Which of the following is the correct expanded form for the series below?
4
Σ-22
»=0
O-1-2-4-8-16
1-2 + 4-8 + 16
O-2-4-8-16
0-2 + 4 - 8 + 16

Which Of The Following Is The Correct Expanded Form For The Series Below?4-22=0O-1-2-4-8-161-2 + 4-8

Answers

Answer 1

Answer:

-1-2-4-8-16

Step-by-step explanation

Answer 2

The solution is, 1-2 + 4-8 + 16, is the correct expanded form for the series Σ-2^n, n = 0 to 4.

What is an exponent in math?

An exponent refers to the number of times a number is multiplied by itself. For example, 2 to the 3rd (written like this: 23) means: 2 x 2 x 2 = 8. 23 is not the same as 2 x 3 = 6. Remember that a number raised to the power of 1 is itself.

here, we have,

given that,

the  series Σ-2^n, n = 0 to 4.

now, we have to find,

the correct expanded form for the series ,

as , we get,

the value of n = 0 to 4

so, putting the value of n = 0,1,2,3,4

we get the series as,

Σ-2^n

= -2^0 + (-2)^1 + (-2)^2 + (-2)^3 + (-2)^4

= 1 -2 + 4 - 8 +16

Hence, The solution is, 1-2 + 4-8 + 16, is the correct expanded form for the series Σ-2^n, n = 0 to 4.

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Answers

Answer:

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Step-by-step explanation:

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Answers

[tex]\frac{2}{4} =\frac{1}{2}[/tex]

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Answers

Answer:

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Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

Step-by-step explanation:

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[tex]{ \dashrightarrow{ \sf { \red{ \frac{2 {x}^{2} - 32}{ {x}^{2} + 10x + 24}}} } } \\ \\ \\ { \dashrightarrow{ \sf{ \red{ \frac{2( {x}^{2} - 16)}{ {x}^{2} +(6x+4x) +24}}}}} \\ \\ \\ { \dashrightarrow{ \sf{ \red{ \frac{2(x + 4)(x - 4)}{ {x}^{2} + 6x + 4x +24}}}}} [/tex]

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Answers

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

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Answers

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Step-by-step explanation:

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Answers

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Answers

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