!pls help!
Use a net to find the surface area

this figure can be divided into three parts one is rectangle other one is semicircle and the third one is one fourth of the circle .so let's find the area of each figure one by one. For the rectangle 12×8 =96

for semicircle that is on the top it has the radius 6 which is a half of 12

so area of the semicircle is

[tex] \frac{1}{2} \pi \: r {}^{2} \\ \frac{1}{2} \times 3.14 \times 6 {}^{2} \\ 3.14 \times 18 \\ 56.52[/tex]

no that's fine. 80 of the 1/4 of the other Circle

[tex] \frac{1}{4} \pi {}^{2} \\ \frac{1}{4} 3.14 \times 8 {}^{2} \\ 3.14 \times 16 \\ 50.24[/tex]

add all these areas

96+56.52+50.24 =202.76

There are 12 month in a year :

6360 ÷ 12 = 530

Thus the labour earns Rs 530 in a month .

To find this out we will divide 6360 by 12 (as there are 12 months in an year) 6360/12 = 530 . Therefore answer = rs 530

Pls follow and mark brainliest.

Answer:

x = 1, y = 2 , z = 3

Step-by-step explanation:

[tex]6x\:+\:2y\:-4z\:=\:-2 \ \ \ \ \ \ \ \ \ -----( 1 ) \:\\\\-3x-4y\:+2z\:=\:-5 \ \ \ \ \ \ ------( 2 ) \:\\\\4x-\:6y\:+3z\:=\:1 \ \ \ \ \ \ \ \ \ \ \ \ ------- ( 3 ) \\\\( 2 ) \times 2=> -6x -8y + 4z = -10 \ \ \ \ \ \ \ -----( 4)[/tex]

Now add ( 1 ) and  (4)

[tex]6x +2y -4z = - 2\\\\-6x-8y - 4z = -10\\\\=>0x -6y + 0 = - 12\\\\-6y = -12[/tex]

y = 2

Now multiply ( 1 ) by  2 and (3) by 3

[tex](1) \times 2 => 12x + 4y -8z = -4\\\\(3) \times 3 => 12x -18y +9z = 3\\\\Subtract \ the \ equation : ( 1) - ( 3) => 0x +22y -17z = -7[/tex] ------ ( 5 )

Substitute y = 2 in ( 5 ) :

[tex]22(2) - 17z = - 7\\\\ 44 - 17z = - 7\\\\ -17z = - 7 - 44\\\\ -17z = -51\\\\[/tex]

z = 3

Substitute z = 3 and y = 2 in ( 1 ) :

[tex]6x + 2y - 4z = - 2\\\\6x + 2( 2) -4( 3) = -2\\\\6x + 4 - 12 = -2\\\\6x - 8 = - 2\\\\6x = - 2 + 8 \\\\6x = 6\\[/tex]

x = 1

Answer:

For cobalt-60, which has a half-life of 5.27 years, 50% remains after 5.27 years (one half-life), 25% remains after 10.54 years (two half-lives), 12.5% remains after 15.81 years (three half-lives), and so on.

Step-by-step explanation:

You can figue out the rest.

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\large\textsf{Guide}\downarrow[/tex]

[tex]\large\textsf{Penny: 1 cent} \\\large\textsf{Nickel: 5 cents}\\\large\textsf{Dime: 10 cents}\\\large\textsf{Quarter: 25 cents}\\\large\textsf{Half dollar: 50 cents}\\\large\textsf{1 bill = 1 dollar}[/tex]

[tex]\large\textsf{6 dimes:}\downarrow[/tex]

[tex]\large\textsf{= 10 + 10 + 10 + 10 + 10 + 10}[/tex]

[tex]\large\textsf{= 20 + 20 + 20}[/tex]

[tex]\large\textsf{= 40 + 20}[/tex]

[tex]\large\textsf{= \bf 60}[/tex]

[tex]\large\textsf{6 dimes = \bf 60 cents}[/tex]

[tex]\large\textsf{8 nickels}[/tex]

[tex]\large\textsf{= 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5}[/tex]

[tex]\large\textsf{= 10 + 10 + 10 + 10}[/tex]

[tex]\mathsf{= 20 + 20}[/tex]

[tex]\large\textsf{= \bf 40}[/tex]

[tex]\large\textsf{8 nickels = \bf 40 cents}[/tex]

[tex]\large\textsf{3 one dollar bills}[/tex]

[tex]\large\textsf{= 1 + 1 + 1}[/tex]

[tex]\large\textsf{= 2 + 1 }[/tex]

[tex]\large\textsf{= \bf 3}[/tex]

[tex]\large\textsf{3 one dollar bills = \bf 3 dollars}[/tex]

[tex]\large\textsf{NOW LETS SOLVE FOR YOUR EQUATION}[/tex]

[tex]\large\textsf{3.00 + 0.60 + 0.40}[/tex]

[tex]\large\textsf{= 3.60 + 0.40 }[/tex]

[tex]\large\textsf{= \bf \$4}[/tex]

[tex]\boxed{\boxed{\large\textsf{Therefore, your answer is: \huge \bf \$4}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

The answers are as follows part A = 30m+15  part B =3m+15+27m

and partC = 30m+15

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition,substraction, multiplication and division.

Part A:- Two expressions that are equivalent to the given expressions are:-

3m   +   15   +   27m

30m  +   15

Part B:  Show that one of your expressions in Part A is equivalent to the given expression using algebraic properties.

3  (  m   +   5    +   9m   )

Open the bracket by multiplying 3 by what is in the bracket

3m   +   15   +   27m

Part C: Show that your other expression from Part A is equivalent to the given expression by substituting a number for m.

3   (  m    +   5   +   9m  )

Open the bracket by multiplying 3 by what is in the bracket

3m    +    15    +     27m

Collect like terms together

3m    +     27m  +   15

=   30m   +    15

To know more about Expression follow

https://brainly.com/question/723406

#SPJ2

Answer:

20°

Step-by-step explanation:

perpendicular from the center on a chord of a circle always bisects the chord.

AR=BR

∴m arcAC=m arc BC=20°

Answer: 15.3 cm

Step-by-step explanation:

The actual length of the line in question is 1.53km.

The scale is 10 cm to 1 km.

You can therefore use direct proportion to solve this.

Assume the length on the drawing is x:

10cm  :   1km

x cm  :   1.53 km

Cross multiply:

x = 15.3 cm

Answer:

396

Step-by-step explanation:

It's a square.

That means that all four sides are equal.

So the two expressions you have been given are equal.

2.5x + 76.5 = 12x - 9            Subtract 2.5x from both sides.

-2.5x               -2.5x  

          76.5 = 9.5x - 9          Add 9 to both sides

           9                 9

          85.5 = 9.5x              Divide by 9.5

       85.5/9.5 = x

x = 9

That is just the value for x. It is not the answer

Side = 12x - 9

Side = 12*9 - 9

Side = 108 - 9

Side = 99

The perimeter = 4 * Side

The perimeter = 4 * 99

Perimeter = 396

9514 1404 393

Answer:

  0.261 ohm

Step-by-step explanation:

If the radius increases by a factor of 0.7/0.4= 7/4, the square of this factor is (7/4)^2 = 49/16. The inverse of this square is 16/49, which is the factor by which the resistance changed.

The resistance of the larger wire is ...

  (16/49)(0.80 ohm) ≈ 0.261 ohm

Answer:

3

Step-by-step explanation:

4.5x 2 = 9

[tex]\sqrt{9}[/tex]= 3

Answer:

$2182.13

Step-by-step explanation:

Simple interest (I) is calculated as

I = [tex]\frac{PRT}{100}[/tex] ( P is principal, R is rate of interest, T is time in years )

Here P = $34,500 , R = 6.9 and T = [tex]\frac{11}{12}[/tex] , then

I = [tex]\frac{34500(6.9)(\frac{11}{12}) }{100}[/tex]

  = 345 × 6.9 × [tex]\frac{11}{12}[/tex]

  = $2182.13

Answer:

9 hundreds that is the answer

Answer:

{2,4,6}

Step-by-step explanation:

Hope it helps you

Answer:

Profit = Selling price - Variable cost  

Formulas:  

F2 =SUMPRODUCT(B2:E2,$B$16:$E$16) copy to F2:F12, F14  

Optimal solution: The company should produce the following quantities (in pounds) of the four varieties of nuts.  

Whole = 1000  

Cluster = 500  

Crunch = 80  

Roasted = 200  

Total profit = $ 2913.20

Step-by-step explanation:

Answer:

(a+b)²=a²+b²+2ab

Step-by-step explanation:

The square of sum of two terms is equal to the squared plus squared plus times product of and . In mathematics, the plus whole squared algebraic identity is called in three ways. The square of sum of two terms identity.

Answer:

A = 41.4°

Step-by-step explanation:

Reference angle = A

Length of Adjacent side = 6

Length of Hypotenuse = 8

Apply the trigonometric function, CAH.

Cos A = Adj/Hyp

Substitute

[tex] Cos(A) = \frac{6}{8} [/tex]

[tex] A = Cos^{-1}(\frac{6}{8}) [/tex]

A = 41.4° (approximated to the nearest tenth)

Answer:

4)8 goats, 3 hens.

Step-by-step explanation:

8*4=32

3*2=6

32+6=38

Answer:

4. (2, 3)

5. (0, 1)

7. (-1, 2)

Step-by-step explanation:

I hope this helps! Have a nice dayy! :)

You're very close. Choices D and E are two of the three answers. The third answer is choice G (-1,2)

If you plug the coordinates of the points into the inequality, you should get a true statement.

For instance, let's try the coordinates of choice G

[tex]-2x + 3y\ge 3\\\\-2(-1) + 3(2)\ge 3\\\\2 + 6\ge 3\\\\8\ge 3\\\\[/tex]

Which is true since 8 is indeed greater than 3. That verifies point G is a solution point. A similar story happens with points D and E as well.

----------

If you tried something like choice A, then,

[tex]-2x + 3y\ge 3\\\\-2*(2) + 3(-3)\ge 3\\\\-4 - 9\ge 3\\\\-13\ge 3\\\\[/tex]

Which is false because -13 is not greater than 3, and -13 is not equal to 3 either. So choice A is a non-answer. You should find that choices B, C, and F are also non-answers.

----------

The graph is below. Notice how points D, E and G are either in the blue shaded region or on the boundary. The boundary line is solid (due to the "or equal to" as part of the inequality sign), so points on the solid boundary line are part of the solution set. The graph is a quick way to visually confirm the answers. I used GeoGebra to make the graph.

So that's why the 3 answers are D, E and G.

Answer:

it says round to the nearest 10th so it wouldn't be 81, it would be 81.8%

Answer:

Buses - 43 people

Vans - 12 people

9514 1404 393

Answer:

  182 lbs

Step-by-step explanation:

You can write the proportion for the required patient weight (w) as ...

  weight/medicine = w/(174.72 mg) = (150 lb)/(144 mg)

  w = (150 lb)(174.72/144) . . . . . multiply by 174.72 mg

  w ≈ 182 lb

The patient's weight is 182 pounds.

Answer:

2+3+4+6 = 15 parts

Village B gets 3 of 15 parts

3/15 * 30000 = 6000 bags

Village C gets 4 of 15 parts

4/15 * 6000 = 8000 bags

Answer:

each "share" needs "15" (2+3+4+6) "portions/bags"

2000 distributions

A-4000 bags/80000 kg

B-6000 bags/120000 kg

C-8000 bags/1680000 kg

D-12000 bags/240000 kg

Step-by-step explanation:

Answer:

s(t) = 160/3  ( 1 - e^(-3t / 200) )

Step-by-step explanation:

volume of pure water in tank  = 1000 L

Brine contains 0.04kg of salt/L

Inflow rate of Brine containing 0.04kg of salt/L = 5L/min

Brine containing 0.06 kg of salt/L

Inflow rate of Brine containing 0.06 kg of salt/L = 10L/min

Solution is thoroughly mixed and drains from tank at 15L/min

a) Determine the amount of salt is in the tank after t minutes

rate of salt entering = 0.2 + 0.6 = 0.8 kg/min

rate of salt leaving = s/1000 * 15

amount of salt at time (t) = s(t)

initial condition s( 0 ) = 0

ds/dt = 0.8 - 15s/1000 = 0.8 - 3s/200

200 ds/dt = ( 160 - 3s )

-200/3  In ( 160 - 3s ) = t + c

Given that ;  t = 0 , s = 0    

c =  - 200/3  In ( 160 )

∴  -200/3  In ( 160 - 3s ) = t - 200/3  In ( 160 )

- 200/3  [ In ( 60 - 3s ) - In ( 160 ) ] = t

therefore:  

In ( 160 - 3s / 160 ) = -3t/200

= ( 160 - 3s / 160 ) = e ^ (-3t/200 )

Hence amount of salt in tank after t minutes

s(t) = 160/3  ( 1 - e^(-3t / 200) )

Answer:

460 is part of the confidence interval, which means that we cannot say that there is significant evidence that the mean mathematics SAT score for entering freshmen class is greater than 460

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.99}{2} = 0.005[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.005 = 0.995[/tex], so Z = 2.575.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 2.575\frac{101}{\sqrt{90}} = 27.4[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 436 - 27.4 = 408.6.

The upper end of the interval is the sample mean added to M. So it is 436 + 27.4 = 463.4.

460 is part of the confidence interval, which means that we cannot say that there is significant evidence that the mean mathematics SAT score for entering freshmen class is greater than 460

Answer:

a) 2 nonsingular 2 by 2  matrices are not closed when added together hence it is not a vector space( i.e. their sum = singular and not nonsingular )

b) 2 singular 2 by 2 matrices is not  closed under addition, hence they are not a vector space. ( i.e. their sum = nonsingular )

Step-by-step explanation:

a) Prove that nonsingular 2 by 2 matrices is not a vector space

2 nonsingular matrices are not closed when added together hence it is not a vector space ( i.e. their sum = singular and not nonsingular )

vector A = [tex]\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right][/tex]    +  vector B =  [tex]\left[\begin{array}{ccc}0&1\\1&0\\\end{array}\right][/tex] = [tex]\left[\begin{array}{ccc}1&1\\1&1\\\end{array}\right][/tex] ( singular vector )

b) Prove that singular 2 by 2 matrices is not a vector space

2 singular 2 by 2 matrices is not  closed under addition, hence they are not a vector space. ( i.e. their sum = nonsingular )

Vector C = [tex]\left[\begin{array}{ccc}1&0\\0&0\\\end{array}\right][/tex]  + vector D = [tex]\left[\begin{array}{ccc}0&0\\0&1\\\end{array}\right][/tex] = [tex]\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right][/tex] ( nonsingular vector )

Max is participating at a school bake sale. Each cookie he sells costs 50 cents. Unfortunately, it took 6 dollars to buy the materials for the cookies. Find how much money would it take for Max to break even.

Answer:

Step-by-step explanation:

4 years ago when Mary was 6, she was one half the age of her brother.  

 How old is her brother now?

Solution :

Let brother's age be = x

Four years ago, brothers age was = (x - 4)

Four years ago Mary was = 6

She was half the age of her brother

                                                   [tex]6 = \frac{1}{2} (x - 4)[/tex]