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The planets move around the center star in different orbits. Which planet has more Vittar is in the same relative position from its star as earth’s orbit isfrom this Sun?

a. The push is 150 N and acts to the right while the frictional force is 150 N and acts to the left.

b. The weight is 490 N and acts downwards while the normal force is 490 N and acts upwards.

c. The package moves 1.8 m

d. The package's acceleration is 0 m/s²

The push is 150 N and acts to the right while the frictional force is 150 N and acts to the left.a

Since the direction of push and the floor is horizontal, and first horizontal force acting on the package is the push and its magnitude is 150 N.

Also, a frictional force also acts to oppose the motion of the package.

Since the packge moves at a constant velocity of 0.6 m/s, its acceleration is zero and thus the net force on the package is zero.

Let

So, F - f = 0

F = f

= 150 N

So, the frictional force is 150 N and opposite to the push.

So, the push is 150 N and acts to the right while the frictional force is 150 N and acts to the left.

The weight is 490 N and acts downwards while the normal force is 490 N and acts upwards.

Since the floor is horizontal, the vertical forces that act on the package are its weight and the normal force due to the ground.

The direction of the weight is downwards while the direction of the normal force is upwards.

Since the floor is horizontal and the package does not move in the vertical direction, the net vertical force is zero.

So, the net force N - W = 0

N = W

= mg

= 50 kg × 9.8 m/s²

= 490 N

So, the weight is 490 N and acts downwards while the normal force is 490 N and acts upwards.

The package moves 1.8 m

Since distance, d = vt where

So, d = vt

= 0.6 m/s × 3 s

= 1.8 m

So, the package moves 1.8 m

The package's acceleration is 0 m/s²

Since the net force on the package is zero, its acceleration is also zero. Since force, F = ma where

Since F = 0,

ma = 0

a = 0

So, the package's acceleration is 0 m/s²

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Answer:

If we take downwards as the positive direction -

m a = m g - T     difference between scale and mg is equal to acceleration

T = m (g - a)

m = 604 / 9.80 = 61.6 kg        mass of student

T = 61.6 (9.80 - 1.98) = 482 N         scale reading

The force when the elevator then accelerates downward at 1.98 m/s² is 725.78 N.

When the lift is stationary (at rest), the student is subject to a downward force equal to 604 N, which is caused by gravity (assumed to be equal to the student's weight according to the scale).

Given:
Force, F = 604 N

Acceleration, a = 1.98 m/s²

The mass can be computed from force and acceleration due to gravity

F = mg

604 N = mass × 9.81

mass = 604 N / 9.81

mass =  61.56 kg

The force is calculated as:

F' = ma

F' = 61.56 kg × 1.98

F' = 121.78 N

The total force is :

Total force = F +F"

Total force = 604 N + 121.78 N

Total force = 725.78 N

Hence, the force when the elevator then accelerates downward at 1.98 m/s² is 725.78 N.

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Answer:

Andre is really disappointed that he didn't make the basketball team as a player this year, but he decides to accept the coach's offer to assist the team in other ways in doing so, he is exercising the self-care strategy of?

Answer

A

Andre is really disappointed that he didn't make the basketball team as a player this year, but he decides to accept the coach's offer, so he is exercising the self-care strategy of being flexible that is in Option A.

Being flexible is an important self-care strategy, as it allows individuals to adjust to and cope with change such as in Andre's case, he had his heart set on being a basketball player, but when that didn't work out, he chose to be flexible and open to new possibilities, worked hard, and also Being flexible can help reduce stress and improve well-being because it allows someone to approach situations with a more positive and open mindset.

Hence, Andre is exercising the self-care strategy of being flexible, which is in Option A, as he didn't make the basketball team as a player this year.

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Answer:

[tex]\theta= (-74.42)^{\circ} C[/tex]

Explanation:

Horizontal speed of water, [tex]v_{xf}=9\ m/s[/tex]

Height, h = -53 (below pool)

We can find firstly the final vertical speed of the water using third equation of kinematics. So

[tex]v^2_{yf}=u^2_{yi}+2(-g)h\\\\v^2_{yf}=2\times -9.8\times -53\\\\v_{yf}=32.23\ m/s[/tex]

Let [tex]\theta[/tex] is the angle where the falling water moving as it enters the  pool. So,

[tex]\tan\theta=\dfrac{v_{yf}}{v_{xf}}\\\\=\dfrac{-32.3}{9}\\\\=-74.42^{\circ} C[/tex]

Hence, the angle is (-74.42)°C.

Answer:

The location of the survey is biased.

Explanation:

If someone left a movie theater, it is most likely because he likes watching movies there. A better place to interview would be on the streets, as it’s less biased there

Answer:

It will be D/ The location of the survey introduced bias!

Explanation:

Answer: electricity

Explanation:

temperature would decrease because you aren’t close to other bodies with similar temperatures, you are now surrounded by air that is cooler than you. the molecules move from hot to cold always.

Temperature is a unit used to describe hotness or coldness. It can be stated in terms of any number of arbitrary scales and shows the direction in which heat energy will naturally flow, i.e., from a hotter body to a colder body (one at a lower temperature).

Temperature is not the same as the energy of a thermodynamic system; for instance, an iceberg has a significantly larger total heat energy than a match, despite the fact that a match is burning at a much higher temperature.

As opposed to extensive characteristics, like mass or volume, temperature is referred to as an intense property—one that is independent of the quantity of matter being considered—along with pressure, density, and other comparable properties.

Therefore, temperature would decrease because you aren’t close to other bodies with similar temperatures, you are now surrounded by air that is cooler than you. the molecules move from hot to cold always.

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Answer: We can see the moon at night because the earth spins in a circle wall it is going around the sun so when the sun go down and the moon comes up the suns light will go over the top of earth and hite the moon the all the light that is hite the moon will bounce off it and the moon it a light color and light shins off lighter colored thing and it will have a little proportion of that light will come and hite earth make the moon very easy to see at night and the most light hits the moon when if it a full moon and is the most brite.

I Hope This Helped!

Answer:

Refraction refers to any bending of waves due to a change in speed. In the case of light being refracted by a prism, dispersion means that the higher the frequency light bends more. In short, Refraction is the bending of light and Dispersion is the frequency dependece of this behaviour.

Answer:

the kinetic energy force made the not to stay in a position if the person is not careful

Answer: 13.7 m/s

Explanation:

[tex]$$Mass of $T r u c k$$ \ \left(m_{T}\right)=3520\mathrm{kg}[/tex]

[tex]V_{T_{y}}=18.5 \mathrm{~m} / \mathrm{s} \\&V_{\text {Tix }}=0 \mathrm{~m} / \mathrm{s}[/tex]

[tex]\mathrm{Mass \ of \ car \ (m_c) = 1480 \ kg}[/tex]

[tex]V_{c i x}=\text { ? ; } V_{c i y}=0 \mathrm{~m} / \mathrm{s}[/tex]

[tex]Final \ velocity $\left(V_{f}\right)=13.6 \mathrm{~m} / \mathrm{s} \ \ \theta=72.6$[/tex]

[tex]v_{f x}=v_{f} \cos \theta=(13.6) \cos 72.6=4.067 \mathrm{~m} / \mathrm{s}[/tex]

[tex]\mathrm {Using \ the \ conservation \ of \ momentum \ along\ the \ $x$-axis}[/tex]

[tex]\begin{aligned}m_{T} v_{T i x}+m_{c} v_{c_{i x}} &=\left(m_{T}+m_{c}\right) v_{f x} \\0+(1480) V_{c_{i x}} &=(3520+1480)(4.067) \\(1480) v_{c i x} &=20335 \\V_{c i x} &=13.7 \mathrm{~m} / \mathrm{sec}\end{aligned}[/tex]

Answer:

13.7 m/s

Explanation:

Given parameters:

Frequency of the wave  = 1520kHz   = 1520 x 10³Hz

Unknown:

Wavelength of the radio photon = ?

Energy of the wave = ?

Solution:

The wavelength of any electromagnetic wave can found using the expression below;

          C = f x ∧

Where C is the velocity of light  = 3 x 10⁸m/s

            f is the frequency of the wave

            ∧ is the wavelength

Since the unknown is ∧, input the known parameters and solve for it;

       3 x 10⁸  = 1520 x 10³  x ∧

    Wavelength  = [tex]\frac{3 x 10^{8} }{1520 x 10^{3} }[/tex]  

   Wavelength  = [tex]\frac{3 x 10^{8} }{1.52 x 10^{6} }[/tex]

  Wavelength  = 1.97 x 10²m

ii. Energy of the wave;

        Energy of a wave  = hf

where h is the planck's constant = 6.63 x 10⁻³⁴ J Hz⁻¹

           f is the frequency of the wave

Input the parameters and solve;

            Energy of the wave = 6.63 x 10⁻³⁴ x 1.52 x 10⁶

                                               = 10.1 x 10⁻²⁸J

The energy of this wave is 10.1 x 10⁻²⁸J

Wavelength of the wave  = 1.97 x 10²m

Energy of the wave = 10.1 x 10⁻²⁸J

Given:

Frequency of the wave  = 1520kHz   = 1520 x 10³Hz

To find:

Wavelength of the radio photon = ?

Energy of the wave = ?

The wavelength of any electromagnetic wave can found using the expression below:

c = f * ∧

Where,

c is the velocity of light  = 3 x 10⁸m/s

f is the frequency of the wave

∧ is the wavelength

On substituting the values:

3 x 10⁸  = 1520 x 10³  x ∧

Wavelength  = 1.97 x 10²m

Energy of a wave  = h*f

where,

h is the Planck's constant = 6.63 x 10⁻³⁴ J Hz⁻¹

f is the frequency of the wave

On substituting the values:

Energy of the wave = 6.63 x 10⁻³⁴ x 1.52 x 10⁶

Energy of the wave = 10.1 x 10⁻²⁸J

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Answer: The Answer is A 1.2 x 10−2 m/s2

The average acceleration of the delivery drone as it slowed down was  -0.012 m/s².

The average acceleration is defined as the average rate of change of velocity with respect to time. Mathematically -

a = Δv/Δt

Given is a delivery drone that uniformly slows down from 45 m/s to 23 m/s in a straight line over a 30-minute duration.

We can write -

[u] = 45 m/s

[v] = 23 m/s

Δt = 30 min = 30 x 60 = 1800 sec

We can write the average acceleration as -

a = Δv/Δt

a = (23 - 45)/1800

a = - 0.012 m/s²

Therefore, the average acceleration of the delivery drone as it slowed down was  -0.012 m/s².

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Answer: 10m per second.

Explanation: 100/10 is 10/1, so it would be 10m per second.

20cm spanner is suitable to open this nut , Because we feel easy to apply force at the end of spanner to rusted nut. It means that as the perpendicular distance between force and axis of rotation increase the magnitude of moment also increase.

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The arrow should be fired with an initial speed of approximately 31.2 m/s to land 90.4 meters away when aimed at a 45.0-degree angle.

To calculate the initial speed required for an arrow fired at a 45.0-degree angle to land 90.4 meters away, we can utilize the principles of projectile motion.

In projectile motion, the horizontal and vertical components of motion are independent. We can break down the initial velocity into its horizontal and vertical components.

Angle of projection (θ) = 45.0 degrees

Range (horizontal distance) (R) = 90.4 meters

We can start by finding the horizontal component of the initial velocity (Vx) using the formula:

Vx = V * cos(θ)

Where V is the initial velocity.

Since the angle is 45.0 degrees, the cosine of 45.0 degrees is equal to 1 / √2.

Vx = V / √2

Next, we can find the vertical component of the initial velocity (Vy) using the formula:

Vy = V * sin(θ)

Again, since the angle is 45.0 degrees, the sine of 45.0 degrees is equal to 1 / √2.

Vy = V / √2

To determine the initial speed required, we need to consider the time of flight (T) for the arrow to reach the range. The time of flight can be calculated using the formula:

T = (2 * Vy) / g

Where g is the acceleration due to gravity (approximately 9.8 m/s^2).

Once we have the time of flight, we can calculate the horizontal component of the initial velocity (Vx) using the formula:

Vx = R / T

Now, we can substitute the expressions for Vx and Vy into the original equation:

Vx = V / √2

Vx = R / T

Solving for V:

V = Vx * √2

V = (R / T) * √2

Plugging in the given values of R and T:

V = (90.4 m / T) * √2

Finally, substituting the value of T:

V = (90.4 m / [(2 * Vy) / g]) * √2

Simplifying further:

V = (90.4 m * g * √2) / (2 * Vy)

V = (90.4 m * 9.8 m/s^2 * √2) / (2 * (V / √2))

V = (90.4 m * 9.8 m/s^2) / V

Squaring both sides:

V^2 = (90.4 m * 9.8 m/s^2) / V

Rearranging the equation:

V^3 = 90.4 m * 9.8 m/s^2

Taking the cube root of both sides:

V = ∛(90.4 m * 9.8 m/s^2)

Using a calculator, the final answer is:

V ≈ 31.2 m/s

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Answer:

22.5 J

Explanation:

GPE=wxh- 45kg divided by 2m= 22.5

Answer:

Nuclease is the answer I know

I hope this is the answer

Answer:

a = 0 m/s²

T = 2m₂g

Explanation:

In this scenario of a pulley with two masses hanging vertically over it, the formula of acceleration is given as follows:

a = g(m₁ - m₂)/(m₁ + m₂)

It is given that:  m₁ = m₂ = m

Therefore,

a = g(m - m)/(m + m)

a = g(0)/(2m)

a = 0 m/s²

The tension of the rope in such case is given by the following formula:

T = 2m₁m₂g/(m₁ + m₂)

It is given that:   m₁ = ∞

Therefore,

T = 2(∞)m₂g/(∞ + m₂)

T = ∞(2m₂g)/∞(1 + m₂/∞)

T = 2m₂g/(1 + 0)

T = 2m₂g

Let R be the radius of cylinder

[tex]m_a + m_b = 4 + 3 = 7kg[/tex]

The angular velocity is 500 RPMs

[tex]\omega ^2 = \frac{500 * 2\pi}{60} rad/s\\N = (M_a + M_b)\omega ^2 R[/tex]

The normal force

[tex]f = \mu N = (M_a + M_b) g\\\mu (M_a + M_b) \omega ^2 R = M_a + M_b\\R = \frac{1}{\mu \omega ^2 R}\\\mu_s = 0.5\\R = \frac{1}{0.5 * (\frac{500 * 2\pi}{60})^2 }\\R = 0.0073m\\R = 7.3mm[/tex]

Since the radius is very little for two block to execute circular motion so system will slide down.

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The work is done against the skier, we call it negative work, and the magnitude of the work done on the skier by the rope is 7500 J.

The work done on the skier by the rope is in opposte direction of the water skier which caused the water skier to fall after some given period of time. Since the work is done against the skier, we call it negative work.

The magnitude of the work done on the skier by the rope is calculated as follows;

W = Fd

where;

F is the applied force on the rope

d is the distance moved by the skier

W = 100 x 75

W = 7500 J

Thus, the magnitude of the work done on the skier by the rope is 7500 J.

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Answer:

i think it is 89

Answer: 1. B, 2. A, 3. C, 4. D

Answer:

1 = B

2 = A

3 = C

4 = D

I hope this helps

The closer together they are the harder it is to hold on to because the magnetic field is stronger as it gets closer.

Answer:

D. The electromagnet's magnetic field is stronger close to it than far from it.​

Answer:

B. 10m/s

Explanation:

If a drone flies 8 m/s due East with respects to the wind and the wind is blowing 6 m/s due North, the speed of the drone with respect to the ground is its displacement.

Displacement is calculated using Pythagoras theorem.

d² = 8²+6²

d² = 64+36

d² = 100

Square root both sides

√d² = √100

d = 10m/s

Hence the distance of the drone with respect to the ground is 10m/s

Option B is correct

Answer:

Adolescent Development

Adolescence is the period of transition between childhood and adulthood. Children who are entering adolescence are going through many changes. This article offers advice for adolescents and parents to negotiate these changes.

Answer:

How do you support adolescent development?

Explanation:

Parents are a key support for teens during this time of growth and reflection. Be aware of the stages of emotional development, and provide clear guidance at each phase. Acknowledge when to give space and independence to teens. Help guide teens to feel good about themselves.

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Answer:

Option (d) is correct.

Explanation:

As the large mass M is found to just balance two of the small mass, m, so

[tex]M=2m\cdots(i)[/tex]

As both the masses M as well as m are forced to go around a bend of 1.0 m at a constant speed of 1.0 m/s.

So, the radius of curvature of the bend (curved path), R= 1.0 m

The speed both the masses, v= 1.0 m/s.

Naturally, without any restriction, all the masses have the tendency to move in a straight line due to its inertia, but here both the masses are moving on the curved path because of the application of the external force on them. This continuous change in the direction is due to the force by the wall of the curved path which is actually the normal reaction by the wall on both the masses.

This reaction force, [tex]F_R[/tex], balance the centrifugal force, F with which the masses have a tendency to go out of the path, the magnitude of this centrifugal force is,

[tex]F = \frac {mv^2}{R}[/tex]

Where m is the mass of the body, v is the speed at that instant, R is the radius of curvature of the path.

So, [tex]F_R=\frac {mv^2}{R}[/tex]

Now, for the small mass, m, the reaction force on it is

[tex]F_R1= \frac {mv^2}{R}[/tex]

[tex]\Rightarrow F_R1= \frac {m(1)^2}{1}[/tex]

[tex]\Rightarrow F_R1= m \cdots(ii)[/tex]

And for the bigger mass, M, the reaction force on it is

[tex]F_R2= \frac {Mv^2}{R}[/tex]

[tex]\Rightarrow F_R2= \frac {M(1)^2}{1}[/tex]

[tex]\Rightarrow F_R2= M[/tex]

By using equation (i), we have

[tex]F_R2= 2m[/tex]

[tex]\Rightarrow F_R2=2F_R1[/tex] [by using (ii)]

[tex]\Rightarrow F_R2 / F_R1 = 2/1[/tex]

So, the ratio of force acting on the bigger mass M to the magnitude of the force acting on the smaller mas m is 2:1.

Hence, option (d) is correct.

Answer:

Explanation:

Time-base of the oscilloscope is set at 500 [tex]\mu s[/tex]/div. It means, one block in horizontal direction represents 500 microseconds. The period of the wave is the time to complete one oscillation and in the picture there is two-block for complete one oscillation, so the period and oscillation are:

[tex]T=(2)(500) =100 \mu s \rightarrow f=\frac{1}{T}=\frac{1}{100 \times 10^{-6}}=10000 Hz[/tex]

the time period of the signal is 1200μs and hence its frequency is 833 Hz

An oscilloscope is a sort of electronic test tool that shows fluctuating electrical voltages visually as a two-dimensional plot of one or more signals as a function of time. The primary goals are to display repeating or single waveforms on the screen that would otherwise occur too quickly for the human eye to discern. The exhibited waveform may then be analysed for amplitude, frequency, rising time, time interval, distortion, and other features. Previously, these values were calculated by manually measuring the waveform against the scales incorporated into the instrument's screen. Modern digital equipment may immediately compute and show these parameters.

Given,

Time knob = 500 μs/div

wavelength of wave in oscilloscope =  2.4 div

Period of time of the wave is 2.4 div×500 μs/div = 1200μs

frequency of the wave is 1/T = 1/12μs = 833 Hz

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