Write the equation of the ellipse with a center at (5,-2), one vertex at (2, -2) and a focus at
(5+ √5,-2)

Answer:

yes

Step-by-step explanation:

The function for position x(t) could be x(t) = 3t^2 - 2t + 10.

In mathematics, a function is a relation between two sets that assigns to each element of the first set exactly one element of the second set. In other words, it is a rule that describes how one set of values is related to another set of values. Functions are used to model real-world scenarios and to solve mathematical problems. Examples of functions include linear equations, polynomials, and trigonometric functions.

This is determined by using the equation x'(t) = a(t). Differentiating both sides of the equation, we get x'(t) = 6t - 2. Integrating this equation, we get x(t) = 3t^2 - 2t + C, where C is the constant of integration. Since x(1) = 10, we can substitute this value into the equation and solve for the constant of integration. Therefore, we get x(t) = 3t^2 - 2t + 10.

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[tex]~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] ~\dotfill[/tex]

[tex](-6x^3 y^5 + 11x^3 y^2) \div (-2x^2 y^3)\implies \cfrac{-6x^3 y^5 + 11x^3 y^2}{-2x^2 y^3} \\\\\\ \cfrac{-6x^3 y^5}{-2x^2 y^3}+\cfrac{11x^3 y^2}{-2x^2 y^3}\implies \cfrac{-6}{-2}\cdot \cfrac{x^3 y^5}{x^2 y^3}+\cfrac{11}{-2}\cdot \cfrac{x^3 y^2}{x^2 y^3} \\\\\\ 3\cdot x^3 x^{-2}y^5 y^{-3}+\cfrac{11}{-2}\cdot \cfrac{x^3 x^{-2}}{y^3 y^{-2}}\implies 3x^{3-2}y^{5-3}-\cfrac{11}{2}\cdot \cfrac{x^{3-2}}{y^{3-2}} \\\\\\ ~\hfill {\Large \begin{array}{llll} 3x y^2 -\cfrac{11x}{2y} \end{array}}~\hfill[/tex]

20 beacuse you need hiking boots to hike

Answer:

25

Step-by-step explanation:

let x = # of participants on the hike

(.80)x = 20

x = 20/0.80 = 25

The wrist circumference in relation to height tells us how big our body frames are.

The wrist circumference in relation to height tells us how big our body frames are. A man who is above 5' 5" tall and with a wrist measurement of 6" would be considered to have tiny bones.

The following chart can be used to establish whether a person has tiny, medium, or large bones by measuring their wrist with a measuring tape and comparing the results.

Women:

under 5'2" in height"

Medium wrist size is between5.5" and5.75" Small wrist size is less than5.5" "

Large is defined as a wrist size of 5.75 or greater."

between 5'2" and 5'5" tall

smaller than 6 inches around the wrist"

Bracelet size 6 is medium "Medium = wrist size between 6.25" and 6.5" Large

Over 5' 5" in height"

Small wrists measure less than 6.25", Medium wrists measure 6.25" to 6.5," and Large wrists measure over 6.5."

Example :

2(x + 3 ) + 2 (x + 4 ) = (x + 3 )( x + 4)

x² + 7x + 12 = 4x + 14

x² + 3x - 2 = 0

(x + 3 / 2 )² = 17 / 4.

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The line passes through the point (-10,1) and has a slope of 3/20 has the equation as: y - 1 = 3/2 (x + 10)

The general form of a linear equation is y - y₁ = m (x - x₁).

It draws attention to the line's slope and one of the line's points (that is not the y-intercept)

The point slope formula is given by y - y₁ = m (x - x₁), where:

y = output value

y₁= the given y coordinate point

m = slope

x = input value

x₁ = the given x coordinate

substituting the point (-10,1) and slope 3/2

y - y₁ = m (x - x₁)

y - 1 = 3/2 (x + 10)

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Answer:

1-3 y

Step-by-step explanation:

Subtract the numbers 4 AND 3 WHICH WOULD EQUAL REWRITING THE ADDITON SO IT CHANGES THE MINUS SIGN TO A PLUS.

Answer:

(0,-4),(1,1)(2,6)

Step-by-step explanation:

Answer:

24 miles

Step-by-step explanation:

each distance between points is 6.

6+6+6+6=24 miles

Answer: The origins of matrices can be traced back to the 18th century, with the work of mathematicians such as Gabriel Cramer, Leonhard Euler, and Joseph-Louis Lagrange. These mathematicians developed the idea of using arrays of numbers to represent systems of linear equations, which led to the development of the concept of matrices.

The term "matrix" itself was first used by James Joseph Sylvester in 1850, although it had been in use informally for some time before then. In 1858, the English mathematician Arthur Cayley first published a systematic theory of matrices, which further developed the field.

Matrix theory was primarily used in the early days to solve systems of linear equations, but it soon found applications in areas such as linear algebra, multivariate statistics, and even quantum mechanics.

In summary, the origins of matrices can be traced back to the 18th century as an idea to represent systems of linear equations, which developed over time with contributions of many mathematicians over the centuries, and now it plays an important role in many field of mathematics and science.

Step-by-step explanation:

Answer:

Domain is all real numbers (basically any number)

Step-by-step explanation:

Step 1: Simplify the expression first

y = 2(x+1)-(3x-2)

y = 2x + 2 -3x + 2

y = -x + 4

Step 2: Observe the graph

y = -x + 4 is simply a linear graph with a negative fixed gradient of -1, with a y-intercept of 4.

Step 3: Identify the domain

For linear graphs, domain is all real numbers.

(No restrictions on the graph according to question)

Therefore exact coordinates of Centroid  = (0,3/2)

The centroid of a flat figure or solid figure, also known as the geometric center or center of figure, in mathematics and physics, is the arithmetic mean position of all the points on the figure's surface. Any n-dimensional Euclidean object is included by the same definition.

A polygon having three edges and three vertices is called a triangle. It is one of the fundamental geometric forms. Triangle ABC is the designation for a triangle with vertices A, B, and C. In Euclidean geometry, any three points that are not collinear produce a distinct triangle and a distinct plane.

This region is a parabola opening downward, with vertex at (0, 49) and a range of y values from 0 to 49. The region is symmetric about the y-axis, This means that the x-coordinate of the centroid is at 0.

To find the y-coordinate:

Integral from -√(49) to √(49) of (49-x²) x dx = [x²(49-x²)/3] from -√(49) to √(49) = (492√(49))/3 = (98√(49))/3

The area is integral from -√(49) to √(49) of (49-x²) dx = [x(49-x²)/2] from -√(49) to √(49) = (49*(2√(49)) - (2/3)(49^(3/2)))/2 = (49*(2*√(49)) - (98√(49))/3)/2

Therefore Centroid = (0, (98√(49))/(49*(2*√(49)) - (98√(49))/3)) = (0,3/2)

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Joey needs to score more than 540 points, to be higher than

70th percentile of all scores.

Percentile is defined as the value below which a given percentage falls under.  

Example: In a group of 20 children, Ben is the 4th tallest and 80% of the children are shorter than you. Hence, it means that Ben is at the 80th percentile.

The percentile formula determines the performance of a person over others. The percentile formula is used in finding where a student stands in the test compared to other candidates. A percentile is a number where a certain percentage of scores fall below the given number.

Given,

Scores of first 9 players:

230, 540, 420, 430, 540, 560, 275, 50, 250

let the score of joey be x.

Scores of all 10 players

230, 540, 420, 430, 540, 560, 275, 50, 250

Dataset in ascending order =

50, 230, 250, 275, 420, 430, 540, 540, 560

70th percentile of the dataset

k = 70

i = the index

n = total number of given data values = 10

i = k/100(n+1)

i = 70/100 (9+1)

i = 70 × 10/100

i = 7

The index of 70th percentile = 7

value of 70th percentile = value of data on index 7.

value of 70th percentile = 540.

Hence, To be higher than 70th percentile of all scores,

Joey should score more than 540.

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Therefore , (1, 3), (2, 5), (3, 7) (4, 9) and (1, 3), (2, 3), (3, 3) (4, 3) are the relations that represent a function.  

According to a function's rule, every x value in the domain has one and only one range of y values. Definition. A one-to-one function exists when there is just one and only one value of x such that f(x) = y.

Here,

The relationship is (1, 3), (2, 5), and (2, 7) (4, 9)

Given that 2 is repeated, the connection is not a function.

The relationship is (1, 3), (2, 5), and (3, 7) (4, 9)

Since there are no repeating numbers, the relation is a function.

The relationship stated is (1, 3), (1, 5), and (1, 7). (4, 9)

The relationship is not a 1 repeated function.

The relationships are (1, 3), (2, 3), and (3, 3). (4, 3)

Since there are no repeating numbers, the relation is a function.

The relationship stated is (1, 2), (2, 5), and (2, 1) (4, 5)

As 2 repeated, the relationship is not a function.

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The following statements are true based on the diagram below

When two or more curves, lines, or edges come together, it is called a vertex (plural: vertices or vertexes) in geometry. As a result of this definition, polygonal and polyhedral corners as well as the intersection of two lines to form an angle are referred to as vertices.

The vertex of an angle is the point at which two rays start or meet, where two line segments join or meet, where two lines intersect (cross), or any other suitable arrangement of rays, segments, and lines that results in two straight "sides" coming together at one location.

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Answer:

x = 14

Step-by-step explanation:

2(x + 4) = 3( -2 + x)  distribute the 2 and the 3.

2(x) + 2(4) = 3(-2) + 3(x)

2x + 8 = -6 + 3x  Subtract 2x from both sides

2x - 2x + 8 = -6 +3x -2x

8 = -6 +x  Add 6 to both sides

8 + 6 = 6 - 6 + x

14 = x

Answer: To determine which store has the cheaper steak, you need to compare the price per pound of steak at each store. To do this, divide the total price by the number of pounds of steak at each store.

At Store A, the price per pound of steak is $6.38 because 25.50 / 4 = <<25.50/4=6.375>>6.375.

At Store B, the price per pound of steak is $6.71 because 40.25 / 6 = <<40.25/6=6.708>>6.708.

Therefore, Store A is cheaper because it has a lower price per pound of steak. The correct answer is Store A.

Step-by-step explanation:

value of x for all solution is  49.11° or 50° and  230°

Before mastering trigonometry, you should have a working knowledge of algebra and geometry. You ought to be able to work with algebraic expressions and equations without any trouble. The Pythagorean theorem, similar triangles, and a few other concepts from geometry should be familiar to you, but not a lot.

7 cos(2x) = 7 cos² (x) - 4

7 cos² (x) - 7 (2cos² (x)-1)- 4=0

7 cos² (x)- 14 cos² (x)+7-4=0

cos² (x)= 3/7

range given from 0 to 360°.

x=49.11° or 50° and  230°

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The ordered pair (x, y) for the given line can be obtained from the graph as (-4, 1).

A straight line can be written in the form of an equation as, y = mx + c.

Two straight lines intersect each other only at one point.

When two straight lines are parallel to each other the angle between them is zero.

The graph of the line is given.

In order to find the coordinate of a point do as follows,

Draw a perpendicular line from any point on the line to the x-axis.

The intersection of this line with the x-axis will give the x-coordinate.

Similarly, find the y-coordinate by drawing a perpendicular line to the y-axis.

Applying the above procedure, a point is obtained as (-4, 1).

Hence, the ordered pair for the line shown in the graph is (-4, 1).

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Answer:

Below

Step-by-step explanation:

1+2+3+4+5 =15       5 lengths will require   4 cuts

(a) As of the Cartesian vector approach, Moment about axes are [tex]M_x = 13\ Ft-lb[/tex], [tex]M_y = 4\ Ft-lb[/tex] and [tex]M_z = 36\ Ft-lb[/tex].

(b) Using a scalar approach, Moment about axes are [tex]M_x = 13\ Ft-lb[/tex], [tex]M_y = 4\ Ft-lb[/tex] and [tex]M_z = 36\ Ft-lb[/tex].

Vector is defined as the quantities that have both magnitude and direction is called a vector quantity and the nature of the quantity is called a vector.  

here,
[tex]\vec F = 4 \hat i + 12\hat j -3 \hat k\\ \vec B = 4 \hat i + 3\hat j - 2 \hat k\\[/tex]

Scalar approach,
moment about the x-axis is given by,
[tex]M_x = B_yF_z - ZF_y\\M_x = 3(-3)-(-2)(12)\\M_x = 13\ Ft-lb[/tex]

Similarly,
[tex]M_y = 4\ Ft-lb,[/tex] and [tex]M_z = 36\ Ft-lb[/tex]

Vector approach,
Moment about the x-axis is given by,
[tex]M_x = U_x \times[ {\vec B \times \vec F]}\\M_x = \left[\begin{array}{ccc}1&0&0\\4&3&-2\\4&12&-3\end{array}\right][/tex]

The above expression given is of determinate, when solving the above determinate,
[tex]M_x = 13\ Ft-lb[/tex]

Similarly,
[tex]M_y = 4\ Ft-lb[/tex] and [tex]M_z = 36\ Ft-lb[/tex],

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The image for P(9, 1.5) after Translation is P'( 12, 1).

Each point in a figure is moved the same distance in the same direction using a type of transformation known as translation.

For example, this transformation moves the parallelogram to the right 5 units and up 3 units. It is written ( x , y ) → ( x + 5 , y + 3 ) .

Given:

P(9, 1.5) with Translating Vector (3, -0.5).

So, Applying the Translation we get

P(9 + 3, 1.5 + (-0.5))

= P(12 , 1.5- 0.5)

= P(12, 1)

hence, the image is P'( 12, 1).

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Answer: a) The control in the experiment, 0 kHz, or no sound, serves as a baseline against which to compare the other treatments. By using the control with no sound, researchers can determine whether the deer's response to the sound-emitting devices is due to the sound itself or some other factor. Without the control, it would be unclear what caused any differences in the deer's responses to the different sound treatments.

(b)(i) One advantage to keeping the loudness at a constant 60 decibels for all treatments is that it allows researchers to directly compare the deer's responses to the different sound pitches without the added variable of loudness.

(b)(ii) One disadvantage to keeping the loudness at a constant 60 decibels for all treatments is that loudness may also play a role in deer's response. So, it would be unclear if the different in deer's responses are due to sound frequency only or also caused by sound loudness

(c) Based on the results shown in the bar chart, it can be seen that the deer's response to the sound-emitting devices varies depending on the pitch of the sound. At lower pitches, around 0.28 kHz, the deer's response is more likely to be negative or neutral, indicating that they move away from or don't move towards the highway. At higher pitches, around 15 kHz, the deer's response is more likely to be positive, indicating that they move towards the highway. It suggests that the frequency of sound has an impact on the deer's response. So, based on this data, we cannot recommend using a sound-emitting device to keep deer from running across highways without further research on the optimal frequency and loudness that should be used to make sure that it is effective and safe for the deer.

Step-by-step explanation:

The sound-emitting device may have both advantages and disadvantages depending on the pitch. More research is necessary to find the optimal frequency and volume for the device to be effective and safe.

Based on the results of the experiment, it would not be advisable to use a sound-emitting device to prevent deer from running across highways without further research. The experiment showed that the deer's response varied depending on the pitch of the sound. Although the device showed some advantages, such as moving deer away from the highway at lower pitches, it also presented potential disadvantages. At higher pitches, the deer had a tendency to move towards the highway, which could increase the risk of accidents. More research would be needed to determine the optimal frequency and volume to use for the device to be both effective and safe for the deer.

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Answer: A. U.S. Landmarks to European Landmarks

Maria has 25 U.S. landmark postcards and 20 European landmark postcards. The ratio of U.S. landmarks to European landmarks can be written as 25:20 or as 25/20.

Alternatively, we can express the ratio as a fraction. If we divide the number of U.S. landmark postcards by the total number of U.S. and European landmark postcards, we get 25/(25+20)=25/45

The last way we can express the ratio as a decimal. By dividing the number of U.S. landmark postcards by the total number of U.S. and European landmark postcards, we can find that the ratio of U.S. landmarks to European landmarks is 25/45 =0.555 or 55.5%

Step-by-step explanation:

Answer:

[tex] \sf \: b) \: 45[/tex]

Step-by-step explanation:

The values given are,

→ u = 7

→ d = 10

→ e = 3.2

Now the expression is,

→ 15(d - u)

Evaluating the expression,

→ 15(d - u)

→ 15(10 - 7)

→ 15 × 3

→ 45

Hence, option (b) is correct.

Answer:45

Step-by-step explanation:

15(10-7)

15(3)

multiply and get 45

Hello there!

Answer:

[tex](9, +\infty)[/tex]

Step-by-step explanation:

It has no real roots only if

[tex] \sqrt{b {}^{2} - 4ac } [/tex]

has no roots. That means that b² - 4ac is smaller than 0:

[tex]b {}^{2} - 4ac < 0 \\ 12 {}^{2} - 4 \times 4 \times k < 0 \\ 144 - 16k < 0 \\ 144 - 144 - 16k < - 144 \\ - 16k < - 144 \\ k > 9 \\ k \: \: \: in \: \: \: (9, +\infty)[/tex]

we can approach this from the standpoint of the discriminant, if the discriminant is negative then we only get complex roots or namely "imaginary" solutions or values, well, let's check before that happens, when the discriminant is 0.

[tex]\qquad \qquad \qquad \textit{discriminant of a quadratic} \\\\\\ y=\stackrel{\stackrel{a}{\downarrow }}{4}x^2\stackrel{\stackrel{b}{\downarrow }}{+12}x\stackrel{\stackrel{c}{\downarrow }}{+k} ~~~~~~~~ \stackrel{discriminant}{b^2-4ac}= \begin{cases} 0&\textit{one solution}\\ positive&\textit{two solutions}\\ negative&\textit{no solution} \end{cases}[/tex]

[tex]0=(12)^2 - 4(4)(k)\implies 0=144-16k\implies 16k=144 \\\\\\ k=\cfrac{144}{16}\implies k=9\hspace{5em} \stackrel{if~k > 9\textit{, then we land on negative territory}}{{\Large \begin{array}{llll} k > 9 \end{array}}}[/tex]

Answer: y^2+8x+12

Step-by-step explanation:

Answer:

31 hecause the èattern is adding 3

Step-by-step explanation:

The equilateral triangle ABC have a side length of 2 units of the radius length of the circle tangent to the line AB.

An equilateral triangle have all its side lengths equal so;

line AB = line BC = line AC

At points B and C where the lines AB and AC are tangent to the circle is the a side length BC of the equilateral triangle

Line BC form the diameter of the circle which is 2 radius of the circle so;

line BC = 2 × radius of the circle

line BC = 2 × 1

line BC = 2

Therefore, the side length of the equilateral triangle is 2 units of the radius of the circle tangent at point B and C.

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