We can be 95% confident that the true value of the regression coefficient for the first explanatory variable falls within the interval (7.69, 17.31).
To find the 95% confidence interval for the true value of the regression coefficient for the first explanatory variable, we can use the t-distribution with degrees of freedom equal to n - k - 1, where n is the sample size and k is the number of explanatory variables (including the intercept).
In this case, n = 66 and k = 5, so the degrees of freedom are 66 - 5 - 1 = 60. Since we want a 95% confidence interval, the significance level is α = 0.05, which means that we need to find the t-value that corresponds to a cumulative probability of 0.025 in the upper tail of the t-distribution.
Using a t-table or a statistical software, we can find that the t-value with 60 degrees of freedom and a cumulative probability of 0.025 in the upper tail is approximately 2.002.
Therefore, the 95% confidence interval for the true value of the regression coefficient for the first explanatory variable is given by:
estimate ± t-value × standard error
= 12.5 ± 2.002 × 2.4
= 12.5 ± 4.81
= (7.69, 17.31)
Thus, we can be 95% confident that the true value of the regression coefficient for the first explanatory variable falls within the interval (7.69, 17.31).
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For which interval(s) is the function increasing and decreasing? y=3x^3 -16x+2
Considering the critical points of the function, we have that:
The function is increasing for |x| > 1.63.The function is decreasing for |x| < 1.63.What are the critical points of a function?The critical points of a function are the values of x for which:
[tex]f^{\prime}(x) = 0[/tex]
In this problem, the function is:
[tex]f(x) = 3x^3 - 16x + 2[/tex]
The derivative is:
[tex]f^{\prime}{x} = 6x^2 - 16[/tex]
The critical points are given as follows:
[tex]6x^2 - 16 = 0[/tex]
[tex]x^2 = \frac{16}{6}[/tex]
[tex]x = \pm \sqrt{\frac{16}{6}}[/tex]
[tex]x = \pm 1.63[/tex]
For x < -1.63, one example of the derivative is:
[tex]f^{\prime}{-2} = 6(-2)^2 - 16 = 8[/tex]
Positive, hence increasing.
For -1.63 < x < 1.63, one example of the derivative is:
[tex]f^{\prime}{0} = 6(0)^2 - 16 = -16[/tex]
Negative, hence decreasing.
For x > 1.63, one example of the derivative is:
[tex]f^{\prime}{2} = 6(2)^2 - 16 = 8[/tex]
Positive, hence increasing.
Hence:
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The table gives the populations of three countries in 2013.
United States Brazil Germany
3.16 × 108 1.96 × 108 8.0 × 107
1) Difference of the populations of Germany and Brazil = 1.16 X 10^8
2) Difference of the populations of Brazil and the United States = 1.2 X 10^8
3) Sum of the populations of Brazil and Germany = 2.76 X 10^8
4) Sum of the populations of the United States and Brazil = 5.12 X 10^8
According to the statement
we have given that the populations of three countries which are
United States is 3.16 × 10^8 and Brazil is 1.96 × 10^8 and Germany is 8.0 × 10^7
And we have to arrange the sums and differences in increasing order of their values.
so, we have to find the
a) the difference of the populations of Germany and Brazil
So,
Difference of the populations of Germany and Brazil = 1.96 X 10^8 - 8 X 10^7 = 116000000 = 1.16 X 10^8
And then we have to find the
b) the sum of the populations of the United States and Brazil
So,
Sum of the populations of the United States and Brazil = 3.16 X 10^8 + 1.96 X 10^8 = 512000000 = 5.12 X 10^8
And then we have to find the
c) the difference of the populations of Brazil and the United States
So,
Difference of the populations of Brazil and the United States = 3.16 X 10^8 - 1.96 X 10^8 = 120000000 = 1.2 X 10^8
And then we have to find the
d) the sum of the populations of Brazil and Germany
So,
Sum of the populations of Brazil and Germany: 1.96 X 10^8 + 8 X 10^7 = 276000000 = 2.76 X 10^8
NOW, we arrange the sum and difference in increasing order of their values.
So,
1) Difference of the populations of Germany and Brazil = 1.16 X 10^8
2) Difference of the populations of Brazil and the United States = 1.2 X 10^8
3) Sum of the populations of Brazil and Germany = 2.76 X 10^8
4) Sum of the populations of the United States and Brazil = 5.12 X 10^8
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kathy uses a 1/2 cup of milk with every bowl of her favorite cereal if there are only 3 3/5 cups of milk left, then how many bowls of cereal would kathy have?
Taking a quotient, we will see that she can make 7 bowls of cereal (and some leftover milk).
How many bowls of cereal would kathy have?We know that for each bowl, she needs 1/2 cups of milk.
And we also know that she has a total of (3 + 3/5) cups of milk.
To know how many bowls she can make, we need to take the quotient between the total that she has and the amount that she needs for each bowl:
(3 + 3/5)/(1/2)
We can rewrite the total as:
3 + 3/5 = 15/5 + 3/5 = 18/5
Then the quotient becomes:
(18/5)/(1/2) = (18/5)*2 = 36/5 = 35/5 + 1/5 = 7 + 1/5
So she can make 7 bowls of cereal (and some leftover milk).
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Measure the angle shown below. a protractor showing an angle going through the tenth tick mark after ten degrees 15° 17° 20° 22°
The value of the angle will be C. 20°
How to calculate the angle?From the information given, it was stated that the protractor showed an angle going through the tenth tick mark after ten degrees.
This means the value of the angle will be:
= 10° + 10°
= 20°
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By use of technology, we investigated Mary’s investment and created the model, M(x) = 3.03(1.28)2x, in thousands of dollars. What was Mary’s initial investment? $4.96 $3,030 $4,960 $3.03
Using an exponential function, it is found that Mary's initial investment was of $3,030.
What is an exponential function?An exponential function is modeled by:
[tex]y = ab^x[/tex].
In which:
a is the initial value.b is the rate of change.Her investment model, in thousands of dollars, is:
[tex]M(x) = 3.03(1.28)^{2x}[/tex]
Then a = 3.03, since we measure the amount in thousands of dollars, Mary's initial investment was of $3,030.
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A sphere of radius 222 inches is cut by three planes passing through its center. This partitions the solid into 888 equal parts, one of which is shown above. The volume of each part is t\pitπt, pi cubic inches. What is the value of ttt?
The value of t based on the information about the sphere is 1.3π.
How to calculate the value?It should be noted that the volume of a sphere is 4/3πr³. In this case, it's divided into 8 equal parts.
Volume of each part = 1/8 × 4/3πr³
= 1/8 × 4/3 × π × 8
= 4/3π
= 1.3πin³
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Find a and k so that the given points lie on the parabola (An algebraic solution is required)
The value of a is -3 and the value of k is 10
A parabola is a U-shaped plane curve where any point is equidistant from a fixed point (known as the focus) and from a fixed line known as the directrix. The parabola is an integral part of the conic section topic
The section of a right circular cone by a plane parallel to the generator of the cone is a parabola. It is the location of a point that moves so that the distance from the fixed point (the focus) is equal to the distance from the fixed line (the directrix).
The fixed point is called the focus
A fixed line is called a directrix
Solving an algebraic equation is the process of finding a number or set of numbers that, when substituted for the variables in the equation, reduce them to an identity. Such a number is called the root of the equation
Here the equation y = a(x -2)^2 + k...........(1)
and two points A(1,7) and B(4, -2) is given
We need to find the value of a and k
Put A(1,7) in equation (1) , we get,
7 = a + k ,therefore k = 7 - a......(2)
Put B(4, -2) in equation (1), we get,
-2 = 4a + k........(3)
Put k= 7-a in (3)
-2 = 4a+7 -a
3a = -9
a= -3
From equation (2) , we get k = 7-(-3)= 10
Hence the value of k is 10 and the value of a is -3
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For the given points to lie on the parabola,
a = -3 and k = 10.
An equation of a curve that has a point on it that is equally spaced from a fixed point and a fixed line is referred to as a parabola. The parabola's fixed line and fixed point are together referred to as the directrix and focus, respectively. It's also crucial to remember that the fixed point is not located on the fixed line. A parabola is a locus of any point that is equally distant from a given point (focus) and a certain line (directrix).
According to the question,
Equation of parabola : y = a[tex](x-2)^{2}[/tex] + k
Points A(1,7) and B(4,-2)
For the points to lie on the parabola,
7 = a[tex](1-2)^{2}[/tex]+k
7 = a + k
Similarly,
-2 = a[tex](4-2)^{2}[/tex] + k
-2 = 4a + k
On solving the two equations simultaneously, we get,
a = -3
k = 10
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A rectangle room has a perimeter of 70m.what would be the length of the longest side of the room?
Answer:
The longest side of room is 24m
The width of a rectangle is 4 less than twice its length. if the area of the rectangle is 75 cm 2 , what is the length of the diagonal?
Answer:
Step-by-step explanation:
A manufacturer produces a commodity where the length of the commodity has approximately normal distribution with a mean of 6.5 inches and standard deviation of 0.5 inches. If a sample of 46 items are chosen at random, what is the probability the sample's mean length is greater than 6.3 inches? Round answer to four decimal places.
The probablity that the sample's mean length is greate than 6.3 inches is0.8446.
Given mean of 6.5 inches,standard deviation of 0.5 inches and sample size of 46.
We have to calculate the probability that the sample's mean length is greater than 6.3 inches is 0.8446.
Probability is the likeliness of happening an event. It lies between 0 and 1.
Probability is the number of items divided by the total number of items.
We have to use z statistic in this question because the sample size is greater than 30.
μ=6.5
σ=0.5
n=46
z=X-μ/σ
where μ is mean and
σ is standard deviation.
First we have to find the p value from 6.3 to 6.5 and then we have to add 0.5 to it to find the required probability.
z=6.3-6.5/0.5
=-0.2/0.5
=-0.4
p value from z table is 0.3446
Probability that the mean length is greater than 6.3inches is 0.3446+0.5=0.8446.
Hence the probability that the mean length is greater than 6.3 inches is 0.8446.
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Determine the missing digit (denoted with*) for the American Express Traveler's Check identification number 783920*814 a) 3
b) 2
c) 6
d) 9
The missing digit for the American Express Traveler's Check identification number is option (C) 6 is the correct answer.
In this question,
A Check Digit is a decimal (or alphanumeric) digit added to a number for the purpose of detecting the sorts of errors humans typically make on data entry.
A check digit is a digit added to a string of numbers for error detection purposes. Normally, the check digit is computed from the other digits in the string. A check digit helps digital systems detect changes when data is transferred from transmitter to receiver.
The last digit of a bar code number is a calculated check digit. The check digit is calculated from all the other numbers in the bar code and helps to confirm the integrity of your bar code number.
The American Express Traveler's Check identification number is 783920*814.
In Airline tickets, there are several digits plus a check digit.
Divide the ID number by 7. The check digit is the remainder.
Sum of digits = 7+8+3+9+2+0+8+1+4
⇒ 42
Now divide the sum by 7, the remainder is
⇒ 42 mod 7 = 42 - (5×7)
⇒ 42 mod 7 = 6
Hence we can conclude that the missing digit for the American Express Traveler's Check identification number is option (C) 6 is the correct answer.
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The ________ could be used to describe a data set by itself, while ___________ would almost never be used to describe a data set by itself.
The mean could be used to describe a data set by itself, while interquartile range would almost never be used to describe a data set by itself.
Brief Description of Mean and Interquartile Range
While interquartile range only assesses the middle half of the data, mean and range deal with the entire set of data. The mean is significant in statistics because it helps us determine where a dataset's "center" is. The mean contains information from each observation in a dataset as a result of how it is calculated.
The interquartile range in descriptive statistics reveals the spread of your distribution's middle half. Any distribution that is sorted from low to high is divided into four equal portions using quartiles. The second and third quartiles, or the center half of your data set, are contained in the interquartile range (IQR).
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Celia uses the steps below to solve the equation Negative StartFraction 3 over 8 EndFraction (negative 8 minus 16 d) + 2 d = 24.
Step 1 Distribute Negative StartFraction 3 over 8 EndFraction over the expression in parentheses.
3 minus 16 d + 2 d = 24
Step 2 Simplify like terms.
3 minus 14 d = 24
Step 3 Subtract 3 from both sides of the equation.
Negative 14 d = 21
Step 4 Divide both sides of the equation by –14.
d = StartFraction 21 over negative 14 EndFraction = Negative three-halves = negative 1 and one-half
Which corrects the error in the step in which Celia made the first error?
In step 1, she should have also distributed Negative StartFraction 3 over 8 EndFraction over 2d, to get 3 minus 16 d + (negative three-fourths d) = 24.
In step 1, she should have also distributed Negative StartFraction 3 over 8 EndFraction over –16d, to get 3 + 6 d + 2 d = 24.
In step 3, she should have added 3 to both sides of the equation to get Negative 14 d = 27.
In step 3, she should have first divided both sides by –14 to get 3 + d = 24
The error in the steps is that In step 1, she should have also distributed -3/8 over –16d, to get 3 + 6 d + 2 d = 24
Simplifying linear equationsGiven the following equation as shown below
-3/8(-8-16d)+2d = 24
Step 1 Distribute -3/8 over the expression in parentheses
3 + 6d + 2d = 24
Simply the like terms
3 + 8d = 24
Subtract 3 from both sides of the equation.
8d = 24 - 3
8d = 21
d = 21/8
Hence the error in the steps is that In step 1, she should have also distributed -3/8 over –16d, to get 3 + 6 d + 2 d = 24
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2. A high-speed train travels at a speed of 200 km/h. If the train sets off from Station A at 12 24 and reaches Station B at 14 12, find the distance between the two stations, giving your answer in metres.
The distance between the two stations is 360km.
What is speed?Speed is the rate of change of distance.
Rate is a measure of one quantity against another in this case distance and time.
Analysis:
time at station A = 12:24
time at station B = 14:12
time spent = 14:12 - 12:24 = 1 hour 48 minutes = convert 48 minutes to hour
we divide 48 by 60 = 0.8
Total time = 1.8 hours
Distance = speed x time = 200 x 1.8 = 360 km
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In the figure below, O is the center of the circle. Name a diameter of the circle.
The diameter of circle O in the image given is: AB.
What is the Diameter of a Circle?The diameter of a circle can be referred to as the largest chord in a circle which is the line segment that passes through the center of a circle with both ends on the circle.
In the image given, AB is the largest chord and also passes through the center of the circle, O.
Thus, the diameter is: AB.
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write 158/4 as a mixed number in simplest terms. thank you :)
158/4 as a mixed number in the simplest term is [tex]39\frac{3}{4}[/tex]
Converting improper fractions to mixed numberThe given fraction is 158/4
The number of times that 158 can be divided by 4 = 39
4 x 39 = 156
The remainder = 159 - 156
The remainder = 3
The mixed number is of the form:
[tex]Quotient\frac{Remaider}{Divisor}[/tex]
Therefore, the mixed number is [tex]39\frac{3}{4}[/tex]
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Solve for x:
[tex] \frak{2 ( 3x + 1 ) + 3 ( 5x + 2 ) = x - 1}[/tex]
[tex] \\ \\ \\ [/tex]
Thank uh -,-
[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]
[tex]\qquad❖ \: \sf \:x = - \dfrac{ 9}{20} [/tex]
[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]
[tex]\qquad❖ \: \sf \:2(3x + 1) + 3(5x + 2) = x - 1[/tex]
[tex]\qquad❖ \: \sf \:6x + 2 + 15x + 6 = x - 1[/tex]
[tex]\qquad❖ \: \sf \:(6x + 15x - x) + (2 + 6 + 1) = 0[/tex]
[tex]\qquad❖ \: \sf \:20x + 9 = 0[/tex]
[tex]\qquad❖ \: \sf \:20x = - 9[/tex]
[tex] \qquad \large \sf {Conclusion} : [/tex]
[tex]\qquad❖ \: \sf \:x =- \cfrac{ 9}{20} [/tex]
[tex]\huge\underline{\red{A}\green{n}\blue{s}\purple{w}\pink{e}\orange{r} →}[/tex]
x = –9/20Step-by-step explanation:
________________________________
→ 2(3x + 1) + 3(5x + 2) = x – 1
→ 6x + 2 + 15x + 6 = x – 1
→ 21x + 8 = x – 1
→ 21x – x = – 1 – 8
→ 20x = – 9
→ x = –9/20
________________________________
Hope it helps you :')PLEASE HELP I HAVE AN HOUR LEFT!!
Which statement correctly identifies an asymptote of g (x) = StartFraction 42 x cubed minus 15 Over 7 x cubed minus 4 x squared minus 3 EndFraction using limits?
Limit of g (x) as x approaches plus-or-minus infinity= 5, so g(x) has an asymptote at x = 5.
Limit of g (x) as x approaches plus-or-minus infinity= 6, so g(x) has an asymptote at x = 6.
Limit of g (x) as x approaches plus-or-minus infinity= 5, so g(x) has an asymptote at y = 5.
Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.
The statement that correctly describes the horizontal asymptote of g(x) is:
Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.
What are the asymptotes of a function f(x)?The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.The horizontal asymptote is the limit of f(x) as x goes to infinity, as long as this value is different of infinity.In this problem, the function is:
[tex]g(x) = \frac{42x^3 - 15}{7x^3 - 4x^2 - 3}[/tex]
The horizontal asymptote is given as follows:
[tex]y = \lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} \frac{42x^3 - 15}{7x^3 - 4x^2 - 3} = \lim_{x \rightarrow \infty} \frac{42x^3}{7x^3} = \lim_{x \rightarrow \infty} 6 = 6[/tex]
Hence the correct statement is:
Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.
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Solve the quadratic equation numerically (using tables of x- and y- values). x(x + 6) = 0 a. x = -1 or x = 3 c. x = 0 or x = -3 b. x = 0 or x = 6 d. x =0 or x = -6
Answer:
d. x =0 or x = -6
Step-by-step explanation:
x(x + 6) = 0
This is telling us that either x is 0 or x is -6, because:
1) when x = 0, 0*(0+6)=0, and
2) when x = -6, -6*(-6+6) = 0; -6(0) = 0
Evaluate 5 - 3(a3 – b2)2 when a = 3 and b = 5.
Answer:
Step-by-step explanation:
Evaluate 5 - 3(a3 – b2)2 when a = 3 and b = 5.
5 - 3 × (a³-b²)² a=3 and b=5
5 - 3 × (3³ - 5²)² =
5 - 3 × (27 - 25)² =
5 - 3 × (2)² =
5 - 3 × 4 =
5 - 12 =
-7
Jim jogged from his house to the gym at 15 km/hr. On the trip home on the same route he walked at 10 km/hr. Together the two trips took him two hours. What is the distance from his home to to the gym
The distance from Jim's home to the gym is 12 km.
What is Speed?Speed is defined as the rate at which the position of object is changed.
Speed = Distance / Time
Here, there are two different speeds given for the same distance.
Average speed is the total distance travelled by the total time taken.
If distance is a constant,
Average speed = 2xy / (x + y), where x and y are two different speeds for the same distance.
Average speed = (2 × 15 × 10) / (15 + 10)
= 12 km/hr
So, Total distance travelled = Average speed × total time taken
= 12 × 2
= 24
Distance = 24 / 2 = 12
Hence, the distance from Jim's home to the gym is 12 km when average speed is taken.
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There are 86,400, frames of animation in 1 hour of anime.
How many frames are there per second?
There are 3,600, seconds in 1 hour.
Answer:
There are 24 frames of animation in 1 second of anime. Step-by-step explanation: There are 60 seconds in 1 minute, and 60 minutes in 1 hour. 60×60=3600, so there are 3600 seconds in 1 hour.Since 3600 seconds and 1 hour is the same, there are 86400 frames of animation in 3600 seconds of anime. To find out how many frames are in one second of anime, divide 86400 by 3600.86400 ÷ 3600 = 24There are 24 frames of animation in 1 second of anime.
The square of y varies directly as the cube of x. when x = 4, y = 2. which equation can be used to find other combinations of x and y?
The equation can be used to find other combinations of x and y is y^2 = (1/16)x^3
How to determine the equation?The direct variation from the square of y to the cube of x is represented as:
y^2 = kx^3
Where k represents the variation constant.
When x = 4, y = 2.
So, we have:
2^2 = k * 4^3
This gives
4 = 64k
Divide both sides by 64
k = 1/16
Substitute k = 1/16 in y^2 = kx^3
y^2 = (1/16)x^3
Hence, the equation can be used to find other combinations of x and y is y^2 = (1/16)x^3
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Choose the correct simplification of the expression ( expression in photo! )
A. G^7h
B. G^3h
C. G^7h^7
D. G^3/h^7
Use the rules of exponents to simplify the expression.
[tex]\large\displaystyle\text{$\begin{gathered}\sf \frac{g^{5}h^{4} }{g^{2}h^{3} } \end{gathered}$}[/tex]
To divide powers with the same base, subtract the exponent in the denominator from the exponent in the numerator.
[tex]\large\displaystyle\text{$\begin{gathered}\sf g^{5-2}h^{4-3} \end{gathered}$}[/tex]Subtract 2 from 5.
[tex]\large\displaystyle\text{$\begin{gathered}\sf g^{3 }h^{3-2} \end{gathered}$}[/tex]Subtract 3 from 4.
[tex]\large\displaystyle\text{$\begin{gathered}\sf g^{3 }h^{1} \end{gathered}$}[/tex]For any term t, t¹ =t.
[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf g^{3}h \end{gathered}$} }[/tex]Therefore, the correct option is "B".
Use cylindrical or spherical coordinates, whichever seems more appropriate. Evaluate z dV E , where E lies above the paraboloid z
The resulted integral is [tex]I=\frac{8}{3} \times \frac{5 \pi}{16}=\frac{5 \pi}{6}[/tex].
What is integrals?In mathematics, an integral is either a number representing the region under a function's graph for a certain interval or just an added to the initial, the derivative of which is initial function (indefinite integral).
Computation of the integrals:
Step 1: We employ the equations in cylindrical coordinates.
[tex]x=r \cos \theta, y=r \sin \theta, z=z[/tex]
Thus, in cylindrical coordinate system,
E lies above the paraboloid [tex]z=r^{2}[/tex] and below the plane [tex]z=2 r \sin \theta[/tex] .
Therefore, the top part E is [tex]z=2 r \sin \theta[/tex] is the cross-section between paraboloid and the plane.
Now, at the cross-section use, [tex]r^{2}=2 r \sin \theta[/tex] and [tex]z=2 r \sin \theta[/tex] .
Thus, the limits are given as ;
[tex]r^{2} \leq z \leq 2 r \sin \theta \quad 0 \leq r \leq 2 \sin \theta[/tex]
Apply the limits as compute the integration;
[tex]\begin{aligned}I=\iiint_{E} z d V &=\int_{0}^{\pi} \int_{0}^{2 \sin \theta} \int_{\tau^{2}}^{2 r \sin \theta} z r d r d z d \theta \\&=\int_{0}^{\pi} \int_{0}^{2 \sin \theta}\left[\frac{z^{2}}{2}\right]_{r^{2}}^{2 r \sin \theta} r d r d \theta \\&=\frac{1}{2} \int_{0}^{\pi} \int_{0}^{2 \sin \theta}\left[4 r^{2} \sin ^{2} \theta-r^{4}\right] r d r d \theta\end{aligned}[/tex]
[tex]\begin{aligned}&=\frac{1}{2} \int_{0}^{\pi} \int_{0}^{2 \sin \theta}\left[4 r^{3} \sin ^{2} \theta-r^{5}\right] d r d \theta \\&=\frac{1}{2} \int_{0}^{\pi}\left[r^{4} \sin ^{2} \theta-\frac{r^{6}}{6}\right]_{0}^{2 \sin \theta} d \theta \\&=\frac{8}{3} \int_{0}^{\pi} \sin ^{6} \theta d \theta\end{aligned}[/tex]
Step 2: Now, calculate for the [tex]I_{1}=\int_{0}^{\pi} \sin ^{6} \theta d \theta[/tex].
[tex]\begin{aligned}\sin ^{6} \theta &=\left(\sin ^{2} \theta\right)^{2} \times \sin ^{2} \theta \\&=\left[\frac{1-\cos 2 \theta}{2}\right]^{2} \times\left[\frac{1-\cos 2 \theta}{2}\right] \\&=\frac{1}{8}\left(1-2 \cos 2 \theta+\cos ^{2} 2 \theta\right)(1-2 \cos 2 \theta) \\&=\frac{1}{8}\left(1-2 \cos 2 \theta+\frac{1+\cos 4 \theta}{2}\right)(1-2 \cos 2 \theta)\end{aligned}[/tex]
[tex]\begin{aligned}&=\frac{1}{16}(3-4 \cos 2 \theta+\cos 4 \theta)(1-2 \cos 2 \theta) \\&=\frac{1}{32}(10-15 \cos 2 \theta+6 \cos 4 \theta-\cos 6 \theta)\end{aligned}[/tex]
Further compute the value of
[tex]\begin{aligned}I_{1} &=\int_{0}^{\pi} \sin ^{6} \theta d \theta \\&=\frac{1}{32} \int_{0}^{\pi}(10-15 \cos 2 \theta+6 \cos 4 \theta-\cos 6 \theta) d \theta \\&=\frac{1}{32}\left[10 \theta-\frac{15 \sin 2 \theta}{2}+\frac{3 \sin 4 \theta}{2}-\frac{\sin 6 \theta}{6}\right]_{0}^{\pi} \\&=\frac{5 \pi}{16}\end{aligned}[/tex]
Therefore, the obtained integral is [tex]I=\frac{8}{3} \times \frac{5 \pi}{16}=\frac{5 \pi}{6}[/tex].
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The complete question is -
Use cylindrical or spherical coordinates, whichever seems more appropriate. Evaluate ∫∫∫E z dV, where E lies above the paraboloid
z = x² + y²
and below the plane z = 2y. Use either the Table of Integrals or a computer algebra system to evaluate the integral.
Of the last 16 people at a carnival booth, 6 won a prize. what is the experimental probability that the next person at the booth will win a prize? write your answer as a fraction or whole number. p(win)
The experimental probability that the subsequent booth competitor will receive a reward is 3/8.
Probability calculationThe possibility of an event occurring is determined by probability.
The probability of the occurrence ranges from 0 to 1.
If the event doesn't happen, it = 0;
otherwise, it = 1.
For instance, the likelihood that it will storm on Sunday ranges from 0 to 1. If it storms, the event is given a value of 1. If it doesn't, the event is given a value of zero.
Depending on the outcome of a study that has been run several times, the experimental probability is calculated.
The number of winners in the games divided by the total number of competitors in those games determines the probability that the following competitor will earn a reward.
So, here the probability = 6/16 = 3/8 (by dividing both the numerator and the denominator by 2).
Therefore, the final solution is P= 3/8 .
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The sum of two odd numbers is 80 and their difference is 6. work out these numbers.
The two odd numbers are 43 and 37.
What are whole numbers?Whole numbers are positive numbers belonging to the set W ∈ {1, 2,3, 4, ...}
The two odd numbers can be represented as (2m-1) and (2n-1) respectively sum=80 and difference = 6
Let m and n be two whole numbers
Therefore
,[tex]2m-1) + (2n-1)= 80\\(2m-1) - (2n-1)= 6\\\\2(m+n-1)=80\\2(m-n)=6\\\\m+n = 41\\m-n=3\\[/tex]
Adding the two equations
[tex](m+n)+(m-n)=2m=44\\m=22\\n=m-3=19\\[/tex]
so m=22 ad n=19. our two odd numbers are 2m-1 = 43 and 2n-1 = 37
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the half life of an element in the periodic table measured over a period of time, t, is modeled by the function f(t)=16(1/2)^t. what is the initial amount of the element
The initial amount of the element is 16
How to determine the initial amount?The function is given as:
f(t) = 16(1/2)^t
Set t = 0, to determine the initial amount
f(0) = 16(1/2)^0
This gives
f(0) = 16 * 1
Evaluate
f(0) = 16
Hence, the initial amount of the element is 16
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A rectangular gate measures 1.2 m by 2.3 m with a 2.4 m diagonal. Is the gate
square? If not, should the diagonal be longer or shorter?
In a group of 55 people, 3x+5 people like banana and x+5 people like apple. If all the people who like apple also like banana and if 2x+15 people like at least one of fruit then find how many like
(i) bananas only,
(ii) none of the fruits
(iii) at most one fruit
also show subset
i. The number of people who like banana only is 20.
ii. The number of people who like none of the fruits is zero.
iii. The number of people who like at most one fruit is 30.
The question has to do with sets.
What is a set?A set a collection of well ordered items
i. How to find how many people like banana only.Since we have 55 people, 3x + 5 people like banana and x + 5 people like apple. If all the people who like apple also like banana and if 2x + 15 people like at least one of fruit then, we have that
3x + 5 + x + 5 + 2x + 15 = 55
3x + 2x + x + 5 + 5 + 15 = 55
6x + 30 = 55
6x = 55 - 25
6x = 30
x = 30/6
x = 5
Since the number of people who like banana only is 3x + 5.
So, number of people who like banana only is n = 3x + 5
= 3(5) + 5
= 15 + 5
= 20
So, the number of people who like banana only is 20.
ii. The number of people who none of the fruits.Since from the question, a person likes at least one fruit, either banana, apple or both. No one likes none of the fruits.
So, the number of people who like none of the fruits is zero.
iii. The number of people who like at most one fruit?To like at most one fruit, the person either likes apple or banana.
So, their sum is n = 3x + 5 + x + 5
= 4x + 10.
Since x = 5, we have n = 4x + 10.
= 4(5) + 10
= 20 + 10
= 30
So, the number of people who like at most one fruit is 30.
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