Which of the following equations has exactly one real solution?
A.
2(x + 14) = 2x + 28
B.
7x + 14 = −2x − 17
C.
2x + 14 = 2x + 14
D.
7x + 14 = 7x − 17

Answers

Answer 1

Answer:

Option A

Step-by-step explanation:

2(x+14)=2x+28

2x+28=2x+28

IT HAS REAL SOLUTION :)

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Related Questions

help me with this thanks

Answers

Answer:

hiii

Step-by-step explanation:

Answer:

Answer is B

Step-by-step explanation:

Front view is the same as viewing from the side, and on top it just looks like a square

Hope I helped

Stephanie can jump rope 12o turns in 3 minutes. How many turns does she make in 1 minute

Answers

She would be able to make 40 in one minute.

To find this, you just divide 120/3 to find how many in one minute.

Answer:

40

Step-by-step explanation:

120 divided by three equals fourty

Michael's class held a food drive for the holidays. There are a total of 29 students in his class. On average, each boy and girl bought 3 cans of food apiece. If the class brought in a total of 87 cans of food, how many boys and how many girls are in the class ?

Answers

Answer:

19 girls snd 10 boys

Which equation below would be perpendicular to the line y = 2?

Answers

I believe that the answer is Y=1/5x

Please help me ASAP I’m really confused

Answers

It’s the one on the top left because it’s supposed to be 5.5.5.5.5 and the other one 4.4.4.4

Can someone please help? I will mark brainliest random answers will be reported

Answers

Answer:

5.1

Step-by-step explanation:

hope it helps thank you

1. y-23=55 2. x-14= -8




3. -15 = n + 18 4. 18.3 + a = 2.7
what are the answers for all of these i need help FAST!!!

Answers

Answer:

1. y = 32

2. x = 6

3. -33 = n

4. a = -15.6

Step-by-step explanation:

1.

y-23=55

 +23  +23          (23 cancels)

y = 32

2.

x - 14 = -8

 +14      +14           (-14 cancels)

   x = 6

3.

-15 = n + 18

    -18       -18          (18 cancels)

    -33 = n

4.

18.3 + a = 2.7

-18.3        -18.3        (18.3 cancels)

         a = -15.6

please please i need this

Answers

Answer:

for 3. the answer is 9

for 4. the answer is 12

Step-by-step explanation:

hope this helped!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

for a cube with side length 4cm, calculate the surface area

Answers

Answer: I believe that’s 96 squared cm

Step-by-step explanation:

The formula for surface area for a cube is 6 times the side to the power of 2

6*4^2 = 96 cm^2

Help asap pls for brainliest!

Answers

Answer:

D

Step-by-step explanation:

Answer:

D

Bro this is the answer!

hi please help with my maths!

Answers

Answer: I need more to solve this

Step-by-step explanation:

Answer:

AB equals 4.535 (4.53478)

Zamir needs to determine the height of the building

What’s the Height “A”
What’s Height “B”
What’s the Height of “X”

PLEASE

Answers

Answer:

Height of the building = 115.4 ft.

Step-by-step explanation:

Height of building = AB + 46.4 + CD + 30.5

By applying Pythagoras theorem in ΔABP,

(26)² = (10)²+ (AB)²

676 - 100 = AB²

AB² = 576

AB = 24 ft

By applying sine rule in ΔCDE,

cos(60°) = [tex]\frac{CD}{CE}[/tex]

CD = CE × [tex]\frac{1}{2}[/tex]

CD = [tex]\frac{29}{2}[/tex]

CD = 14.5 ft

Total Height = 24 + 46.4 + 14.5 + 30.5

                     = 115.4 ft

Two data sets contain an equal number of values. The double box and whisker plot represents the values in the data set. Compare the data sets using measures of center and variation.

Answers

Answer with explanation:

From the box and whisker plot of seventh grade we have:

The minimum value =6

First quartile or lower quartile i.e. = 14

Median or second quartile i.e. = 18

Third quartile or upper quartile i.e. =22

and maximum value = 26

From the box and whisker plot of eighth grade we have:

The minimum value =22

First quartile or lower quartile i.e. = 26

Median or second quartile i.e. = 30

Third quartile or upper quartile i.e. = 34

and maximum value = 38

a)

The overlap of the two sets of data is as follows.

   The upper quartile or third quartile of seventh grade is same as the minimum value of the data of eighth grade.

   And the maximum value of seventh grade is same as the lower quartile of eighth grade.

b)

IQR is calculated as the difference of the Upper quartile and the lower quartile

i.e.

so, IQR of seventh grade is:

22-14=8

IQR of seventh grade=8

IQR of eighth grade is:

34-26=8

Hence, IQR of eighth grade=8

c)

The difference of the median of the two data sets is:

30-18=12

Hence, the difference of median is: 12

d)

As the IQR of both the sets is same i.e. 8.

Hence, the number that must be multiplied by IQR so that it is equal to the difference between the medians of the two sets is:

Hence, the number is : 1.5

Answer:

ive seen this before

Step-by-step explanation:

SOMEONE PLEASE HELP ME I WILL GIVE BRAINLIST TO THE PERSON WHO GIVES ME THE CORRECT ANSWER

Three shipping companies want to compare the mean numbers of deliveries their drivers complete in a day.

The first two shipping companies provided their data from a sample of drivers in a table.

Company C showed its data in a dot plot.


Answer the questions to compare the mean number of deliveries for the three companies.





1. How many drivers did company C use in its sample?


Write your answer in the space below.









2. What is the MAD for company C's data? Show your work.


Write your answer in the space below.









3. Which company had the greatest mean number of deliveries?


Write your answer in the space below.









4. Compare the means for companies A and B. By how many times the MAD do their means differ? Show your work.


Write your answer in the space below.

Answers

Answer:

Step-by-step explanation:

1. 10

2.The mean is ten because 6 + 7 + 8 + 9 + 10 + 10 + 10 + 12 + 14 + 14 = 100/10. The (Mean) = 10

3. is A and B

Thats all i have still stuck on number 4 sorry

If 25% of an item is 20$, what is the original price?
I will give Brainliest
ASAP!!!

Answers

Answer:

I think that the original price would be $30, but I'm not completely sure.

Step-by-step explanation:

Half (50%) of 40 would be 20, and half of 20 (25%) would be 10. Add 10 to 20 to get 30, because you are adding the %25 back to $20.

Hope this helps!

Answer:

$80

Step-by-step explanation:

25% = 1/4

To get original price multiply by 4:

$20 × 4 = $80

Which of the following shows the least expensive unit price?

Answers

it would be the first one because each orange costs $0.34

Answer:

A (3 Oranges For $1.02)

Step-by-step explanation:

3 Oranges for $1.02 is $0.34 for each Orange

4 Oranges For $1.52 is $0.38 for each Orange

6 Oranges for $2.46 is $0.41 for each Orange

5 Oranges for $1.75 is $0.35 for each Orange

Which Makes The First One The Cheapest Out Of All

Of 77 third graders, on Monday 3 were absent from Room 101, 4 were absent from Room 102, and 2 were absent from Room 103. How many third graders attended school that day? ​

Answers

Answer:

68

Step-by-step explanation:

Their are 77 total, 77-3= 74-4= 70-2= 68

there are 68 3rd graders left

Do 9-77

What is the equation of the line that passes through the points ( 5,-2) and (-5,0)

Answers

Answer:

y=-1/5x-1

Step-by-step explanation:

4ax + 2bx =??
Es urgente

Answers

Answer:

2x(2a + b)

Step-by-step explanation:

4ax+ 2bx

= 2x (2a + b)

please help first image pleaseeeeee............................................

Answers

I think the answer is 2 for the math , not sure mark brainliest pls

Answer:

1:2

Step-by-step explanation:

Point B has coordinates ​(4,1​). The​ x-coordinate of point A is -8. The distance between point A and point B is 13 units. What are the possible coordinates of point​ A?

Answers

Answer:

The possible coordinates of point A are (-8,-4) or (-8,6)

Step-by-step explanation:

The distance between two points is given by the formula

[tex]d = \sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2} }[/tex]

For point A [tex](x_{1} , y_{1})[/tex]; [tex]x_{1}= -8[/tex] and [tex]y_{1}[/tex] is unknown

For point B [tex](x_{2} , y_{2})[/tex]; (4,1) i.e [tex]x_{2}=4[/tex] and [tex]y_{2}=1[/tex]

and d = 13

Putting the values into the equation,

[tex]13= \sqrt{[(4-(-8)]^{2} + (1-y_{1})^{2} }\\13= \sqrt{[(4+8)]^{2} + (1-y_{1})^{2} }\\13= \sqrt{12^{2} + (1-y_{1})^{2} }\\13^{2} = 12^{2} + (1-y_{1})^{2} \\169 = 144 +(1-y_{1})^{2}\\169-144 = (1-y_{1})^{2}\\25 = 1 -2y_{1} +y_{1}^{2} \\y_{1}^{2} -2y_{1}+1-25 =0\\y_{1}^{2} -2y_{1}-24 =0\\y_{1}^{2} -6y_{1} + 4y_{1} -24 =0 \\y_{1}(y_{1}-6) +4(y_{1} -6) = 0\\(y_{1}+4)(y_{1}-6) =0\\(y_{1}+4)=0 or (y_{1}-6) =0[/tex]

[tex]y_{1}+4= 0[/tex] or [tex]y_{1}-6 =0[/tex]

[tex]y_{1} =-4[/tex] or [tex]y_{1} = 6[/tex]

Hence, the possible coordinates of point A are (-8,-4) or (-8,6)

Q1.) Morgan buys 3 pairs of socks for $1.29 each and a pair of shoes for $29.95. The sales tax is 8 %.
What is the total amount she spends including tax?

Answers

Answer:

She spends $36.53

Plz help will mark you brainliest if correct

Answers

Answer:

B

Step-by-step explanation:

5/1 is not equal to 6/2 or 7/3 or 8/4

Answer:

The answer would be B instead of D

Evaluate the following expression. log4 256
A. 64
B. 16 C. 4 D. 8

Answers

The correct answer is c.4

The simplified value of the expression  [tex]log_4[/tex] 256 is 4.

Thus, option (C) is correct.

To evaluate the expression [tex]log_4[/tex] 256, determine the power to which 4 must be raised to obtain 256.

So, the equation can be set up

[tex]4^x[/tex] = 256.

Now, put the value of x one by one as

[tex]4^2 = 16[/tex]

[tex]4^3 = 64[/tex]

[tex]4^4 = 256[/tex]

Thus, when the number 4 raise to the power 4 it gives 256.

Thus, option (C) is correct.

Learn more about Exponents here:

https://brainly.com/question/5497425

#SPJ6



Can someone please help me with this problem. Thank you

Answers

Answer:

B

Step-by-step explanation:

what does s equal?pls help me plsss.

Answers

Answer:

s< -7/11

Step-by-step explanation:

finish the lyrics

a potoao flew

Answers

Around my room before you came.

Answer: around my room before you came

Step-by-step explanation:

A linguist at a large university was studying the word length of papers submitted by students en
humanities programs. From a random sample of 25 papers, the linguist counted the number of words
used in each paper. The 95 percent confidence interval was calculated to be (20,995, 22,905).
Assuming all conditions for inference are met, which of the following is a correct interpretation of the
interval?

Answers

Answer:

We are 95 percent confident that the mean word length for all papers submitted by students in humanities programs is between 20,995 words and 22,905 words

Step-by-step explanation:

The confidence interval is used to predict the mean for the entire humanities program, not just the sample.

please help, if u get it I’ll give you brainliest!!
find the area with explanation!

Answers

Answer:

4ft

Step-by-step explanation:

we will use the formula which states area of triangles is equal to base multiplied height divided by 2

base=5ft

height=8ft

area=5*8/2

=13/2

=6.5ft

this pic is not clear pls mention better next time I was confused what is 4ft and what is 8ft however if I have understood wrong I have also written the formula.

The half-life of the isotope Osmium-183 is 12 hours. Choose the equation below that gives the remaining mass of Osmium-183 in grams, M.
after n half-lives have elapsed if there was an initial mass of 590 grams before decay. Then, use the equation to determine the mass remaining
after 36 hours have passed
Mn = 590. ()": M3 – 148
D
M, = 590 C4)*-* : My ~ 148
Mn = 590 - ()": Mz - 74
Mi = 590 - (1) * + : Mz - 74

Answers

The given equations are incomprehensible, I'm afraid...

You're given that osmium-183 has a half-life of 12 hours, so for some initial mass M₀, the mass after 12 hours is half that:

1/2 M₀ = M₀ exp(12k)

for some decay constant k. Solve for this k :

1/2 = exp(12k)

ln(1/2) = 12k

k = 1/12 ln(1/2) = - ln(2)/12

Now for some starting mass M₀, the mass M remaining after time t is given by

M = M₀ exp(kt )

So if M₀ = 590 g and t = 36 h, plugging these into the equation with the previously determined value of k gives

M = 590 exp(36k) = 73.75

so 73.75 ≈ 74 g of Os-183 are left.

Alternatively, notice that the given time period of 36 hours is simply 3 times the half-life of 12 hours, so 1/2³ = 1/8 of the starting amount of Os-183 is left:

590/8 = 73.75 ≈ 74

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