Students collect $24 for every 10 tickets sold. Suppose m is the amount of money the students collect for selling r raffle tickets. Write an equation that reflects the relationship between m and r

Answer:

Next plug the y into the second equation to solve for x

Now we know x and we can plug into the original equation (1)

Rate brainlist and drop a follow for future help

Answer:

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    6*x-6*y-(18)=0  

STEP

1

:

Pulling out like terms

1.1     Pull out like factors :

  6x - 6y - 18  =   6 • (x - y - 3)  

Equation at the end of step

1

:

STEP

2

:

Equations which are never true:

2.1      Solve :    6   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Equation of a Straight Line

2.2     Solve   x-y-3  = 0

Tiger recognizes that we have here an equation of a straight line. Such an equation is usually written y=mx+b ("y=mx+c" in the UK).

Step-by-step explanation:

x= 1 y= 1

hope am right if i am, pls brainliest

Answer:

No

Step-by-step explanation:

A: C = 60 + 0.15m (C is total cost and m is no. of miles)

B: C = 25d (d is no. of days)

For a weekend trip, there are 2 days.

This means that the cost for B is 2*$25, which is $50.

It doesn't matter how many miles are driven for A because the cost will always be at least $60.

This means that B is cheaper and that Jason is inaccurate.

Answer:

Aaliyah is 18years old now

Step-by-step explanation:

let AJ's age=x

Aaliyah's age=3x

Four years ago,

AJ's age=x-4

Aaliyah's age=3x-4

3x-4=7(x-4)

3x-4=7x-28

3x-7x=-28+4

-4x=-24

x=6

Aaliyah's present age=3x=3×6=18

Answer:

21$

Step-by-step explanation:

2 pizzas =18 plus 3 toppings which equals 21$

Full question attached

Answer and explanation:

Null hypothesis : all population proportions are equal, p1=p2=p3=p4

Alternative hypothesis : Not all population proportions are equal

To find our p-value using chi Square method, we first find expected frequencies from observed frequencies above

Expected Frequencies:

Gender A. B. C. D

Male. 46.81 46.81 44.21 43.17

Female 43.19. 43.19 40.79 39.83

Total = 348

chi Square for table = (observed frequency - expected frequency)²/expected frequency

Gender. A. B. C. D

Male. 0.10 0.17 0.52 0.40

Female 0.11 0.18 0.56 0.44

x²= 2.49

Degrees of freedom(df)= k – 1 = (4 – 1) = 3

Using the chi Square table with degree of freedom = 3, 2 and x²= 2.49 shows, the p –value = 0.4771 therefore we do not reject null hypothesis since p value is greater than significance level 0.08

We do not reject the null hypothesis

b. There is no evidence of differences in proportion

9514 1404 393

Answer:

  74.28 ft

Step-by-step explanation:

The tangent of the angle is the ratio of opposite side (lighthouse height) to adjacent side (distance from lighthouse).

  tan(23°) = height/(175 ft)

  height = (175 ft)·tan(23°) ≈ 74.28 ft

Answer:

The club must sell 18 jackets to break even

Step-by-step explanation:

Given:

C = 20x + 270

Where,

x = number of jackets

Equation for revenue R in terms of the number of jackets

Revenue = price × quantity

Price of the jacket = $35

Quantity of the jacket = x

Revenue = price × quantity

= 35 * x

R = 35x

Break even point is the point at which cost is equal to revenue, that is, no gain; no loss.

Cost = revenue

20x + 270 = 35x

270 = 35x - 20x

270 = 15x

x = 270 / 15

= 18

x = 18 jackets

The club must sell 18 jackets to break even

Answer:

torture

Step-by-step explanation:

I was just working on a prblem like this and I hate it

f(x)=5x-3

use the substitution method

f(5)=(5)(5)-3

multiply the parentheses first

using: PEDMAS

P=Parentheses

E= Exponents

D=Division

M=Multiplication

A= Addition

S=Subtraction

(5)(5)=25

25-3

=22

answer:

f(5)=22

Answer:

Check mark number

2

4

5

Answer:

5 x 13,50= 6,750

Step-by-step explanation:

5,400 is the answer of the persentage. I subtracted 6,750 from 1350 and got 6,750

Cost of 1 night:-

[tex]\\ \sf\longmapsto \dfrac{1350}{5}[/tex]

[tex]\\ \sf\longmapsto \dfrac{270}{1}[/tex]

[tex]\\ \sf\longmapsto 270[/tex]

Answer:

5250

i hope this is right.

Answer:

5250

Step-by-step explanation:

person on my top got it ^

Answer: SAS

Step-by-step explanation:

It is given that the two sides are congruent.

The angle between the two congruent sides is also congruent because of the vertical angle theorem.

Since a side, angle, and side are congruent, the theorem is SAS.

Answer:

100x-p*1%

Step-by-step explanation:

Answer:

75

a(0.80)=60

a=60/0.80

a=75

Step-by-step explanation:

For 4.

4b + 2b + 3b = 180°< Sum of angles of triangle >

9b = 180°

b = 180° / 9

b = 20°

4b = 4* 20° = 80°

2b = 2* 20° = 40°

3b = 3 * 20° = 60°

For 5.

x = 64° + 45° <Exterior angle of a triangle is equal to the sum of two opposite interior angles>

x = 109°

Hope it helps :)

Answer:

12

Step-by-step explanation:

To find perimeter, add the lengths of each side. 5 + 4 + 3 = 12

Answer:

12

Step-by-step explanation:

5+4+3

Answer:

Put 2 feet down for both of them and add 3 extra feet for nate

Step-by-step explanation:

Answer:

add 3 extra feet for Nate and put 2 feet from the both of them

Step-by-step explanation:

Answer:

y = -4x - 9

Step-by-step explanation:

Use slope intercept form, y = mx + b, where m is the slope and b is the y intercept.

Since we are already given the slope and y intercept, we just have to plug them into the equation to find the equation:

y = mx + b

y = -4x - 9

So, y = -4x - 9 is the equation of the line in slope intercept form

Answer:

15) K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]

19) P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]

20) Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)

Step-by-step explanation:

We are to find the derivative of the questions pointed out.

15) K(t) = 5(5^(t)) - 2(3^(t))

Using implicit differentiation, we have;

K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]

19) P(w) = 2e^(w) - (2^(w))/5

P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]

20) Q(W) = 3w^(-2) + w^(-2/5) - w^(¼)

Q'(w) = -6w^(-2 - 1) + (-2/5)w^(-2/5 - 1) - ¼w^(¼ - 1)

Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)

Answer:

123idbd8dbokeofyccbdid12332

Answer:

Step-by-step explanation:

-6n + 2.9 = 11

subtract 2.9 from both sides

-6n = 8.1

divide both sides by -6

n = -1.35

2/3n - 3 = 8

add 3 to both sides

2/3n = 11

multiply both sides by 3

2n = 33

divide both sides by 2

n = 16.5

hope this helps <3

Answer:

left side:

-6n = 11 - 2.9

-6n = 8.1

n = - 8.1/6

n = - 1.35

right side:

2/3 n = 8 + 3

2/3 n = 11

n = 33/2

n = 16.5

Answer:

24 is the correct answer

Answer:

[tex]\displaystyle \frac{2 \cdot sin2x-cos2x}{5e^x} + C[/tex]

Step-by-step explanation:

The integration by parts formula is: [tex]\displaystyle \int udv = uv - \int vdu[/tex]

Let's find u, du, dv, and v for [tex]\displaystyle \int e^-^x \cdot cos2x \ dx[/tex] .

Plug these values into the IBP formula:

Now let's evaluate the integral [tex]\displaystyle \int \frac{sin2x}{2} \cdot -e^-^x dx[/tex].

Let's find u, du, dv, and v for this integral:

Plug these values into the IBP formula:

Factor 1/4 out of the integral and we are left with the exact same integral from the question.

Let's substitute this back into the first IBP equation.

Simplify inside the brackets.

Distribute the negative sign into the parentheses.

Add the like term to the left side.

Make the fractions have common denominators.

Simplify this equation.

Multiply the right side by the reciprocal of 5/4.

The 4's cancel out and we are left with:

Factor [tex]e^-^x[/tex] out of the numerator.

Simplify this by using exponential properties.

The final answer is [tex]\displaystyle \int e^-^x \cdot cos2x \ dx = \frac{2 \cdot sin2x-cos2x}{5e^x} + C[/tex].

Answer:

[tex]\displaystyle\int e^{-x}\cos(2x)\, dx=\frac{2\sin(2x)-\cos(2x)}{5e^x}+C[/tex]

Step-by-step explanation:

We would like to integrate the following integral:

[tex]\displaystyle \int e^{-x}\cdot \cos(2x)\, dx[/tex]

Since this is a product of two functions, we can consider using Integration by Parts given by:

[tex]\displaystyle \int u\, dv =uv-\int v\, du[/tex]

So, let’s choose our u and dv. We can choose u base on the following guidelines: LIATE; or, logarithmic, inverse trig., algebraic, trigonometric, and exponential.

Since trigonometric comes before exponential, we will let:

[tex]u=\cos(2x)\text{ and } dv=e^{-x}\, dx[/tex]

By finding the differential of the left and integrating the right, we acquire:

[tex]du=-2\sin(2x)\text{ and } v=-e^{-x}[/tex]

So, our integral becomes:

[tex]\displaystyle \int e^{-x}\cdot \cos(2x)\, dx=(\cos(2x))(-e^{-x})-\int (-e^{-x})(-2\sin(2x))\, dx[/tex]

Simplify:

[tex]\displaystyle \int e^{-x}\cdot \cos(2x)\, dx=-e^{-x}\cos(2x)-2\int e^{-x}\sin(2x)\, dx[/tex]

Since we ended up with another integral of a product of two functions, we can apply integration by parts again. Using the above guidelines, we get that:

[tex]u=\sin(2x)\text{ and } dv=e^{-x}\, dx[/tex]

By finding the differential of the left and integrating the right, we acquire:

[tex]du=2\cos(2x)\, dx\text{ and } v=-e^{-x}[/tex]

This yields:

[tex]\displaystyle \int e^{-x}\cdot \cos(2x)\, dx=-e^{-x}\cos(2x)-2\Big[(\sin(2x))(-e^{-x})-\int (-e^{-x})(2\sin(2x))\, dx\Big][/tex]

Simplify:

[tex]\displaystyle \int e^{-x}\cdot \cos(2x)\, dx=-e^{-x}\cos(2x)-2\Big[-e^{-x}\sin(2x)+2\int e^{-x}\cos(2x)\, dx\Big][/tex]

We can distribute:

[tex]\displaystyle \int e^{-x}\cdot \cos(2x)\, dx=-e^{-x}\cos(2x)+2e^{-x}\sin(2x)-4\int e^{-x}\cos(2x)\, dx[/tex]

The integral on the right is the same as our original integral. So, we can isolate it:

[tex]\displaystyle \Big(\int e^{-x}\cos(2x)\, dx\Big)+4\Big(\int e^{-x}\cos(2x)\, dx)\Big)=-e^{-x}\cos(2x)+2e^{-x}\sin(2x)[/tex]

Combine like integrals:

[tex]\displaystyle 5 \int e^{-x}\cos(2x)\, dx=-e^{-x}\cos(2x)+2e^{-x}\sin(2x)[/tex]

We can factor out an e⁻ˣ from the right:

[tex]\displaystyle 5\int e^{-x}\cos(2x)\, dx=e^{-x}\Big(-\cos(2x)+2\sin(2x)\Big)[/tex]

Dividing both sides by 5 yields:

[tex]\displaystyle \int e^{-x}\cos(2x)\, dx=\frac{e^{-x}}{5}\Big(-\cos(2x)+2\sin(2x)\Big)[/tex]

Rewrite. We of course also need the constant of integration. Therefore, our final answer is:

[tex]\displaystyle\int e^{-x}\cos(2x)\, dx=\frac{2\sin(2x)-\cos(2x)}{5e^x}+C[/tex]

Answer:

20%

Step-by-step explanation:

Answer:

k=1/2

It is a reduction

Step-by-step explanation:

To the scale factor, you simply divide the length of the post image by the image.

10/20=k

1/2=k