What is the weight of a 25 kg object on Earth with an acceleration due to gravity of 9.8m/s/s?

2.45 n
24.5 n
245 n
2450 n​

Answers

Answer 1
245 n hope this helps
What Is The Weight Of A 25 Kg Object On Earth With An Acceleration Due To Gravity Of 9.8m/s/s?2.45 N24.5

Related Questions

What are characteristics of wide-angle lenses?

Answers

One of the characteristics of a wide-angle lens is the ability to capture the expanse of a scene in an image with its wide angle of view. Also, it is able to create an intriguing deformed effect when you photograph the subject from a close distance. These characteristics can be utilised to bring out the shape of a subject or the depth of a landscape. That being said, care is needed as distortion is more likely to occur toward the edges of the image. To make effective use of a wide-angle lens, it is important to control both the angle of view as well as distortions in the image at the same time. By doing so, you will be able to add a dynamic touch to your photographic expression.

What x rays travel at the speed of

Answers

What is the speed? Like we need the pic or something

Which statement best describes this situation

Answers

Answer:

what situation?

Explanation:

Which subatomic particle identifies the element?

A.
protons

B.
electrons

C.
neutrons

D.
atomic mass

Answers

a. protons.ekgfsbdbsi

Answer:

A. Protons

Explanation:

Atomic number is an indicator of how many protons an element possesses in its nucleus. We use atomic number to identify an element. For example, carbon has 6 protons and an atomic number of 6.

Which word best completes the sentence?

Select the word from the drop-down menu

He is quite
Choose...
despite never having left his smalL TOWEN

Answers

Answer:

it’s cosmopolitan

Explanation:

k12

An official major league baseball has a mass of 0.14 kg. A pitcher throws a 40 m/s fastball which is hit by the batter straight back up the middle at a speed of 46 m/s.
a) What is the change in momentum of the ball during the collision with the bat?
b) If this collision occurs during a time of 0.012 seconds, what is the average force exerted by the bat on the ball?

Answers

Answer:

(a) The change in momentum is 12.04 kg-m/s

(b) The force exerted by the bat is 1003.33 N

Explanation:

Given that,

The mass of a ball, m = 0.14 kg

Initial speed of the ball, u = 40 m/s

Final speed of the ball, v = -46 m/s

(a) The change in momentum of the ball during the collision with the bat is given by :

[tex]\Delta p=m(v-u)\\\\=0.14(-46-40)\\\\=-12.04\ kg-m/s[/tex]

(b) Time for collision, t = 0.012 s

Now the force can be calculated as follows :

[tex]F=\dfrac{\Delta p}{t}\\\\F=\dfrac{12.04}{0.012}\\\\=1003.33\ N[/tex]

Hence, this is the required solution.

Answer:

a. = 12.04 kg*m/s

b. = 1,003.3N

Explanation:

The answer above is correct.

The (BLANK) island were where Darwin made many important observations.

Answers

Answer:

I know theirs South American coast he was there a lot

6xy from -12xy
please give me a answer this question​

Answers

6 floors down from 12 floors underground = 18 floors underground.

6 degrees colder than 12 degrees below zero  =  18 degrees below zero

6 brown cows taken away from -12 brown cows = -18 brown cows

6 cars sold from a dealer that 12 cars were stolen from = 18 cars gone

6xy taken away from -12xy  =  -18xy

If your water heat has an efficiency of 95 percent, how much energy would it take to heat 45kg of water from 23 C to 60 C. (The specific heat of water is 4.18 J/g/C.) Please show your work

Answers

Answer: 6611.715 joules

Explanation:

Q = MxCxdeltaT = 6959.7 which is 100%

95% = 6611.715

A screw-jack used to lift a bus is a
A) first order lever
B) second order lever
C) pulley
D) screw

Answers

second order lever broski

Please help me with this 29 points

Answers

Answer:

)Give the definition of poverty line as defined by the World Bank.

In what way does water change when condensation occurs?

from gas to liquid

from liquid to solid

from liquid to gals

from solid to liquid

Answers

from gas to liquid

please mark brainliest

it takes a cheetah just 3s to reach its top speed of 30m/s what is it's acceleration​

Answers

The acceleration will be "10 m/s²".

Given values are:

Speed,

v = 30 m/s

Time,

t = 3 s

As we know,

→ [tex]Acceleration = \frac{Speed}{Time}[/tex]

or,

→                   [tex]a = \frac{v}{t}[/tex]

By substituting the values,

                       [tex]= \frac{30}{3}[/tex]

                       [tex]= 10 \ m/s^2[/tex]

Thus the above solution is correct.    

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Help please :)

X-ray waves are transmitted by ....... ?

Answers

Answer:

im not sure maybe viberation

Explanation:

Answer:

X-ray waves are transmitted by ....... body tissues with very little absorption

Hope it helps

Please mark me as the brainliest

Thank you

it takes 840s to walk completely around a circular track, moving at a speed of 1.20m/s? what is the radius of the track?

Answers

Answer:

160.43 meters

Explanation:

T=(2*pi*r)/v

840=(2*pi*r)/1.2

1008=2*pi*r

504=pi*r

160.43=radius

The distance around the circular track is equal to its circumference. If it takes840 s  to complete the path with a velocity of 1.20 m/s then the radius of the path will be 160 m.

What is velocity?

Velocity is a physical quantity measuring the distance traveled by unit time. It is a vector quantity thus, characterized by its magnitude and direction. Velocity is usually expressed in m/s.

Velocity is the ratio of distance to the time taken to complete the travel. Thus, greater distance within short time indicates greater velocity.

Given that the time take to complete the circular path = 840 s

velocity = 1.20 m/s

distance = circumference of the circular path = 2πr.

distance = time × velocity

2πr = 840 s × 1.20 m/s

      = 1008 m.

Therefore, the radius r of the circular path  = 1008 m/ 2 π = 160 m.

Hence, the radius of the circular path 160 m.

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One of the smallest planes ever flown was the Bumble Bee II, which had a mass of 180 kg. If the pilot’s mass was 70 kg, what was the velocity of both plane and pilot if their momentum was 20,800 kg∙m/s to the west?

Answers

Answer:

83.2 m/s to the West

Explanation:

From the question given above, the following data were obtained:

Mass of plane = 180 Kg

Mass of pilot = 70 Kg

Momentum = 20800 Kg∙m/s West

Velocity =?

Next, we shall determine the total mass. This can be obtained as follow:

Mass of plane = 180 Kg

Mass of pilot = 70 Kg

Total mass =?

Total mass = Mass of plane + Mass of pilot

Total mass = 180 + 70

Total mass = 250 Kg

Finally, we shall determine the velocity. This can be obtained as follow:

Total mass = 250 Kg

Momentum = 20800 Kg∙m/s West

Velocity =?

Momentum = mass × Velocity

20800 = 250 × Velocity

Divide both side by 250

Velocity = 20800 / 250

Velocity = 83.2 m/s West

Thus, the velocity of both plane and pilot is 83.2 m/s to the West

How much power does motor provides an elevator in a building when the total mass when loaded is 500 kg to a height of 3m in 25 seconds?

Answers

I don’t know...I just need points...sorry

An alumium rod when measured with a steel scale both being at 25 degree celcius appears to be 1 meter long. If the scale is correct at 0 degree celcius, what is the true length of the rod at 25 degree celcius? What wull be the length of rod at 0 degree celcius?​

Answers

Given:
temperature at which the rod is measured= 25°
length of aluminium rod measured at 25°C= 1 meter
temperature at which the scale is correct= 0°C
Linear expansivity of steel= 12* 10^-6
linear expansivity of aluminum= 26* 10^-6
To find:
True length of rod at 25°C
Length of rod at 0°C
Solution:
Let the length of the aluminum and steel rod at 0°C be L0A and L0S respectively.
Length of the steel scale at 25°C , thermal expansion is:
LA25 = LA0(1+ (αS - αA)25)
LA0 = LA25/ (1+ (αS-αA)t)
LA0 = 100/ (1+ (12*10^-6 - 26*10^-6)25)
LA0 ≈ 100.05 cm at 0°C
2. Let the length at 25°C of the aluminium trod be LA25
The actual measure of aluminum rod at 25°C, will be
LA25 = 100 * (1+ 26* 10^-6*25)
LA25 ≈ 100.06 cm

3. If a spring extends by 3 cm when a 4 N weight is suspended from it, find the extension
when the weight is changed to
(a) 8 N
(b) 10 N
(c) 14 N

Answers

8N - 6cm
10N - 7.5cm
14N - 10.5cm

Astronauts living on the International Space Station have zero gravitational acceleration.

True
False

Answers

True I think sorry if not correct, I only want to help :)

19. In a turtle race, a 20 kg turtle moves with a velocity of 0.1 m/s. What is the kinetic energy of the turtle?

A. 20 J

B. 0.2 J

C. 0.1 J

Answers

Answer:
C
Explanation:
KE=1/2mv^2
KE=1/2(20)(0.1)^2
0.1^2= 0.01
KE= 1/2(20)(0.01)
KE= 0.1 J

Help please :)

Infrared waves are transmitted by ....... ?

Answers

Infrared light is the part of the electromagnetic spectrum, and is an electromagnetic form of radiation. It comes from the heat and thermal radiation, and it is not visible to the naked eyes. In infrared transmission, senders can be simple light emitting diodes (LEDs) or laser diodes. Photodiodes act as receivers.
Infrared light is the part of the electromagnetic spectrum, and is an electromagnetic form of radiation. It comes from the heat and thermal radiation, and it is not visible to the naked eyes. In infrared transmission, senders can be simple light emitting diodes (LEDs) or laser diodes. Photodiodes act as receivers.

You are driving your car on a very cold late Fall day. You clear a turn and see a couple of pedestrians standing at the cross walk. They are eager to cross the road and to get into the warmth of their apartment as soon as possible. You have two options: continue driving your car as you were without lowering your speed and drive right by the pedestrians OR slow down, stop right at the crosswalk, and yield to the pedestrians. Although by Virginia law the choice is clear, what about Physics laws? Which scenario (passing by or slowing down and stopping at the crosswalk to yield) will minimize the time the pedestrians are out in the cold freezing before they can cross the road?
Make the following assumptions in your argument. Before you noticed the pedestrians, you are moving with a constant velocity v=22 miles/hour. The distance at which you noticed the pedestrians is D=23 meters. Write down a symbolic expression for the amount of time, tpass , the pedestrians will have to wait till they cross the road if you simply drive by without slowing down or speeding up.
Write down a symbolic expression for the amount of time, tstop, the pedestrians will have to wait till they cross the road if you slow down, come to a complete stop at the crosswalk and yield to the pedestrians.

Answers

Answer:

t_pass = 2.34 m

t_stop = 4.68 s

Thus, for the car passing at constant speed the pedestrian will have to wait less.

Explanation:

If the car is moving with constant speed, then the time taken by it will be given as:

[tex]t_{pass} = \frac{D}{v}[/tex]

where,

t_pass = time taken = ?

D = Distance covered = 23 m

v = constant speed = (22 mi/h)(1609.34 m/1 mi)(1 h/3600 s) = 9.84 m/s

Therefore,

[tex]t_{pass} = \frac{23\ m}{9.84\ m/s} \\[/tex]

t_pass = 2.34 m

Now, for the time to stop the car, we will use third equation of motion to get the acceleration first:

[tex]2as = v_{f}^{2} - v_{i}^2\\a = \frac{v_{f}^{2} - v_{i}^2}{2D}\\\\a = \frac{(0\ m/s)^{2}-(9.84\ m/s)^2}{(2)(23\ m)}\\\\a = -2.1\ m/s^2[/tex]

Now, for the passing time we use first equation of motion:

[tex]v_{f} = v_{i} + at_{stop}\\t_{stop} = \frac{v_{f}-v_{i}}{a}\\\\t_{stop} = \frac{0\ m/s - 9.84\ m/s}{-2.1\ m/s^2}[/tex]

t_stop = 4.68 s

Constant velocity is the velocity which covers the same distance for each interval of the time.

The time required to pass is 2.34 seconds and the time to stop is 4.68 seconds.

What is constant velocity?

Constant velocity is the velocity which covers the same distance for each interval of the time.

It can be given as,

[tex]v=\dfrac{x}{t}[/tex]

As the distance covered by the car is 23 meters and the constant velocity of the car is 22 miles per second.

Convert the unit of velocity in m/s the value obtained will be 9.84 m/s.

Thus amount of time, [tex]t_{pass}[/tex] is,

[tex]9.84=\dfrac{23}{t_{pass} } \\t_{pass} =\dfrac{23}{9.84} \\t_{pass} =2.34[/tex]

As the distance covered by the car is 23 meters and the constant velocity of the car is 22 miles per second.

Convert the unit of velocity in m/s the value obtained will be 9.84 m/s.

Thus amount of time, [tex]t_{pass}[/tex] is,

[tex]9.84=\dfrac{23}{t_{pass} } \\t_{pass} =\dfrac{23}{9.84} \\t_{pass} =2.34[/tex]

According to the third equation of the motion acceleration can be given as,

[tex]v^2-u^2=2ax\\a=\dfrac{v^2-u^2}{2x}\\a=\dfrac{0^2-9.84^2}{2\times 23}\\a=-2.1 \rm \; m/s^2[/tex]

Now, use the first equation of motion, to get the required time,

[tex]v=u+at\\0=9.84+(-2.1)t\\t=4.68\rm \; s[/tex]

Therefore, the time required to pass is 2.34 seconds and the time to stop is 4.68 seconds.

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Suppose that a uniform rope of length L resting on a frictionless horizontal surface, is accelerated along the direction of its length by means of a force F, pulling it at one end. A mass M is accelerated by the rope. Assuming the mass of the rope to be m and the acceleration is a. Stated in terms of the product ma, what is the tension in the rope at the position 0.3 L from the end where the force F is applied if the mass M is 1.5 times the mass of the rope m?

Answers

Answer:

2.2 ma

Explanation:

Given :

Length of the rope = L

Mass of the rope = m

Mass of the object pulled by the rope = M

M = 1.5 m

So, L [tex]$\rightarrow$[/tex] m

For unit length [tex]$\rightarrow \frac{m}{L}$[/tex]

∴ 0.3 L = [tex]$0.3 \ L \left(\frac{m}{L}\right)$[/tex]

            = 0.3 m

And for remaining 0.7 L =  [tex]$0.7 \ L \left(\frac{m}{L}\right)$[/tex]

            = 0.7 m

By Newtons law of motion,

F - T = ( 0.3 m) a .........(1)

T = ( M + 0.7 m) a

T = ( 1.5 m + 0.7 m) a

T = ( 2.2 m ) a  ..............(2)

So from equation (1) and (2), we have

Tension on the rope

T = 2.2 ma

weight is measured in units called

Answers

Pounds

If you are talking about the unit of measurement for weight is that of force it would be Newtons.

The weight is measured in a unit called Newton. The newton is a standard unit of weight measurements.

The International System of Units (SI) uses Newtons (N) as the unit of weight measurement. Weight is frequently expressed in pounds (lb) or ounces (oz) in some nations that employ the Imperial system. However, Newton is the accepted weight measurement unit in scientific and international contexts.

The International System of Units (SI) uses Newton as the primary unit of weight measurement. Sir Isaac Newton, a great physicist who significantly influenced our understanding of classical mechanics, is honored by having his name attached to it. Newton is the force needed to accelerate a mass of one kilogram by one meter per second squared in the SI system.

Hence, the weight is measured in a unit called Newton. The newton is a standard unit of weight measurements.

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Netwtons 1st law of motion

Answers

Answer:

Newton's first law states that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force. This postulate is known as the law of inertia.

Explanation:

when is an object considered to be in motion​

Answers

Answer:

An object is considered to be in motion only when its position changes over time with reference to a point which will be known as orgin

During a circus act, an elderly performer thrills the crowd by catching a cannon ball shot at him. The cannon ball has a mass of 39.0 kg and its horizontal component of velocity is 6.50 m/s just before the 65.0 kg performer catches it. If the performer is initially motionless on nearly frictionless roller skates, what is his speed immediately after catching the cannon ball

Answers

Answer:

[tex]2.4375\ \text{m/s}[/tex]

Explanation:

[tex]m_1[/tex] = Mass of cannon ball = 39 kg

[tex]m_2[/tex] = Mass of performer = 65 kg

[tex]u_1[/tex] = Initial horizontal component of cannon ball's velocity = 6.5 m/s

[tex]u_2[/tex] = Initial horizontal component of performer's velocity = 0

v = Velocity of combined mass

As the momentum of the system is conserved we have

[tex]m_1u_1+m_2u_2=(m_1+m_2)v\\\Rightarrow v=\dfrac{m_1u_1+m_2u_2}{m_1+m_2}\\\Rightarrow v=\dfrac{39\times 6.5+0}{39+65}\\\Rightarrow v=2.4375\ \text{m/s}[/tex]

The speed of the performer immediately after catching the cannon ball is [tex]2.4375\ \text{m/s}[/tex].

An instructor wishes to determine the wavelength of the light in a laser beam. To do so, she directs the beam toward a partition with two tiny slits separated by 0.180 mm. An interference pattern appears on a screen that lies 5.30 m from the slit pair. The instructor's measurements show that two adjacent bright interference fringes lie 1.60 cm apart on the screen. What is the laser's wavelength (in nm) ?

Answers

Answer:

λ = 5.434 x 10⁻⁷ m = 543.4 nm

Explanation:

To solve this problem we can use the formula provided by Young's Double Slit experiment:

[tex]\Delta x = \frac{\lambda L}{d}\\\\\lambda = \frac{\Delta xd}{L}[/tex]

where,

λ = wavelength of light = ?

Δx = distance between adjacent bright fringes = 1.6 cm = 0.016 m

d = slit separation = 0.18 mm = 0.00018 m

L = Distance between slits and screen = 5.3 m

Therefore,

[tex]\lambda = \frac{(0.016\ m)(0.00018\ m)}{5.3\ m}[/tex]

λ = 5.434 x 10⁻⁷ m = 543.4 nm

You push a 1.5 kg ball across a desk for 2 seconds, so that 10 J of work have been done. How much power was produced?

Answer

Answers

Answer:

i need help with the same question

Explanation:

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