write the equation for the reaction associated with the kb2 of carbonate, co32–.

Answer:

i put c

Explanation:

Rocks' ages are determined through radiometric dating, which takes into account the ratio of two different isotopes in a sample. Geologists can use tools like these to assess the age of a material,Mass spectrometer for thermal ionization Thus, option C is correct.

How rocks are structured in strata and how they fit into the larger geological history are the main topics of stratigraphic study. This approach is best suited for studying sedimentary rocks. Cross dating is a method for using fossils to determine a rock's relative age.

Therefore, Index fossils are sought after by geologists in geological strata. Index fossils are useful because they show the relative dates of the rock layers in which they are discovered. Since radioactive isotopes deteriorate with known time intervals.

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Answer:

A fly hits a windshield of a truck.

Explanation:

newton's first law

Answer:

A

Explanation:

have a great day!!!!!!!!

Answer:

A DC power supply, commutator, rotor armature, axle, and a field magnet.

Answer:

The atomic number increases across a period and down the group or family. The atomic mass generally increases with atomic number with a few exceptions.

Complete Question:

Check the file attached to get the complete question

Answer:

In the film Ice word Revenge, vehicle 2 did not fall of the cliff because,  but in Claire's test, vehicle 2 off the cliff because

Explanation:

In Claire's test, the weight of vehicle 1 is either equal to or greater than the weight of vehicle 2, so it was sufficient to push it down the cliff.  In the film Ice word revenge, the weight of vehicle 1 is less than the weight of vehicle 2, it is not sufficient to make it fall off the cliff ( Note: Looking exactly the same in the movie, as Claire claimed, does not mean they have the same mass). Therefore if Claire wants a collision that will not make the vehicle 2 fall off the cliff, he should collide it with a vehicle of lesser mass/weight.

Answer:

Sexual Reproduction

Explanation:

In Asexual Reproduction offsprings are know as ramets and many ramets are known as clowns. So, when two parents are involved genetic variations occur in offspring. Pollen possess male gamete (antherozoid/sperm) and ovule possess egg.

A part

Answer: 0.25

Explanation: M = moles of solute / volume of solution (L)

First, you need to calculate the number of moles using the given mass and the molar mass.

15 g74.692 g/mol≈0.20 mol

Then, you can solve for molarity using the molarity equation. The answer should be reported to two significant figures.

M=0.20 mol/ 0.800 L = 0.25 M

The molar concentration of  NiO solution is 0.251 M.

Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.

The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.

In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.Considering the given example, molar concentration of NiO   is found out as follows,

molar concentration=15/74.69 ×1/0.8= 0.251 M.

where 74.69 is molar mass of NiO.

Thus, the molar concentration of NiO is 0.251 M.

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Answer:

Explanation:

First convert the grams of Calcium Bromide to moles by using the atomic weight. Then use the formula for molarity, which is moles per liter.

CaBr2 = 199.9 g/mol

10/199.9 = 0.05 moles of CaBr2

[tex]0.5M=\frac{0.05mol}{x}[/tex]

x = 0.1L or 100mL

Answer:

Explanation:

First we convert the given masses of reactants to moles, using their respective molar masses:

2.39 kmol of CO₂ would react completely with (2.39 * 2) 4.78 kmol of NH₃. There are not as many NH₃ kmoles so NH₃ is the limiting reactant.

We calculate how much urea would form with a 100% yield, using the moles of limiting reactant:

We convert that amount to kg:

Finally we calculate the percent yield:

Answer:

[tex]\Delta Tfp_{NaCl}= -14.0\°C\\\\\Delta Tfp_{CaCl_2}=-11.1\°C[/tex]

Explanation:

Hello!

In this case, since the freezing point depression caused by the addition of a solute, we use the following formula:

[tex]\Delta Tfp= i*m*Kfp[/tex]

Thus, we first need to compute the molality of each solute, as shown below:

[tex]m_{NaCl}=\frac{220.g/(58.44g/mol)}{1.00kg} =3.76m\\\\m_{CaCl_2}=\frac{220.g/(110.98g/mol)}{1.00kg} =1.98m[/tex]

Next, since NaCl has two ionic species, one Na⁺ and one Cl⁻, and CaCl₂ three, one Ca²⁺ and two Cl⁻, the van't Hoff's factors are 2 and 3 respectively, therefore the freezing point depressions turn out:

[tex]\Delta Tfp_{NaCl}= 2*3.76m*-1.86\°C/m=-14.0\°C\\\\\Delta Tfp_{CaCl_2}= 3*1.98m*-1.86\°C/m=-11.1\°C[/tex]

It means that CaCl₂ is still better than NaCl because produces involves a higher melting point for the ice, so it would melt faster.

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Answer:

3 × 10 L

Explanation:

Step 1: Given and required data

Step 2: Convert "T" to Kelvin

When working with gases, we need to use the absolute temperature. We can convert Celsius to Kelvin using the following expression.

K = °C + 273.15

K = 77°C + 273.15 = 350 K

Step 3: Calculate the volume (V) of the tank

We can calculate the volume occupied by the gas using the ideal gas equation.

P × V = n × R × T

V = n × R × T/P

V = 4.5 mol × (0.082 atm.L/mol.K) × 350 K/5 atm = 3 × 10 L

Answer:

No

No

Yes 25cm

Explanation:

1) mass can't be divided by distance.

2) the measurements are completely different but under the same category of distance. you can only divide it if meters was cm and squared

3) measurements the same and you can multiply it

The volume occupied by 7.455 moles of pentanol is 553.5 mL or 0.5535 L.

The molar mass of a given compound is the mass of one mole of that compound. It is expressed in unit as grams per mole (g/mol).

To calculate the volume of pentanol occupied by 7.455 moles of the substance, we can use the following formula:

Volume = (number of moles x molar mass) / density

The molar mass of pentanol (C3H8O) can be calculated as:

3 x atomic mass of carbon (12.01 g/mol) = 36.03 g/mol 8 x atomic mass of hydrogen (1.01 g/mol) = 8.08 g/mol 1 x atomic mass of oxygen (16.00 g/mol) = 16.00 g/mol Total molar mass = 60.11 g/mol

Placing the given values into the formula, we get:

Volume = (7.455 mol x 60.11 g/mol) / 0.8110 g/mL Volume = 553.5 mL or 0.5535 L

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Answer:

B)

Explanation:

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Answer:

( : The correct option is, (a) anode

Explanation:

Answer:

1.5

Explanation:

From;

BO = ½(B – A)

BO= Bond order

B= Number of bonding electrons

A = Number of antibonding electrons

For the sigma bonds, there are 2 bonding electrons and 0 nonbonding electrons.

σ BO = ½(B – A) = ½(2 – 0) = 1

π bond order for 6 C-C bonds;

π BO = ½(B – A) = ½(6 – 0) = 3

For each  π bond, BO = 3/6 = 0.5.

Hence, for a single C-C bond in benzene, the total Bond order = σ + π = 1 + 0.5 = 1.5.

Answer:

Case 1 (energy level): In an atom, an electron jumps from energy level 1 to energy level 3. ... The energy will increase.

Explanation:

Answer:

Limiting reactant: Cl2.

Max mass of PCl3 = 41.44 g.

P4 leftover = 5.51 g.

Explanation:

Hello!

In this case, since the undergoing chemical reaction is:

[tex]P_4+6Cl_2\rightarrow 4PCl_3[/tex]

In order to compute the maximum amount of PCl3, it is necessary to compute the grams of this product produced by each reactant, just as shown below, whereas molar masses and mole ratios are used:

[tex]m_{PCl_3}^{by\ P_4}=14.3gP_4*\frac{1molP_4}{123.89gP_4} *\frac{4molPCl_3}{1molP_4} *\frac{137.33gPCl_3}{1molPCl_3} =63.41gPCl_3\\\\m_{PCl_3}^{by\ Cl_2}=32.1gCl_2*\frac{1molCl_2}{70.91gCl_2} *\frac{4molPCl_3}{6molCl_2} *\frac{137.33gPCl_3}{1molPCl_3} =41.44gPCl_3[/tex]

Thus, since chlorine gas yields fewer grams of PCl3 than P4 we infer Cl2 is the limiting reactant and 63.41 grams of PCl3 product are yielded.

Finally, for the excess reactant, we see a difference of 63.41-41.44=21.97g, so we can compute of the leftover of P4 as follows:

[tex]m_{P_4}^{leftover}=21.97gPCl_3*\frac{1molPCl_3}{137gPCl_3} *\frac{1molP_4}{4molPCl_3} *\frac{137.33gP_4}{1molP_4} =5.5gP_4[/tex]

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Answer:

C₁₅N₃H₁₅

Explanation:

Follow the sequence ...

%/100wt => grams/100wt => moles => mole ratio => reduce mole ratio (divide by smaller mole value) => empirical ratio.

Note: If the above calculation comes out with a fraction (for most textbook problems) do the following:

--.25 => multiply empirical ratio by 4

--.50 => multiply empirical ratio by 2

--.75 => multiply empirical ratio by 4

Or, if initial data is given in grams, convert to %/100wt. (example at end of problem)

This Problem:  

         %/100wt.   grams         moles =mass/formula wt.

%C = 75.95% => 75.95g => 75.95g/12.0107g·mol⁻¹ = 6.325 mole OS

%N = 17.72% =>  17.72g => 17.72g/14.0067g·mol⁻¹ = 1.2651 mole N  

%H =  6.33% =>   6.33g =>  6.33g/1.00794g·mol⁻¹ = 6.28 mol H              

(∑  =   100%    | assume 100g cpd  => ( grams => 100g compound would contain 75.95g C, 17.72g N & 6.33g H )

=> mole ratio =>  C : N : H => 6.3235 : 1.2651 : 6.28  

=> reduce mole ratio ( divide by smaller mole value ) ...

=> 6.3235/1.2651 : 1.2651/1.2651 : 6.28/1.2651 =>  empirical ratio is => 5:1:5

empirical formula => C₅NH₅

empirical formula wt. = 5C + 1N + 5H = 5(12) + 1(14) + 5(1) = 79

=> molecular ratio (n) => molecular wt (given) = N · empirical formula wt

=> N =  molecular wt / empirical wt = 240/79 = 3

∴ Molecular Formula is =>  C₅NH₅ X 3 => C₁₅N₃H₁₅

________________________________________

EXAMPLE: Empirical Formula Problem with initial data in grams:

Assume an oxide of Osmium (compd wt) = 2.89 grams contains 2.16 gram Osmium, what is the empirical formula?

Use given mass values to calculate %/100wt then use the sequence

% => grams => moles => reduce => emp. ratio => emp. formula

%Os = 2.16g/2.89g x 100% = 74.74%

%Oxy = [(2.89g -2.16g)/2.89] x 100% = 25.26% or use 100% - 74.74% = 25.26%

%  => g => moles => reduce => emp formula

%Os   = 74.74% => 74.74g => 74.74g/190.23g·mol⁻¹ = 0.3929 mol Os

%Oxy = 25.26% => 25.26g => 25.26g/16g·mol⁻¹ = 1.5788 mole Oxy

Reduce mole ratio (divide by smaller mole value) => empirical ratioo

=> Os:Oxy => 0.3929/0.3929 : 1.5788/0.3929 = 1 : 4

=> Empirical Formula => OsO₄

Answer:

She's right that there's a difference, and you are right that it's all just electromagnetic waves!

The key to this is that there is no such thing as "white light" when you really get down to it. Each light emits a range of wavelengths of light. If they have a sufficiently even distribution of wavelengths, we tend to call that light "white," but we can only use that term informally.

Both the sun and the light bulb emit so-called "Blackbody radiation." This is the particular spectrum of light that's associated with the random thermal emissions of a hot object. Cool objects tend to emit more of their energy in the longer wavelengths like reds and IRs, while hotter objects emit more energy in the shorter wavelengths like blues and UV.

Blackbody graphic

(Note, there are other possible emission spectra, but those are associated with different materials doing the emissions and, for the purposes of this discussion, they aren't too important. We can just claim the emissions are all blackbody)

If you notice, as you get hotter, a larger portion of the energy is emitted in the blue, violet, and ultraviolet. That's how you get a sunburn from the sun. It's harder to get a sunburn from an artificial light, not because it's artificial, but because those lights are almost always cooler than the sun. They don't have as much UV content. Instead, they have more red and yellow, which incidentally is why pictures taken indoors look very yellow. If you use a strobe, however, all those yellow hues go away because a strobe light is very warm, with lots of blues.

You can get a sunburn from artificial light, of course. Tanning beds are the obvious example, but there are other interesting ones. When you're a jeweler working in platinum, for instance, you need to wear UV protective gear (like glasses or even sunscreen). Platinum's melting point is so hot that it actually emits quite a lot of UV light and can give you a sunburn!

Other than these spectra, there is nothing different between light from an artificial source and light from the sun. Photons are photons.

Explanation:

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Answer:

No.2, No.3 and No.4 answers are same. Give the options properly.

Answer:

C. From the air in the stratosphere

Explanation:

I hope it will help

Answer:

The composition of the objects because not all the planets have been explored

Answer:

because all chemical reaction involve the rearrangement of atoms, the mass is an electron is negatively charged, it has a mass approximately 1/2000 that of a, Atoms of an element that contain the same number of protons but a different Copy and complete the following tables concerning the isotopes of silicon SI-28.

Explanation:

Answer:

the answer is A

Explanation: