .The density of toluene at temperature of the experiment is 0.864g/ml .what is the density of the solid?
The density of the solid is =0.3076g/ml
Calculation of the density of solidThe mass of solid in flask = 36.65g
The volume of both solid and Toluene = 50ml
The mass of both solid and Toluene = 58.58g
The density of toluene = 0.864g/ml
The density of the solid = X
Note: The density of the solid is calculated from the density of both the solid and toluene.
But the density of solid+ toluene;
=mass/volume
= 58.58g/50ml
= 1.1716g/ml
Therefore the density of solid alone = density of both solid +toluene - density of toluene.
= 1.1716g/ml - 0.864g/ml
= 0.3076g/ml
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How do you separate Sand Potassium Nitrate and Champhor
what is the name of p214
diphosphorus tetraiodide is the name of the p2I4 compound.
What is the name of p2I4?The name of p2I4 is diphosphorus tetraiodide because there are two atoms with phosphorus and four atoms with iodine. We know that 'di' word is used for two while on the other hand, tetra word is used for four.
So we can conclude that diphosphorus tetraiodide is the name of the p2I4 compound.
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How can mechanical waves help in the treatment of cancer?
Mechanical waves can help in the treatment of cancer due to heat generated by the high frequency waves.
What is mechanical wave?A mechanical wave is a wave that requires material medium for its propagation, example include;
water waves, sound waves, and seismic waves. Mechanical waves in treatment of cancersSound wave in example of mechanical wave because it requires material medium for its propagation.
High-frequency sound waves (HIFU) is used in the treatment of cancer because the strong beam generates heat which is directed to a specific part of a cancer.
The heat generated destroys the cancer cells.
Thus, mechanical waves can help in the treatment of cancer due to heat generated by the high frequency waves.
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help me out with this question
The concentration will be 12 M. The first option is the correct one.
ConcentrationIt is calculated by dividing the number of moles of solute present in a solution by the volume of the solution.
In this case, the number of moles of solute = 1.2 mols
volume of solvent = 100 mL or 0.1 L
Concentration of the solution = 1.2/0.1 = 12 mol/L or 12 M
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A mixture contains NaHCO3
together with unreactive components. A 1.68 g sample of the mixture reacts with HA
to produce 0.561 g of CO2
.
The molar mass of NaHCO3
is 84.01 g/mol
and the molar mass of CO2
is 44.01 g/mol.
What is the percent by mass of NaHCO3
in the original mixture?
Answer: 63.75 %
Explanation:
The balanced chemical equation for this reaction is:
NaHCO3 + HA = NaA + H2O + CO2
According to the chemical equation, one mole of NaHCO3 will react with one mole of HA to form one mole of NaA, H2O and CO2. All the components are in same mole ratio of 1:1:1:1
So,
Moles of CO2 = weight/molar mass = 0.561/44 = 0.01275 moles
Moles of CO2 will be equal to moles of NaHCO3 = 0.01275 moles
Moles = weight/mass
Weight = moles × mass
So the weight of NaHCO3 = 0.01275 × 84.01 = 1.071 g
The percentage mass of NaHCO3 in the original mixture =(1.071/1.68)× 100% = 63.75 %
Therefore, the percent by mass of NaHCO3 in the original mixture was 63.75 %
The question is in the photo
The concentration of LiOH in the reaction is 0.103 M
What is the concentration of lithium hydroxide?This is a neutralization reaction and the equation of the reaction is written as; H2SO4(aq) + 2LiOH(aq) ---->Li2SO4(aq) + H2O(l)
The average volume of acid used is obtained from;
8.54 + 8.51 + 8.68/ 3 = 8.58 mL
CA = 0.150 M
VA = 8.58 mL
CB = ?
VB= 25.0 mL
NA = 1
NB = 2
CAVA/CBVB = NA/NB
CAVANB = CBVBNA
CB = CAVANB/VBNA
CB = 0.150 * 8.58 * 2/25.0 * 1
CB = 0.103 M
The concentration of LiOH in the reaction is 0.103 M
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State which substance is undergoing oxidation and which substance is undergoing reduction in the following reaction:
N2 (g) + 3 H2 (g) ---> 2 NH3 (g)
Answer:
H₂(g) = oxidized
N₂(g) = reduced
Explanation:
Oxidized substances lose electrons and increase in oxidation number. Reduced substances gain electrons and decrease in oxidation number.
Lone elements always have an oxidation number of 0. So, N₂(g) and H₂(g) have oxidation numbers of 0.
Within compounds, hydrogen generally always have an oxidation of +1. Therefore, the hydrogen in NH₃(g) has an oxidation number of +1. In order to make the overall compound neutral, the nitrogen in NH₃(g) must have an oxidation number of -3 (to balance the +3 from the 3 hydrogens).
Since H₂(s) is losing electrons (goes from 0 to +1), it is being oxidized. Since N₂(g) is gaining electrons (goes from 0 to -3), it is being reduced.
Identify the Brønsted–Lowry acid and the Brønsted–Lowry
base on the left side of each of the following equations, and
also identify the conjugate acid and conjugate base of each
on the right side:
HCOOH(aq) + PO43-(aq) gives HCOO-(aq) + HPO42-(aq)
The following applies to the above equation:
Brønsted–Lowry acid - HCOOHBrønsted–Lowry base - PO43-Conjugate acid - HPO42-Conjugate base - HCOO-What is Bronsted-Lowry acid and base?Brønsted-Lowry acid is the any chemical species that acts as a donor of protons while Brønsted-Lowry base is any chemical species that acts as a proton acceptor.
In the following equation: HCOOH(aq) + PO43-(aq) = HCOO-(aq) + HPO42-(aq)
HCOOH is the proton (H+) donor, hence, is the Brønsted-Lowry acidPO43- is the donor acceptor, hence, is the Brønsted-Lowry baseHCOO- is the conjugate base that forms from the acidHPO42- is the conjugate acid that forms from the baseLearn more about Brønsted-Lowry acid and base at: https://brainly.com/question/15885173
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How many atoms of oxygen are present in 7.51 grams of
glycine with formula C₂H5O2N?
1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N. Details about number of atoms can be found below.
How to calculate number of atoms?
The number of atoms of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number.
However, the number of moles of oxygen in glycine can be calculated using the following expression:
Molar mass of C₂H5O2N = 75.07g/mol
Mass of oxygen in glycine = 32g/mol
Hence; 32/75.07 × 7.51 = 3.2grams of oxygen in glycine
Moles of oxygen = 3.2g ÷ 16g/mol = 0.2moles
Number of atoms of oxygen = 0.2 × 6.02 × 10²³ = 1.205 × 10²³ atoms
Therefore, 1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N.
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Balance the following reactions
a) Ca (s) + H₂O (1)→ Ca(OH)2 (aq) + H₂ (g)
b) Al2O3 (s) + C(s) + Cl₂ (g) → AICI3 (s) + CO (g)
c) FeCl3 (aq) + H₂S (g) → Fe2S3 (s) + HCI (aq)
d) CaCO3 (s) + HCI (aq) → Ca Cl₂ (aq) + CO2 (g) + H₂O (1)
Answer:
a) Ca (s) + 2 H₂O (l) ---> Ca(OH)₂ (aq) + H₂ (g)
b) Al₂O₃ (s) + 3 C (s) + 3 Cl₂ (g) ---> 2 AICI₃ (s) + 3 CO (g)
c) 2 FeCl₃ (aq) + 3 H₂S (g) ---> Fe₂S₃ (s) + 6 HCI (aq)
d) CaCO₃ (s) + 2 HCI (aq) ---> CaCl₂ (aq) + CO₂ (g) + H₂O (l)
Explanation:
For an equation to be balanced, there must be an equal amount of each type of atom on both sides of the reaction. The reactants are on the left side and the products are on the right side.
a) ------------------------------------------------------------------------------------------------------
The unbalanced equation:
Ca (s) + H₂O (l) ---> Ca(OH)₂ (aq) + H₂ (g)
Reactants: 1 calcium, 2 hydrogen, 1 oxygen
Products: 1 calcium, 4 hydrogen, 2 oxygen
The balanced equation:
Ca (s) + 2 H₂O (l) ---> Ca(OH)₂ (aq) + H₂ (g)
Reactants: 1 calcium, 4 hydrogen, 2 oxygen
Products: 1 calcium, 4 hydrogen, 2 oxygen
b) ------------------------------------------------------------------------------------------------------
The unbalanced equation:
Al₂O₃ (s) + C (s) + Cl₂ (g) ---> AICI₃ (s) + CO (g)
Reactants: 2 aluminum, 3 oxygen, 1 carbon, 2 chlorine
Products: 1 aluminum, 1 oxygen, 1 carbon, 3 chlorine
The balanced equation:
Al₂O₃ (s) + 3 C (s) + 3 Cl₂ (g) ---> 2 AICI₃ (s) + 3 CO (g)
Reactants: 2 aluminum, 3 oxygen, 3 carbon, 6 chlorine
Products: 2 aluminum, 3 oxygen, 3 carbon, 6 chlorine
c) ------------------------------------------------------------------------------------------------------
The unbalanced equation:
FeCl₃ (aq) + H₂S (g) ---> Fe₂S₃ (s) + HCI (aq)
Reactants: 1 iron, 3 chlorine, 2 hydrogen, 1 sulfur
Products: 2 iron, 1 chlorine, 1 hydrogen, 3 sulfur
The balanced equation:
2 FeCl₃ (aq) + 3 H₂S (g) ---> Fe₂S₃ (s) + 6 HCI (aq)
Reactants: 2 iron, 6 chlorine, 6 hydrogen, 3 sulfur
Products: 2 iron, 6 chlorine, 6 chlorine, 3 sulfur
d) ------------------------------------------------------------------------------------------------------
The unbalanced equation:
CaCO₃ (s) + HCI (aq) ---> CaCl₂ (aq) + CO₂ (g) + H₂O (l)
Reactants: 1 calcium, 1 carbon, 3 oxygen, 1 hydrogen, 1 chlorine
Products: 1 calcium, 1 carbon, 3 oxygen, 2 hydrogen, 2 chlorine
The balanced equation:
CaCO₃ (s) + 2 HCI (aq) ---> CaCl₂ (aq) + CO₂ (g) + H₂O (l)
Reactants: 1 calcium, 1 carbon, 3 oxygen, 2 hydrogen, 2 chlorine
Products: 1 calcium, 1 carbon, 3 oxygen, 2 hydrogen, 2 chlorine
a gas has a density of 3.21 g/L at stp what is the gas
The gas is bromine. (This is a fact)
The molar heat of fusion of gold is 12.550 kJ mol–1. At its melting point, how much mass of melted gold must solidify to release 235.0 kJ of energy?
The mass of melted gold to release the energy would be 3, 688. 8 Kg
How to determine the massIt is important to note that the formula for energy is
Q = n × HF
Where
n = number of moles
HF = heat of fusion
Let's find number of moles
235.0 = n × 12.550
number of moles = [tex]\frac{235}{12. 550}[/tex] = 18. 725 moles
The molar mass of Gold is 197g/ mol
We have that;
Number of moles = mass/ molar mass
Mass = number of moles × molar mass
Substitute the values
Mass = 18. 725 × 197
Mass = 3, 688. 8 Kg
Thus, the mass of melted gold to release the energy would be 3, 688. 8 Kg
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please help me with this question
1. The resulting concentration will be 0.00044 mol/L
2. The minimum mass of sodium sulfite to add will be 0.4032 grams.
Stoichiometric problems1. Using m1v1=m2v2
m1 = 0.01 mol/L, v1 = 20 mL, v2 = 450 mL
m2 = m1v1/v2 = 0.01 x 20/450 = 0.00044 mol/L
2. [tex]Na_2SO_3 + Ca(NO_3)_2 --- > 2NaNO_3 + CaSO_3[/tex]
Mole ratio of the reactants = 1:1
Mole of 80 mL, 0.0400 mol/L Ca(NO3)2 = 80/1000 x 0.0400 = 0.0032 mol
Equivalent mole of Na2SO3 = 0.0032 moles
Mass of 0.0032 moles Na2SO3 = 0.0032 x 126 = 0.4032 grams
Thus, the minimum mass of sodium sulfite to be added must be 0.4032 grams.
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