Plasma can be found naturally in
O water and ice.
O stars and lightning.
O wood and metal.
O comets and asteroids.

Answers

Answer 1

Answer:

stars and lightning. this is the answer ok

Answer 2
The sun and other stars consist of plasma. Plasma is also found naturally in lightning and the northern and southern lights. Human-made plasma is found in fluorescent lights, plasma TV screens and plasma spheres.

Hope it helped

Related Questions

Which set of coefficients will correctly balance the following skeleton equation?
Fe + Cl2 →FeCl3

Answers

Answer:

2Fe + 3Cl2 → 2FeCl3

Explanation:

Question 2 (1 point)
(02.01 LC)
Which scientist proposed the model of an atom as a solid sphere? (1 point)

John Dalton

Niels Bohr

Ernest Rutherford

William Crookes

Answers

Answer:

John Dalton

Explanation:

Both John Dalton and Democritus thought that the atom was an indivisible sphere until J.J. Thompson came out with the plum pudding model. Hope I helped!

Can u please help me name which one it is

Answers

i think it’s D.
sorry if it’s wrong

Answer:

I think it is C

Explanation:

A certain protein transports a sodium ion from the inside of the cell membrane to the outside using active transport. Which of the following must be true? A. There is no change in concentration before or after transport. B. The transport process did not use chemical energy. C. After transport, the concentration of protein in the cell decreases. D. After transport, the concentration of sodium is lower inside the cell.

Answers

D is the answer because all the sodium will lower the cells inside due to the membrane using active transport

Astronauts go to live on the International Space Station for a period of ________ month(s). A one B three C six D nine

Answers

Answer:

The answer is C. six months

Explanation:

I hope this helps you bestie:))

Pls someone help rn!! Pls pls

Answers

Answer:

A. Mass = 61kg, weight on moon = 97.8N

Explanation:

To calculate the weight (force) from Mass of a body, the following formula is used:

W = mg

Where;

W = weight (Newtons)

m = mass (kg)

g = acceleration due to gravity (9.8m/s²)

According to this question, a scale shows that I weigh 600N on Earth, the mass on Earth can be calculated thus:

Using W = mg

m = W/g

m = 600/9.8

m = 61.2

m = 61kg

However, this mass on Earth will weigh differently on the Moon because gravity in the moon is 1.6 N/kg. The weight of the 61kg on the Moon is:

W(moon) = mass × gravity

W = 61 × 1.6

W = 97.6 N

Therefore, Mass = 61kg, weight on moon = 97.8N

HELP WHOEVER ANSWERS WILL BE MARKED BRAINLIEST!!!

Answers

There you go :)))))))))

The extraction of iron from ore is represented by the chemical reaction equation.
Fe2O3 + 3CO → 2Fe + 3CO2
Calculate the mass of carbon (II) oxide required for the reduction of 40 kg of iron (III) oxide

Answers

Answer:

21 Kg of CO.

Explanation:

The balanced equation for the reaction is given below:

Fe₂O₃ + 3CO —> 2Fe + 3CO₂

Next, we shall determine the masses of Fe₂O₃ and CO that reacted from the balanced equation. This can be obtained as illustrated below:

Molar mass of Fe₂O₃ = (56×2) + (16×3)

= 112 + 48

= 160 g/mol

Mass of Fe₂O₃ from the balanced equation = 1 × 160 = 160 g

Molar mass of CO = 12 + 16 = 28 g/mol

Mass of CO from the balanced equation = 3 × 28 = 84 g

SUMMARY:

From the balanced equation above,

160 g Fe₂O₃ required 84 g of CO.

Finally, we shall determine the mass of of CO required for the reduction of 40 kg of Fe₂O₃. This can be obtained as follow:

From the balanced equation above,

160 g Fe₂O₃ required 84 g of CO.

Therefore, 40 Kg of Fe₂O₃ will require = (40 kg × 84 g) / 160 g = 21 Kg of CO.

Thus, 21 Kg of CO is required for the reaction.

Which of these statements best supports the idea that a cell is the basic unit of a living organism?

A.
The number of cells in an organism affects the size of that organism.
B.
A tissue is composed of cells with similar structure and function.
C.
Some organisms have only one cell.
D.
All organisms are made up of one or more cells.

Answers

Answer:

The answer is D.

Explanation:

I searched it up :)

What is the atomic mass of element XX if 3.6 moles of the substance has a mass of 192 grams?

Answers

Answer:

53.3g/mol

Explanation

Moles=mass/molar mass

Molar mass= mass/moles

Molar mass= 192/3.6

= 53.3

Elizabeth REALLY didn’t study, and she also wrote the formula for dicarbon tetrafluoride as “C2F5”. Describe why her answer is incorrect.

Answers

Answer:

correct formula: C2F4

Explanation:

tetra means 4. There are 2 C and 4 F in dicarbon tetrafluoride.

chemical properties of elements

Answers

Answer:

Atomic number. The atomic number indicates the number of protons within the core of an atom. ...

Atomic mass. The name indicates the mass of an atom, expressed in atomic mass units (amu). ...

Electronegativity according to Pauling. let me know if you need more ;)

The subscript represents the number of ____________ in a chemical equation.

Answers

Answer: Atoms

Good luck!

Kevin is working on a model that shows the positions of Earth, the Moon, and the Sun during the phases of
the Moon. How should he position them to show a New Moon?

Answers

Answer:

Explanation:what’s the answer

Answer: A. With Earth between the Moon and the Sun.

Explanation:

How many atoms are in 1.50 moles of Zinc?

Answers

There are 18 atoms in 1.5 moles of Zinc

A 497.9-gallon steel storage tank contains 91.7kg of methane. If the temperature is 23.7˚C what is the pressure inside the tank?

Answers

Answer:

74.08 atm

Explanation:

We'll begin by converting 91.7 kg to grams (g). This can be obtained as follow:

1 kg = 1000 g

Therefore,

91.7 kg = 91.7 kg × 1000 g / 1 kg

91.7 kg = 91700 g

Next, we shall determine the number of mole present in 91700 g of methane, CH₄. This can be obtained as follow:

Mass of CH₄ = 91700 g

Molar mass of CH₄ = 12 + (4"1)

= 12 + 4

= 16 g/mol

Mole of CH₄ =?

Mole = mass /Molar mass

Mole of CH₄ = 91700 / 16

Mole of CH₄ = 5731.25 moles

Next, we shall convert 497.9 gallon to litres (L). This can be obtained as follow:

1 gallon = 3.785 L

Therefore,

497.9 gallon = 497.9 × 3.785

497.9 gallon = 1884.55 L

Next, we shall convert 23.7 ˚C to Kelvin temperature. This can be obtained as follow:

T(K) = T(˚C) + 273

T(˚C) = 23.7 ˚C

T(K) = 23.7 °C + 273

T(K) = 296.7 K

Finally, we shall determine the pressure in the tank as follow:

Number of mole (n) = 5731.25

Volume = 1884.55 L

Temperature (T) = 296.7 K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =?

PV = nRT

P × 1884.55 = 5731.25 × 0.0821 × 296.7

P × 1884.55 = 139607.92

Divide both side by 1884.55

P = 139607.92 / 1884.55

P = 74.08 atm

Therefore the pressure in the tank is 74.08 atm

Fill in the blanks. 3NH3

Answers

Answer:

3, 9, 3

Explanation:

The coefficient of 3 tells us that there are three molecules (the chemical unit of NH3). Each molecule of ammonia (NH3) is made up of 1 atom of nitrogen bonded to 3 atoms of hydrogen.

Since there are three molecules, we have three times the amount of atoms there are in one molecule.

3 x 1 = 3 nitrogen

3 x 3 = 9 hydrogen

Sulfur
how many electron shells in 4th shell?

Answers

Answer:

16 electrons in a sulfur atom. Looking at the picture, you can see there are two electrons in shell one, eight in shell two, and six in shell three.

Explanation:

(b) The student collects the H2(g) produced by the reaction and measures its volume over water at 298 K after carefully
equalizing the water levels inside and outside the gas-collection tube, as shown in the diagram below. The volume is
measured to be 45.6 mL. The atmospheric pressure in the lab is measured as 765 torr, and the equilibrium vapor pressure
of water at 298 K is 24 torr,
45
46
Gas
Water
Calculate the following.
() The number of moles of h2 produced in the reaction

Answers

Answer:

The pressure of  H₂(g) = 741 torr

Explanation:

Given that:

The atmospheric pressure measured in the lab  = 765 torr

The vapor pressure of water = 24 torr

By applying Dalton's Law of Partial Pressure :

Making The Pressure inside the tube due to the H₂(g) the subject of the formula :

we have:

= (765 -24) torr

= 741 torr

According to ideal gas law and Dalton's law of partial pressure, 0.0136 moles of hydrogen are produced in the reaction.

What is ideal gas law?

The ideal gas law is a equation which is applicable in a hypothetical state of an ideal gas.It is a combination of Boyle's law, Charle's law,Avogadro's law and Gay-Lussac's law . It is given as, PV=nRT where R= gas constant whose value is 8.314.The law has several limitations.It is applicable to ideal gases which have hypothetical existence.Law was proposed by Benoit Paul Emile Clapeyron.

In the given problem, according to Dalton's law of partial pressure, pressure =765-24=741 torr

Substituting the given values in the ideal gas equation, n=PV/RT

n=741×45.6×10[tex]^-3[/tex]/8.314×298=0.0136 moles.

Thus 0.0136 moles of hydrogen are produced in the reaction.

Learn more about ideal gas law,here:

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One component of smog is nitrogen
monoxide, NO. A car produces about 8 g of
this gas per day. What is the volume at STP?

Answers

Answer:

V = 5.97 L

Explanation:

Hello!

In this case, according to the ideal gas law:

[tex]PV=nRT[/tex]

We would need to solve for V as we know the temperature and pressure as the gas it at STP conditions (273 K and 1 atm respectively):

[tex]V=\frac{nRT}{P}[/tex]

Next, we compute the moles in 8 g of NO, given its molar mass of 30.01 g/mol:

[tex]n=\frac{8g}{30.01g/mol}=0.267mol[/tex]

Therefore, we obtain the following volume:

[tex]V=\frac{0.267mol*0.08206\frac{atm*L}{mol*K}*273K}{1atm}\\\\V=5.97 L[/tex]

Best regards!

How many grams equal 4.3 x 1024 atoms of oxygen (02)?

Answers

Answer: 248.66g

Explanation:

4.3e24 / 6.23e23 = 6.9 mols O2

6.9(18.02*2)=248.66

Rick is creating a love potion for Morty. To make the potion, Rick's needs 51 mL of a mixture solution where 40% is carbonated water. After checking around his shop, Rick finds two solutions he could use. The first solution he found is 65% green tea, 15% carbonated water, and 20% whole milk. The second solution is 17% orange juice, 38% lemonade, and 45% carbonated water. How much of the first solution and second solution does Rick need to mix together to create the love potion? Round your final answers to one decimal place. You may solve this problem using any method we have learned in the class.

Answers

Answer:

The amount of the first solution rick needs to mix together to create the love portion is 8.5 mL

Explanation:

So as to make the love potion, we have;

The percentage of carbonated water in the love portion = 40%

The percentage of green tea in the first solution = 65%

The percentage of carbonated water in the first solution = 15%

The percentage of whole milk in the first solution = 20%

The percentage of orange juice in the second solution = 17%

The percentage of lemonade in the second solution = 38%

The percentage of carbonated water in the second solution = 45%

Let 'x' represent the volume in mL of the first solution added to make the love portion, and let 'y' be the volume in mL of the second solution added to make the love portion, we have;

x + y = 51...(1)

0.15·x + 0.45·y = 0.40×51 = 20.4

0.15·x + 0.45·y = 20.4...(2)

Solving the system of simultaneous equation by making 'y' the subject of each of the equation gives;

For equation (1)

y = 51 - x

For equation (2)

y = 20.4/0.45 - (0.15/0.45)·x = 136 - 3·x

y = 136/3 - (1/3)·x

Equating the two equations of 'y', gives;

51 - x = 136/3 - (1/3)·x

51 - 136/3 = x - (1/3)·x

17/3 = (2/3)·x

(2/3)·x = 17/3

x = (3/2) × (17/3) = 17/2 = 8.5

x = 8.5

y = 51 - x = 42.5

y = 42.5

Therefore, the amount of the first solution rick needs to mix together to create the love portion, x = 8.5 mL

What is the mass of 0.063x10^-4 moles of aluminum sulphate ?

Answers

Answer:

The mass of 0.063*10⁻⁴ moles of aluminum sulphate  is 2.15*10⁻³ grams.

Explanation:

Aluminum sulfate Al₂(SO₄)₃ has a molar mass of 342.15 g/mol.

Molar mass is the amount of mass that a substance contains in one mole of a substance, which can be an element or a compound.

So in this case you can apply the following rule of three: if 342.15 grams are present in 1 mole of aluminum sulfate, how much mass is present in 0.063*10⁻⁴ moles of the compound?

[tex]mass of aluminum sulphate=\frac{0.063*10^{-4}moles*342.15 grams }{1 mole}[/tex]

mass of aluminum sulphate= 2.15*10⁻³ grams

The mass of 0.063*10⁻⁴ moles of aluminum sulphate  is 2.15*10⁻³ grams.

After you set up your apparatus for the second part of the experiment, your group begins to add the textbooks on top of the plunger. It appears that the plunger continues to drop with every added book and does not return to its original place after the books are removed. What possible sources of error could be given for this experimental outcome? Be specific and give at least two reasons.

Answers

The possible sources of error that could be given for this experimental outcome is the change in the density of the air.

What is an experiment?

An experiment simply means the procedure that is carried out in order to refute a particular hypothesis. It should be noted that experiments are important to provide insights into the cause and effect of a particular situation.

In this situation, with every added book, the volume of that air column will reduce. It is just important that the temperature should remain constant when the gas compression is taking place.

Another source of error is the assumption of moles that was assumed was constant during the experiment. In this scenario, it's possible that some gas could have escaped while the compression was taking place.

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Copper has a specific heat of 0,900 J(g C). How much energy in kJ is needed to raise the temperature of a 700 g block of aluminum from 30.7°C to 82,1C?(show your steps)

Answers

Answer:

32.4 kJ

Explanation:

Given that:

Specific heat capacity fo copper, c = 0.9

Mass of copper, m = 700 g

Temperature change, dθ ;t2 - t1 = (82.1 - 30.7) = 51.4

Energy required, E = mcdθ

E = 700 * 0.9 * 51.4

E = 32382 J

Energy required on kJ

32382 / 1000

= 32.382 kJ

= 32.4 kJ

I need help with like 35 questions anyone willing to help please let me know I have discord

UnknownGoddxss#2795

Please I only have like 5 hours to complete this

Answers

Answer and Explanation:

The molar mass of a substance is all of the weights from the elements combined.

So, we have the elements

CU, S, and [tex]O_{4}[/tex]

CU has a mass is 65

S mass is 32

O has a mass of 16, but there's 4 atoms of O, so we do 16 times 4, which is 64.

Now we add.

65 + 32 + 64 is 161.

So, the answer is 160, or answer choice A.

#teamtrees #PAW (Plant And Water)

Balance the chemical equation
C2H6+O2 = CO2 +H2O

Answers

c26886
........................

Which of the following is a characteristic of both the Earth and the Moon?
Fossils and fossil
fuels under the
surface
Rocky surface
covered with
landforms
Flowing water in
Oceans and rivers
Atmosphere
containing oxygen

Answers

Answer:

rocky surface covered with landforms

Explanation:

Cool air can hold less water vapor than warm air. Apply this fact to explain why clouds and precipitation form on the windward side of the mountain.​

Answers

The pressure is directly proportional to temperature (when the pressure decrease the temperature decrease too). Because the air parcel expands so the molecules will not interact with each other as much.

The energy of the particles does not change but the fact that the particles are more spaced out means the parcel is cooler.

so now, the warmer a parcel of air the more water vapor it can hold. so, if a parcel of air cools it's ability to hold water vapor drops and if it drops to a low enough point that is when the water vapor will condense and turn back into liquid water. This is how clouds and precipitation form on the the windward side of the mountain.

Clouds and precipitation form on the windward side of the mountain due to change in temperature and pressure.

What is the relation between pressure and temperature?

Temperature of any substance is directly proportional to the pressure of that substance.

If the temperature of the wind increases so that winds get warmer and at the same time pressure of gas also increases, due to which particles will go far from each other. After this warm air rises up and cools down will condenses to form clouds, after this precipitate will falls on the windward side of the mountain.

Hence due to temperature and pressure precipitate will form on the windward side of the mountain.​

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Liquids B and C are partially miscible at 25 oC. When one starts with 1 mol of C at 25 oC and isothermally adds B a little at a time, a two-phase system first appears when a bit more than 0.125 mol of B has been added; continuing to add B, one finds the two-phase system becomes a one-phase system when a total of 3 mol of B has been added. For a system consisting of 2.5 mol of B and 2 mol of C at 25 oC, find the number of moles of B and of C present in each phase.

Answers

Answer:

[tex]0.8\overline 3[/tex] moles of A and 2.5 moles of B in the one-phase system

[tex]1.1 \overline 6[/tex] moles of A and [tex]0.1458 \overline 3[/tex] moles of B in the two-phase system

[tex]0.3541 \overline 6[/tex] moles of B remains in the system

Explanation:

The given parameters are;

The extent of miscibility of liquid B and C = Partially miscible

The number of moles of liquid B added to 1 mole of liquid A that forms a two-phase system = 0.125 mol of liquid B

The number of moles of liquid B added to 1 mole of liquid A that forms a one -phase system = 3 moles of liquid B

Whereby the system consist of 2.5 mol of B and 2 mol of C at 25°C, we have;

The 1 mole of A mixes with 3 moles of B to form a single phase solution

Therefore;

2.5 moles of B will mix with (1/3)×2.5 moles of A = 5/6 moles of A

The remaining number of moles of A in the system = 2 - 5/6 =  7/6 moles of A

Similarly, we have;

At least, 0.125 mole of B combines with 1 mole of A to form a two-phase system

7/6 moles of A will combine with 7/6 × 0.125 = 7/48 moles of B to form a two-phase system

The number of moles of B left = 0.5 - 7/48 = 17/48 = 0.3541[tex]\overline 6[/tex] moles of A

Therefore, we have;

5/6 moles of A and 2.5 moles of B in the one-phase system

7/6 moles of A and 7/48 moles of B in the two-phase system

17/48 moles of B remaining in the system

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