X + 6 > 18
Please help and show work if can.

Answer:

p = 30, n = 7, a = 15

Step-by-step explanation:

Let's say that p is the amount of stuffies Peyton sold, n is the amount of stuffies Nathan sold, and a is the amount of stuffies Alexandra sold.

Peyton sold two more than four times the stuffies Nathan sold.

This means that: p = 2 + 4n (n = (p-2)/4)

Each stuffie was sold for $2.50. Together they fundraised $130.Alexandra sold half as many stuffies as Peyton.

This means that: a = p/2

Each stuffie was sold for $2.50. Together they fundraised $130.

This means that: 2.50p + 2.50n + 2.50a = 2.50(p + n + a) = 130

We can make the equation in terms of p by substituting a and n.

2.50(p + n + a)

= 2.50(p + (p-2)/4 + p/2)

= 2.50(4p/4 + (p-2)/4 + 2p/4)   [Make the p's have a denominator of 4]

= 2.50((4p + p - 2 + 2p)/4)

= 2.50((7p-2)/4)

= 5/2 * (7p-2)/4

= 5(7p-2)/8

= (35p-10)/8 = 130

35p-10 = 1040

35p = 1050

p = 30

n = (30-2)/4

  = 7

a = 30/2

  = 15

Answer:

[tex]fg(7)=143.95[/tex]

Step-by-step explanation:

We are given that

[tex]f(x) = (x -2)^2 -3[/tex] for x > −2

[tex]g(x) = 2x+6x^{-2}[/tex] for x > 2

We have to find fg(7)

[tex]fg(7)=f(g(7))[/tex]

[tex]=f(2(7)+6(7)^{-2})[/tex]

=[tex]f(14+\frac{6}{49})[/tex]

=[tex]f(\frac{692}{49})[/tex]

692/49>-2

fg(7)=[tex](\frac{692}{49}-2)^2-3[/tex]

=[tex]146.95-3[/tex]

Hence, [tex]fg(7)=143.95[/tex]

Answer:

0.43,9/10,0.92

Step-by-step explanation:

Answer:

0.43, 9/10, 0.92

Step-by-step explanation:

9/10=0.9=0.90

Answer:

The answer is C

Step-by-step explanation:

1-(-7)=8

9-(-3)=12

8/12=2/3

Answer:

c > 20

make a number line that starts with the number 16 and ends with 22.

on the number 20 circle it (don't fill in the circle).

then draw an arrow to the right on top of the circle that you circled.

Step-by-step explanation:

Answer:y=x-5

Step-by-step explanation: Use (y2-y1)/(x2-x1) fill those in and get (4-1)/(9-6) which is 3/3 and that is 1 for the slope. Now fill in y=1x with a given coordinate and try to find the y-intercept so we would do 1=1(6) and we need to make the right side equal to the left so we subtract 5. Ending us with y=x-5.

Answer:

253.75 square feet

Answer:

Substitute your answer for Step 1 into the second equation to solve for Z.

Step-by-step explanation:

Price of a book costing sh.250

reduced to sh.200

percentage decrease on the price = (250-200)/250×100

= 20%

Finishing the angles of the smaller triangle if E is 90 and F is 30 then G needs to be 180-90-30 = 60 degrees.

Angles G and C are supplementary angles which need to equal 180 degrees

Angle c = 180-g = 180-60 = 120

Angle c = 120 degrees.

Answer:

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180° , then Δ EGF

∠ G = 180° - (90 + 30)° = 180° - 120° = 60°

------------------------------------------------------------

c and g are adjacent angles and sum to 180° , then

c + g = 180° , that is

c + 60° = 180° ( subtract 60° from both sides )

c = 120

That is ∠ C = 120°

Answer:

c. 36·x

Step-by-step explanation:

Part A

The details of the circle are;

The area of the circle, A = 12·π cm²

The diameter of the circle, d = [tex]\overline {AB}[/tex]

Given that [tex]\overline {AB}[/tex] is the diameter of the circle, we have;

The length of the arc AB = Half the the length of the circumference of the circle

Therefore, we have;

A = 12·π = π·d²/4 = π·[tex]\overline {AB}[/tex]²/4

Therefore;

12 = [tex]\overline {AB}[/tex]²/4

4 × 12 = [tex]\overline {AB}[/tex]²

[tex]\overline {AB}[/tex]² = 48

[tex]\overline {AB}[/tex] = √48 = 4·√3

[tex]\overline {AB}[/tex] = 4·√3

The circumference of the circle, C = π·d = π·[tex]\overline {AB}[/tex]

Arc AB = Half the the length of the circumference of the circle = C/2

Arc AB = C/2 = π·[tex]\overline {AB}[/tex]/2

[tex]\overline {AB}[/tex] = 4·√3

∴ C/2 = π·4·√3/2 = 2·√3·π

The length of arc AB = 2·√3·π cm

Part B

The given parameters are;

The length of [tex]\overline {OF}[/tex] = The length of [tex]\overline {FB}[/tex]

Angle D = angle B

The radius of the circle = 6·x

The measure of arc EF = 60°

The required information = The perimeter of triangle DOB

We have;

Given that the base angles of the triangles DOB are equal, we have that ΔDOB is an isosceles triangle, therefore;

The length of [tex]\overline {OD}[/tex] = The length of [tex]\overline {OB}[/tex]

The length of [tex]\overline {OB}[/tex] = [tex]\overline {OF}[/tex] + [tex]\overline {FB}[/tex] = [tex]\overline {OF}[/tex] + [tex]\overline {OF}[/tex] = 2 × [tex]\overline {OF}[/tex]

∴ The length of [tex]\overline {OD}[/tex] = 2 × [tex]\overline {OF}[/tex] = The length of [tex]\overline {OB}[/tex]

Given that arc EF = 60°, and the point 'O' is the center of the circle, we have;

∠EOF = The measure of arc EF = 60° = ∠DOB

Therefore, in ΔDOB, we have;

∠D + ∠B = 180° - ∠DOB = 180° - 60° = 120°

∵ ∠D = ∠B, we have;

∠D + ∠B = ∠D + ∠D = 2 × ∠D = 120°

∠D = ∠B = 120°/2 = 60°

All three interior angles of ΔDOB = 60°

∴ ΔDOB is an equilateral triangle and all sides of ΔDOB are equal

Therefore;

The length of [tex]\overline {OD}[/tex] = The length of [tex]\overline {OB}[/tex] = The length of [tex]\overline {DB}[/tex]  = 2 × [tex]\overline {OF}[/tex]

The perimeter of ΔDOB = The length of [tex]\overline {OD}[/tex] + The length of [tex]\overline {OB}[/tex] + The length of [tex]\overline {DB}[/tex] = 2 × [tex]\overline {OF}[/tex] + 2 × [tex]\overline {OF}[/tex] + 2 × [tex]\overline {OF}[/tex] = 6 × [tex]\overline {OF}[/tex]

∴ The perimeter of ΔDOB = 6 × [tex]\overline {OF}[/tex]

The radius of the circle = [tex]\overline {OF}[/tex] = 6·x

∴ The perimeter of ΔDOB = 6 × 6·x = 36·x

Answer:

width is 1 cm

Step-by-step explanation:

The SA of a rectangular prism is SA = 2(lw + wh + hl)

We are given the length, the height, and the SA, and we need to find the width. So we plug in the known values into this equation:

10 = 2(2w + w + 1*2)

10 = 2(3w+2)

10 = 6w+4

6=6w

w=1

We can check the answer by plugging in all the values into the equation:

10 = 2(2*1+1*1+1*2)

10 = 2(5)

10 = 10

Answer:

x=0

Step-by-step explanation:

4 ( 2.5) ^x = 4

Divide each side by 4

4/4 ( 2.5) ^x = 4/4

( 2.5) ^x = 1

Take the log of each side

log  ( 2.5) ^x =  log (1)

x log ( 2.5) = log 1

x log (2.5) = 0

Divide each side by log (2.5)

x = 0

Answer:

{F, G, H, I, J, K, L, M, N, O, P}

are the points between segment EQ :)

Answer:125√3:6

Step-by-step explanation:

Answer:

$625.6

Step-by-step explanation:

Information about the holiday:

7 night holiday

$340 per person

8% discount if you book before 31 March

Number of people Naseem booked the holiday for = 2

Date of booking of the holiday = 15 February

Total cost of the holiday per person = cost per person - discount before March 31

= $340 - 8% of $340

= 340 - 8/100 * 340

= 340 - 0.08 * 340

= 340 - 27.2

= $312.8

Total cost of the holiday for 2 persons = 2 × Total cost of the holiday per person

= 2 * $312.8

= $625.6

Answer:

Angle N=32

Arc NQ=106

Step-by-step explanation:

Angle N is a inscribed angle of Arc MP so that means Angle N measures 32.

Angle NPQ is a inscribed angle of Arc NQ so that means Arc NQ is twice the measures of NPQ so

Arc NQ=106

Answer:

yes what would u like help with

Answer:

3/5 is expressed as 60% in terms of Percentage.

Let's convert the fraction 3/5 into percent. Now, 60/100 is expressed as 65% in terms of percentage.

Answer:

8 hours

Step-by-step explanation:

In 4 hours she earns 16 dollars

Since this is proportional ( goes through zero), we can multiply by 2

8 hours = 32 dollars

Jada needs to walk the dog for, 8 hours.

4x8 = 32

Answer:

c. the solution is 3 times as large as 6x(365x12)

Step-by-step explanation:

c. the solution is 3 times as large as 6x(365x12)

Answer:

go a head what can i help you with

Answer:

Step-by-step explanation:

[tex]y_A = 9x -3x - 4 \\y_A = 6x - 4\\\\y_B = 12x - 4\\\\y_C = 5x + x - 4\\y_C = 6x -4[/tex]

Standard equation of a line with slope, m and y - intercept b is y = mx + b.

Clearly. for  the second equation has a different coefficient for x.

a ) The coefficient for x , is the slope of the line.

     Though the y - intercept for each equation is same = - 4.

    For example :

  Expression A = 2 , when x = 1

  Expression B = 8 , when x = 1

  Expression C = 2 , when x = 1

b) From above :

        [tex]y_A \ and \ y_C \ are \ the \ same \ expression.[/tex]

c) Expression A and  C are equivalent because the coefficient of x

    is the same  for A and  C.

Answer:

D is the outlier

Step-by-step explanation:

An outlier is a point that is far from the other points

We can draw a line that roughly represents an equation for the points

A,B ,C are all near the line

D is not along the line

I think c because from what remember taking this test

Answer:

140m

Step-by-step explanation:

3/4 = .75

x/.7 = 150/.75

multiply both sides by .7

x = 150/.75 * .7

x = 140m

Answer:

[tex]8 \frac{1}{3} \div 4 \frac{1}{2} = \frac{50}{27} = 1.851 = 1 \frac{23}{27} [/tex]

Answer:

1/3

Step-by-step explanation:

If it was supposed to be a negative answer, there would be negative numbers in the sequence. So that narrows it do to 3 and 1/3. And now we know that 27*3 isn't 9 but 27*1/3=9 and so on.

Answer:

your answer will have to be 3

Step-by-step explanation:

from 27 to 9, we divided by 3

from 9 to 3, we divided by 3

from 1 to 1/3, we divided by 3

from 1/3 to 1/9, we divided by 3

from 1/9 to 1/27, we divided by 3

so basically the common ratio will have to be 3

Given:

[tex]PQRS\sim TUVW[/tex]

In the given figure, PS=x, RS=35, UV=20, VW=25 and TW=15

To find:

The scale factor from PQRS to TUVW.

Solution:

We have,

[tex]PQRS\sim TUVW[/tex]

We know that the corresponding sides of similar figures are proportional. The scale factor is the ratio of one side of image and corresponding side of preimage.

The scale factor is:

[tex]k=\dfrac{VW}{RS}[/tex]

[tex]k=\dfrac{25}{35}[/tex]

[tex]k=\dfrac{5}{7}[/tex]

Therefore, the scale factor from PQRS to TUVW is [tex]k=\dfrac{5}{7}[/tex].