Write and answer the following in your answer sheet.

Answer:     Distance to close end of island is 3000/tan(75.8); distance to far end is 3000/tan(15.6). The difference is 9985.676 feet or about 1.9 miles.

Explanation:  2 explanation Balloon, flying or levitating, has no front to recon with, so two possible answers.

tan(90–15.6)+or-tan(90–75.08) * 3000= length of island

Answer:

It is considered the finale of High School. Which depicts what role you should become in College... it is also the ticket to ur high school diploma

Explanation:

Answer: 4 - ? = 12

Explanation: maybe

Answer:

“First-Generation Student”

Parameterize S in cylindrical coordinates by the vector function

r(u, v) = (x(u, v), y(u, v), z(u, v))

with

x(u, v) = u cos(v)

y(u, v) = u sin(v)

z(u, v) = 36 - u²

with 0 ≤ u ≤ 3 and 0 ≤ v ≤ 2π. Take the normal vector to S to be

[tex]\vec n = \dfrac{\partial r}{\partial u} \times \dfrac{\partial r}{\partial v} = (2u^2\cos(v),2u^2\sin(v),u)[/tex]

so that the surface element is

[tex]dS = \|\vec n\| \, du\,dv = u \sqrt{1+4u^2}\, du\, dv[/tex]

Then the surface integral is

[tex]\displaystyle \iint_S y^2\,ds = \int_0^{2\pi} \int_0^3 u\sqrt{1+4u^2} \, du\, dv[/tex]

[tex]\displaystyle \iint_S y^2\,ds = 2\pi \int_0^3 u\sqrt{1+4u^2} \, du[/tex]

[tex]\displaystyle \iint_S y^2\,ds = \frac{2\pi}8 \int_0^3 8u\sqrt{1+4u^2} \, du[/tex]

[tex]\displaystyle \iint_S y^2\,ds = \frac\pi4 \int_0^3 \sqrt{1+4u^2} \, d(1+4u^2)[/tex]

[tex]\displaystyle \iint_S y^2\,ds = \frac\pi4 \cdot \frac23(1+4u^2)^{\frac32} \bigg|_0^3 = \boxed{\frac\pi6 \left(37^{\frac32}-1\right)}[/tex]

Answer:

A is the correct answer

Explanation:

EDGE

A centroid in a triangle, is the point where all the medians meet.

now a peculiar thing about the centroid is that, it cuts all medians in a 2:1 ratio. So, if that's true, then the median AE, is being cut in two segments AD and DE and AD : DE are on a 2 : 1 ratio.

In a triangle, the centroid is the point of intersection of the three medians, which are line segments joining each vertex to the midpoint of the opposite side.

The centroid divides each median into two segments, with the distance from the centroid to the vertex being twice the distance from the centroid to the midpoint of the opposite side.

Let M be the midpoint of side AB, N be the midpoint of side AC, and P be the midpoint of side BC. Then, we have:

CD = 2DP

CE = 2DN

We are also given that DE = 15. Since D is the centroid, we have:

AD = BD = CD/3

AE = CE/3

DC + DP = PC

CE + DN = NE

AD + AE = DE

Using these relationships, we can find CD and CE:

CD = 2DP = 2(PC - DC) = 2((AD + DP) - (AD/3)) = 2(2AD/3) = 4AD/3

CE = 2DN = 2(NE - CE) = 2((AE + DN) - (AE/3)) = 2(2AE/3) = 4AE/3

To find AD and AE, we can use the fact that AD + AE = DE and AD = BD:

AD + BD = DE

AD + (2AD/3) = 15

5AD/3 = 15

AD = 9

AE = DE - AD = 15 - 9 = 6

Substituting these values into the equations for CD and CE, we get:

CD = 4AD/3 = 4(9)/3 = 12

CE = 4AE/3 = 4(6)/3 = 8

Therefore, CD = 12 and CE = 8.

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Answer:

The SAT is the longer of the two tests at three hours without the essay, and three hours and 50 minutes with the essay. The ACT is three hours and 35 minutes with the writing section, and three hours without it. The lengths of each sections vary between the two tests, which can be seen below.

Answer:

The correct answer to the question is 0.3 m/s i.e the speed of the wave is 0.3 m/s.

Answer:

Photons travel in harmonic waves at the fastest speed possible in the universe: 186,282 miles per second (299,792,458 meters per second) in a vacuum, also known as the speed of light. The waves have certain characteristics, given as frequency, wavelength or energy.

Answer:

28.25

Explanation:

Answer:

because shes a piggy.

Explanation:

Answer:

yeaaaa

Explanation:

Mud digger

We kick the mud by the pound

Our tires stay roarin' while we ridin' through the town

Mud digger

And I keep a bad truck around

Big truck tall suspension, 40-inches from the ground

Mud digger

And my Chevy sittin' on 44's

Pipes louder than glass packs, straight pipes y'all know

Mud digger

If y'all don't know how the mud diggin' goes

Then get a couple of tickets to a mud boggin' show

Using the appropriate sample size formula, the minimum number of samples required is 267

Using the relation :

Substituting the values into the equation :

N = [(1.96² × (0.5 × 0.5)) / 0.0036]

N = (0.9604 / 0.0036)

N = 266.777

N = 267

Hence, the minimum number of samples required is 267

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The above question wants to assess your writing ability, therefore it is not correct for me to write the thesis statement for you, but I will show you how to write it.

First, you should know that a thesis statement is a short, direct, and objective paragraph that shows your opinion or position on a particular issue.

This opinion must be substantiated by evidence taken from research sources, for this reason, you should read the sources that have been presented to you or research articles, essays, and publications on the subject.

After that, you can answer your question as follows:

An example of a thesis statement would be: According to the reading, the function of zoos will become increasingly obsolete due to the growth of environmental awareness and animal rights.

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Answer:

Eat foods that can give you energy like natural foods, carbohydrates, and protein.

Nutrition  is an important part of your health so make sure to check nutrition facts.

Exercise to keep your blood, heart, and your body moving.

Really try not to eat a lot of junk food because it can keep you from being healthy.

Grow by also being in a good mood because when your sad it decreases energy.

You can keep up your energy by following these amazing steps.

Explanation:

Considering the data in the question, the focal length of the objective lens that will give a total magnification of 200x is 0.8cm focal length.

The whole question is:

You are using a microscope with a 10x eyepiece. What focal length of the objective lens will give a total magnification of 200x? Assume a length L = 160mm.

Given that total magnification is 200

And the Assume length is 160

Since we used a microscope with a 10x eyepiece, the magnification would be divided by 10.

=> 200 ÷ 10 = 20.

Also, the focal length is measured in centimeters or meters; we would change the millimeters of focal length to centimeters. Therefore, we have 160 ÷ 10 = 16

The formula for the focal length of the objective lens = assumed length ÷ total magnification.

=> 16 ÷ 20 = 0.8cm.

Hence, in this case, it is concluded that the correct answer is "0.8cm."

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Answer:

how happy

Explanation:

Answer:

1. Co ( s ) - metallic bonding

2. CoCl₂ ( s ) - ionic bonding

3. CCl₄ ( l ) - covalent bonding

Explanation:

Metallic bonding -

It is the type of bonding present between the atoms of the metals , via the electrostatic interaction between the metal and the delocalized electrons , is known as metallic bonding .

For example ,

Mostly metals show metallic bonding .

Ionic bonding -

It is the type of bonding present between the ions i.e. , the cation and the anion is known as ionic bonding .

For example ,

Mostly ionic compound , like salts show ionic bonding .

Covalent bonding -

It is the type of bonding which is present between shared pair of electrons , is known as covalent bonding .

For example ,

Most of the carbon compounds are capable to show covalent bonding .

Hence , from the question ,

1. Co ( s ) - metallic bonding

2. CoCl₂ ( s ) - ionic bonding

3. CCl₄ ( l ) - covalent bonding  

Answer It's D (1924 - 1929)

hope this helps :)

Explanation: edge 2023

Answer: United States could not remain separate.

Explanation: cause i be smart

The author’s first use of the key term illusion suggest about American foreign policy is The United States could not remain separate.

The 'illusion of isolation' means that America tried to pretend to be an isolationist continent, meaning that it would have nothing to do with the politics of other countries, however, that turned out to be a lie, especially when it openly entered WWII.

Security, prosperity, and the creation of a better world are the three most prominent goals of American foreign policy.

Security, the protection of America's interests and citizens, is a perennial concern, but America has tried to achieve security in different ways throughout its long history.

The four main objectives of U.S. foreign policy are the protection of the United States and its citizens and allies, the assurance of continuing access to international resources and markets, the preservation of a balance of power in the world, and the protection of human rights and democracy.

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Answer:

Explanation:

Diagram?

Answer: $150

Please mark me brainliest!

Explanation: 3 + 10 = 13

                      13 + 30 = 43

                      43 + 100 = 143

                      143 + 7 = $150

if 1 = 15 and 6=20 what is 3

=

25

Answer: 29,29,27,27 :)

Answer:

Fossils helped teach scientist by giving information of the species that lived back then.

Explanation:

The fossils have clues on them help identify what they are.

alterations in various aspects of society over time according to pitrim Sorkin cyclical theory of social change the principle of immant change is the natural tendency of a society structure to swing back and forth between the ideotional and sensate culture

A significant alteration to a society's structure is social change. Numerous facets of a society, including its economic, political, cultural, ethical, and identity problems, can be affected by social change.

The major alteration of social structure and cultural norms over time is referred to as social change. Social ties that have remained constant over time and become routine or repetitive are referred to as social structures.

Among the key forces influencing societal development are population growth and composition, the natural environment, social conflict, culture, and technology.

Cultural lag is the term used to describe a delayed shift in one area of society as a result of a change in a different area of society.

Therefore, Alterations in social change various aspects of society over time.

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Encontrando y resolviendo un sistema de ecuaciones, veremos que hay 9 camionetas y 3 autos.

Sabemos que hay 12 vehículos en el camión.

Definamos:

tal que a + c = 12

La masa total será:

a*2 ton + c*3 ton

Y sabemos que el camión lleva 33 toneladas, entonces tenemos:

a*2 ton + c*3 ton = 33 ton

Así encontramos el sistema de ecuaciones:

a + c = 12

a*2 ton + c*3 ton = 33 ton

Para resolverlo, primero aislamos una de las variables en una de las ecuaciones, aislemos a en la primera:

a = 12 - c

Ahora reemplazamos esto en la otra:

(12 - c)*2 ton + c*3 ton = 33 ton

24 ton + c*1 ton = 33 ton

c*1 ton = 9 ton.

c = 9

Es decir, hay 9 camionetas.

Entonces los 3 vehículos restantes son autos.

Hay 9 camionetas y 3 autos.

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Explanation:

Using the normal distribution, it is found that the probability that the volunteer selected will receive a certificate of merit given that the  number of hours the volunteer worked is less than 90 is closest to:

B 0.123

In a normal distribution with mean \muμ and standard deviation \sigmaσ , the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}Z=σX−μ

It measures how many standard deviations the measure is from the mean.  

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

The mean is of 80, hence \mu = 80μ=80 .

The standard deviation is of 7, hence \sigma = 7σ=7 .

The minimum value is the 80th percentile, which means that it is X_mXm when Z has a p-value of 0.8.

The probability that the volunteer selected will receive a certificate of merit given that the number of hours the volunteer worked is less than 90 is P(X_m < X < 90)P(Xm<X<90) , which is the p-value of Z when X = 90 subtracted by the p-value of Z when X = X_mX=Xm , hence the p-value of Z when X = 90 subtracted by 0.8.

Z = \frac{X - \mu}{\sigma}Z=σX−μ

Z = \frac{90 - 80}{7}Z=790−80

Z = 1.43Z=1.43

Z = 1.43Z=1.43 has a p-value of 0.9236.

0.9236 - 0.8 = 0.1236, hence closest to 0.123, option B.

Using the normal distribution, it is found that the probability that the volunteer selected will receive a certificate of merit given that the  number of hours the volunteer worked is less than 90 is closest to:

Letter B

In a normal distribution with mean and standard deviation , the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}\\Z=\sigma X - \mu[/tex]

It measures how many standard deviations the measure is from the mean. After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X. In this problem:

The probability that the volunteer selected will receive a certificate of merit given that the number of hours the volunteer worked is less than 90, which is the p-value of Z when X = 90 subtracted by the p-value of Z when X = X_mX=Xm , hence the p-value of Z when X = 90 subtracted by 0.8.

[tex]Z = \frac{X - \mu}{\sigma}\\Z=\sigma X - \mu\\Z = \frac{90 - 80}{7}\\Z=790 - 80\\Z = 1.43Z=1.43[/tex]

Has a p-value of 0.9236.

[tex]0.9236 - 0.8 = 0.1236[/tex]

Hence closest to 0.123.

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Stokes' theorem says that the surface integral of the curl of the vector field F across the surface S is equal to the line integral of F along the boundary of S.

In this case, the boundary is a circle in the x,y-plane with radius 2. (To see this, set z = 0 and rearrange the equation for the paraboloid as x² + y² = 4.)

Then

[tex]\displaystyle \iint_S (\nabla\times\vec F)\cdot d\vec s = \int_{\partial S} \vec F \cdot d\vec r[/tex]

where

[tex]\vec r = 2\cos(t) \,\vec\imath + 2\sin(t) \,\vec\jmath[/tex]

parameterizes the circular boundary of S with 0 ≤ t ≤ 2π. Then

[tex]d\vec r = \dfrac{d\vec r}{dt}\,\dt = (-2\sin(t)\,\vec\imath + 2\cos(t)\,\vec\jmath)\,dt[/tex]

and the integral becomes

[tex]\displaystyle \iint_S (\nabla\times\vec F)\cdot d\vec s = \int_{\partial S} \vec F \cdot d\vec r[/tex]

[tex]\displaystyle \iint_S (\nabla\times\vec F)\cdot d\vec s = \int_0^{2\pi} \vec F(\vec r(t)) \cdot \frac{d\vec r}{dt}\,dt[/tex]

[tex]\displaystyle \iint_S (\nabla\times\vec F)\cdot d\vec s \\= \int_0^{2\pi} ((2\cos(t))^2 \sin(0)\,\vec\imath + (2\sin(t))^2\,\vec\jmath + (2\cos(t))(2\sin(t))\,\vec k) \cdot(-2\sin(t)\,\vec\imath + 2\cos(t)\,\vec\jmath)\,dt[/tex]

[tex]\displaystyle \iint_S (\nabla\times\vec F)\cdot d\vec s = \int_0^{2\pi} 8\sin^2(t)\cos(t) \, dt[/tex]

[tex]\displaystyle \iint_S (\nabla\times\vec F)\cdot d\vec s = \int_0^{2\pi} 8\sin^2(t) \, d(\sin(t))[/tex]

[tex]\displaystyle \iint_S (\nabla\times\vec F)\cdot d\vec s = \frac83 (\sin^3(2\pi)-\sin^3(0)) = \boxed{0}[/tex]

The probability that the student that's selected will be in grade 10 given that the student ordered French fries as the side will be 71/248.

From the information given, the number of students that are in grade 10 is 105. Out of all the students, 34 had salad and 71 had French fries. The total students in the school that are French fries was 248.

Therefore, the probability that the student that's selected will be in grade 10 given that the student ordered French fries as the side will be calculated thus:

= Number of students who French fries in grade 10 / Total number of people that had French fries

= 71/248

In conclusion, the correct option is 71/248.

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