A 26-year-old male buys 100/300/100 liability insurance, collision insurance with a $100 deductible, and comprehensive insurance with a $250 deductible What is his total annual premium? Liability Insurance Type Bodily injury Amount Premium 25/50 $220 50/100 $310 100/300 $450 25 $175 50 $245 100 $375 Property damage Collision & Comprehensive Premiums Deductible Collision Comprehensive $215 $129 $250 $185 $102 $500 $148 $85 $100 Rating Factor a Male 3.0 Female 1.45 Age 17-20 21-24 25-29 1.2 215 1.55 1.0 $1142.00 $1765.45 $1770.10 $1785.25​

The standard deviation of the difference in means is (-1.96, 1.96).  There is no significant difference between coverage speed at 95%

The speed characteristics are given as_

[tex]$$ \begin{aligned}\bar{x}_1 & =35.5 & \bar{x}_2 & =38.7 \\\sigma_1 & =7.5 & \sigma_2 & =7.4 \\n_1 & =250 & n_2 & =280\end{aligned}$$[/tex]

The standard deviation is a summary measure of the differences of each observation from the mean. If the differences themselves were added up, the positive would exactly balance the negative and so their sum would be zero.

So

[tex]$$\begin{aligned}z=\frac{\overline{x_1}-\bar{x}_2}{\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}} & =\frac{35.5-38.7}{\sqrt{\frac{(7.5)^2}{250}+\frac{(7.4)^2}{280}}} \\& =\frac{-3.2}{\sqrt{0.225+0.1956}} \\& =\frac{-3.2}{0.64852} \\\z & =-4.9343\end{aligned}$$[/tex]

at 95% confidence acceptance region is: [tex]$$(-1.96,1.96)[/tex]

But [tex]$z \notin(-1.96,1.96)$[/tex]

So, there is no significant difference between coverage speed at 95%.

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The standard deviation of the difference in means is 0.4696 and acceptance region is (-1.96 , 1.96). So, there was no significant difference between the average speed sample data at the 95% confidence level.

Speed data was collected on a section of road during and after repair work. Now the significance level for mean rate = 95% = 0.95 The equation for the standard deviation of the mean difference is:

σd = √(σ₁²/n₁ + σ₂²/n₂).

For the first data sample,

Sample mean for average velocity, X₁

= 35.5 mph

sample size, n₁ = 250

standard deviation, σ₁ = 2.5 mph

sample seconds, sample mean for

average velocity, X₂ = 38.7 mph

sample size, n₂ = 280

standard deviation, σ₂ = 7.4 mph.

It is statistically significant to see if there is a difference between the two population means. Using the two sample Z =( X₁-bar - X₂-bar )/√(σ₁²/n₁) + (σ₂²/n₂)}

Substituting all known values,

Z = ( 35.5 - 38.

7 )/(2,5)²/250 + (7,4)²/280

=> Z = - 3,2/√0,025 + 0.1956

=> Z = -3.2/0.4696

=> Z = - 6.8832

95% confidence interval, tolerance range is (-1.96, 1.96). However, Z∉(-1.96 , 1.96)

So, there is no signification difference for means between avaerage speed at 95%.

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Complete question :

Speed data were collected at a section of highway during and after utility maintenance work: The speed characteristics are given as, and as shown below. Determine whether there was any significant difference between the average speed at the 95% confidence level (Z=1.96). The standard deviation of the difference in means is given as σd = √(σ₁²/n₁ + σ₂²/n₂). DATA: uav₁= 35.5 mph, uav₂= 38.7 mph ,σ₁ = 2.5 mph, σ₂= 7.4 mph n₁ = 250, n₂ = 280

The rate, in inches per hour, at which rain fell during that time on Friday is 3/10 inches per hour.

Option d is the answer

Rate is the ratio that compares two quantities of different units. It can be used to express how fast something is changing, or how much of one quantity is present for a certain amount of another quantity.

In this case, the rate, in inches per hour, at which rain fell during that time on Friday will be:

rate = (3/4) / (2 1/2)

rate = 3/10 inches per hour

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Complete Question

Rain fell at a constant rate for 2 1/2 hours on Friday. During that time, the total amount of rain that fell was 3/4 inch. What is the rate, in inches per hour, at which rain fell during that time on Friday?

a 3 1/3

b 1 7/8

c 8 1/5

d 3/10

The first partial derivatives of the function [tex]w=e^v/u+v^2[/tex] are:

∂w/∂u = [tex]-e^v/(u+v^2)^2[/tex]

∂w/∂v = [tex](e^v + 2ve^v)/(u+v^2)[/tex]

First partial derivatives are used to find the rate of change of a function with respect to one variable while holding the other variables constant. They are represented by the symbol ∂f/∂x or ∂f/∂y, where f is the function, x and y are the variables, and ∂ is the partial derivative. They are used to calculate the slope of a surface at a point in a multi-variable function.

The first partial derivative with respect to u is the derivative of w with respect to u, holding v constant.

To find this we can use the chain rule:

∂w/∂u = [tex]-e^v/(u+v^2)^2[/tex]

The first partial derivative with respect to v is the derivative of w with respect to v, holding u constant.

To find this we can use the chain rule:

∂w/∂v = [tex]e^v/(u+v^2)[/tex] + 2v [tex]e^v/(u+v^2)[/tex] = [tex](e^v + 2ve^v)[/tex]/[tex](u+v^2)[/tex]

So the first partial derivatives of the function [tex]w=e^v/u+v^2[/tex] are:

∂w/∂u = [tex]-e^v/(u+v^2)^2[/tex]

∂w/∂v = [tex](e^v + 2ve^v)[/tex]/[tex](u+v^2)[/tex]

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The complete question is -

Find the first partial derivatives of the function. [tex]w=e^v/u+v^2[/tex]

A scale factor of 7 is it an enlargement neither.

Scale factor is a ratio of two corresponding lengths, areas, or volumes of similar shapes. When two shapes are similar, one can be enlarged or reduced to create the other. The scale factor is the number by which a figure is multiplied or divided to form a similar figure. It is used in many areas of mathematics, including geometry, trigonometry, and algebra. It is also used in engineering and architecture to create drawings of scaled-down or scaled-up objects.

A scale factor of 7 does not necessarily indicate an enlargement or reduction; it simply states that the size of an object has been multiplied by a factor of 7. It could either increase or decrease the size of the object, depending on the original size of the object and the direction of the scale factor.

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Answer:

Brand z

Step-by-step explanation:

Answer:

X

Step-by-step explanation:

for W its 20/12 which is 5/3 or roughly 1.66. for X its 1500/1125 which is 4/3 or around 1.33. for Y its 100/65 which is 20/13 or around 1.54. and for Z its 50/25 or just 2.

Answer:

h(x) =-5x^2 -1

Step-by-step explanation:

same function just move down 3 so y intercept changes only and 2-3= -1.

Therefore , the area of such field is 7725 square feet as a result, which is the answer to the given trapezoid problem.

A trapezoid is a quadrilateral that has at least one connected pair of sides. It has the name trapezium. By definition, a trapezoid in Euclidean geometry is a convex quadrilateral. The trapezoid's base is made up of its parallel sides. A closed, flat shape having two neighboring sides and four consecutive sides is called a trapezoid. The parallel walls and base of the trapezoid are commonly referred as as the parallel sides and the legs, respectively.

Here,

We can solve the problem using the clue and formula provided.

Since the question asks for the number of square feet of grass, we are certain that we are solving for area,

Additionally,

it mentions that the two stands are 125 feet and 81 feet apart and that the stadium is 75 feet high (facing downhill) (b1 and b2).

Thus, the equation can be resolved.

=>A = 75((125+81)/2)

=> A = 75(206/2)

=> A = 75(103) (103)

=> A= 7725

The field measures 7725 square feet in size.

The area of such field is 7725 square feet as a result, which is the answer to the given trapezoid problem.

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The equation of the line will be y = -4x - 24.

An equation of the line is defined as a linear equation having a degree of one. The equation of the line contains two variables x and y. And the third parameter is the slope of the line which represents the elevation of the line.

The general form of the equation of the line:-

y = mx + c

m = slope

c = y-intercept

Slope = ( y₂ - y₁ ) / ( x₂ - x₁ )

Given that the line is passing through the point  (−6, 0) and (0, −24).

Ther slope of the point is calculated as,

Slope = ( y₂ - y₁ ) / ( x₂ - x₁ )

Slope = ( -24 - 0 ) / (0  - (-6)

Slope = -4

The y-intercept will be calculated as,

y = mx + c

y = -4x + c

0 =-4 x - 6 + c

c = -24

The equation of the line will be,

y = mx + c

y = -4x - 24

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The account has a $10.720.77 balance after 6 years.

Compound interest can be calculated by using the formula P(1 + r)t, where P stands for principal (the original sum), r for rate (the interest rate), and t for time (in years).

Let's first round up the percentage rate to the nearest whole number by adding 1. In decimal form, 5% is 0.05. 1 + 0.05 is 1.05.

We'll raise that decimal to the power of six now that we're trying to find the amount after six years. 1.05^5 is 1.34009564062. Do not remove this long decimal from your calculator despite its length.

It must be multiplied by the primary, which is equal to 8,000. When the numbers are added together, the result, rounded to the nearest hundredth, is 10,720.765125, or 10,720.77. There.

The account has a $10.720.77 balance after 6 years.

The complete question is,

Following the specified time, determine the balance in each account. After six years, $8000 in principal has earned 5% yearly compound interest.

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The number of hours Ramiro worked overtime is 5 hours.

Ramiro earns $20 an hour during the week and $30 an hour for overtime on the weekends.

One week, Ramiro earned a total of $650. he worked a total of 30 hours, including both weekday and weekend hours.

The number of hours Ramiro worked on the weekend can be calculated as follows;

using equation,

let

x = number of hours worked during the week

y = number of hours worked during overtime

Hence,

20x + 30y = 650

x + y = 30

multiply equation(ii) by 20

20x + 30y = 650

20x + 20y = 600

subtract the equations

10y = 50

y = 50 / 10

y  =5

Therefore, the number of hours worked overtime is 5 hours.

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The percent increase in the number of songs is 212%.

The general formula to find the percent increase is:

P = 100%*( final value - initial value)/(initial value).

Here we know that the initial value is 25 songs, and the final value is 78 songs, replacing these numbers of the formula above, we will get:

P = 100%*(78 - 25)/25

P = 100%*53/25

P = 212%

So there was an increase of 212% in the number of songs.

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The equations give values of 1/2 and -11/8

you should be aware that two equations are solved simultaneously if they are solved together

The given equations are

-8x+10y=16 .............................1

-4x-5y=13 ..................................2

Multiply equation 2 by 2 to have

-8x -10y=26

Subtract equation 1 from equation 2

-8x+10y=16

-(-8x-10y=26)  To get

The we have 20y = 10

Make y the subject of the relation

y=1/2

Put y = 1/2 in equation 1

-8x +10(1/2) = 16

-8x +5 = 16

-8x = 16-5

-8x = 11

Making x the subject of the formula we have

x=-11/8

In conclusion the values of x and y are -11/8 and 1/2 respectively

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Answer:

32

Step-by-step explanation:

Answer: oh easy its 1220703250

Step-by-step explanation:

Answer:

x=-8

Step-by-step explanation:

Follow the steps in the image.

-Hope this Helped

The equation for the magnitude of the acceleration of the system is equals to the

a = g (m₂ - m₁μ꜀ cosθ - m₁sinθ )/(m₁ + m₂ ).

We have, two blocks with masses say m₁ = 3.8 kg and m₂ = 8.6 kg inclined on the plane at angle θ=39° above the horizontal. Also, cofficient of friction, μ=0.39. According to problem, In case of block 1 , accelerate up the inclined plane, Then forces along y-axis,

Net force during vertical motion = 0

=> Fₙ - m₁gcosθ = 0 --(1)

On horizontal direction,

Again net force = 0

=> T - f꜀ - m₁gsinθ = m₁a --(2) ( using Newton's second law)

For block 2, Vertical motion

So, net vertical force = 0

=> - T + m₂g = m₂a --(3)

Now, f꜀ = μ꜀ Fₙ= μ꜀ m₁g cosθ

so, T - μ꜀ m₁g cosθ - m₁gsinθ = m₁ a --(4)

Using the equation (4) and (3), we have to determine the equation for acceleration, a.

Adding (3) from (4),

m₁ a + m₂a = -μ꜀ m₁g cosθ - m₁gsinθ + m₂g + T - T

=> (m₁ a + m₂a) = g ( -m₁cosθ - m₁ sinθ + m₂)

=> a ( m₁ + m₂ ) = g (-m₁μ꜀ cosθ - m₁ sinθ + m₂)

=> a = g (- m₁μ꜀ cosθ - m₁sinθ + m₂)/(m₁ + m₂ )

by plugging all the above values we can calculate the magnitude of acceleration.

Hence, required equation is a = g (m₂ - m₁μ꜀cosθ - m₁sinθ)/(m₁ + m₂) .

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Complete question:

Referring to the image to the above figure , the mass of block 1 is m1=3.8 kg while the mass of block 2 is m2=8.6 kg. The coefficient of friction between m1 and the inclined surface is μ=0.39. The inclined surface is at an angle θ=39∘ above the horizontal. Using the variables from the problem statement together with the acceleration due to gravity, g , write an equation for the magnitude of the acceleration of the system. hint: based upon the numeric choices, block 1 will accelerate up the incline while the suspended block, block 2, accelerates vertically downward.

Answer:

9

Step-by-step explanation:

X= -2, substitute -2 for X in the function

-(-2)+7, = 2+7

=9

The vertical line test can be used to determine whether a graph represents a function. A vertical line includes all points with a particular x value.

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Answer:

The measure of 21 and 22 doesn't make sense as they are not specific angles and they are not defined as to what angle you are refering to.

Without proper context and information, I am unable to provide an accurate answer to your question. Can you please provide more context, or explain what exactly you are trying to ask ?

Step-by-step explanation:

If z is a standard normal variable then the probability of P(-1.5 < z < 1.09) is 0.79533

Here it is given that Z is a standard normal variable. This imples that the mean of Z is 1 and the standard deviation is 0. Hence we get

μ = 1

σ = 0

Now we need to find the probability P(-1.5 < z < 1.09)

We know that P(a < X < b) = P(X < b) - P(X < a)

= P(z < 1.09) - P(z < -1.5)

We know that P(x < -a) = 1 - P(x < a)

= P(z < 1.09) + P(z < 1.5) - 1

Now looking up the s-score for 1.09 and 1.5 in the z-table we get

0.86214 + 0.93319 - 1

= 0.79533

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The requried scale factor from Figure A to Figure B is given as 1 / 3.

The scale factor is defined as the ratio of the modified change in length to the original length.

here,
The measure of the one side of triangle A = 6 units
The measure of the one side of triangle B = 2

Scale factor = length of the side of B / A
Scale factor = 2 / 6 = 1/3

Thus, the requried scale factor from Figure A to Figure B is given as 1 / 3.

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Answer: 2

Step-by-step explanation: Hope this helped

A possible equation to represent the total number of roses the florist will need to use in this situation is 36 + 12x= y.

This is a short mathematical expression that relates variables represented by letters by using mathematical symbols such as  +, -, x, and the symbol =.

Based on this, a possible equation is 36 + 12x= y.

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Answer:

 line that intersects two or more lines at a distinct points is known as transversal line.

Answer:

A Transversal

Step-by-step explanation: A transversal is a line that intersects two or more lines in the same plane.

The linear equation has no solutions, thus, it is not an identity.

An equation is an identity if it is true for any value of x.

So, if here we can find a unique solution ( or not solutions at all) for the linear equation, then we will prove that the equation is not an identity.

The linear equation is:

3*(x + 2) + 4 = 3x + 9

If we simplify the left side, we will get:

3*(x + 2) + 4 = 3x + 9

3*x + 3*2 + 4 = 3x + 9

3x + 6 + 4 = 3x + 9

3x + 10 = 3x + 9

Subtracting 3x in both sides we will get:

10 = 9

This equation has no solutions, then it is not an identity.

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There will be n linear factors of a polynomial function f of degree n

We derive the above answer based on the following explanation,

The Linear Factorization Theorem states that . . . if f(x) is a polynomial of degree n, where n > 0, then f has precisely n linear factors f(x) = an(x – c1)( x – c2) . . . (x – cn) where c1, c2, . . . , cn are complex numbers.

Let us assume f to be a polynomial function with real coefficients and suppose a+bi, b≠0, is a zero of f(x). Then, by the Factor Theorem, x−(a+bi) is a factor of f(x). For f to have real coefficients, x-(a−bi) must also be a factor of f(x). This is true because any factor other than x−(a−bi) when multiplied by x−(a+bi), will leave imaginary components in the product. Only conjugate pair multiplication will get rid of the imaginary components and produce real coefficients.

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The dimension of Nul A = 0 and the dimension of Col A = 4. means that the matrix A has no solutions for the homogeneous equation A × x = 0, which means that its null space is trivial, and it has 4 linearly independent columns, which means that its column space is 4-dimensional.

In other words, it is the number of linearly independent vectors x that satisfy the equation Ax = 0.

The dimension of Col A, also known as the column space of the matrix A, is the dimension of the subspace spanned by the columns of the matrix A. In other words, it is the number of linearly independent columns of matrix A.

In general, it is not possible to determine the dimensions of Nul A and Col A of a matrix just by looking at its elements. In order to find the dimensions, we need to perform the row echelon form or reduced row echelon form of the matrix to find the rank and the nullity which is the difference in the number of columns and rank.

For the specific matrix A provided, the rank of the matrix is not provided, thus we can not determine the dimension of the Nul A and Col A.

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